## Engage NY Eureka Math 1st Grade Module 4 Lesson 12 Answer Key

### Eureka Math Grade 1 Module 4 Lesson 12 Sprint Answer Key

A

Write the missing number. Pay attention to the + and – signs.

Question 1.

3 + ☐ = 4

Answer:1

Given two numbers are 3 and 4

Considering the missing number as x

Then

3+x=4

x=4-3

x=1

Question 2.

1 + ☐ = 4

Answer:3

Given two numbers are 1 and 4

Considering the missing number as x

Then

1+x=4

x=4-1

x=3

Question 3.

4 – 1 = ☐

Answer:3

Given two numbers are 1 and 4

By removing 1 from 4 we get 3

4-1=3

Question 4.

4 – 3 = ☐

Answer:1

Given two numbers are 3 and 4

By removing 3 from 4 we get 1

4-3=1

Question 5.

3 + ☐ = 5

Answer:2

Given two numbers are 3 and 5

Considering the missing number as x

Then

3+x=5

x=5-3

x=2

Question 6.

2 + ☐ = 5

Answer:3

Given two numbers are 2 and 5

Considering the missing number as x

Then

2+x=5

x=5-2

x=3

Question 7.

5 – 2 = ☐

Answer:3

Given two numbers are 5 and 2

5-2=3

Question 8.

5 – 3 = ☐

Answer:2

Given two numbers are 5 and 3

By removing 3 from 5 we get 2

5-3=2

Question 9.

4 + ☐ = 6

Answer:2

Given two numbers are 6 and 4

Considering the missing number as x

Then

4+x=6

x=6-4

x=2

Question 10.

2 + ☐ = 6

Answer:4

Given two numbers are 2 and 6

Considering the missing number as x

Then

2+x=6

x=6-2

x=4

Question 11.

6 – 2 = ☐

Answer:4

Given two numbers are 2 and 6

By removing 2 from 6 we get 4

6-2=4

Question 12.

6 – 4 = ☐

Answer:2

Given two numbers are 6 and 4

By removing 4 from 6 we get 2

6-4=2

Question 13.

6 – 3 = ☐

Answer:3

Given two numbers are 6 and 3

By removing 3 from 6 we get 3

6-3=3

Question 14.

3 + ☐ = 6

Answer:3

Given two numbers are 3 and 6

Considering the missing number as x

Then

3+x=6

x=6-3

x=3

Question 15.

6 – ☐ = 3

Answer:3

Given two numbers are 3 and 6

Considering the missing number as x

Then

6-x=3

x=6-3

x=3

Question 16.

3 + ☐ = 7

Answer:4

Given two numbers are 3 and 7

Considering the missing number as x

Then

3+x=7

x=7-3

x=4

Question 17.

7 = 4 + ☐

Answer:3

Given two numbers are 7 and 4

Considering the missing number as x

Then

7=4+x

x=7-4

x=3

Question 18.

7 – 4 = ☐

Answer:3

Given two numbers are 7 and 4

By removing 4 from 7 we get 3

7-4=3

Question 19.

7 – 3 = ☐

Answer:4

Given two numbers are 7 and 3

By removing 3 from 7 we get 4

7-3=4

Question 20.

3 + ☐ = 8

Answer:5

Given two numbers are 3 and 8

Considering the missing number as x

Then

3+x=8

x=8-3

x=5

Question 21.

8 = 5 + ☐

Answer:3

Given two numbers are 8 and 5

Considering the missing number as x

Then

8=5+x

x=8+5

x=3

Question 22.

☐ = 8 – 5

Answer:3

Given two numbers are 8 and 5

By removing 5 from 8 we get 3

3=8-5

Question 23.

☐ = 8 – 3

Answer:5

Given two numbers are 8 and 3

By removing 3 from 8 we get 5

5=8-3

Question 24.

3 + ☐ = 9

Answer:6

Given two numbers are 3 and 9

Considering the missing number as x

Then

3+x=9

x=9-3

x=6

Question 25.

9 = 6 + ☐

Answer:3

Given two numbers are 9 and 6

Considering the missing number as x

Then

9=6+x

x=9-6

x=3

Question 26.

☐ = 9 – 6

Answer:3

Given two numbers are 9 and 6

By removing 6 from 9 we get 3

3=9-6

Question 27.

☐ = 9 – 3

Answer:6

Given two numbers are 9 and 3

By removing 3 from 9 we get 6

6=9-3

Question 28.

9 – 4 = ☐ + 2

Answer:3

LHS :-

Given two numbers are 9 and 4

By removing 4 from 9 we get 5

9-4=5

RHS:-

Lets consider missing number as x

LHS=x+2

Since LHS=5

5=x+2

x=5-2

x=3

Verification:

9-4=3+2

5=5

LHS=RHS

Hence proved

Question 29.

☐ + 3 = 9 – 3

Answer:3

RHS:-

Given two numbers are 9 and 3

By removing 3 from 9 we get 6

9-3=6

LHS:-

Lets consider missing number as x

x+3=RHS

Since RHS=6

x+3=6

x=6-3

x=3

Verification:

3+3=9-3

6=6

LHS=RHS

Hence proved

Question 30.

☐ – 7 = 8 – 6

Answer:9

RHS:-

Given two numbers are 8 and 6

By removing 6 from 8 we get 2

8-6=2

LHS:-

Lets consider missing number as x

x-7=RHS

Since RHS=2

x-7=2

x=2+7

x=9

Verification:

9- 7 = 8 – 6

2=2

LHS=RHS

Hence proved

B

Write the missing number. Pay attention to the + and – signs.

Question 1.

4 + ☐ = 4

Answer:0

Given two numbers are 4 and 4

Lets consider the missing number as x

4+x=4

x=4-4

x=0

Question 2.

0 + ☐ = 4

Answer:4

Given two numbers are 0 and 4

Lets consider the missing number as x

0+x=4

x=4-0

x=4

Question 3.

4 – 0 = ☐

Answer:4

Given two numbers are 0 and 4

By removing 0 from 4 we get 4

4-0=4

Question 4.

4 – 4 = ☐

Answer:0

Given two numbers are 4 and 4

By removing 4 from 4 we get 0

4-4=0

Question 5.

4 + ☐ = 5

Answer:1

Given two numbers are 5 and 4

Considering the missing number as x

Then

4+x=5

x=5-4

x=1

Question 6.

1 + ☐ = 5

Answer:4

Given two numbers are 1 and 5

Considering the missing number as x

Then

1+x=5

x=5-1

x=4

Question 7.

5 – 1 = ☐

Answer:4

Given two numbers are 1 and 5

By removing 1 from 5 we get 4

5-1=4

Question 8.

5 – 4 = ☐

Answer:1

Given two numbers are 5 and 4

By removing 5 from 4 we get 1

5-4=1

Question 9.

5 + ☐ = 6

Answer:1

Given two numbers are 5 and 6

Considering the missing number as x

Then

5+x=6

x=6-5

x=1

Question 10.

1 + ☐ = 6

Answer:5

Given two numbers are 1 and 6

Considering the missing number as x

Then

1+x=6

x=6-1

x=5

Question 11.

6 – 1 = ☐

Answer:5

Given two numbers are 1 and 6

By removing 1 from 6 we get 5

6-1=5

Question 12.

6 – 5 = ☐

Answer:1

Given two numbers are 6 and 5

By removing 6 from 5 we get 1

6-5=1

Question 13.

2 + ☐ = 6

Answer:4

Given two numbers are 6 and 2

Considering the missing number as x

Then

2+x=6

x=6-2

x=4

Question 14.

4 + ☐ = 6

Answer:2

Given two numbers are 6 and 4

Considering the missing number as x

Then

4+x=6

x=6-4

x=2

Question 15.

6 – 4 = ☐

Answer:2

Given two numbers are 6 and 4

By removing 4 from 6 we get 2

6-4=2

Question 16.

2 + ☐ = 7

Answer:5

Given two numbers are 2 and 7

Considering the missing number as x

Then

2+x=7

x=7-2

x=5

Question 17.

7 = 5 + ☐

Answer:2

Given two numbers are 7 and 5

Considering the missing number as x

Then

7=5+x

x=7-5

x=2

Question 18.

7 – 5 = ☐

Answer:2

Given two numbers are 7 and 5

By removing 5 from 7 we get 2

7-5=2

Question 19.

7 – 2 = ☐

Answer:5

Given two numbers are 7 and 2

By removing 7 from 2 we get 5

7-2=5

Question 20.

2 + ☐ = 8

Answer:6

Given two numbers are 2 and 8

Considering the missing number as x

Then

2+x=8

x=8-2

x=6

Question 21.

8 = 6 + ☐

Answer:2

Given two numbers are 8 and 6

Considering the missing number as x

Then

8=6-x

x=8-6

x=2

Question 22.

☐ = 8 – 6

Answer:2

Given two numbers are 8 and 6

By removing 6 from 8 we get 2

2=8-6

Question 23.

☐ = 8 – 2

Answer:6

Given two numbers are 8 and 2

By removing 2 from 8 we get 6

6=8-2

Question 24.

2 + ☐ = 9

Answer:7

Given two numbers are 2 and 9

Considering the missing number as x

Then

2+x=9

x=9-2

x=7

Question 25.

9 = 7 + ☐

Answer:2

Given two numbers are 9 and 7

Considering the missing number as x

Then

9=7+x

x=9-7

x=2

Question 26.

☐ = 9 – 7

Answer:2

Given two numbers are 9 and 7

By removing 7 from 9 we get 2

2=9-7

Question 27.

☐ = 9 – 2

Answer:7

Given two numbers are 2 and 9

By removing 2 from 9 we get 7

7=9-2

Question 28.

9 – 3 = ☐ + 3

Answer:3

LHS :-

Given two numbers are 9 and 3

By removing 3 from 9 we get 6

9-3=6

RHS:-

Lets consider missing number as x

LHS=x+3

Since LHS=6

6=x+3

x=6-3

x=3

Verification:

9-3=3+3

6=6

LHS=RHS

Hence proved

Question 29.

☐ + 2 = 9 – 4

Answer:3

RHS:-

Given two numbers are 9 and 4

By removing 4 from 9 we get 5

9-4=5

LHS:-

Lets consider missing number as x

x+2=RHS

Since RHS=5

x+2=5

x=5-2

x=3

Verification:

3+2=9-4

5=5

LHS=RHS

Hence proved

Question 30.

☐ – 6 = 8 – 3

Answer:0

RHS:-

Given two numbers are 8 and 3

By removing 3 from 8 we get 5

8-3=5

LHS:-

Lets consider missing number as x

x-6=RHS

Since RHS=5

x-6=5

x=5+6

x=11

Verification:

11-6=8-3

5=5

LHS=RHS

Hence proved

### Eureka Math Grade 1 Module 4 Lesson 12 Problem Set Answer Key

Fill in the missing numbers to match the picture. Write the matching number bond.

Question 1.

12 + 20 = _____

Answer:32

A number bond is a simple addition of two numbers that add up to give the sum. Using number bonds, one can instantly tell the answer without the need for the actual calculation. Number bonds help us to understand that a whole number is made up of parts.

There are 10 grapes in one bunch and 2 sape

rately in the first image

And in the second image there 2 bunchs of 10 grapes in each

By adding 12 with 20 we get 32

12+20=32

Question 2.

15 + _____ = _____

Answer:25

A number bond is a simple addition of two numbers that add up to give the sum. Using number bonds, one can instantly tell the answer without the need for the actual calculation. Number bonds help us to understand that a whole number is made up of parts.

There are 10 beads in one bracelet and 5 saperately in the first image

And in the second image there 1 bracelet of 10 beads

By adding 15 with 10 we get 25

15+10=25

Question 3.

______ + _______ = ______

Answer:38

A number bond is a simple addition of two numbers that add up to give the sum. Using number bonds, one can instantly tell the answer without the need for the actual calculation. Number bonds help us to understand that a whole number is made up of parts.

There are 10 cubes 8 cubes saperately in the first image

And in the second image there 2 sets of 10 cubes

By adding 18 with 20 we get 38

18+20=38

Question 4.

______ + _______ = ______

Answer:39

A number bond is a simple addition of two numbers that add up to give the sum. Using number bonds, one can instantly tell the answer without the need for the actual calculation. Number bonds help us to understand that a whole number is made up of parts.

There are 2 tens 9 dots saperately in the first image

And in the second image there is 1 ten

By adding 29 with 10 we get 39

29+10=39

Draw using quick tens and ones. Complete the number bond, and write the sum in the place value chart and the number sentence.

Question 5.

19 + 10 = _______

Answer: 29

Given two numbers are 19 and 10

19 is equal to 1 ten and 9 ones

10 is equal to 1 ten and 0 ones

By adding 19 with 10 we get 29

19+10=29

Question 6.

20 + 14 = _______

Answer:34

Given two numbers are 20 and 14

20 is equal to 2 ten and 0 ones

14 is equal to 1 ten and 4 ones

By adding 20 with 14 we get 34

20+14=34

Use arrow notation to solve.

Question 7.

Answer:23

10 more than 13 is 23

Question 8.

Answer:20

20 more than 19 is 39

Question 9.

Answer:16

10 more than 16 is 26

Question 10.

Answer:18

20 more than 18 is 38

Use the dimes and pennies to complete the place value charts and the number sentences.

Question 11.

Answer: 33

In the first set there are 2 dimes and 3 pennies = 23

In the second set there is 1 dime = 10

By adding 23 with 10 we get 33

23+10=33

Question 12.

Answer: 36

In the first set there are 1 dime and 6 pennies = 16

In the second set there is 2 dimes = 20

By adding 20 with 16 we get 36

16+20=36

### Eureka Math Grade 1 Module 4 Lesson 12 Exit Ticket Answer Key

Complete the number sentences. Use quick tens, the arrow way, or coins to show your thinking.

28 + 10 = ________

Answer: 38

In the first set there are 2 dimes and 8 pennies = 28

In the second set there is 1 dime = 10

By adding 28 with 10 we get 38

28+10=38

14 + 20 = _________

Answer: 34

In the first set there are 1 dimes and 4 pennies = 14

In the second set there is 2 dimes = 20

By adding 20 with 14 we get 24

14+20=24

### Eureka Math Grade 1 Module 4 Lesson 12 Homework Answer Key

Fill in the missing numbers to match the picture. Complete the number bond to match.

Question 1.

20 + 13 = _________

Answer:33

A number bond is a simple addition of two numbers that add up to give the sum. Using number bonds, one can instantly tell the answer without the need for the actual calculation. Number bonds help us to understand that a whole number is made up of parts.

There are 2 boxes of pencles in the first image

And in the second image there is 1 box od 10 pencles and 3 pencles saperatly

By adding 20 with 13 we get 33

20+13=33

Question 2.

17 + ____ = _______

Answer:37

A number bond is a simple addition of two numbers that add up to give the sum. Using number bonds, one can instantly tell the answer without the need for the actual calculation. Number bonds help us to understand that a whole number is made up of parts.

There is 1 flowerpot with 10 flowers and 7 flowers sepaterly in the first image

And in the second image there are 2 flowerpots with 10 flowers in each

By adding 17 with 20 we get 37

17+20=37

Question 3.

______ + _______ = _______

Answer:38

A number bond is a simple addition of two numbers that add up to give the sum. Using number bonds, one can instantly tell the answer without the need for the actual calculation. Number bonds help us to understand that a whole number is made up of parts.

There is 1 bag of apple with 10 apples in the first image that is 1 ten and 0 ones

And in the second image there 2 bags with 10 applesand 8 apples saperatly that is 2 tens and 8 ones

By adding 10 with 28 we get 38

10+28=38

Question 4.

______ + _______ = _______

Answer:49

first image has 3 tens and 0 ones which is equal to 30

Second image has 1 tensand 9 ones which is equal to 19

By adding 30 with 19 we get 49

30+19=49

Draw using quick tens and ones. Complete the number bond and the number sentence.

Question 5.

______ + _______ = _______

Answer: 27

First image has 1 ten and 7 ones which is equal to 17

Second image has 1ten and 0 ones

By adding 17 with 10 we get 27

17+10=27

Question 6.

Answer:39

First image has 1 ten and 9 ones which is equal to 19

Second image has 2 ten and 0 ones

By adding 19 with 20 we get 39

19+20=39

Use arrow notation to solve.

Question 7.

Answer:29

10 more than 19 is 29

Question 8.

Answer:39

30 more than 9 is 39

Question 9.

Answer: 28

10 more than 28 is 388

Question 10.

Answer:11

20 more than 11 is 31

Use the dimes and pennies to complete the place value charts.

Question 11.

Answer:20

First image has 1 dime and 8 pennies =18

Second image has 2 dimes =20

By adding 20 with 18 we get 38