Tag: Eureka Math Grade 3 Answer Key

Engage NY Eureka Math 3rd Grade Module 1 Lesson 16 Answer Key

Eureka Math Grade 3 Module 1 Answer Key

Eureka Math Grade 3 Module 1 Lesson 16 Pattern Sheet Answer Key

Multiply.

multiply by 4 (6–10)

Answer:


Explanation:
Multiplied by 4 (6–10) as shown above.

Eureka Math Grade 3 Module 1 Lesson 16 Problem Set Answer Key

Question 1.
Label the array. Then, fill in the blanks below to make true number sentences.

Answer:
6 × 4 = 24

Explanation:
Labeled the array and filled the blanks to make true number sentences as (6 × 4) = (5 × 4) + (1 × 4) = 20 + 4 = 24.
6 × 4 we write as ((5 + 1 ) × 4).
So 6 × 4 = 24.

Answer:

7 X 4 = 28,

Explanation:
Labeled the array and filled the blanks to make true number sentences as (7 × 4) = (5 × 4) + (2 × 4) = 20 + 8 = 28.
7 × 4 we write as ((5 + 2) × 4).
So, 7 × 4 = 28.

Answer:
8 × 4 = 32,

Explanation:
Labeled the array and filled the blanks to make true number sentences as (8 × 4) = (5 × 4) + (3 × 4) = 20 + 12 = 32.
8 × 4 we write as ((5 + 3) × 4).
So, 8 × 4 = 32.

Answer:
9 × 4 = 36,

Explanation:
Labeled the array and filled the blanks to make true number sentences as (9 × 4) = (5 × 4) + (4 × 4) = 20 + 16 = 36.
9 × 4 we write as ((5 + 4) × 4).
So, 9 × 4 = 36.

Question 2.
Match the equal expressions.

Answer:

Explanation:
Matched the equal expressions as
(5 × 4) + (3 × 4) = (5 + 3) × 4 = 8 × 4 = 32,
(5 × 4) + (1 × 4) = (5 + 1) × 4 = 6 × 4 = 24,
(5 × 4) + (4 × 4) = (5 + 4) × 4 = 9 × 4 = 36,
(5 × 4) + (2 × 4) = (5 + 2) × 4 = 7 × 4 = 28.

Question 3.
Nolan draws the array below to find the answer to the multiplication expression 10 × 4. He says, “10 × 4 is just double 5 × 4.” Explain Nolan’s strategy.

Answer:
Nolan’s strategy is 10 × 4 = 2 × (5 × 4) = 2 × 20 = 40, or 10 × 4 = 40,

Explanation:
Given Nolan draws the array  to find the answer to the multiplication expression 10 × 4.
Nolan says, “10 × 4 is just double 5 × 4.” Nolan’s strategy is 10 × 4 = 2 × (5 × 4) = 2 × 20 = 40 is same as 10 × 4 = 40.
So, “10 × 4 is just double 5 × 4.”

Eureka Math Grade 3 Module 1 Lesson 16 Exit Ticket Answer Key

Destiny says, “I can use 5 × 4 to find the answer to 7 × 4.”
Use the array below to explain Destiny’s strategy using words and numbers.

Answer:

Explanation:
Given Destiny says, “I can use 5 × 4 to find the answer to 7 × 4.”
Used the array to explain Destiny’s strategy using words and numbers as to find 7 × 4 we write 7 as (5 + 2) and multiply with 4 as
(5 + 2) × 4 = (5 × 4) + (2 × 4) = 20 + 8 = 28, So we used 5 × 4 to find the answer for 7 × 4.

Eureka Math Grade 3 Module 1 Lesson 16 Homework Answer Key

Question 1.
Label the array. Then, fill in the blanks below to make true number sentences.

Answer:

Explanation:
Labeled the array and filled in the blanks to make true number sentences as 6 × 4 = (5 × 4) + (1 × 4) = 20 + 4 = 24, or 6 × 4 = 24.

Answer:

Explanation:
Labeled the array and filled in the blanks to make true number sentences as 8 × 4 = (5 × 4) + (3 × 4) = 20 + 12 = 32,
or 8 × 4 = 32.

Question 2.
Match the multiplication expressions with their answers.

Answer:

Explanation:
Matched the multiplication expressions with their answers as
4 × 6 = 24,
4 × 7 = 28,
4 × 8 = 32,
4 × 9 = 36.

Question 3.
The array below shows one strategy for solving 9 × 4.
Explain the strategy using your own words.

Answer:

Explanation:
Given the array shown one strategy for solving 9 × 4.
The strategy used is 9 × 4 = (5 × 4) + (4 × 4) = 20 + 16 = 36,
9 × 4 = 36.

Engage NY Eureka Math 3rd Grade Module 7 Lesson 19 Answer Key

Eureka Math Grade 3 Module 7 Lesson 19 Problem Set Answer Key

Question 1.
Use unit square tiles to make rectangles for each given number of unit squares. Complete the charts to show how many rectangles you can make for each given number of unit squares. The first one is done for you. You might not use all the spaces in each chart.

Number of unit squares = 12 Number of rectangles I made:  3
Width	Length
1	12
2	6
3	4

Answer:

Number of unit squares = 13 Number of rectangles I made: _________
Width	Length
1	13

Number of unit squares = 13 Number of rectangles I made: ____1_____
Width	Length
1	13

Number of unit squares = 14 Number of rectangles I made: __2_______
Width	Length
1	14
2	7

Number of unit squares = 15 Number of rectangles I made: _____2____
Width	Length
1	15
2	6

Number of unit squares = 16 Number of rectangles I made: ___3______
Width	Length
1	16
4	5
2	6

Number of unit squares = 17 Number of rectangles I made: _____2____
Width	Length
1	17
2	7

Number of unit squares = 18 Number of rectangles I made: __3______
Width	Length
1	18
3	6
2	9

Explanation:
Perimeter of rectangle = 2 ( Length + Width )

Question 2.
Create a line plot with the data you collected in Problem 1.
Number of Rectangles Made with Unit Squares

Answer:

Explanation:
Number of Rectangles Made with Unit Squares in the Problem 1 are plotted using the number line as X = 1 Rectangle on each number.

Question 3.
Which numbers of unit squares produce three rectangles?
Answer:
The numbers of unit squares produce three rectangles are number 12, number 16 and the number 18.

Explanation:

The numbers of unit squares produce three rectangles are number 12, number 16 and the number 18.

Question 4.
Why do some numbers of unit squares, such as 13, only produce one rectangle?
Answer:
Some numbers likely to produce only one rectangle because they have only one pair of factors that can multiply to make that number. So, among that numbers 13 is one of the numbers.

Explanation:
Some numbers likely to produce only one and itself.  They have only one pair of factors that can multiply to make that number. So, among that numbers 13 is one of the numbers.

Eureka Math Grade 3 Module 7 Lesson 19 Exit Ticket Answer Key

Use unit square tiles to make rectangles for the given number of unit squares. Complete the chart to show how many rectangles you made for the given number of unit squares. You might not use all the spaces in the chart.

Number of unit squares = 20 Number of rectangles I made: _____4____
Width	Length

Answer:

Explanation:
Number of rectangles formed by using 20 square tiles = 4.

Eureka Math Grade 3 Module 7 Lesson 19 Homework Answer Key

Question 1.
Cut out the unit squares at the bottom of the page. Then, use them to make rectangles for each given number of unit squares. Complete the charts to show how many rectangles you can make for each given number of unit squares. You might not use all the spaces in each chart.

Answer:

Number of unit squares = 6 Number of rectangles I made: ____2___
Width	Length
1	6
2	3

Number of unit squares = 7 Number of rectangles I made: ____1_____
Width	Length
1	7

Number of unit squares = 8 Number of rectangles I made: _________
Width	Length
1	8
2	6

Number of unit squares = 9 Number of rectangles I made: _________
Width	Length
1	9
3	3

Number of unit squares = 10 Number of rectangles I made: _________
Width	Length
1	10
2	5

Number of unit squares = 11 Number of rectangles I made: _________
Width	Length
1	11

Answer:
Explanation:
Number of rectangles formed by using given number of square tiles are counted and represented in the table chart.

Question 2.
Create a line plot with the data you collected in Problem 1.
Number of Rectangles Made with Unit Squares

a. Luke looks at the line plot and says that all odd numbers of unit squares produce only 1 rectangle. Do you agree? Why or why not?
b. How many X’s would you plot for 4 unit squares? Explain how you know.

Answer:
a.  Luke looks at the line plot and says that all odd numbers of unit squares produce only 1 rectangle. No, I disagree with the Luke’s statement because only prime numbers have factors as itself and number one. Here, numbers 7 and 11 are prime numbers not odd numbers, so they have only formed one rectangle.

b. Number of rectangles formed by 4 unit square are only 2 because number 4 has factors as 1 and itself and number 2.

Explanation:
a.
Prime numbers are the positive integers having only two factors, 1 and the integer itself.
Odd numbers are whole numbers that cannot be divided exactly into pairs.

b. Factors of number 4 =( 1, 4 ); ( 2,2 ).
Number of rectangles formed by 4 unit square are only 2 because number 4 has factors as 1 and itself and number 2.

Engage NY Eureka Math 3rd Grade Module 1 Lesson 15 Answer Key

Eureka Math Grade 3 Module 1 Answer Key

Eureka Math Grade 3 Module 1 Lesson 15 Pattern Sheet Answer Key

Multiply.

multiply by 4 (1–5)

Answer:


Explanation:
Multiply by 4 (1–5) the expression as shown above.

Eureka Math Grade 3 Module 1 Lesson 15 Problem Set Answer Key

Question 1.
Label the tape diagrams and complete the equations. Then,
draw an array to represent the problems.

Answer:

Explanation:
Labeled the tape diagram and completed the equations,
Drawn an array to represent the problems as
2 × 4 = 8, 4 × 2 = 8.

Answer:

Explanation:
Labeled the tape diagram and completed the equations,
Drawn an array to represent the problems as
3 × 4 = 12, 4 × 3 = 12.

Answer:

Explanation:
Labeled the tape diagram and completed the equations,
Drawn an array to represent the problems as
7 × 4 = 28, 4 × 7 = 28.

Question 2.
Draw and label 2 tape diagrams to model why the statement in the box is true.

Answer:

Statement in the box is true,

Explanation:
Drawn and labeled 2 tape diagrams to model the statement in the box is true because as  4 × 6 = 24 and 6 × 4 = 24, both have result value as 24, So the statement is true.

Question 3.
Grace picks 4 flowers from her garden. Each flower has 8 petals. Draw and label a tape diagram to show how many petals there are in total.

Answer:
In total there are 32 petals,

Explanation:
Given Grace picks 4 flowers from her garden and each flower has 8 petals. Drawn and labeled a tape diagram as shown above total number of petals are
4 × 8 = 32 petals are there in total.

Question 4.
Michael counts 8 chairs in his dining room. Each chair has 4 legs. How many chair legs are there altogether?

Answer:
There are 32 chair legs altogether,

Explanation:
Given Michael counts 8 chairs in his dining room and each chair has 4 legs, So number of chair legs altogether are 8 × 4 = 32, therefore, there are 32 chair legs altogether.

Eureka Math Grade 3 Module 1 Lesson 15 Exit Ticket Answer Key

Draw and label 2 tape diagrams to show that 4 × 3 = 3 × 4.
Use your diagrams to explain how you know the statement is true.

Answer:

Shown 4 × 3 = 3 X 4 as
4 cups × 3 cups = 12 cups,
3 cups x 4 cups = 12 cups,

Explanation:
Drawn and labeled 2 tape diagrams to show that 4 × 3 = 3 × 4
Used cups to explain the statement is true as taken 4 boxes of 3 cups each and 3 boxes of 4 cups each so that 4 × 3 = 3 × 4, both results values are same 12.

Eureka Math Grade 3 Module 1 Lesson 15 Homework Answer Key

Question 1.
Label the tape diagrams and complete the equations.
Then, draw an array to represent the problems.

Answer:

Explanation:
Labeled the tape diagrams and completed the equations as 4 × 3 = 12, 3 × 4 = 12 and drawn an array of  4 × 3 to represent the problems
as shown above in the picture.

Answer:

Explanation:
Labeled the tape diagrams and completed the equations as 4 × 9 = 36, 9 × 4 = 36 and drawn an array of  4 × 9, 9 × 4 to represent the problems as shown above in the picture.

Answer:

Explanation:
Labeled the tape diagrams and completed the equations as 6 × 4 = 24, 4 × 6 = 24 and drawn an array of  6 × 4, 4 × 6 to represent the problems as shown above in the picture.

Question 2.
Seven clowns hold 4 balloons each at the fair. Draw and label a tape diagram to show the total number of balloons the clowns hold.

Answer:
The total number of balloons the clowns hold are 28,

Explanation:
Given seven clowns hold 4 balloons each at the fair.
Drawn and labeled a tape diagram to show the total number of balloons the clowns hold as 7 × 4 = 28 balloons.

Question 3.
George swims 7 laps in the pool each day. How many laps does George swim after 4 days?

Answer:
George swims 28 laps after 4 days.

Explanation:
Given George swims 7 laps in the pool each day. So number of laps George swims after 4 days are
7 × 4 =28 laps.

Engage NY Eureka Math 3rd Grade Module 1 Lesson 14 Answer Key

Eureka Math Grade 3 Module 1 Answer Key

Eureka Math Grade 3 Module 1 Lesson 14 Sprint Answer Key

A
Multiply or Divide by 3

Answer:

Question 1.
2 × 3 =

Answer:
2 × 3 = 6,

Explanation:
Given 2 × 3 we multiply 2 with 3,
we get 6 as 2 × 3 = 6.

Question 2.
3 × 3 =

Answer:
3 × 3 = 9,

Explanation:
Given 3 × 3 we multiply 3 with 3,
we get 9 as 3 × 3 = 9.

Question 3.
4 × 3 =

Answer:
4 × 3 = 12,

Explanation:
Given 4 × 3 we multiply 4 with 3,
we get 12 as 4 × 3 = 12.

Question 4.
5 × 3 =

Answer:
5 × 3 = 15,

Explanation:
Given 5 × 3 we multiply 5 with 3,
we get 15 as 5 × 3 = 15.

Question 5.
1 × 3 =

Answer:
1 × 3 = 6,

Explanation:
Given 1 × 3 we multiply 1 with 3,
we get 3 as 1 × 3 = 3.

Question 6.
6 ÷ 3 =

Answer:
6 ÷ 3 = 2,

Explanation:
Given 6 ÷ 3 we divide 6 by 3,
we get 2 as 6 ÷ 3 = 2.

Question 7.
9 ÷ 3 =

Answer:
9 ÷ 3 = 3,

Explanation:
Given 9 ÷ 3 we divide 9 by 3,
we get 3 as 9 ÷ 3 = 3.

Question 8.
15 ÷ 3 =

Answer:
15 ÷ 3 = 5,

Explanation:
Given 15 ÷ 3 we divide 15 by 3,
we get 5 as 15 ÷ 3 = 5.

Question 9.
3 ÷ 1 =

Answer:
3 ÷ 1 = 3,

Explanation:
Given 3 ÷ 1 we divide 3 by 1,
we get 3 as 3 ÷ 1 = 3.

Question 10.
12 ÷ 3 =

Answer:
12 ÷ 3 = 4,

Explanation:
Given 12 ÷ 3 we divide 12 by 3,
we get 4 as 12 ÷ 3 = 4.

Question 11.
6 × 3 =

Answer:
6 × 3 = 18,

Explanation:
Given 6 × 3 we multiply 6 with 3,
we get 18 as 6 × 3 = 18.

Question 12.
7 × 3 =

Answer:
7 × 3 = 21,

Explanation:
Given 7 × 3 we multiply 7 with 3,
we get 21 as 7 × 3 = 21.

Question 13.
8 × 3 =

Answer:
8 × 3 = 24,

Explanation:
Given 8 × 3 we multiply 8 with 3,
we get 24 as 8 × 3 = 24.

Question 14.
9 × 3 =

Answer:
9 × 3 = 27,

Explanation:
Given 9 × 3 we multiply 9 with 3,
we get 27 as 9 × 3 = 27.

Question 15.
10 × 3 =

Answer:
10 × 3 = 30,

Explanation:
Given 10 × 3 we multiply 10 with 3,
we get 30 as 10 × 3 = 30.

Question 16.
24 ÷ 3 =

Answer:
24 ÷ 3 = 8,

Explanation:
Given 24 ÷ 3 we divide 24 by 3,
we get 8 as 24 ÷ 3 = 8.

Question 17.
21 ÷ 3 =

Answer:
21 ÷ 3 = 7,

Explanation:
Given 21 ÷ 3 we divide 21 by 3,
we get 7 as 27 ÷ 3 = 7.

Question 18.
27 ÷ 3 =

Answer:
27 ÷ 3 = 9,

Explanation:
Given 27 ÷ 3 we divide 27 by 3,
we get 9 as 27 ÷ 3 = 9.

Question 19.
18 ÷ 3 =

Answer:
18 ÷ 3 = 6,

Explanation:
Given 18 ÷ 3 we divide 18 by 3,
we get 6 as 18 ÷ 3 = 6.

Question 20.
30 ÷ 3 =

Answer:
30 ÷ 3 = 10,

Explanation:
Given 30 ÷ 3 we divide 30 by 3,
we get 10 as 30 ÷ 3 = 10.

Question 21.
__ × 3 = 15

Answer:
5 × 3 = 15,

Explanation:
Given __ × 3 = 15, Let us take missing number
as x, So x ×  3 = 15, means x = 15 ÷ 3 = 5,
therefore 5 × 3 = 15.

Question 22.
__ × 3 = 12

Answer:
4 × 3 = 12,
Explanation:
Given __ × 3 = 12, Let us take missing number
as x, So x ×  3 = 12, means x = 12 ÷ 3 = 4,
therefore 4 × 3 = 12.

Question 23.
__ × 3 = 30

Answer:
10 × 3 = 30,

Explanation:
Given __ × 3 = 30, Let us take missing number
as x, So x ×  3 = 30, means x = 30 ÷ 3 = 10,
therefore 10 × 3 = 30.

Question 24.
__ × 3 = 6

Answer:
2 × 3 = 6,

Explanation:
Given __ × 3 = 6, Let us take missing number
as x, So x ×  3 = 6, means x = 6 ÷ 3 = 2,
therefore 2 × 3 = 6.

Question 25.
__ × 3 = 9

Answer:
3 × 3 = 9,

Explanation:
Given __ × 3 = 9, Let us take missing number
as x, So x ×  3 = 9, means x = 9 ÷ 3 = 3,
therefore 3 × 3 = 9.

Question 26.
30 ÷ 3 =

Answer:
30 ÷ 3 = 10,

Explanation:
Given 30 ÷ 3 we divide 30 by 3,
we get 10 as 30 ÷ 3 = 10.

Question 27.
15 ÷ 3 =

Answer:
15 ÷ 3 = 5,

Explanation:
Given 15 ÷ 3 we divide 15 by 3,
we get 5 as 15 ÷ 3 = 5.

Question 28.
3 ÷ 1 =

Answer:
3 ÷ 1 = 3,

Explanation:
Given 3 ÷ 1 we divide 3 by 1,
we get 3 as 3 ÷ 1 = 3.

Question 29.
6 ÷ 3 =

Answer:
6 ÷ 3 = 2,

Explanation:
Given 6 ÷ 3 we divide 6 by 3,
we get 2 as 6 ÷ 3 = 2.

Question 30.
9 ÷ 3 =

Answer:
9 ÷ 3 = 3,

Explanation:
Given 9 ÷ 3 we divide 9 by 3,
we get 3 as 9 ÷ 3 = 3.

Question 31.
__ × 3 = 18

Answer:
6 × 3 = 18,

Explanation:
Given __ × 3 = 18, Let us take missing number
as x, So x ×  3 = 18, means x = 18 ÷ 3 = 6,
therefore 6 × 3 = 18.

Question 32.
__ × 3 = 21

Answer:
7 × 3 = 21,

Explanation:
Given __ × 3 = 21, Let us take missing number
as x, So x ×  3 = 21, means x = 21 ÷ 3 = 7,
therefore 7 × 3 = 21.

Question 33.
__ × 3 = 27

Answer:
9 × 3 = 27,

Explanation:
Given __ × 3 = 27, Let us take missing number
as x, So x ×  3 = 27, means x = 27 ÷ 3 = 9,
therefore 9 × 3 = 27.

Question 34.
__ × 3 = 24

Answer:
8 × 3 = 24,

Explanation:
Given __ × 3 = 24, Let us take missing number
as x, So x ×  3 = 24, means x = 24 ÷ 3 = 8,
therefore 8 × 3 = 24.

Question 35.
21 ÷ 3 =

Answer:
21 ÷ 3 = 7,

Explanation:
Given 21 ÷ 3 we divide 21 by 3,
we get 7 as 21 ÷ 3 = 7.

Question 36.
27 ÷ 3 =

Answer:
27 ÷ 3 = 9,

Explanation:
Given 27 ÷ 3 we divide 27 by 3,
we get 9 as 27 ÷ 3 = 9.

Question 37.
18 ÷ 3 =

Answer:
18 ÷ 3 = 6,

Explanation:
Given 18 ÷ 3 we divide 18 by 3,
we get 6 as 18 ÷ 3 = 6.

Question 38.
24 ÷ 3 =

Answer:
24 ÷ 3 = 8,

Explanation:
Given 24 ÷ 3 we divide 24 by 3,
we get 8 as 24 ÷ 3 = 8.

Question 39.
11 × 3 =

Answer:
11 × 3 = 33,

Explanation:
Given 11 × 3 we multiply 11 with 3,
we get 33 as 11 × 3 = 33.

Question 40.
33 ÷ 3 =

Answer:
33 ÷ 3 = 11,

Explanation:
Given 33 ÷ 3 we divide 33 by 3,
we get 11 as 33 ÷ 3 = 11.

Question 41.
12 × 3 =

Answer:
12 × 3 = 36,

Explanation:
Given 12 × 3 we multiply 12 with 3,
we get 36 as 12 × 3 = 36.

Question 42.
36 ÷ 3 =

Answer:
36 ÷ 3 = 12,

Explanation:
Given 36 ÷ 3 we divide 36 by 3,
we get 12 as 36 ÷ 3 = 12.

Question 43.
13 × 3 =

Answer:
13 × 3 = 39,

Explanation:
Given 13 × 3 we multiply 13 with 3,
we get 39 as 13 × 3 = 39.

Question 44.
39 ÷ 3 =

Answer:
39 ÷ 3 = 13,

Explanation:
Given 39 ÷ 3 we divide 39 by 3,
we get 13 as 39 ÷ 3 = 13.

B
Multiply or Divide by 3

Answer:

Question 1.
1 × 3 =

Answer:
1 × 3 = 3,

Explanation:
Given 1 × 3 we multiply 1 with 3,
we get 3 as 1 × 3 = 3.

Question 2.
2 × 3 =

Answer:
2 × 3 = 6,

Explanation:
Given 2 × 3 we multiply 2 with 3,
we get 6 as 2 × 3 = 6.

Question 3.
3 × 3 =

Answer:
3 × 3 = 9,

Explanation:
Given 3 × 3 we multiply 3 with 3,
we get 9 as 3 × 3 = 9.

Question 4.
4 × 3 =

Answer:
4 × 3 = 12,

Explanation:
Given 4 × 3 we multiply 4 with 3,
we get 12 as 4 × 3 = 12.

Question 5.
5 × 3 =

Answer:
5 × 3 = 15,

Explanation:
Given 5 × 3 we multiply 5 with 3,
we get 15 as 5 × 3 = 15.

Question 6.
9 ÷ 3 =

Answer:
9 ÷ 3 = 3,

Explanation:
Given 9 ÷ 3 we divide 9 by 3,
we get 3 as 9 ÷ 3 = 3.

Question 7.
6 ÷ 3 =

Answer:
6 ÷ 3 = 2,

Explanation:
Given 6 ÷ 3 we divide 6 by 3,
we get 2 as 6 ÷ 3 = 2.

Question 8.
12 ÷ 3 =

Answer:
12 ÷ 3 = 4,

Explanation:
Given 12 ÷ 3 we divide 12 by 3,
we get 4 as 12 ÷ 3 = 4.

Question 9.
3 ÷ 1 =

Answer:
3 ÷ 1 = 3,

Explanation:
Given 3 ÷ 1 we divide 3 by 1,
we get 3 as 3 ÷ 1 = 3.

Question 10.
15 ÷ 3 =

Answer:
15 ÷ 3 = 5,

Explanation:
Given 15 ÷ 3 we divide 15 by 3,
we get 5 as 15 ÷ 3 = 5.

Question 11.
10 × 3 =

Answer:
10 × 3 = 30,

Explanation:
Given 10 × 3 we multiply 10 with 3,
we get 30 as 10 × 3 = 30.

Question 12.
6 × 3 =

Answer:
6 × 3 = 18,

Explanation:
Given 6 × 3 we multiply 6 with 3,
we get 18 as 6 × 3 = 18.

Question 13.
7 × 3 =

Answer:
7 × 3 = 21,

Explanation:
Given 7 × 3 we multiply 7 with 3,
we get 21 as 7 × 3 = 21.

Question 14.
8 × 3 =

Answer:
8 × 3 = 24,

Explanation:
Given 8 × 3 we multiply 8 with 3,
we get 24 as 8 × 3 = 24.

Question 15.
9 × 3 =

Answer:
9 × 3 = 27,

Explanation:
Given 9 × 3 we multiply 9 with 3,
we get 27 as 9 × 3 = 27.

Question 16.
21 ÷ 3 =

Answer:
21 ÷ 3 = 7,

Explanation:
Given 21 ÷ 3 we divide 21 by 3,
we get 7 as 21 ÷ 3 = 7.

Question 17.
18 ÷ 3 =

Answer:
18 ÷ 3 = 6,

Explanation:
Given 18 ÷ 3 we divide 18 by 3,
we get 6 as 18 ÷ 3 = 6.

Question 18.
24 ÷ 3 =

Answer:
24 ÷ 3 = 8,

Explanation:
Given 24 ÷ 3 we divide 24 by 3,
we get 8 as 24 ÷ 3 = 8.

Question 19.
30 ÷ 3 =

Answer:
30 ÷ 3 = 10,

Explanation:
Given 30 ÷ 3 we divide 30 by 3,
we get 10 as 30 ÷ 3 = 10.

Question 20.
27 ÷ 3 =

Answer:
27 ÷ 3 = 9,

Explanation:
Given 27 ÷ 3 we divide 27 by 3,
we get 9 as 27 ÷ 3 = 9.

Question 21.
__ × 3 = 12

Answer:
4 × 3 = 12,

Explanation:
Given __ × 3 = 12, Let us take missing number
as x, So x ×  3 = 12, means x = 12 ÷ 3 = 4,
therefore 4 × 3 = 12.

Question 22.
__ × 3 = 15

Answer:
5 × 3 = 15,

Explanation:
Given __ × 3 = 15, Let us take missing number
as x, So x ×  3 = 15, means x = 15 ÷ 3 = 5,
therefore 5 × 3 = 15.

Question 23.
__ × 3 = 6

Answer:
2 × 3 = 6,

Explanation:
Given __ × 3 = 6, Let us take missing number
as x, So x ×X  3 = 6, means x = 6 ÷ 3 = 2,
therefore 2 × 3 = 6.

Question 24.
__ × 3 = 30

Answer:
10 × 3 = 30,

Explanation:
Given __ × 3 = 30, Let us take missing number
as x, So x ×  3 = 30, means x = 30 ÷ 3 = 10,
therefore 10 × 3 = 30.

Question 25.
__ × 3 = 9

Answer:
3 × 3 = 9,

Explanation:
Given __ × 3 = 9, Let us take missing number
as x, So x ×  3 = 9, means x = 9 ÷ 3 = 3,
therefore 3 × 3 = 9.

Question 26.
6 ÷ 3 =

Answer:
6 ÷ 3 = 2,

Explanation:
Given 6 ÷ 3 we divide 6 by 3,
we get 2 as 6 ÷ 3 = 2.

Question 27.
3 ÷ 1 =

Answer:
3 ÷ 1 = 3,

Explanation:
Given 3 ÷ 1 we divide 3 by 1,
we get 3 as 3 ÷ 1 = 3.

Question 28.
30 ÷ 3 =

Answer:
30 ÷ 3 = 10,

Explanation:
Given 30 ÷ 3 we divide 30 by 3,
we get 10 as 30 ÷ 3 = 10.

Question 29.
15 ÷ 3 =

Answer:
15 ÷ 3 = 5,

Explanation:
Given 15 ÷ 3 we divide 15 by 3,
we get 5 as 15 ÷ 3 = 5.

Question 30.
9 ÷ 3 =

Answer:
9 ÷ 3 = 3,

Explanation:
Given 9 ÷ 3 we divide 9 by 3,
we get 3 as 9 ÷ 3 = 3.

Question 31.
__ × 3 = 18

Answer:
6 × 3 = 18,

Explanation:
Given __ × 3 = 18, Let us take missing number
as x, So x ×  3 = 18, means x = 18 ÷ 3 = 6,
therefore 6 × 3 = 18.

Question 32.
__ × 3 = 24

Answer:
8 × 3 = 24,

Explanation:
Given __ × 3 = 24, Let us take missing number
as x, So x ×  3 = 24, means x = 24 ÷ 3 = 8,
therefore 8 × 3 = 24.

Question 33.
__ × 3 = 27

Answer:
9 × 3 = 27,

Explanation:
Given __ × 3 = 27, Let us take missing number
as x, So x ×  3 = 27, means x = 27 ÷ 3 = 9,
therefore 9 × 3 = 27.

Question 34.
__ × 3 = 21

Answer:
7 × 3 = 21,

Explanation:
Given __ × 3 = 21, Let us take missing number
as x, So x ×  3 = 21, means x = 21 ÷ 3 = 7,
therefore 7 × 3 = 21.

Question 35.
24 ÷ 3 =

Answer:
24 ÷ 3 = 8,

Explanation:
Given 24 ÷ 3 we divide 24 by 3,
we get 8 as 24 ÷ 3 = 8.

Question 36.
27 ÷ 3 =

Answer:
27 ÷ 3 = 9,

Explanation:
Given 27 ÷ 3 we divide 27 by 3,
we get 9 as 27 ÷ 3 = 9.

Question 37.
18 ÷ 3 =

Answer:
18 ÷ 3 = 6,

Explanation:
Given 18 ÷ 3 we divide 18 by 3,
we get 6 as 18 ÷ 3 = 6.

Question 38.
21 ÷ 3 =

Answer:
21 ÷ 3 = 7,

Explanation:
Given 21 ÷ 3 we divide 21 by 3,
we get 7 as 21 ÷ 3 = 7.

Question 39.
11 × 3 =

Answer:
11 × 3 = 33,

Explanation:
Given 11 × 3 we multiply 11 with 3,
we get 33 as 11 × 3 = 33.

Question 40.
33 ÷ 3 =

Answer:
33 ÷ 3 = 11,

Explanation:
Given 33 ÷ 3 we divide 33 by 3,
we get 11 as 33 ÷ 3 = 11.

Question 41.
12 × 3 =

Answer:
12 × 3 = 36,

Explanation:
Given 12 × 3 we multiply 12 with 3,
we get 36 as 12 × 3 = 36.

Question 42.
36 ÷ 3 =

Answer:
36 ÷ 3 = 12,

Explanation:
Given 36 ÷ 3 we divide 36 by 3,
we get 12 as 36 ÷ 3 = 12.

Question 43.
13 × 3 =

Answer:
13 × 3 = 39,

Explanation:
Given 13 × 3 we multiply 13 with 3,
we get 39 as 13 × 3 = 39.

Question 44.
39 ÷ 3 =

Answer:
39 ÷ 3 = 13,

Explanation:
Given 39 ÷ 3 we divide 39 by 3,
we get 13 as 39 ÷ 3 = 13.

Eureka Math Grade 3 Module 1 Lesson 14 Problem Set Answer Key

Question 1.
Skip-count by fours. Match each answer to the appropriate expression.

Answer:

Skipped-counts by fours.
Matched each answer to the appropriate expression as
4 = 1 × 4,
8 = 2 × 4,
12 = 3 × 4,
16 = 4 × 4,
20 = 5 × 4,
24 = 6 × 4,
28 = 7 × 4,
32 = 8 × 4,
36 = 9 × 4,
40 = 10 × 4.

Question 2.
Mr. Schmidt replaces each of the 4 wheels on 7 cars.
How many wheels does he replace? Draw and label a tape diagram to solve.
Mr. Schmidt replaces _____28______ wheels.

Answer:
Mr. Schmidt replaces 28 wheels on 7 cars,

Explanation:
Given Mr. Schmidt replaces each of the 4 wheels on 7 cars.
Drawn and labeled a tape diagram to solve how many wheels he replaced as shown above, So the number of wheels replaced are
7 × 4 = 28, therefore, Mr. Schmidt replaces 28 wheels.

Question 3.
Trina makes 4 bracelets. Each bracelet has 6 beads.
Draw and label a tape diagram to show the total number of beads Trina uses.

Answer:
Trina uses 24 beads to make 4 bracelets,

Explanation:
Given Trina makes 4 bracelets. Each bracelet has 6 beads.
Draw and label a tape diagram to show the total number of beads Trina uses as 4 X 6 =24 beads.

Question 4.
Find the total number of sides on 5 rectangles.

Answer:
Total number of sides on 5 rectangles are 20 side,

Explanation:
We know a rectangle has 4 sides, So number of sides on 5 rectangles are 5 × 4 = 20 sides.

Eureka Math Grade 3 Module 1 Lesson 14 Exit Ticket Answer Key

Arthur has 4 boxes of chocolates. Each box has 6 chocolates inside. How many chocolates does Arthur have altogether? Draw and label a tape diagram to solve.

Eureka Math Grade 3 Module 1 Lesson 14 Homework Answer Key

Question 1.
Skip-count by fours. Match each answer to the appropriate expression.

Answer:

Skipped-counts by fours.
Matched each answer to the appropriate expression as
4 = 1 × 4,
8 = 2 × 4,
12 = 3 × 4,
16 = 4 × 4,
20 = 5 × 4,
24 = 6 × 4,
28 = 7 × 4,
32 = 8 × 4,
36 = 9 × 4,
40 = 10 × 4.

Question 2.
Lisa places 5 rows of 4 juice boxes in the refrigerator.
Draw an array and skip-count to find the total number of juice boxes.
There are ____20_______ juice boxes in total.

Answer:
The total number of juice boxes are 20,

Explanation:
Given Lisa places 5 rows of 4 juice boxes in the refrigerator.
Drawn an array and skipped-count for finding the total
number of juice boxes are as 5 × 4 = 20 juice boxes in total.

Question 3.
Six folders are placed on each table. How many folders are there on 4 tables? Draw and label a tape diagram to solve.

Answer:
There are 24 folders on 4 tables,

Explanation:
Given Six folders are placed on each table. So number of folders are there on 4 tables are 4 X 6 = 24,
Drawn and labeled a tape diagram to solve as shown above,
Therefore, there are 24 folders on 4 tables.

Question 4.
Find the total number of corners on 8 squares.

Answer:
The total number of corners on 8 squares is 32,

Explanation:
We know a square has 4 corners,

So 8 squares will have 8 × 4 = 32 corners,
therefore, the total number of corners on 8 squares is 32.

Engage NY Eureka Math 3rd Grade Module 1 Lesson 13 Answer Key

Eureka Math Grade 3 Module 1 Answer Key

Eureka Math Grade 3 Module 1 Lesson 13 Sprint Answer Key

A
Multiply or Divide by 2

Answer:

Question 1.
2 × 2 =

Answer:
2 × 2 = 4

Explanation:
Given 2 × 2 we multiply 2 with 2,
we get 4 as 2 × 2 = 4.

Question 2.
3 × 2 =
Answer:
3 × 2 = 6,

Explanation:
Given 3 × 2 we multiply 3 with 2,
we get 6 as 3 × 2 = 6.

Question 3.
4 × 2 =

Answer:
4 × 2 = 8,

Explanation:
Given 4 × 2 we multiply 4 with 2,
we get 8 as 4 × 2 = 8.

Question 4.
5 × 2 =

Answer:
5 × 2 = 10,
Explanation:
Given 5 × 2 we multiply 5 with 2,
we get 10 as 5 × 2 = 10.

Question 5.
1 × 2 =

Answer:
1 × 2 = 2,

Explanation:
Given 1 × 2 we multiply 1 with 2,
we get 2 as 1 × 2 = 2.

Question 6.
4 ÷ 2 =

Answer:
4 ÷ 2 = 2,

Explanation:
Given 4 ÷ 2 we divide 4 by 2,
we get 2 as 4 ÷ 2 = 2.

Question 7.
6 ÷ 2 =

Answer:
6 ÷ 2 = 3,
Explanation:
Given 6 ÷ 2 we divide 6 by 2,
we get 3 as 6 ÷ 2 = 3.

Question 8.
10 ÷ 2 =

Answer:
10 ÷ 2 = 5,

Explanation:
Given 10 ÷ 2 we divide 10 by 2,
we get 5 as 10 ÷ 2 = 5.

Question 9.
2 ÷ 1 =

Answer:
2 ÷ 1 = 2,

Explanation:
Given 2 ÷ 1 we divide 2 by 1,
we get 2 as 2 ÷ 1 = 2.

Question 10.
8 ÷ 2 =

Answer:
8 ÷ 2 = 4,

Explanation:
Given 8 ÷ 2 we divide 8 by 2,
we get 4 as 8 ÷ 2 = 4.

Question 11.
6 × 2 =

Answer:
6 × 2 = 12,

Explanation:
Given 6 × 2 we multiply 6 with 2,
we get 12 as 6 × 2 = 12.

Question 12.
7 × 2 =

Answer:
7 × 2 = 14,
Explanation:
Given 7 × 2 we multiply 7 with 2,
we get 14 as 7 × 2 = 14.

Question 13.
8 × 2 =

Answer:
8 × 2 = 16,

Explanation:
Given 8 × 2 we multiply 8 with 2,
we get 16 as 8 × 2 = 16.

Question 14.
9 × 2 =

Answer:
9 × 2 = 18,

Explanation:
Given 9 × 2 we multiply 9 with 2,
we get 18 as 9 × 2 = 18.

Question 15.
10 × 2 =

Answer:
10 × 2 = 20,

Explanation:
Given 10 × 2 we multiply 10 with 2,
we get 20 as 10 × 2 = 20.

Question 16.
16 ÷ 2 =
16 ÷ 2 = 8,

Explanation:
Given 16 ÷ 2 we divide 16 by 2,
we get 8 as 16 ÷ 2 = 8.

Question 17.
14 ÷ 2 =
14 ÷ 2 = 7,

Explanation:
Given 14 ÷ 2 we divide 14 by 2,
we get 7 as 14 ÷ 2 = 7.

Question 18.
18 ÷ 2 =

Answer:
18 ÷ 2 = 9,

Explanation:
Given 18 ÷ 2 we divide 18 by 2,
we get 9 as 18 ÷ 2 = 9.

Question 19.
12 ÷ 2 =

Answer:
12 ÷ 2 = 6,

Explanation:
Given 12 ÷ 2 we divide 12 by 2,
we get 6 as 12 ÷ 2 = 6.

Question 20.
20 ÷ 2 =

Answer:
20 ÷ 2 = 10,

Explanation:
Given 20 ÷ 2 we divide 20 by 2,
we get 10 as 20 ÷ 2 = 10.

Question 21.
__ × 2 = 10

Answer:
5 × 2 = 10,

Explanation:
Given __ × 2 = 10, Let us take missing number
as ×, So 5 × 2 = 10, means x = 10 ÷ 2 = 5,
therefore 5 × 2 = 10.

Question 22.
__ × 2 = 12

Answer:
6 × 2 = 12,

Explanation:
Given __ × 2 = 12, Let us take missing number as x, So 6 × 2 = 12, means x = 12 ÷ 2 = 6,
therefore 6 × 2 = 12.

Question 23.
__ × 2 = 20

Answer:
10 × 2 = 20,

Explanation:
Given __ × 2 = 20, Let us take missing number as x, So x × 2 = 20, means x = 20 ÷ 2 = 10,
therefore 10 × 2 = 20.

Question 24.
__ × 2 = 4

Answer:
2 × 2 = 4,

Explanation:
Given __ × 2 = 4, Let us take missing number as x, So x × 2 = 4, means x = 4 ÷ 2 = 2,
therefore 2 × 2 = 4.

Question 25.
__ × 2 = 6

Answer:
3 × 2 = 6,

Explanation:
Given __ × 2 = 6, Let us take missing number as x, So x × 2 = 6, means x = 6 ÷ 2 = 3,
therefore 3 × 2 = 6.

Question 26.
20 ÷ 2 =

Answer:
20 ÷ 2 = 10,

Explanation:
Given 20 ÷ 2 we divide 20 by 2,
we get 10 as 20 ÷ 2 = 10.

Question 27.
10 ÷ 2 =

Answer:
10 ÷ 2 = 5,

Explanation:
Given 10 ÷ 2 we divide 10 by 2,
we get 5 as 10 ÷ 2 = 5.

Question 28.
2 ÷ 1 =

Answer:
2 ÷ 1 = 2,

Explanation:
Given 2 ÷ 1 we divide 2 by 1,
we get 2 as 2 ÷ 1 = 2.

Question 29.
4 ÷ 2 =

Answer:
4 ÷ 2 = 2,

Explanation:
Given 4 ÷ 2 we divide 4 by 2,
we get 2 as 4 ÷ 2 = 2.

Question 30.
6 ÷ 2 =

Answer:
6 ÷ 2 = 3,

Explanation:
Given 6 ÷ 2 we divide 6 by 2,
we get 3 as 6 ÷ 2 = 3.

Question 31.
__ × 2 = 12

Answer:
6 × 2 = 12,

Explanation:
Given __ × 2 = 12, Let us take missing number
as x, So x × 2 = 12, means x = 12 ÷ 2 = 6,
therefore 6 × 2 = 12.

Question 32.
__ × 2 = 14

Answer:
7 × 2 = 14,

Explanation:
Given __ × 2 = 14, Let us take missing number as x, So x × 2 = 14, means x = 14 ÷ 2 = 7,
therefore 7 × 2 = 14.

Question 33.
__ × 2 = 18

Answer:
9 × 2 = 18,

Explanation:
Given __ × 2 = 18, Let us take missing number as x, So x × 2 = 18, means x = 18 ÷ 2 = 9,
therefore 9 × 2 = 18.

Question 34.
__ × 2 = 16

Answer:
8 × 2 = 16,

Explanation:
Given __ × 2 = 16, Let us take missing number as x, So x × 2 = 16, means x = 16 ÷ 2 = 8,
therefore 8 × 2 = 16.

Question 35.
14 ÷ 2 =

Answer:
14 ÷ 2 = 7,

Explanation:
Given 14 ÷ 2 we divide 14 by 2,
we get 7 as 14 ÷ 2 = 7.

Question 36.
18 ÷ 2 =

Answer:
18 ÷ 2 = 9,

Explanation:
Given 18 ÷ 2 we divide 18 by 2,
we get 9 as 18 ÷ 2 = 9.

Question 37.
12 ÷ 2 =

Answer:
12 ÷ 2 = 6,

Explanation:
Given 12 ÷ 2 we divide 12 by 2,
we get 6 as 12 ÷ 2 = 6.

Question 38.
16 ÷ 2 =

Answer:
16 ÷ 2 = 8,

Explanation:
Given 16 ÷ 2 we divide 16 by 2,
we get 8 as 16 ÷ 2 = 8.

Question 39.
11 × 2 =

Answer:
11 × 2 = 22,

Explanation:
Given 11 × 2 we multiply 11 with 2,
we get 22 as 11 × 2 = 22.

Question 40.
22 ÷ 2 =
22 ÷ 2 = 11,

Explanation:
Given 22 ÷ 2 we divide 22 by 2,
we get 11 as 22 ÷ 2 = 11.

Question 41.
12 × 2 =

Answer:
12 × 2 = 24,

Explanation:
Given 12 × 2 we multiply 12 with 2,
we get 24 as 12 × 2 = 24.

Question 42.
24 ÷ 2 =

Answer:
24 ÷ 2 = 12,

Explanation:
Given 24 ÷ 2 we divide 24 by 2,
we get 12 as 24 ÷ 2 = 12.

Question 43.
14 × 2 =

Answer:
14 × 2 = 28,

Explanation:
Given 14 × 2 we multiply 14 with 2,
we get 28 as 14 × 2 = 28.

Question 44.
28 ÷ 2 =

Answer:
28 ÷ 2 = 14,

Explanation:
Given 28 ÷ 2 we divide 28 by 2,
we get 14 as 28 ÷ 2 = 14.

B
Multiply or Divide by 2

Answer:

Question 1.
1 × 2 =

Answer:
1 × 2 = 2,

Explanation:
Given 1 × 2 we multiply 1 with 2,
we get 2 as 1 × 2 = 2.

Question 2.
2 × 2 =

Answer:
2 × 2 = 4,

Explanation:
Given 2 × 2 we multiply 2 with 2,
we get 4 as 2 × 2 = 4.

Question 3.
3 × 2 =

Answer:
3 × 2 = 6,

Explanation:
Given 3 × 2 we multiply 3 with 2,
we get 6 as 3 × 2 = 6.

Question 4.
4 × 2 =

Answer:
4 × 2 = 8,

Explanation:
Given 4 × 2 we multiply 4 with 2,
we get 8 as 4 × 2 = 8.

Question 5.
5 × 2 =

Answer:
5 × 2 = 10,

Explanation:
Given 5 × 2 we multiply 5 with 2,
we get 10 as 5 × 2 = 10.

Question 6.
6 ÷ 2 =

Answer:
6 ÷ 2 = 3,

Explanation:
Given 6 ÷ 2 we divide 6 by 2,
we get 3 as 6 ÷ 2 = 3.

Question 7.
4 ÷ 2 =

Answer:
4 ÷ 2 = 2,

Explanation:
Given 4 ÷ 2 we divide 4 by 2,
we get 2 as 4 ÷ 2 = 2.

Question 8.
8 ÷ 2 =

Answer:
8 ÷ 2 = 4,

Explanation:
Given 8 ÷ 2 we divide 8 by 2,
we get 4 as 8 ÷ 2 = 4.

Question 9.
2 ÷ 1 =

Answer:
2 ÷ 1 = 2,

Explanation:
Given 2 ÷ 1 we divide 2 by 1,
we get 2 as 2 ÷ 1 = 2.

Question 10.
10 ÷ 2 =

Answer:
10 ÷ 2 = 5,

Explanation:
Given 10 ÷ 2 we divide 10 by 2,
we get 5 as 10 ÷ 2 = 5.

Question 11.
10 × 2 =

Answer:
10 × 2 = 20,

Explanation:
Given 10 × 2 we multiply 10 with 2,
we get 20 as 10 × 2 = 20.

Question 12.
6 × 2 =

Answer:
6 × 2 = 12,

Explanation:
Given 6 × 2 we multiply 6 with 2,
we get 12 as 6 × 2 = 12.

Question 13.
7 × 2 =

Answer:
7 × 2 = 14,

Explanation:
Given 7 × 2 we multiply 7 with 2,
we get 14 as 7 × 2 = 14.

Question 14.
8 × 2 =

Answer:
8 × 2 = 16,

Explanation:
Given 8 × 2 we multiply 8 with 2,
we get 16 as 8 × 2 = 16.

Question 15.
9 × 2 =

Answer:
9 × 2 = 18,

Explanation:
Given 9 × 2 we multiply 9 with 2,
we get 18 as 9 × 2 = 18.

Question 16.
14 ÷ 2 =

Answer:
14 ÷ 2 = 7,

Explanation:
Given 14 ÷ 2 we divide 14 by 2,
we get 7 as 14 ÷ 2 = 7.

Question 17.
12 ÷ 2 =

Answer:
12 ÷ 2 = 6,

Explanation:
Given 12 ÷ 2 we divide 12 by 2,
we get 6 as 12 ÷ 2 = 6.

Question 18.
16 ÷ 2 =

Answer:
16 ÷ 2 = 8,

Explanation:
Given 16 ÷ 2 we divide 16 by 2,
we get 8 as 16 ÷ 2 = 8.

Question 19.
20 ÷ 2 =

Answer:
20 ÷ 2 = 10,

Explanation:
Given 20 ÷ 2 we divide 20 by 2,
we get 10 as 20 ÷ 2 = 10.

Question 20.
18 ÷ 2 =

Answer:
18 ÷ 2 = 9,

Explanation:
Given 18 ÷ 2 we divide 18 by 2,
we get 9 as 18 ÷ 2 = 9.

Question 21.
__ × 2 = 12

Answer:
6 × 2 = 12,

Explanation:
Given __ × 2 = 12, Let us take missing number
as x, So x × 2 = 12, means x = 12 ÷ 2 = 6,
therefore 6 × 2 = 12.

Question 22.
__ × 2 = 10

Answer:
5 × 2 = 10,

Explanation:
Given __ × 2 = 10, Let us take missing number
as x, So x × 2 = 10, means x = 10 ÷ 2 = 5,
therefore 5 × 2 = 10.

Question 23.
__ × 2 = 4

Answer:
2 × 2 = 4,

Explanation:
Given __ × 2 = 4, Let us take missing number
as x, So x × 2 = 4, means x = 4 ÷ 2 = 2,
therefore 2 × 2 = 4.

Question 24.
__ × 2 = 20

Answer:
10 X× 2 = 20,

Explanation:
Given __ × 2 = 20, Let us take missing number
as x, So x × 2 = 20, means x = 20 ÷ 2 = 10,
therefore 10 × 2 = 20.

Question 25.
__ × 2 = 6

Answer:
3 × 2 = 6,

Explanation:
Given __ × 2 = 6, Let us take missing number
as x, So x × 2 = 6, means x = 6 ÷ 2 = 3,
therefore 3 × 2 = 6.

Question 26.
4 ÷ 2 =

Answer:
4 ÷ 2 = 2,

Explanation:
Given 4 ÷ 2 we divide 4 by 2,
we get 2 as 4 ÷ 2 = 2.

Question 27.
2 ÷ 1 =

Answer:
2 ÷ 1 = 2,

Explanation:
Given 2 ÷ 1 we divide 2 by 1,
we get 2 as 2 ÷ 1 = 2.

Question 28.
20 ÷ 2 =

Answer:
20 ÷ 2 = 10,

Explanation:
Given 20 ÷ 2 we divide 20 by 2,
we get 10 as 20 ÷ 2 = 10.

Question 29.
10 ÷ 2 =

Answer:
10 ÷ 2 = 5,

Explanation:
Given 10 ÷ 2 we divide 10 by 2,
we get 5 as 10 ÷ 2 = 5.

Question 30.
6 ÷ 2 =

Answer:
6 ÷ 2 = 3,

Explanation:
Given 6 ÷ 2 we divide 6 by 2,
we get 3 as 6 ÷ 2 = 3.

Question 31.
__ × 2 = 12

Answer:
6 × 2 = 12,

Explanation:
Given __ × 2 = 12, Let us take missing number
as x, So x × 2 = 12, means x = 12 ÷ 2 = 6,
therefore 6 × 2 = 12.

Question 32.
__ × 2 = 16

Answer:
8 × 2 = 16,

Explanation:
Given __ X 2 = 16, Let us take missing number
as x, So x × 2 = 16, means x = 16 ÷ 2 = 8,
therefore 8 × 2 = 16.

Question 33.
__ × 2 = 18

Answer:
9 × 2 = 18,

Explanation:
Given __ × 2 = 18, Let us take missing number
as x, So x × 2 = 18, means x = 18 ÷ 2 = 9,
therefore 9 × 2 = 18.

Question 34.
__ × 2 = 14

Answer:
7 × 2 = 14,

Explanation:
Given __ × 2 = 14, Let us take missing number
as x, So x × 2 = 14, means x = 14 ÷ 2 = 7,
therefore 7 × 2 = 14.

Question 35.
16 ÷ 2 =

Answer:
16 ÷ 2 = 8,

Explanation:
Given 16 ÷ 2 we divide 16 by 2,
we get 8 as 16 ÷ 2 = 8.

Question 36.
18 ÷ 2 =

Answer:
18 ÷ 2 = 9,

Explanation:
Given 18 ÷ 2 we divide 18 by 2,
we get 9 as 18 ÷ 2 = 9.

Question 37.
12 ÷ 2 =

Answer:
12 ÷ 2 = 6,

Explanation:
Given 12 ÷ 2 we divide 12 by 2,
we get 6 as 12 ÷ 2 = 6.

Question 38.
14 ÷ 2 =

Answer:
14 ÷ 2 = 7,

Explanation:
Given 14 ÷ 2 we divide 14 by 2,
we get 7 as 14 ÷ 2 = 7.

Question 39.
11 × 2 =

Answer:
11 × 2 = 22,

Explanation:
Given 11 × 2 we multiply 11 with 2,
we get 22 as 11 × 2 = 22.

Question 40.
22 ÷ 2 =

Answer:
22 ÷ 2 = 11,

Explanation:
Given 22 ÷ 2 we divide 22 by 2,
we get 11 as 22 ÷ 2 = 11.

Question 41.
12 × 2 =

Answer:
12 × 2 = 24,

Explanation:
Given 12 × 2 we multiply 12 with 2,
we get 24 as 12 × 2 = 24.

Question 42.
24 ÷ 2 =

Answer:
24 ÷ 2 = 12,

Explanation:
Given 24 ÷ 2 we divide 24 by 2,
we get 12 as 24 ÷ 2 = 12.

Question 43.
13 × 2 =

Answer:
13 × 2 = 26,

Explanation:
Given 13 × 2 we multiply 13 with 2,
we get 23 as 13 × 2 = 26.

Question 44.
26 ÷ 2 =

Answer:
26 ÷ 2 = 13,

Explanation:
Given 26 ÷ 2 we divide 26 by 2,
we get 26 as 26 ÷ 2 = 13.

Eureka Math Grade 3 Module 1 Lesson 13 Problem Set Answer Key

Question 1.
Fill in the blanks to make true number sentences.

Explanation:
Filled the blanks to make true number sentences as
1 × 3 = 3, 3 ÷ 3 = 1,
2 × 3 = 6, 6 ÷ 3 = 2,
3 × 3 = 9, 9 ÷ 3 = 3,
4 × 3 = 12, 12 ÷ 3 = 4,
5 × 3 = 15, 15 ÷ 3 = 5,
6 × 3 = 18, 18 ÷ 3 = 6,
7 × 3 = 21, 21 ÷ 3 = 7,
8 ×3 = 24, 24 ÷ 3 = 8,
9 × 3 = 27, 27 ÷ 3 = 9,
10 × 3 = 30, 30 ÷ 3 = 10.

Question 2.
Mr. Lawton picks tomatoes from his garden.
He divides the tomatoes into bags of 3.

a. Circle to show how many bags he packs.
Then, skip-count to show the total number of tomatoes.

Answer:

Circled the bags as 4,
The total number of tomatoes are 12,

Explanation:
Given Mr. Lawton picks tomatoes from his garden.
He divides the tomatoes into bags of 3.
a. Circled and showed number of bags he packs
as 12 ÷ 3 = 4 bags,
Then, skipped-count and showed the total number of
tomatoes are 4 × 3 = 12.

b. Draw and label a tape diagram to represent the problem.
____12____ ÷ 3 = ___4 bags__________
Mr. Lawton packs ___4____ bags of tomatoes.

Mr. Lawton packs  4 bags of tomatoes,

Explanation:
Drawn and labeled a tape diagram to represent
the problem as shown above 12 ÷ 3 = 4 bags.

Question 3.
Camille buys a sheet of stamps that measures 15 centimeters long.
Each stamp is 3 centimeters long.
How many stamps does Camille buy?
Draw and label a tape diagram to solve.
Camille buys ____5_____ stamps.

Answer:
Camille buy’s 5 stamps,

Explanation:
Given Camille buys a sheet of stamps that measures
15 centimeters long and each stamp is 3 centimeters long.
So number of  stamps Camille buy’s is 15 ÷ 3 = 5 stamps,
Drawn and labeled a tape diagram to solve as shown above.

Question 4.
Thirty third-graders go on a field trip. They are equally
divided into 3 vans. How many students are in each van?

Answer:
In each van there are 11 students,

Explanation:
Given thirty third-graders go on a field trip and they are equally
divided into 3 vans. So number of  students in each van are
33 ÷ 3 = 11, Therefore in each van there are 11 students.

Question 5.
Some friends spend $24 altogether on frozen yogurt.
Each person pays $3. How many people buy frozen yogurt?

Answer:
8 people buy’s frozen yogurt,

Explanation:
Given some friends spend $24 altogether on frozen yogurt
and each person pays $3, So number of people buy’s frozen
yogurt is $24 ÷ $3 = 8, Therefore 8 people buy’s frozen yogurt.

Eureka Math Grade 3 Module 1 Lesson 13 Exit Ticket Answer Key

Question 1.
Andrea has 21 apple slices. She uses 3 apple slices to
decorate 1 pie. How many pies does Andrea make?
Draw and label a tape diagram to solve.

Answer:
Andrea makes 7 pies,

Explanation:
Given Andrea has 21 apple slices and she uses 3 apple slices to
decorate 1 pie. So number of pies Andrea makes are 21 ÷ 3 = 7,
Drawn and labeled a tape diagram to solve as shown above.

Question 2.
There are 24 soccer players on the field. They form 3 equal teams.
How many players are on each team?

Answer:
Number of players in each team are 8,

Explanation:
Given there are 24 soccer players on the field and
they form 3 equal teams, So number of players in
each team are 24 ÷ 3 = 8 players.

Eureka Math Grade 3 Module 1 Lesson 13 Homework Answer Key

Question 1.
Fill in the blanks to make true number sentences.

Answer:

Explanation:
Filled in the blanks to make true number sentences as
2 × 3 = 6, 6 ÷ 3 = 2, 1 x 3 = 3, 3 ÷ 3 =1,
7 × 3 = 21, 21 ÷ 3 = 7 and 9 × 3 = 27, 27 ÷ 3 = 9.

Question 2.
Ms. Gillette’s pet fish are shown below.
She keeps 3 fish in each tank.

a. Circle to show how many fish tanks she has.
Then, skip-count to find the total number of fish.

Answer:
Circled the fish tanks as 5,
The total number of fishes are 15,

Explanation:
Given Ms. Gillette’s pet fishes, She keeps 3 fish in each tank,
Circled to show number of fish tanks she has.
Then, skipped-count to find the total number of fishes as
5 × 3 = 15.

b. Draw and label a tape diagram to represent the problem.
_____15______ ÷ 3 = ____5______
Ms. Gillette has ___5____ fish tanks.

Answer:
Ms. Gillette has 5 fish tanks.

Explanation:
Drawn and labeled a tape diagram to represent the problem as shown above 15 ÷ 3 = 5 fish tanks.

Question 3.
Juan buys 18 meters of wire. He cuts the wire into pieces that are each 3 meters long. How many pieces of wire does he cut?

Answer:
Juan cuts 6 pieces of wire.

Explanation:
Given Juan buys 18 meters of wire and he cuts the wire into pieces that are each 3 meters long So number of pieces of wire he cuts is 18 ÷ 3 = 6 pieces.

Question 4.
A teacher has 24 pencils. They are divided equally among 3 students. How many pencils does each student get?

Answer:
Each student will get 8 pencils,

Explanation:
Given a teacher has 24 pencils and they are divided equally among 3 students, So number of pencils each student gets is
24 ÷ 3 = 8 pencils.

Question 5.
There are 27 third-graders working in groups of 3. How many groups of third-graders are there?

Answer:
There are 9 groups of third-graders working,

Explanation:
Given there are 27 third-graders working in groups of 3,
So, the number of groups of third-graders working are 27 ÷ 3 = 9 groups.

Engage NY Eureka Math 3rd Grade Module 7 Lesson 18 Answer Key

Eureka Math Grade 3 Module 7 Lesson 18 Problem Set Answer Key

Question 1.
Use unit squares to build as many rectangles as you can with an area of 24 square units. Shade in squares on your grid paper to represent each rectangle that you made with an area of 24 square units.
a. Estimate to draw and label the side lengths of each rectangle you built in Problem 1. Then, find the perimeter of each rectangle. One rectangle is done for you.

P = 24 units + 1 unit + 24 units + 1 unit = 50 units
b. The areas of the rectangles in part (a) above are all the same. What do you notice about the perimeters?
Answer:
a. Perimeter of ABCD rectangle = 22units.
Perimeter of EFGH rectangle = 28units.
Perimeter of IJKL rectangle = 20units.

b. All rectangles drawn in the above1.a are not the same sided figures. They are not having same perimeters because their lengths are different compared to one another.

Explanation:
a.



Perimeter of ABCD rectangle =  Side + Side + Side + Side
= AB + BC + CD + DA
= 8units + 3units + 8units + 3units
= 11units + 8units + 3units
= 19units + 3units
= 22units.
Perimeter of EFGH rectangle = Side + Side + Side + Side
= EF + FG + GH + HE
= 12units + 2units + 12units + 2units
= 14units + 12units + 2units
= 26units + 2units
= 28units.
Perimeter of IJKL rectangle = Side + Side + Side + Side
= IJ + JK + KL + KI
= 6units + 4 units + 6units + 4 units
= 10units + 6units + 4units
= 16units + 4units
= 20units.

b. All rectangles drawn in the above 1a are not the same figures. They are not having same perimeters.

Question 2.
Use unit square tiles to build as many rectangles as you can with an area of 16 square units. Estimate to draw each rectangle below. Label the side lengths.
a. Find the perimeters of the rectangles you built.
b. What is the perimeter of the square? Explain how you found your answer.
Answer:
a. Perimeter of OPQR Rectangle = 14units.
Perimeter of EFGH Rectangle = 34units.

b. Perimeter of ABCD Square= 16units. As, the sides in a square are equal, we can multiple the number of sides into the side value to get the Perimeter of square instead of adding them separately.

Explanation:
a.


Perimeter of OPQR Rectangle = Side + Side + Side + Side
= OP + PQ + QR + RO
= 5units + 2units + 5units + 2units
= 7units + 5units + 2units
= 12units + 2units
= 14units.
Perimeter of EFGH Rectangle = Side + Side + Side + Side
= EF + FG+ GH + HE
= 16units + 1unit + 16units + 1unit
= 17units + 16units + 1unit
= 33units + 1unit
= 34unit.

b.

Perimeter of ABCD Square= 4 × Side
= 4 × 4units
= 16units.

Question 3.
Doug uses square unit tiles to build rectangles with an area of 15 square units. He draws the rectangles as shown below but forgets to label the side lengths. Doug says that Rectangle A has a greater perimeter than Rectangle B. Do you agree? Why or why not?

Answer:
Yes, Doug is correct, the perimeter of rectangle A is greater than the perimeter of the rectangle B because in the appearance itself we notice that rectangle A is bigger in size than that of rectangle B.

Explanation:

Well, comparing the rectangles drawn by Doug its easy to say rectangle A is going to have the greater perimeter that compared to the perimeter of the rectangle B because the size of the rectangle A is bigger than that of rectangle B.

Eureka Math Grade 3 Module 7 Lesson 18 Exit Ticket Answer Key

Tessa uses square-centimeter tiles to build rectangles with an area of 12 square centimeters. She draws the rectangles as shown below. Label the unknown side lengths of each rectangle. Then, find the perimeter of each rectangle.

P = _____

P = _____

P = _____
Answer:
Perimeter of the ABCD Rectangle = 26cm.
Perimeter of the EFGH Rectangle = 12cm.
Perimeter of the IJKL Rectangle = 16cm.

Explanation:

The unknown side are measured by using a ruler by me.
Perimeter of the ABCD Rectangle = Side + Side + Side + Side
= AB + BC + CD + DA
= 12cm + 1cm + 12cm + 1cm
= 13cm + 12cm + 1cm
= 25cm + 1cm
= 26cm.
Perimeter of the EFGH Rectangle = Side + Side + Side + Side
= EF + FG + GH+ HE
= 3cm + 3cm + 3cm + 3cm
= 6cm + 3cm + 3cm
= 9cm + 3cm
= 12cm.
Perimeter of the IJKL Rectangle = Side + Side + Side + Side
IJ + JK + KL + KI
= 6cm + 2cm + 6cm + 2cm
= 8cm + 6cm + 2cm
= 14cm + 2cm
= 16cm.

Eureka Math Grade 3 Module 7 Lesson 18 Homework Answer Key

Question 1.
Shade in squares on the grid below to create as many rectangles as you can with an area of 18 square centimeters.

Answer:
ABCD rectangle
EFGH rectangle
IJKL rectangle.

Explanation:

Question 2.
Find the perimeter of each rectangle in Problem 1 above.
Answer:
Perimeter of the ABCD rectangle = 20units.
Perimeter of the EFGH rectangle = 12units.
Perimeter of the IJKL rectangle = 18units.

Explanation:

Perimeter of the ABCD rectangle = Side + Side + Side + Side
= AB + BC + CD + DA
= 8units + 2units + 8units + 2units
= 10units + 8units + 2units
= 18units + 2units
= 20units.
Perimeter of the EFGH rectangle = Side + Side + Side + Side
= EF + FG + GH+ HE
= 4units + 2units + 4units + 2units
= 6units + 4units + 2units
= 10units + 2units
= 12units.
Perimeter of the IJKL rectangle = Side + Side + Side + Side
= IJ + JK + KL + LI
=  5units + 4units + 5units + 4units
= 9units + 5units + 4units
= 14units + 4units
= 18units.

Question 3.
Estimate to draw as many rectangles as you can with an area of 20 square centimeters. Label the side lengths of each rectangle.
a. Which rectangle above has the greatest perimeter? How do you know just by looking at its shape?
b. Which rectangle above has the smallest perimeter? How do you know just by looking at its shape?
Answer:
a. Among all the three rectangles drawn, through looks  IJKL Rectangles is having greater perimeter compared to other rectangles. We can say that by seeing the length of the rectangles, which length is high that going to have greater perimeter.

b. Among all the three rectangles drawn, through looks  EFGH Rectangles is having smallest perimeter compared to other rectangles. We can say that by seeing the length of the rectangles.

Explanation:
a.

Perimeter of the ABCD Rectangle = Side + Side + Side + Side
= AB + BC + CD + DA
= 7units + 4units + 7units + 4units
= 11units + 7units + 4units
= 18units + 4units
= 22units.
Perimeter of the EFGH Rectangle = Side + Side + Side + Side
= EF + FG + GH + HE
= 5units + 3units + 5units + 3units
= 8units + 5units + 3units
= 13units + 3units
= 16units.
Perimeter of the IJKL Rectangle = Side + Side + Side + Side
= IJ + JK + KL + LI
= 11units + 2units + 11units + 2units
= 13units + 11units + 2units
= 24units + 2units
= 26 units.

b. Among all the three rectangles drawn, through looks  EFGH Rectangles is having the smallest perimeter compared to other rectangles. We can say that by seeing the length of the rectangles, which length is small that going to have the smallest perimeter.

Engage NY Eureka Math 3rd Grade Module 1 Lesson 12 Answer Key

Eureka Math Grade 3 Module 1 Answer Key

Eureka Math Grade 3 Module 1 Lesson 12 Pattern Sheet Answer Key

Multiply.

multiply by 3 (6–10)

Answer:
Multiplied by 3 (6–10) as shown below

Eureka Math Grade 3 Module 1 Lesson 12 Problem Set Answer Key

Question 1.
There are 8 birds at the pet store. Two birds are in each cage.
Circle to show how many cages there are.

8 ÷ 2 = ____4______
There are ___4____ cages of birds.

Answer:
There are 4 cages of birds,

Explanation:
Given there are 8 birds at the pet store and two
birds are in each cage.
The number of cages are 8 ÷ 2 = 4 cages,
Circled to show 4 cages of birds as shown above.

Question 2.
The pet store sells 10 fish. They equally divide the fish into 5 bowls.
Draw fish to find the number in each bowl.

5 × ___2____ = 10
10 ÷ 5 = ___2_____
There are ____2____ fish in each bowl.

Answer:
There are 2 fish in each bowl,

Explanation:
Given the pet store sells 10 fish and they are equally divided the fish into 5 bowls.
Means each bowl has 10 ÷ 5 = 2 fish ( 5 X 2 = 10),
Drawn fish and found the number in each bowl as 2 fish,

Question 3.
Match.

Explanation:
Matched expressions as
10 ÷ 2 = 5,
16 ÷ 2 = 8,
18 ÷ 2 = 9,
14 ÷ 2 = 7 and
12 ÷ 2 = 6.

Question 4.
Laina buys 14 meters of ribbon. She cuts her ribbon into 2 equal pieces. How many meters long is each piece?
Label the tape diagram to represent the problem, including the unknown.

Each piece is ____7______ meters long.

Answer:
Laina’s each piece of ribbon is 7 meters long,

Explanation:
Given Laina buys 14 meters of ribbon and she cuts her ribbon into 2 equal pieces. So number of meters long each piece is 14 ÷ 2 = 7 meters long,
Labeled the tape diagram to represent the problem, including the unknown as shown in the above picture.

Question 5.
Roy eats 2 cereal bars every morning. Each box has a total
of 12 bars. How many days will it take Roy to finish 1 box?

It will take Roy to  finish 1 box in 6 days,

Explanation:
Given Roy eats 2 cereal bars every morning and each box has a total of 12 bars.
So, the Number of days it will take Roy to finish 1 box is
12 ÷ 2 = 6 days.

Question 6.
Sarah and Esther equally share the cost of a present.
The present costs $18. How much does Sarah pay?

Answer:
Sarah pay’s $9 for the present,

Explanation:
Given Sarah and Esther equally share the cost of a present.
The present costs $18, As 2 persons have equally paid for the present each paid $18 ÷ 2 = $9,
Therefore  Sarah pay’s $9 for the present.

Eureka Math Grade 3 Module 1 Lesson 12 Exit Ticket Answer Key

There are 14 mints in 1 box. Cecilia eats 2 mints each day.
How many days does it take Cecilia to eat 1 box of mints?
Draw and label a tape diagram to solve.

It takes Cecilia ____7___ days to eat 1 box of mints.

Cecilia eats 1 box of mints in 7 days,

Explanation:
Given there are 14 mints in 1 box and Cecilia eats 2 mints each day. So, number of days it will take Cecilia to eat 1 box of mints are 14 ÷ 2 = 7 days,
Drawn and labeled a tape diagram to solve as shown above in the picture.

Eureka Math Grade 3 Module 1 Lesson 12 Homework Answer Key

Question 1.
Ten people wait in line for the roller coaster.
Two people sit in each car. Circle to find the total number of cars needed.

10 ÷ 2 = ____5______
There are ___5____ cars needed.

Answer:
Number of cars needed are 5,

Explanation:
Given Ten people wait in line for the roller coaster,
Two people sit in each car. So, the number of cars needed are
10 ÷ 2 = 5, Circled the total 5 number of cars needed as shown above in the picture.

Question 2.
Mr. Ramirez divides 12 frogs equally into 6 groups for students to study. Draw frogs to find the number in each group.
Label known and unknown information on the tape diagram to help you solve.

6 × ___2____ = 12
12 ÷ 6 = ___2____
There are ____2____ frogs in each group.

Answer:
The number of frogs in each group are 2,

Explanation:
Given Mr. Ramirez divides 12 frogs equally into 6 groups for students to study. Drawn frogs to find the number in each group as 12 ÷ 6 = 2 frogs, Labeled known and unknown information on the tape diagram and solved as shown above in the picture.

Question 3.
Match.

Explanation:
Matched expressions as
10 ÷ 2 = 5,
16 ÷ 2 = 8,
18 ÷ 2 = 9 and
14 ÷ 2 = 7 respectively.

Question 4.
Betsy pours 16 cups of water to equally fill 2 bottles. How many cups of water are in each bottle?
Label the tape diagram to represent the problem, including the unknown.
There are ____8_____ cups of water in each bottle.

Answer:
There are 8 cups of water in each bottle,

Explanation:
Given Betsy pours 16 cups of water to equally fill 2 bottles,
So, number of cups of water in each bottle are 16 ÷ 2 = 8 cups,
Labeled the tape diagram to represent the problem including the unknown as shown above in the picture.

Question 5.
An earthworm tunnels 2 centimeters into the ground each day. The earthworm tunnels at about the same pace every day. How many days will it take the earthworm to tunnel 14 centimeters?

Answer:
It will take 7 days for the earthworm to tunnel 14 centimeters into the ground,

Explanation:
Given an earthworm tunnels 2 centimeters into the ground each day and the earthworm tunnels at about the same pace every day, It will take the earthworm to tunnel 14 centimeters is 14 ÷ 2 = 7 days.

Question 6.
Sebastian and Teshawn go to the movies. The tickets cost $16 in total. The boys share the cost equally. How much does Teshawn pay?

Answer:
Teshawn pays $8 cost for the ticket,

Explanation:
Given Sebastian and Teshawn go to the movie and the tickets cost $16 in total. Both the boys share the cost equally means each had cost of $16 ÷ 2 = $8,
Therefore Teshawn pays $8 cost for the ticket.

Engage NY Eureka Math 3rd Grade Module 7 Lesson 17 Answer Key

Eureka Math Grade 3 Module 7 Lesson 17 Problem Set Answer Key

Question 1.
The shapes below are made up of rectangles. Label the unknown side lengths. Then, write and solve an equation to find the perimeter of each shape.
a.

P =
Answer:
Perimeter of the given figure = 16 cm.

Explanation:

Length of the side AB in the given figure = 4 cm
Length of the side BC in the given figure = 2 cm
Length of the side CD in the given figure = 2 cm
Length of the side ED in the given figure = 1 cm
Length of the side EF in the given figure = 2 cm
Length of the side FA in the given figure = 3 cm
Length of the side GD in the given figure = 2 cm
Perimeter of the given figure = Length of the side AB + Length of the side BC + Length of the side CD + Length of the side ED + Length of the side EF + Length of the side FA + Length of the side GD
= 4 cm + 2 cm + 2 cm + 1 cm + 2 cm + 3 cm + 2cm
= 6 cm + 2 cm + 1 cm + 2 cm + 3 cm + 2cm
= 8 cm + 1 cm + 2 cm + 3 cm + 2cm
= 9 cm + 2 cm + 3 cm + 2cm
= 11 cm + 3 cm + 2cm
= 14 cm + 2 cm
= 16 cm.

b.

P =
Answer:
Perimeter of the given figure = 16ft.

Explanation:

Length of the side AB in the given figure = 2ft
Length of the side BC in the given figure = 1ft
Length of the side CD in the given figure = 1ft
Length of the side DE in the given figure = 1ft
Length of the side EF in the given figure = 2ft
Length of the side GF in the given figure = 2ft
Length of the side GH in the given figure = 5ft
Length of the side HA in the given figure = 2ft
Perimeter of the given figure = Length of the side AB + Length of the side BC + Length of the side CD + Length of the side DE + Length of the side EF + Length of the side GF + Length of the side GH + Length of the side HA
= 2ft + 1ft + 1ft + 1ft  + 2ft + 2ft+ 5ft + 2ft
= 3ft + 1ft + 1ft  + 2ft + 2ft+ 5ft + 2ft
= 4ft + 1ft  + 2ft + 2ft+ 5ft + 2ft
= 5ft + 2ft + 2ft+ 5ft + 2ft
= 7ft + 2ft + 5ft + 2ft
= 9ft + 5ft + 2ft
= 14ft + 2ft
= 16ft.

c.

P =
Answer:
Perimeter of the given figure = 24m.

Explanation:

Length of the side AB in the given figure = 2m
Length of the side BC in the given figure = 2m
Length of the side CD in the given figure = 4m
Length of the side DE in the given figure = 2m
Length of the side EF in the given figure = 4m
Length of the side GF in the given figure = 2m
Length of the side GH in the given figure = 2m
Length of the side HA in the given figure = 6m
Perimeter of the given figure = Length of the side AB + Length of the side BC + Length of the side CD + Length of the side DE + Length of the side EF + Length of the side GF + Length of the side GH + Length of the side HA
= 2m + 2m + 4m + 2m + 4m + 2m + 2m + 6m
= 4m + 4m + 2m + 4m + 2m + 2m + 6m
= 8m + 2m + 4m + 2m + 2m + 6m
= 10m + 4m + 2m + 2m + 6m
= 14m + 2m + 2m + 6m
= 16m + 2m + 6m
= 18m + 6m
= 24m.

d.

P =
Answer:
Perimeter of the given figure = 26yd.

Explanation:

Length of the side AB in the given figure = 7yd
Length of the side BC in the given figure = 2yd
Length of the side CD in the given figure = 2yd
Length of the side DE in the given figure = 4yd
Length of the side EF in the given figure = 2yd
Length of the side FG in the given figure = 2yd
Length of the side GH in the given figure = 1yd
Length of the side HI in the given figure = 2yd
Length of the side IJ in the given figure = 2yd
Length of the side JA in the given figure = 2yd
Perimeter of the given figure = Length of the side AB + Length of the side BC + Length of the side CD + Length of the side DE + Length of the side EF + Length of the side FG + Length of the side GH + Length of the side HI + Length of the side IJ + Length of the side JA
= 7yd + 2yd + 2yd + 4yd + 2yd + 2yd + 1yd + 2yd + 2yd + 2yd
= 9yd + 2yd + 4yd + 2yd + 2yd + 1yd + 2yd + 2yd + 2yd
= 11yd + 4yd + 2yd + 2yd + 1yd + 2yd + 2yd + 2yd
= 15yd + 2yd + 2yd + 1yd + 2yd + 2yd + 2yd
= 17yd + 2yd + 1yd + 2yd + 2yd + 2yd
= 19yd + 1yd + 2yd + 2yd + 2yd
= 20yd + 2yd + 2yd + 2yd
= 22yd + 2yd + 2yd
= 24yd + 2yd
= 26yd.

Question 2.
Nathan draws and labels the square and rectangle below. Find the perimeter of the new shape.

Answer:
Perimeter of the  ACDF  new shape = 48cm.

Explanation:

Length of the side of AB in the given figure = 6cm
Length of the side of BC in the given figure = 12cm
Length of the side of CD in the given figure = 6cm
Length of the side of DE in the given figure = 12cm
Length of the side of EF in the given figure = 6cm
Length of the side of FA in the given figure = 6cm
Perimeter of the ACDF new shape = Length of the side of AB + Length of the side of BC + Length of the side of CD + Length of the side of DE + Length of the side of EF + Length of the side of FA
= 6cm + 12cm + 6cm + 12cm + 6cm + 6cm
= 18cm + 6cm + 12cm + 6cm + 6cm
= 24cm + 12cm + 6cm + 6cm
= 36cm + 6cm + 6cm
= 42cm + 6cm
= 48cm.

Question 3.
Label the unknown side lengths. Then, find the perimeter of the shaded rectangle.

Answer:
Perimeter of the DFGC shaded rectangle = 26in.

Explanation:

Shaded rectangle = DFGC
Length of the side of AB of the given figure  = 16in
Length of the side of BG of the given figure = 2in
Length of the side of GC of the given figure = EA – BG = 7in – 2in = 5in.
Length of the side of CD of the given figure= AB – DE = 16in – 8in = 8in.
Length of the side of DE of the given figure= 8in
Length of the side of EA of the given figure= 7in
Length of the side of DF of the given figure= 5in
Length of the side of FG of the given figure= 8in
Perimeter of the DFGC shaded rectangle = Length of the side of FG + Length of the side of GC + Length of the side of CD + Length of the side of DF
= 8in + 5in + 8in + 5in
= 13in + 8in + 5in
= 21in + 5in
= 26in.

Eureka Math 3rd Grade Module 7 Lesson 17 Exit Ticket Answer Key

Label the unknown side lengths. Then, find the perimeter of the shaded rectangle.

Answer:
Perimeter of the FGDE shaded rectangle = 30m.

Explanation:

Shaded rectangle = FGDE
Length of the side AB in the given figure = 12m
Length of the side BC in the given figure = 14m
Length of the side CD in the given figure = 5m
Length of the side DE in the given figure = AB – CD = 12m – 5m = 7m.
Length of the side EF in the given figure = BC – FA = 14m – 6m = 8m.
Length of the side FA in the given figure = 6m
Length of the side FG in the given figure = 7m
Length of the side GD in the given figure = 8m
Perimeter of the FGDE shaded rectangle = Length of the side FG  + Length of the side GD + Length of the side DE + Length of the side EF
= 7m + 8m + 7m + 8m
= 15m + 7m + 8m
= 22m + 8m
= 30m.

Eureka Math Grade 3 Module 7 Lesson 17 Homework Answer Key

Question 1.
The shapes below are made up of rectangles. Label the unknown side lengths. Then, write and solve an equation to find the perimeter of each shape.
a.

P =
Answer:
Perimeter of the given figure = 32m.

Explanation:

Length of the side of AB in the given figure = 4m
Length of the side of BC in the given figure = 9m
Length of the side of CD in the given figure = 7m
Length of the side of DE in the given figure = 2m
Length of the side of EF in the given figure = 3m
Length of the side of FA in the given figure = 7m
Perimeter of the given figure = Length of the side of AB + Length of the side of BC + Length of the side of CD + Length of the side of DE + Length of the side of EF + Length of the side of FA
= 4m + 9m + 7m + 2m + 3m + 7m
= 13m + 7m + 2m + 3m + 7m
= 20m + 2m + 3m + 7m
= 22m + 3m + 7m
= 25m + 7m
= 32m.

b.

P =
Answer:
Perimeter of the given figure = 34 cm.

Explanation:

Length of the side of AB in the given figure = 2 cm
Length of the side of BC in the given figure = 4 cm
Length of the side of CD in the given figure = 4 cm
Length of the side of DE in the given figure = 3 cm
Length of the side of EF in the given figure = 2 cm
Length of the side of FG in the given figure = 5 cm
Length of the side of GH in the given figure = 8 cm
Length of the side of HA in the given figure = 6 cm
Perimeter of the given figure = Length of the side of AB + Length of the side of BC + Length of the side of CD + Length of the side of DE + Length of the side of EF + Length of the side of FG + Length of the side of GH + Length of the side of HA
= 2 cm + 4 cm + 4 cm + 3 cm + 2 cm + 5 cm + 8 cm + 6 cm
= 6 cm + 4 cm + 3 cm + 2 cm + 5 cm + 8 cm + 6 cm
= 10 cm + 3 cm + 2 cm + 5 cm + 8 cm + 6 cm
= 13 cm + 2 cm + 5 cm + 8 cm + 6 cm
= 15 cm + 5 cm + 8 cm + 6 cm
= 20 cm + 8 cm + 6 cm
= 28 cm + 6 cm
= 34 cm.

c.

P =
Answer:
Perimeter of the given figure = 40in.

Explanation:

Length of the side of AB in the given figure = 12in
Length of the side of BC in the given figure = 2in
Length of the side of CD in the given figure = 4in
Length of the side of DE in the given figure = 6in
Length of the side of EF in the given figure = 4in
Length of the side of FG in the given figure = 6in
Length of the side of GH in the given figure = 4in
Length of the side of HA in the given figure = 2in
Perimeter of the given figure = Length of the side of AB  + Length of the side of BC + Length of the side of CD + Length of the side of DE + Length of the side of EF + Length of the side of FG + Length of the side of GH + Length of the side of HA
= 12in + 2in + 4in + 6in + 4in + 6in + 4in + 2in
= 14in + 4in + 6in + 4in + 6in + 4in + 2in
= 18in + 6in + 4in + 6in + 4in + 2in
= 24in + 4in + 6in + 4in + 2in
= 28in + 6in + 4in + 2in
= 34in + 4in + 2in
= 38in + 2in
= 40in.

d.

P =
Answer:
Perimeter of the given figure = 30ft.

Explanation:

Length of the side of AB in the given figure = 8ft
Length of the side of BC in the given figure = 3ft
Length of the side of CD in the given figure = 3ft
Length of the side of DE in the given figure = 1ft
Length of the side of EF in the given figure = 3ft
Length of the side of FG in the given figure = 3ft
Length of the side of GH in the given figure = 2ft
Length of the side of HA in the given figure = 7ft
Perimeter of the given figure = Length of the side of AB + Length of the side of BC + Length of the side of CD  + Length of the side of DE + Length of the side of EF + Length of the side of FG + Length of the side of GH + Length of the side of HA
= 8ft + 3ft + 3ft + 1ft + 3ft + 3ft + 2ft + 7ft
= 11ft + 3ft + 1ft + 3ft + 3ft + 2ft + 7ft
= 14ft + 1ft + 3ft + 3ft + 2ft + 7ft
= 15ft + 3ft + 3ft + 2ft + 7ft
= 18ft + 3ft + 2ft + 7ft
= 21ft + 2ft + 7ft
= 23ft + 7ft
= 30ft.

Question 2.
Sari draws and labels the squares and rectangle below. Find the perimeter of the new shape.

Answer:
Perimeter of the new shape = 72cm.

Explanation:

Length of the side of AB in the given figure = 6cm
Length of the side of BC in the given figure = 18cm
Length of the side of CD in the given figure = 6cm
Length of the side of DE in the given figure = 6cm
Length of the side of EF in the given figure = 6cm
Length of the side of FG in the given figure = 18cm
Length of the side of GH in the given figure = 6cm
Length of the side of HA in the given figure = 6cm
Perimeter of the new shape = Length of the side of AB + Length of the side of BC + Length of the side of CD + Length of the side of DE + Length of the side of EF + Length of the side of FG + Length of the side of GH + Length of the side of HA
= 6cm + 18cm + 6cm + 6cm + 6cm + 18cm + 6cm + 6cm
= 24cm + 6cm + 6cm + 6cm + 18cm + 6cm + 6cm
= 30cm + 6cm + 6cm + 18cm + 6cm + 6cm
= 36cm + 6cm + 18cm + 6cm + 6cm
= 42cm + 18cm + 6cm + 6cm
= 60cm + 6cm + 6cm
= 66cm + 6cm
= 72cm.

Question 3.
Label the unknown side lengths. Then, find the perimeter of the shaded rectangle.

Answer:
Perimeter of the shaded rectangle = 37in.

Explanation:

Shaded rectangle =  BCDG
Length of the side of AB in the given figure = 5in
Length of the side of BC in the given figure =  EF – AB = 18in – 5in = 13in
Length of the side of CD in the given figure = FA – DE = 8in – 2in = 6in
Length of the side of DE in the given figure = 2in
Length of the side of EF in the given figure = 18in
Length of the side of FA in the given figure = 8in
Length of the side of GB in the given figure = 6in
Length of the side of GD in the given figure = 13in
Perimeter of the shaded rectangle = Length of the side of BC+ Length of the side of CD + Length of the side of GD + Length of the side of GB
= 13in + 6in + 13in + 6in
= 19in + 13in + 6in
= 31in + 6in
= 37in.

Engage NY Eureka Math 3rd Grade Module 1 Lesson 11 Answer Key

Eureka Math Grade 3 Module 1 Answer Key

Eureka Math Grade 3 Module 1 Lesson 11 Pattern Sheet Answer Key

Multiply.

Answer:

multiply by 3 (1–5)


Explanation:
Multiplied by 3 (1–5) as shown above.

Eureka Math Grade 3 Module 1 Lesson 11 Problem Set Answer Key

Question 1.
Mrs. Prescott has 12 oranges. She puts 2 oranges in each bag.
How many bags does she have?
a. Draw an array where each column shows a bag of oranges.
___12___ ÷ 2 = ___6_____.

Mrs. Prescott have 6 bags,

Explanation:
Given Mrs. Prescott has 12 oranges and she puts 2 oranges in each bag, So number of bags she have are 12 ÷ 2 = 6 bags,

a. Drawn an array where each column shows a bag of oranges as shown above in the picture.

b. Redraw the oranges in each bag as a unit in the tape diagram.
The first unit is done for you. As you draw, label the diagram with known and unknown information from the problem.

b.

Explanation:
Redrawn the oranges in each bag as a unit in the tape diagram, labeled the diagram with known and unknown information from the problem as 6 × 2 = 12 oranges, or 12 ÷ 2 = 6 bags.

Question 2.
Mrs. Prescott arranges 18 plums into 6 bags. How many plums are in each bag? Model the problem with both an array and a labeled tape diagram. Show each column as the number of plums in each bag.
There are ____3_____ plums in each bag.

Mrs. Prescott arranges 3 plums in each bag,

Explanation:
Given Mrs. Prescott arranges 18 plums into 6 bags.
So number of  plums in each bag are 18 ÷ 6 = 3 bags
Modeled the problem with both an array and labeled tape diagram as shown each column as the number of plums in each bag.

Question 3.
Fourteen shopping baskets are stacked equally in 7 piles.
How many baskets are in each pile? Model the problem with both an array and a labeled tape diagram.
Show each column as the number of baskets in each pile.

There are 2 baskets in each pile,

Explanation:
Given Fourteen shopping baskets are stacked equally in 7 piles.
So number of baskets in each pile are 14 ÷ 7 = 2 baskets,
Modeled the problem with both an array and labeled tape diagram. Shown each column as the number of baskets in each pile.

Question 4.
In the back of the store, Mr. Prescott packs 24 bell peppers equally into 8 bags. How many bell peppers are in each bag?
Model the problem with both an array and labeled tape diagram.
Show each column as the number of bell peppers in each bag.

There are 3 bell peppers in each bag,

Explanation:
Given In the back of the store, Mr. Prescott packs 24 bell peppers equally into 8 bags. So number of  bell peppers in each bag are 24 ÷ 8 = 3 bell peppers,
Modeled the problem with both an array and labeled tape diagram and shown each column as the number of bell peppers in each bag.

Question 5.
Olga saves $2 a week to buy a toy car. The car costs $16.
How many weeks will it take her to save enough to buy the toy?

Answer:
It will take 8 weeks to buy a toy car,

Explanation:
Given Olga saves $2 a week to buy a toy car.
The car costs $16. So number of weeks will it take her to save enough to buy the toy is $16 ÷ $2 = 8 weeks.

Eureka Math Grade 3 Module 1 Lesson 11 Exit Ticket Answer Key

Ms. McCarty has 18 stickers. She puts 2 stickers on each homework paper and has no more left.
How many homework papers does she have?
Model the problem with both an array and a labeled tape diagram.

Ms. McCarty has 9 homework papers,

Explanation:
Given Ms. McCarty has 18 stickers and she puts 2 stickers on each homework paper and has no more left.
So number of homework papers does she have are 18 ÷ 2 = 9 homework papers,
Modeled the problem with both an array and labeled tape diagram as shown above in the picture.

Eureka Math Grade 3 Module 1 Lesson 11 Homework Answer Key

Question 1.
Fred has 10 pears. He puts 2 pears in each basket.
How many baskets does he have?
a. Draw an array where each column represents the number of pears in each basket.
___10____ ÷ 2 = ___5_____

Fred has 5 baskets ,

Explanation:
Given Fred has 10 pears and he puts 2 pears in each basket.
So number of baskets does he have are 10 ÷ 2 = 5 baskets,

a. Drawn an array where each column represents the number of pears in each basket as shown in the picture above.

b. Redraw the pears in each basket as a unit in the tape diagram.
Label the diagram with known and unknown information from the problem.

Redrawn the pears in each basket as a unit in the tape diagram,

Explanation:
Redrawn the pears in each basket as a unit in the tape diagram.
Labeled the diagram with known and unknown information from the problem as 10 ÷ 2 = 5 baskets or 5 × 2 = 10 pears.

Question 2.
Ms. Meyer organizes 15 clipboards equally into 3 boxes.
How many clipboards are in each box? Model the problem with both an array and a labeled tape diagram. Show each column as the number of clipboards in each box.
There are ____5_____ clipboards in each box.

Ms. Meyer organizes 5 clipboards in each box,

Explanation:
Given Ms. Meyer organizes 15 clipboards equally into 3 boxes.
So, Number of clipboards in each box are 15 ÷ 3 = 5,
Modeled the problem with both an array and labeled tape diagram as shown above each column has 5 number of clipboards in each box.

Question 3.
Sixteen action figures are arranged equally on 2 shelves.
How many action figures are on each shelf?
Model the problem with both an array and a labeled tape diagram. Show each column as the number of action figures on each shelf.

There are 8 action figures on each shelf,

Explanation:
Given Sixteen action figures are arranged equally on 2 shelves.
So number of action figures on each shelf are 16 ÷ 2 = 8,
Modeled the problem with both an array and labeled tape diagram as show each column has 8 number of action figures on each shelf.

Question 4.
Jasmine puts 18 hats away. She puts an equal number of hats on 3 shelves. How many hats are on each shelf?
Model the problem with both an array and a labeled tape diagram. Show each column as the number of hats on each shelf.

On each shelf there are 6 hats,

Explanation:
Given Jasmine puts 18 hats away and she puts an equal number of hats on 3 shelves. So number of hats on each shelf are 18 ÷ 3 = 6 hats,
Modeled the problem with both an array and labeled tape diagram as shown each column has 6 number of hats on each shelf.

Question 5.
Corey checks out 2 books a week from the library.
How many weeks will it take him to check out a total of 14 books?

Corey will take 7 weeks to check out total 14 books,

Explanation:
Given Corey checks out 2 books a week from the library.
So, number of weeks it will take Corey to check out a total of 14 books are 14 ÷ 2 = 7 weeks.