## Engage NY Eureka Math 3rd Grade Module 1 Lesson 16 Answer Key

### Eureka Math Grade 3 Module 1 Lesson 16 Pattern Sheet Answer Key

Multiply.

multiply by 4 (6–10)

Explanation:
Multiplied by 4 (6–10) as shown above.

### Eureka Math Grade 3 Module 1 Lesson 16 Problem Set Answer Key

Question 1.
Label the array. Then, fill in the blanks below to make true number sentences.

6 × 4 = 24

Explanation:
Labeled the array and filled the blanks to make true number sentences as (6 × 4) = (5 × 4) + (1 × 4) = 20 + 4 = 24.
6 × 4 we write as ((5 + 1 ) × 4).
So 6 × 4 = 24.

7 X 4 = 28,

Explanation:
Labeled the array and filled the blanks to make true number sentences as (7 × 4) = (5 × 4) + (2 × 4) = 20 + 8 = 28.
7 × 4 we write as ((5 + 2) × 4).
So, 7 × 4 = 28.

8 × 4 = 32,

Explanation:
Labeled the array and filled the blanks to make true number sentences as (8 × 4) = (5 × 4) + (3 × 4) = 20 + 12 = 32.
8 × 4 we write as ((5 + 3) × 4).
So, 8 × 4 = 32.

9 × 4 = 36,

Explanation:
Labeled the array and filled the blanks to make true number sentences as (9 × 4) = (5 × 4) + (4 × 4) = 20 + 16 = 36.
9 × 4 we write as ((5 + 4) × 4).
So, 9 × 4 = 36.

Question 2.
Match the equal expressions.

Explanation:
Matched the equal expressions as
(5 × 4) + (3 × 4) = (5 + 3) × 4 = 8 × 4 = 32,
(5 × 4) + (1 × 4) = (5 + 1) × 4 = 6 × 4 = 24,
(5 × 4) + (4 × 4) = (5 + 4) × 4 = 9 × 4 = 36,
(5 × 4) + (2 × 4) = (5 + 2) × 4 = 7 × 4 = 28.

Question 3.
Nolan draws the array below to find the answer to the multiplication expression 10 × 4. He says, “10 × 4 is just double 5 × 4.” Explain Nolan’s strategy.

Nolan’s strategy is 10 × 4 = 2 × (5 × 4) = 2 × 20 = 40, or 10 × 4 = 40,

Explanation:
Given Nolan draws the array  to find the answer to the multiplication expression 10 × 4.
Nolan says, “10 × 4 is just double 5 × 4.” Nolan’s strategy is 10 × 4 = 2 × (5 × 4) = 2 × 20 = 40 is same as 10 × 4 = 40.
So, “10 × 4 is just double 5 × 4.”

### Eureka Math Grade 3 Module 1 Lesson 16 Exit Ticket Answer Key

Destiny says, “I can use 5 × 4 to find the answer to 7 × 4.”
Use the array below to explain Destiny’s strategy using words and numbers.

Explanation:
Given Destiny says, “I can use 5 × 4 to find the answer to 7 × 4.”
Used the array to explain Destiny’s strategy using words and numbers as to find 7 × 4 we write 7 as (5 + 2) and multiply with 4 as
(5 + 2) × 4 = (5 × 4) + (2 × 4) = 20 + 8 = 28, So we used 5 × 4 to find the answer for 7 × 4.

### Eureka Math Grade 3 Module 1 Lesson 16 Homework Answer Key

Question 1.
Label the array. Then, fill in the blanks below to make true number sentences.

Explanation:
Labeled the array and filled in the blanks to make true number sentences as 6 × 4 = (5 × 4) + (1 × 4) = 20 + 4 = 24, or 6 × 4 = 24.

Explanation:
Labeled the array and filled in the blanks to make true number sentences as 8 × 4 = (5 × 4) + (3 × 4) = 20 + 12 = 32,
or 8 × 4 = 32.

Question 2.
Match the multiplication expressions with their answers.

Explanation:
Matched the multiplication expressions with their answers as
4 × 6 = 24,
4 × 7 = 28,
4 × 8 = 32,
4 × 9 = 36.

Question 3.
The array below shows one strategy for solving 9 × 4.
Explain the strategy using your own words.

Explanation:
Given the array shown one strategy for solving 9 × 4.
The strategy used is 9 × 4 = (5 × 4) + (4 × 4) = 20 + 16 = 36,
9 × 4 = 36.

## Engage NY Eureka Math 3rd Grade Module 1 Lesson 15 Answer Key

### Eureka Math Grade 3 Module 1 Lesson 15 Pattern Sheet Answer Key

Multiply.

multiply by 4 (1–5)

Explanation:
Multiply by 4 (1–5) the expression as shown above.

### Eureka Math Grade 3 Module 1 Lesson 15 Problem Set Answer Key

Question 1.
Label the tape diagrams and complete the equations. Then,
draw an array to represent the problems.

Explanation:
Labeled the tape diagram and completed the equations,
Drawn an array to represent the problems as
2 × 4 = 8, 4 × 2 = 8.

Explanation:
Labeled the tape diagram and completed the equations,
Drawn an array to represent the problems as
3 × 4 = 12, 4 × 3 = 12.

Explanation:
Labeled the tape diagram and completed the equations,
Drawn an array to represent the problems as
7 × 4 = 28, 4 × 7 = 28.

Question 2.
Draw and label 2 tape diagrams to model why the statement in the box is true.

Statement in the box is true,

Explanation:
Drawn and labeled 2 tape diagrams to model the statement in the box is true because as  4 × 6 = 24 and 6 × 4 = 24, both have result value as 24, So the statement is true.

Question 3.
Grace picks 4 flowers from her garden. Each flower has 8 petals. Draw and label a tape diagram to show how many petals there are in total.

In total there are 32 petals,

Explanation:
Given Grace picks 4 flowers from her garden and each flower has 8 petals. Drawn and labeled a tape diagram as shown above total number of petals are
4 × 8 = 32 petals are there in total.

Question 4.
Michael counts 8 chairs in his dining room. Each chair has 4 legs. How many chair legs are there altogether?

There are 32 chair legs altogether,

Explanation:
Given Michael counts 8 chairs in his dining room and each chair has 4 legs, So number of chair legs altogether are 8 × 4 = 32, therefore, there are 32 chair legs altogether.

### Eureka Math Grade 3 Module 1 Lesson 15 Exit Ticket Answer Key

Draw and label 2 tape diagrams to show that 4 × 3 = 3 × 4.
Use your diagrams to explain how you know the statement is true.

Shown 4 × 3 = 3 X 4 as
4 cups × 3 cups = 12 cups,
3 cups x 4 cups = 12 cups,

Explanation:
Drawn and labeled 2 tape diagrams to show that 4 × 3 = 3 × 4
Used cups to explain the statement is true as taken 4 boxes of 3 cups each and 3 boxes of 4 cups each so that 4 × 3 = 3 × 4, both results values are same 12.

### Eureka Math Grade 3 Module 1 Lesson 15 Homework Answer Key

Question 1.
Label the tape diagrams and complete the equations.
Then, draw an array to represent the problems.

Explanation:
Labeled the tape diagrams and completed the equations as 4 × 3 = 12, 3 × 4 = 12 and drawn an array of  4 × 3 to represent the problems
as shown above in the picture.

Explanation:
Labeled the tape diagrams and completed the equations as 4 × 9 = 36, 9 × 4 = 36 and drawn an array of  4 × 9, 9 × 4 to represent the problems as shown above in the picture.

Explanation:
Labeled the tape diagrams and completed the equations as 6 × 4 = 24, 4 × 6 = 24 and drawn an array of  6 × 4, 4 × 6 to represent the problems as shown above in the picture.

Question 2.
Seven clowns hold 4 balloons each at the fair. Draw and label a tape diagram to show the total number of balloons the clowns hold.

The total number of balloons the clowns hold are 28,

Explanation:
Given seven clowns hold 4 balloons each at the fair.
Drawn and labeled a tape diagram to show the total number of balloons the clowns hold as 7 × 4 = 28 balloons.

Question 3.
George swims 7 laps in the pool each day. How many laps does George swim after 4 days?

George swims 28 laps after 4 days.

Explanation:
Given George swims 7 laps in the pool each day. So number of laps George swims after 4 days are
7 × 4 =28 laps.

## Engage NY Eureka Math 3rd Grade Module 1 Lesson 14 Answer Key

### Eureka Math Grade 3 Module 1 Lesson 14 Sprint Answer Key

A
Multiply or Divide by 3

Question 1.
2 × 3 =

2 × 3 = 6,

Explanation:
Given 2 × 3 we multiply 2 with 3,
we get 6 as 2 × 3 = 6.

Question 2.
3 × 3 =

3 × 3 = 9,

Explanation:
Given 3 × 3 we multiply 3 with 3,
we get 9 as 3 × 3 = 9.

Question 3.
4 × 3 =

4 × 3 = 12,

Explanation:
Given 4 × 3 we multiply 4 with 3,
we get 12 as 4 × 3 = 12.

Question 4.
5 × 3 =

5 × 3 = 15,

Explanation:
Given 5 × 3 we multiply 5 with 3,
we get 15 as 5 × 3 = 15.

Question 5.
1 × 3 =

1 × 3 = 6,

Explanation:
Given 1 × 3 we multiply 1 with 3,
we get 3 as 1 × 3 = 3.

Question 6.
6 ÷ 3 =

6 ÷ 3 = 2,

Explanation:
Given 6 ÷ 3 we divide 6 by 3,
we get 2 as 6 ÷ 3 = 2.

Question 7.
9 ÷ 3 =

9 ÷ 3 = 3,

Explanation:
Given 9 ÷ 3 we divide 9 by 3,
we get 3 as 9 ÷ 3 = 3.

Question 8.
15 ÷ 3 =

15 ÷ 3 = 5,

Explanation:
Given 15 ÷ 3 we divide 15 by 3,
we get 5 as 15 ÷ 3 = 5.

Question 9.
3 ÷ 1 =

3 ÷ 1 = 3,

Explanation:
Given 3 ÷ 1 we divide 3 by 1,
we get 3 as 3 ÷ 1 = 3.

Question 10.
12 ÷ 3 =

12 ÷ 3 = 4,

Explanation:
Given 12 ÷ 3 we divide 12 by 3,
we get 4 as 12 ÷ 3 = 4.

Question 11.
6 × 3 =

6 × 3 = 18,

Explanation:
Given 6 × 3 we multiply 6 with 3,
we get 18 as 6 × 3 = 18.

Question 12.
7 × 3 =

7 × 3 = 21,

Explanation:
Given 7 × 3 we multiply 7 with 3,
we get 21 as 7 × 3 = 21.

Question 13.
8 × 3 =

8 × 3 = 24,

Explanation:
Given 8 × 3 we multiply 8 with 3,
we get 24 as 8 × 3 = 24.

Question 14.
9 × 3 =

9 × 3 = 27,

Explanation:
Given 9 × 3 we multiply 9 with 3,
we get 27 as 9 × 3 = 27.

Question 15.
10 × 3 =

10 × 3 = 30,

Explanation:
Given 10 × 3 we multiply 10 with 3,
we get 30 as 10 × 3 = 30.

Question 16.
24 ÷ 3 =

24 ÷ 3 = 8,

Explanation:
Given 24 ÷ 3 we divide 24 by 3,
we get 8 as 24 ÷ 3 = 8.

Question 17.
21 ÷ 3 =

21 ÷ 3 = 7,

Explanation:
Given 21 ÷ 3 we divide 21 by 3,
we get 7 as 27 ÷ 3 = 7.

Question 18.
27 ÷ 3 =

27 ÷ 3 = 9,

Explanation:
Given 27 ÷ 3 we divide 27 by 3,
we get 9 as 27 ÷ 3 = 9.

Question 19.
18 ÷ 3 =

18 ÷ 3 = 6,

Explanation:
Given 18 ÷ 3 we divide 18 by 3,
we get 6 as 18 ÷ 3 = 6.

Question 20.
30 ÷ 3 =

30 ÷ 3 = 10,

Explanation:
Given 30 ÷ 3 we divide 30 by 3,
we get 10 as 30 ÷ 3 = 10.

Question 21.
__ × 3 = 15

5 × 3 = 15,

Explanation:
Given __ × 3 = 15, Let us take missing number
as x, So x ×  3 = 15, means x = 15 ÷ 3 = 5,
therefore 5 × 3 = 15.

Question 22.
__ × 3 = 12

4 × 3 = 12,
Explanation:
Given __ × 3 = 12, Let us take missing number
as x, So x ×  3 = 12, means x = 12 ÷ 3 = 4,
therefore 4 × 3 = 12.

Question 23.
__ × 3 = 30

10 × 3 = 30,

Explanation:
Given __ × 3 = 30, Let us take missing number
as x, So x ×  3 = 30, means x = 30 ÷ 3 = 10,
therefore 10 × 3 = 30.

Question 24.
__ × 3 = 6

2 × 3 = 6,

Explanation:
Given __ × 3 = 6, Let us take missing number
as x, So x ×  3 = 6, means x = 6 ÷ 3 = 2,
therefore 2 × 3 = 6.

Question 25.
__ × 3 = 9

3 × 3 = 9,

Explanation:
Given __ × 3 = 9, Let us take missing number
as x, So x ×  3 = 9, means x = 9 ÷ 3 = 3,
therefore 3 × 3 = 9.

Question 26.
30 ÷ 3 =

30 ÷ 3 = 10,

Explanation:
Given 30 ÷ 3 we divide 30 by 3,
we get 10 as 30 ÷ 3 = 10.

Question 27.
15 ÷ 3 =

15 ÷ 3 = 5,

Explanation:
Given 15 ÷ 3 we divide 15 by 3,
we get 5 as 15 ÷ 3 = 5.

Question 28.
3 ÷ 1 =

3 ÷ 1 = 3,

Explanation:
Given 3 ÷ 1 we divide 3 by 1,
we get 3 as 3 ÷ 1 = 3.

Question 29.
6 ÷ 3 =

6 ÷ 3 = 2,

Explanation:
Given 6 ÷ 3 we divide 6 by 3,
we get 2 as 6 ÷ 3 = 2.

Question 30.
9 ÷ 3 =

9 ÷ 3 = 3,

Explanation:
Given 9 ÷ 3 we divide 9 by 3,
we get 3 as 9 ÷ 3 = 3.

Question 31.
__ × 3 = 18

6 × 3 = 18,

Explanation:
Given __ × 3 = 18, Let us take missing number
as x, So x ×  3 = 18, means x = 18 ÷ 3 = 6,
therefore 6 × 3 = 18.

Question 32.
__ × 3 = 21

7 × 3 = 21,

Explanation:
Given __ × 3 = 21, Let us take missing number
as x, So x ×  3 = 21, means x = 21 ÷ 3 = 7,
therefore 7 × 3 = 21.

Question 33.
__ × 3 = 27

9 × 3 = 27,

Explanation:
Given __ × 3 = 27, Let us take missing number
as x, So x ×  3 = 27, means x = 27 ÷ 3 = 9,
therefore 9 × 3 = 27.

Question 34.
__ × 3 = 24

8 × 3 = 24,

Explanation:
Given __ × 3 = 24, Let us take missing number
as x, So x ×  3 = 24, means x = 24 ÷ 3 = 8,
therefore 8 × 3 = 24.

Question 35.
21 ÷ 3 =

21 ÷ 3 = 7,

Explanation:
Given 21 ÷ 3 we divide 21 by 3,
we get 7 as 21 ÷ 3 = 7.

Question 36.
27 ÷ 3 =

27 ÷ 3 = 9,

Explanation:
Given 27 ÷ 3 we divide 27 by 3,
we get 9 as 27 ÷ 3 = 9.

Question 37.
18 ÷ 3 =

18 ÷ 3 = 6,

Explanation:
Given 18 ÷ 3 we divide 18 by 3,
we get 6 as 18 ÷ 3 = 6.

Question 38.
24 ÷ 3 =

24 ÷ 3 = 8,

Explanation:
Given 24 ÷ 3 we divide 24 by 3,
we get 8 as 24 ÷ 3 = 8.

Question 39.
11 × 3 =

11 × 3 = 33,

Explanation:
Given 11 × 3 we multiply 11 with 3,
we get 33 as 11 × 3 = 33.

Question 40.
33 ÷ 3 =

33 ÷ 3 = 11,

Explanation:
Given 33 ÷ 3 we divide 33 by 3,
we get 11 as 33 ÷ 3 = 11.

Question 41.
12 × 3 =

12 × 3 = 36,

Explanation:
Given 12 × 3 we multiply 12 with 3,
we get 36 as 12 × 3 = 36.

Question 42.
36 ÷ 3 =

36 ÷ 3 = 12,

Explanation:
Given 36 ÷ 3 we divide 36 by 3,
we get 12 as 36 ÷ 3 = 12.

Question 43.
13 × 3 =

13 × 3 = 39,

Explanation:
Given 13 × 3 we multiply 13 with 3,
we get 39 as 13 × 3 = 39.

Question 44.
39 ÷ 3 =

39 ÷ 3 = 13,

Explanation:
Given 39 ÷ 3 we divide 39 by 3,
we get 13 as 39 ÷ 3 = 13.

B
Multiply or Divide by 3

Question 1.
1 × 3 =

1 × 3 = 3,

Explanation:
Given 1 × 3 we multiply 1 with 3,
we get 3 as 1 × 3 = 3.

Question 2.
2 × 3 =

2 × 3 = 6,

Explanation:
Given 2 × 3 we multiply 2 with 3,
we get 6 as 2 × 3 = 6.

Question 3.
3 × 3 =

3 × 3 = 9,

Explanation:
Given 3 × 3 we multiply 3 with 3,
we get 9 as 3 × 3 = 9.

Question 4.
4 × 3 =

4 × 3 = 12,

Explanation:
Given 4 × 3 we multiply 4 with 3,
we get 12 as 4 × 3 = 12.

Question 5.
5 × 3 =

5 × 3 = 15,

Explanation:
Given 5 × 3 we multiply 5 with 3,
we get 15 as 5 × 3 = 15.

Question 6.
9 ÷ 3 =

9 ÷ 3 = 3,

Explanation:
Given 9 ÷ 3 we divide 9 by 3,
we get 3 as 9 ÷ 3 = 3.

Question 7.
6 ÷ 3 =

6 ÷ 3 = 2,

Explanation:
Given 6 ÷ 3 we divide 6 by 3,
we get 2 as 6 ÷ 3 = 2.

Question 8.
12 ÷ 3 =

12 ÷ 3 = 4,

Explanation:
Given 12 ÷ 3 we divide 12 by 3,
we get 4 as 12 ÷ 3 = 4.

Question 9.
3 ÷ 1 =

3 ÷ 1 = 3,

Explanation:
Given 3 ÷ 1 we divide 3 by 1,
we get 3 as 3 ÷ 1 = 3.

Question 10.
15 ÷ 3 =

15 ÷ 3 = 5,

Explanation:
Given 15 ÷ 3 we divide 15 by 3,
we get 5 as 15 ÷ 3 = 5.

Question 11.
10 × 3 =

10 × 3 = 30,

Explanation:
Given 10 × 3 we multiply 10 with 3,
we get 30 as 10 × 3 = 30.

Question 12.
6 × 3 =

6 × 3 = 18,

Explanation:
Given 6 × 3 we multiply 6 with 3,
we get 18 as 6 × 3 = 18.

Question 13.
7 × 3 =

7 × 3 = 21,

Explanation:
Given 7 × 3 we multiply 7 with 3,
we get 21 as 7 × 3 = 21.

Question 14.
8 × 3 =

8 × 3 = 24,

Explanation:
Given 8 × 3 we multiply 8 with 3,
we get 24 as 8 × 3 = 24.

Question 15.
9 × 3 =

9 × 3 = 27,

Explanation:
Given 9 × 3 we multiply 9 with 3,
we get 27 as 9 × 3 = 27.

Question 16.
21 ÷ 3 =

21 ÷ 3 = 7,

Explanation:
Given 21 ÷ 3 we divide 21 by 3,
we get 7 as 21 ÷ 3 = 7.

Question 17.
18 ÷ 3 =

18 ÷ 3 = 6,

Explanation:
Given 18 ÷ 3 we divide 18 by 3,
we get 6 as 18 ÷ 3 = 6.

Question 18.
24 ÷ 3 =

24 ÷ 3 = 8,

Explanation:
Given 24 ÷ 3 we divide 24 by 3,
we get 8 as 24 ÷ 3 = 8.

Question 19.
30 ÷ 3 =

30 ÷ 3 = 10,

Explanation:
Given 30 ÷ 3 we divide 30 by 3,
we get 10 as 30 ÷ 3 = 10.

Question 20.
27 ÷ 3 =

27 ÷ 3 = 9,

Explanation:
Given 27 ÷ 3 we divide 27 by 3,
we get 9 as 27 ÷ 3 = 9.

Question 21.
__ × 3 = 12

4 × 3 = 12,

Explanation:
Given __ × 3 = 12, Let us take missing number
as x, So x ×  3 = 12, means x = 12 ÷ 3 = 4,
therefore 4 × 3 = 12.

Question 22.
__ × 3 = 15

5 × 3 = 15,

Explanation:
Given __ × 3 = 15, Let us take missing number
as x, So x ×  3 = 15, means x = 15 ÷ 3 = 5,
therefore 5 × 3 = 15.

Question 23.
__ × 3 = 6

2 × 3 = 6,

Explanation:
Given __ × 3 = 6, Let us take missing number
as x, So x ×X  3 = 6, means x = 6 ÷ 3 = 2,
therefore 2 × 3 = 6.

Question 24.
__ × 3 = 30

10 × 3 = 30,

Explanation:
Given __ × 3 = 30, Let us take missing number
as x, So x ×  3 = 30, means x = 30 ÷ 3 = 10,
therefore 10 × 3 = 30.

Question 25.
__ × 3 = 9

3 × 3 = 9,

Explanation:
Given __ × 3 = 9, Let us take missing number
as x, So x ×  3 = 9, means x = 9 ÷ 3 = 3,
therefore 3 × 3 = 9.

Question 26.
6 ÷ 3 =

6 ÷ 3 = 2,

Explanation:
Given 6 ÷ 3 we divide 6 by 3,
we get 2 as 6 ÷ 3 = 2.

Question 27.
3 ÷ 1 =

3 ÷ 1 = 3,

Explanation:
Given 3 ÷ 1 we divide 3 by 1,
we get 3 as 3 ÷ 1 = 3.

Question 28.
30 ÷ 3 =

30 ÷ 3 = 10,

Explanation:
Given 30 ÷ 3 we divide 30 by 3,
we get 10 as 30 ÷ 3 = 10.

Question 29.
15 ÷ 3 =

15 ÷ 3 = 5,

Explanation:
Given 15 ÷ 3 we divide 15 by 3,
we get 5 as 15 ÷ 3 = 5.

Question 30.
9 ÷ 3 =

9 ÷ 3 = 3,

Explanation:
Given 9 ÷ 3 we divide 9 by 3,
we get 3 as 9 ÷ 3 = 3.

Question 31.
__ × 3 = 18

6 × 3 = 18,

Explanation:
Given __ × 3 = 18, Let us take missing number
as x, So x ×  3 = 18, means x = 18 ÷ 3 = 6,
therefore 6 × 3 = 18.

Question 32.
__ × 3 = 24

8 × 3 = 24,

Explanation:
Given __ × 3 = 24, Let us take missing number
as x, So x ×  3 = 24, means x = 24 ÷ 3 = 8,
therefore 8 × 3 = 24.

Question 33.
__ × 3 = 27

9 × 3 = 27,

Explanation:
Given __ × 3 = 27, Let us take missing number
as x, So x ×  3 = 27, means x = 27 ÷ 3 = 9,
therefore 9 × 3 = 27.

Question 34.
__ × 3 = 21

7 × 3 = 21,

Explanation:
Given __ × 3 = 21, Let us take missing number
as x, So x ×  3 = 21, means x = 21 ÷ 3 = 7,
therefore 7 × 3 = 21.

Question 35.
24 ÷ 3 =

24 ÷ 3 = 8,

Explanation:
Given 24 ÷ 3 we divide 24 by 3,
we get 8 as 24 ÷ 3 = 8.

Question 36.
27 ÷ 3 =

27 ÷ 3 = 9,

Explanation:
Given 27 ÷ 3 we divide 27 by 3,
we get 9 as 27 ÷ 3 = 9.

Question 37.
18 ÷ 3 =

18 ÷ 3 = 6,

Explanation:
Given 18 ÷ 3 we divide 18 by 3,
we get 6 as 18 ÷ 3 = 6.

Question 38.
21 ÷ 3 =

21 ÷ 3 = 7,

Explanation:
Given 21 ÷ 3 we divide 21 by 3,
we get 7 as 21 ÷ 3 = 7.

Question 39.
11 × 3 =

11 × 3 = 33,

Explanation:
Given 11 × 3 we multiply 11 with 3,
we get 33 as 11 × 3 = 33.

Question 40.
33 ÷ 3 =

33 ÷ 3 = 11,

Explanation:
Given 33 ÷ 3 we divide 33 by 3,
we get 11 as 33 ÷ 3 = 11.

Question 41.
12 × 3 =

12 × 3 = 36,

Explanation:
Given 12 × 3 we multiply 12 with 3,
we get 36 as 12 × 3 = 36.

Question 42.
36 ÷ 3 =

36 ÷ 3 = 12,

Explanation:
Given 36 ÷ 3 we divide 36 by 3,
we get 12 as 36 ÷ 3 = 12.

Question 43.
13 × 3 =

13 × 3 = 39,

Explanation:
Given 13 × 3 we multiply 13 with 3,
we get 39 as 13 × 3 = 39.

Question 44.
39 ÷ 3 =

39 ÷ 3 = 13,

Explanation:
Given 39 ÷ 3 we divide 39 by 3,
we get 13 as 39 ÷ 3 = 13.

### Eureka Math Grade 3 Module 1 Lesson 14 Problem Set Answer Key

Question 1.
Skip-count by fours. Match each answer to the appropriate expression.

Skipped-counts by fours.
Matched each answer to the appropriate expression as
4 = 1 × 4,
8 = 2 × 4,
12 = 3 × 4,
16 = 4 × 4,
20 = 5 × 4,
24 = 6 × 4,
28 = 7 × 4,
32 = 8 × 4,
36 = 9 × 4,
40 = 10 × 4.

Question 2.
Mr. Schmidt replaces each of the 4 wheels on 7 cars.
How many wheels does he replace? Draw and label a tape diagram to solve.
Mr. Schmidt replaces _____28______ wheels.

Mr. Schmidt replaces 28 wheels on 7 cars,

Explanation:
Given Mr. Schmidt replaces each of the 4 wheels on 7 cars.
Drawn and labeled a tape diagram to solve how many wheels he replaced as shown above, So the number of wheels replaced are
7 × 4 = 28, therefore, Mr. Schmidt replaces 28 wheels.

Question 3.
Trina makes 4 bracelets. Each bracelet has 6 beads.
Draw and label a tape diagram to show the total number of beads Trina uses.

Trina uses 24 beads to make 4 bracelets,

Explanation:
Given Trina makes 4 bracelets. Each bracelet has 6 beads.
Draw and label a tape diagram to show the total number of beads Trina uses as 4 X 6 =24 beads.

Question 4.
Find the total number of sides on 5 rectangles.

Total number of sides on 5 rectangles are 20 side,

Explanation:
We know a rectangle has 4 sides, So number of sides on 5 rectangles are 5 × 4 = 20 sides.

### Eureka Math Grade 3 Module 1 Lesson 14 Exit Ticket Answer Key

Arthur has 4 boxes of chocolates. Each box has 6 chocolates inside. How many chocolates does Arthur have altogether? Draw and label a tape diagram to solve.

### Eureka Math Grade 3 Module 1 Lesson 14 Homework Answer Key

Question 1.
Skip-count by fours. Match each answer to the appropriate expression.

Skipped-counts by fours.
Matched each answer to the appropriate expression as
4 = 1 × 4,
8 = 2 × 4,
12 = 3 × 4,
16 = 4 × 4,
20 = 5 × 4,
24 = 6 × 4,
28 = 7 × 4,
32 = 8 × 4,
36 = 9 × 4,
40 = 10 × 4.

Question 2.
Lisa places 5 rows of 4 juice boxes in the refrigerator.
Draw an array and skip-count to find the total number of juice boxes.
There are ____20_______ juice boxes in total.

The total number of juice boxes are 20,

Explanation:
Given Lisa places 5 rows of 4 juice boxes in the refrigerator.
Drawn an array and skipped-count for finding the total
number of juice boxes are as 5 × 4 = 20 juice boxes in total.

Question 3.
Six folders are placed on each table. How many folders are there on 4 tables? Draw and label a tape diagram to solve.

There are 24 folders on 4 tables,

Explanation:
Given Six folders are placed on each table. So number of folders are there on 4 tables are 4 X 6 = 24,
Drawn and labeled a tape diagram to solve as shown above,
Therefore, there are 24 folders on 4 tables.

Question 4.
Find the total number of corners on 8 squares.

The total number of corners on 8 squares is 32,

Explanation:
We know a square has 4 corners,

So 8 squares will have 8 × 4 = 32 corners,
therefore, the total number of corners on 8 squares is 32.

## Engage NY Eureka Math 3rd Grade Module 1 Lesson 13 Answer Key

### Eureka Math Grade 3 Module 1 Lesson 13 Sprint Answer Key

A
Multiply or Divide by 2

Question 1.
2 × 2 =

2 × 2 = 4

Explanation:
Given 2 × 2 we multiply 2 with 2,
we get 4 as 2 × 2 = 4.

Question 2.
3 × 2 =
3 × 2 = 6,

Explanation:
Given 3 × 2 we multiply 3 with 2,
we get 6 as 3 × 2 = 6.

Question 3.
4 × 2 =

4 × 2 = 8,

Explanation:
Given 4 × 2 we multiply 4 with 2,
we get 8 as 4 × 2 = 8.

Question 4.
5 × 2 =

5 × 2 = 10,
Explanation:
Given 5 × 2 we multiply 5 with 2,
we get 10 as 5 × 2 = 10.

Question 5.
1 × 2 =

1 × 2 = 2,

Explanation:
Given 1 × 2 we multiply 1 with 2,
we get 2 as 1 × 2 = 2.

Question 6.
4 ÷ 2 =

4 ÷ 2 = 2,

Explanation:
Given 4 ÷ 2 we divide 4 by 2,
we get 2 as 4 ÷ 2 = 2.

Question 7.
6 ÷ 2 =

6 ÷ 2 = 3,
Explanation:
Given 6 ÷ 2 we divide 6 by 2,
we get 3 as 6 ÷ 2 = 3.

Question 8.
10 ÷ 2 =

10 ÷ 2 = 5,

Explanation:
Given 10 ÷ 2 we divide 10 by 2,
we get 5 as 10 ÷ 2 = 5.

Question 9.
2 ÷ 1 =

2 ÷ 1 = 2,

Explanation:
Given 2 ÷ 1 we divide 2 by 1,
we get 2 as 2 ÷ 1 = 2.

Question 10.
8 ÷ 2 =

8 ÷ 2 = 4,

Explanation:
Given 8 ÷ 2 we divide 8 by 2,
we get 4 as 8 ÷ 2 = 4.

Question 11.
6 × 2 =

6 × 2 = 12,

Explanation:
Given 6 × 2 we multiply 6 with 2,
we get 12 as 6 × 2 = 12.

Question 12.
7 × 2 =

7 × 2 = 14,
Explanation:
Given 7 × 2 we multiply 7 with 2,
we get 14 as 7 × 2 = 14.

Question 13.
8 × 2 =

8 × 2 = 16,

Explanation:
Given 8 × 2 we multiply 8 with 2,
we get 16 as 8 × 2 = 16.

Question 14.
9 × 2 =

9 × 2 = 18,

Explanation:
Given 9 × 2 we multiply 9 with 2,
we get 18 as 9 × 2 = 18.

Question 15.
10 × 2 =

10 × 2 = 20,

Explanation:
Given 10 × 2 we multiply 10 with 2,
we get 20 as 10 × 2 = 20.

Question 16.
16 ÷ 2 =
16 ÷ 2 = 8,

Explanation:
Given 16 ÷ 2 we divide 16 by 2,
we get 8 as 16 ÷ 2 = 8.

Question 17.
14 ÷ 2 =
14 ÷ 2 = 7,

Explanation:
Given 14 ÷ 2 we divide 14 by 2,
we get 7 as 14 ÷ 2 = 7.

Question 18.
18 ÷ 2 =

18 ÷ 2 = 9,

Explanation:
Given 18 ÷ 2 we divide 18 by 2,
we get 9 as 18 ÷ 2 = 9.

Question 19.
12 ÷ 2 =

12 ÷ 2 = 6,

Explanation:
Given 12 ÷ 2 we divide 12 by 2,
we get 6 as 12 ÷ 2 = 6.

Question 20.
20 ÷ 2 =

20 ÷ 2 = 10,

Explanation:
Given 20 ÷ 2 we divide 20 by 2,
we get 10 as 20 ÷ 2 = 10.

Question 21.
__ × 2 = 10

5 × 2 = 10,

Explanation:
Given __ × 2 = 10, Let us take missing number
as ×, So 5 × 2 = 10, means x = 10 ÷ 2 = 5,
therefore 5 × 2 = 10.

Question 22.
__ × 2 = 12

6 × 2 = 12,

Explanation:
Given __ × 2 = 12, Let us take missing number as x, So 6 × 2 = 12, means x = 12 ÷ 2 = 6,
therefore 6 × 2 = 12.

Question 23.
__ × 2 = 20

10 × 2 = 20,

Explanation:
Given __ × 2 = 20, Let us take missing number as x, So x × 2 = 20, means x = 20 ÷ 2 = 10,
therefore 10 × 2 = 20.

Question 24.
__ × 2 = 4

2 × 2 = 4,

Explanation:
Given __ × 2 = 4, Let us take missing number as x, So x × 2 = 4, means x = 4 ÷ 2 = 2,
therefore 2 × 2 = 4.

Question 25.
__ × 2 = 6

3 × 2 = 6,

Explanation:
Given __ × 2 = 6, Let us take missing number as x, So x × 2 = 6, means x = 6 ÷ 2 = 3,
therefore 3 × 2 = 6.

Question 26.
20 ÷ 2 =

20 ÷ 2 = 10,

Explanation:
Given 20 ÷ 2 we divide 20 by 2,
we get 10 as 20 ÷ 2 = 10.

Question 27.
10 ÷ 2 =

10 ÷ 2 = 5,

Explanation:
Given 10 ÷ 2 we divide 10 by 2,
we get 5 as 10 ÷ 2 = 5.

Question 28.
2 ÷ 1 =

2 ÷ 1 = 2,

Explanation:
Given 2 ÷ 1 we divide 2 by 1,
we get 2 as 2 ÷ 1 = 2.

Question 29.
4 ÷ 2 =

4 ÷ 2 = 2,

Explanation:
Given 4 ÷ 2 we divide 4 by 2,
we get 2 as 4 ÷ 2 = 2.

Question 30.
6 ÷ 2 =

6 ÷ 2 = 3,

Explanation:
Given 6 ÷ 2 we divide 6 by 2,
we get 3 as 6 ÷ 2 = 3.

Question 31.
__ × 2 = 12

6 × 2 = 12,

Explanation:
Given __ × 2 = 12, Let us take missing number
as x, So x × 2 = 12, means x = 12 ÷ 2 = 6,
therefore 6 × 2 = 12.

Question 32.
__ × 2 = 14

7 × 2 = 14,

Explanation:
Given __ × 2 = 14, Let us take missing number as x, So x × 2 = 14, means x = 14 ÷ 2 = 7,
therefore 7 × 2 = 14.

Question 33.
__ × 2 = 18

9 × 2 = 18,

Explanation:
Given __ × 2 = 18, Let us take missing number as x, So x × 2 = 18, means x = 18 ÷ 2 = 9,
therefore 9 × 2 = 18.

Question 34.
__ × 2 = 16

8 × 2 = 16,

Explanation:
Given __ × 2 = 16, Let us take missing number as x, So x × 2 = 16, means x = 16 ÷ 2 = 8,
therefore 8 × 2 = 16.

Question 35.
14 ÷ 2 =

14 ÷ 2 = 7,

Explanation:
Given 14 ÷ 2 we divide 14 by 2,
we get 7 as 14 ÷ 2 = 7.

Question 36.
18 ÷ 2 =

18 ÷ 2 = 9,

Explanation:
Given 18 ÷ 2 we divide 18 by 2,
we get 9 as 18 ÷ 2 = 9.

Question 37.
12 ÷ 2 =

12 ÷ 2 = 6,

Explanation:
Given 12 ÷ 2 we divide 12 by 2,
we get 6 as 12 ÷ 2 = 6.

Question 38.
16 ÷ 2 =

16 ÷ 2 = 8,

Explanation:
Given 16 ÷ 2 we divide 16 by 2,
we get 8 as 16 ÷ 2 = 8.

Question 39.
11 × 2 =

11 × 2 = 22,

Explanation:
Given 11 × 2 we multiply 11 with 2,
we get 22 as 11 × 2 = 22.

Question 40.
22 ÷ 2 =
22 ÷ 2 = 11,

Explanation:
Given 22 ÷ 2 we divide 22 by 2,
we get 11 as 22 ÷ 2 = 11.

Question 41.
12 × 2 =

12 × 2 = 24,

Explanation:
Given 12 × 2 we multiply 12 with 2,
we get 24 as 12 × 2 = 24.

Question 42.
24 ÷ 2 =

24 ÷ 2 = 12,

Explanation:
Given 24 ÷ 2 we divide 24 by 2,
we get 12 as 24 ÷ 2 = 12.

Question 43.
14 × 2 =

14 × 2 = 28,

Explanation:
Given 14 × 2 we multiply 14 with 2,
we get 28 as 14 × 2 = 28.

Question 44.
28 ÷ 2 =

28 ÷ 2 = 14,

Explanation:
Given 28 ÷ 2 we divide 28 by 2,
we get 14 as 28 ÷ 2 = 14.

B
Multiply or Divide by 2

Question 1.
1 × 2 =

1 × 2 = 2,

Explanation:
Given 1 × 2 we multiply 1 with 2,
we get 2 as 1 × 2 = 2.

Question 2.
2 × 2 =

2 × 2 = 4,

Explanation:
Given 2 × 2 we multiply 2 with 2,
we get 4 as 2 × 2 = 4.

Question 3.
3 × 2 =

3 × 2 = 6,

Explanation:
Given 3 × 2 we multiply 3 with 2,
we get 6 as 3 × 2 = 6.

Question 4.
4 × 2 =

4 × 2 = 8,

Explanation:
Given 4 × 2 we multiply 4 with 2,
we get 8 as 4 × 2 = 8.

Question 5.
5 × 2 =

5 × 2 = 10,

Explanation:
Given 5 × 2 we multiply 5 with 2,
we get 10 as 5 × 2 = 10.

Question 6.
6 ÷ 2 =

6 ÷ 2 = 3,

Explanation:
Given 6 ÷ 2 we divide 6 by 2,
we get 3 as 6 ÷ 2 = 3.

Question 7.
4 ÷ 2 =

4 ÷ 2 = 2,

Explanation:
Given 4 ÷ 2 we divide 4 by 2,
we get 2 as 4 ÷ 2 = 2.

Question 8.
8 ÷ 2 =

8 ÷ 2 = 4,

Explanation:
Given 8 ÷ 2 we divide 8 by 2,
we get 4 as 8 ÷ 2 = 4.

Question 9.
2 ÷ 1 =

2 ÷ 1 = 2,

Explanation:
Given 2 ÷ 1 we divide 2 by 1,
we get 2 as 2 ÷ 1 = 2.

Question 10.
10 ÷ 2 =

10 ÷ 2 = 5,

Explanation:
Given 10 ÷ 2 we divide 10 by 2,
we get 5 as 10 ÷ 2 = 5.

Question 11.
10 × 2 =

10 × 2 = 20,

Explanation:
Given 10 × 2 we multiply 10 with 2,
we get 20 as 10 × 2 = 20.

Question 12.
6 × 2 =

6 × 2 = 12,

Explanation:
Given 6 × 2 we multiply 6 with 2,
we get 12 as 6 × 2 = 12.

Question 13.
7 × 2 =

7 × 2 = 14,

Explanation:
Given 7 × 2 we multiply 7 with 2,
we get 14 as 7 × 2 = 14.

Question 14.
8 × 2 =

8 × 2 = 16,

Explanation:
Given 8 × 2 we multiply 8 with 2,
we get 16 as 8 × 2 = 16.

Question 15.
9 × 2 =

9 × 2 = 18,

Explanation:
Given 9 × 2 we multiply 9 with 2,
we get 18 as 9 × 2 = 18.

Question 16.
14 ÷ 2 =

14 ÷ 2 = 7,

Explanation:
Given 14 ÷ 2 we divide 14 by 2,
we get 7 as 14 ÷ 2 = 7.

Question 17.
12 ÷ 2 =

12 ÷ 2 = 6,

Explanation:
Given 12 ÷ 2 we divide 12 by 2,
we get 6 as 12 ÷ 2 = 6.

Question 18.
16 ÷ 2 =

16 ÷ 2 = 8,

Explanation:
Given 16 ÷ 2 we divide 16 by 2,
we get 8 as 16 ÷ 2 = 8.

Question 19.
20 ÷ 2 =

20 ÷ 2 = 10,

Explanation:
Given 20 ÷ 2 we divide 20 by 2,
we get 10 as 20 ÷ 2 = 10.

Question 20.
18 ÷ 2 =

18 ÷ 2 = 9,

Explanation:
Given 18 ÷ 2 we divide 18 by 2,
we get 9 as 18 ÷ 2 = 9.

Question 21.
__ × 2 = 12

6 × 2 = 12,

Explanation:
Given __ × 2 = 12, Let us take missing number
as x, So x × 2 = 12, means x = 12 ÷ 2 = 6,
therefore 6 × 2 = 12.

Question 22.
__ × 2 = 10

5 × 2 = 10,

Explanation:
Given __ × 2 = 10, Let us take missing number
as x, So x × 2 = 10, means x = 10 ÷ 2 = 5,
therefore 5 × 2 = 10.

Question 23.
__ × 2 = 4

2 × 2 = 4,

Explanation:
Given __ × 2 = 4, Let us take missing number
as x, So x × 2 = 4, means x = 4 ÷ 2 = 2,
therefore 2 × 2 = 4.

Question 24.
__ × 2 = 20

10 X× 2 = 20,

Explanation:
Given __ × 2 = 20, Let us take missing number
as x, So x × 2 = 20, means x = 20 ÷ 2 = 10,
therefore 10 × 2 = 20.

Question 25.
__ × 2 = 6

3 × 2 = 6,

Explanation:
Given __ × 2 = 6, Let us take missing number
as x, So x × 2 = 6, means x = 6 ÷ 2 = 3,
therefore 3 × 2 = 6.

Question 26.
4 ÷ 2 =

4 ÷ 2 = 2,

Explanation:
Given 4 ÷ 2 we divide 4 by 2,
we get 2 as 4 ÷ 2 = 2.

Question 27.
2 ÷ 1 =

2 ÷ 1 = 2,

Explanation:
Given 2 ÷ 1 we divide 2 by 1,
we get 2 as 2 ÷ 1 = 2.

Question 28.
20 ÷ 2 =

20 ÷ 2 = 10,

Explanation:
Given 20 ÷ 2 we divide 20 by 2,
we get 10 as 20 ÷ 2 = 10.

Question 29.
10 ÷ 2 =

10 ÷ 2 = 5,

Explanation:
Given 10 ÷ 2 we divide 10 by 2,
we get 5 as 10 ÷ 2 = 5.

Question 30.
6 ÷ 2 =

6 ÷ 2 = 3,

Explanation:
Given 6 ÷ 2 we divide 6 by 2,
we get 3 as 6 ÷ 2 = 3.

Question 31.
__ × 2 = 12

6 × 2 = 12,

Explanation:
Given __ × 2 = 12, Let us take missing number
as x, So x × 2 = 12, means x = 12 ÷ 2 = 6,
therefore 6 × 2 = 12.

Question 32.
__ × 2 = 16

8 × 2 = 16,

Explanation:
Given __ X 2 = 16, Let us take missing number
as x, So x × 2 = 16, means x = 16 ÷ 2 = 8,
therefore 8 × 2 = 16.

Question 33.
__ × 2 = 18

9 × 2 = 18,

Explanation:
Given __ × 2 = 18, Let us take missing number
as x, So x × 2 = 18, means x = 18 ÷ 2 = 9,
therefore 9 × 2 = 18.

Question 34.
__ × 2 = 14

7 × 2 = 14,

Explanation:
Given __ × 2 = 14, Let us take missing number
as x, So x × 2 = 14, means x = 14 ÷ 2 = 7,
therefore 7 × 2 = 14.

Question 35.
16 ÷ 2 =

16 ÷ 2 = 8,

Explanation:
Given 16 ÷ 2 we divide 16 by 2,
we get 8 as 16 ÷ 2 = 8.

Question 36.
18 ÷ 2 =

18 ÷ 2 = 9,

Explanation:
Given 18 ÷ 2 we divide 18 by 2,
we get 9 as 18 ÷ 2 = 9.

Question 37.
12 ÷ 2 =

12 ÷ 2 = 6,

Explanation:
Given 12 ÷ 2 we divide 12 by 2,
we get 6 as 12 ÷ 2 = 6.

Question 38.
14 ÷ 2 =

14 ÷ 2 = 7,

Explanation:
Given 14 ÷ 2 we divide 14 by 2,
we get 7 as 14 ÷ 2 = 7.

Question 39.
11 × 2 =

11 × 2 = 22,

Explanation:
Given 11 × 2 we multiply 11 with 2,
we get 22 as 11 × 2 = 22.

Question 40.
22 ÷ 2 =

22 ÷ 2 = 11,

Explanation:
Given 22 ÷ 2 we divide 22 by 2,
we get 11 as 22 ÷ 2 = 11.

Question 41.
12 × 2 =

12 × 2 = 24,

Explanation:
Given 12 × 2 we multiply 12 with 2,
we get 24 as 12 × 2 = 24.

Question 42.
24 ÷ 2 =

24 ÷ 2 = 12,

Explanation:
Given 24 ÷ 2 we divide 24 by 2,
we get 12 as 24 ÷ 2 = 12.

Question 43.
13 × 2 =

13 × 2 = 26,

Explanation:
Given 13 × 2 we multiply 13 with 2,
we get 23 as 13 × 2 = 26.

Question 44.
26 ÷ 2 =

26 ÷ 2 = 13,

Explanation:
Given 26 ÷ 2 we divide 26 by 2,
we get 26 as 26 ÷ 2 = 13.

### Eureka Math Grade 3 Module 1 Lesson 13 Problem Set Answer Key

Question 1.
Fill in the blanks to make true number sentences.

Explanation:
Filled the blanks to make true number sentences as
1 × 3 = 3, 3 ÷ 3 = 1,
2 × 3 = 6, 6 ÷ 3 = 2,
3 × 3 = 9, 9 ÷ 3 = 3,
4 × 3 = 12, 12 ÷ 3 = 4,
5 × 3 = 15, 15 ÷ 3 = 5,
6 × 3 = 18, 18 ÷ 3 = 6,
7 × 3 = 21, 21 ÷ 3 = 7,
8 ×3 = 24, 24 ÷ 3 = 8,
9 × 3 = 27, 27 ÷ 3 = 9,
10 × 3 = 30, 30 ÷ 3 = 10.

Question 2.
Mr. Lawton picks tomatoes from his garden.
He divides the tomatoes into bags of 3.

a. Circle to show how many bags he packs.
Then, skip-count to show the total number of tomatoes.

Circled the bags as 4,
The total number of tomatoes are 12,

Explanation:
Given Mr. Lawton picks tomatoes from his garden.
He divides the tomatoes into bags of 3.
a. Circled and showed number of bags he packs
as 12 ÷ 3 = 4 bags,
Then, skipped-count and showed the total number of
tomatoes are 4 × 3 = 12.

b. Draw and label a tape diagram to represent the problem.
____12____ ÷ 3 = ___4 bags__________
Mr. Lawton packs ___4____ bags of tomatoes.

Mr. Lawton packs  4 bags of tomatoes,

Explanation:
Drawn and labeled a tape diagram to represent
the problem as shown above 12 ÷ 3 = 4 bags.

Question 3.
Camille buys a sheet of stamps that measures 15 centimeters long.
Each stamp is 3 centimeters long.
How many stamps does Camille buy?
Draw and label a tape diagram to solve.

Explanation:
Given Camille buys a sheet of stamps that measures
15 centimeters long and each stamp is 3 centimeters long.
So number of  stamps Camille buy’s is 15 ÷ 3 = 5 stamps,
Drawn and labeled a tape diagram to solve as shown above.

Question 4.
Thirty third-graders go on a field trip. They are equally
divided into 3 vans. How many students are in each van?

In each van there are 11 students,

Explanation:
Given thirty third-graders go on a field trip and they are equally
divided into 3 vans. So number of  students in each van are
33 ÷ 3 = 11, Therefore in each van there are 11 students.

Question 5.
Some friends spend $24 altogether on frozen yogurt. Each person pays$3. How many people buy frozen yogurt?

Explanation:
Given some friends spend $24 altogether on frozen yogurt and each person pays$3, So number of people buy’s frozen
yogurt is $24 ÷$3 = 8, Therefore 8 people buy’s frozen yogurt.

### Eureka Math Grade 3 Module 1 Lesson 13 Exit Ticket Answer Key

Question 1.
Andrea has 21 apple slices. She uses 3 apple slices to
decorate 1 pie. How many pies does Andrea make?
Draw and label a tape diagram to solve.

Andrea makes 7 pies,

Explanation:
Given Andrea has 21 apple slices and she uses 3 apple slices to
decorate 1 pie. So number of pies Andrea makes are 21 ÷ 3 = 7,
Drawn and labeled a tape diagram to solve as shown above.

Question 2.
There are 24 soccer players on the field. They form 3 equal teams.
How many players are on each team?

Number of players in each team are 8,

Explanation:
Given there are 24 soccer players on the field and
they form 3 equal teams, So number of players in
each team are 24 ÷ 3 = 8 players.

### Eureka Math Grade 3 Module 1 Lesson 13 Homework Answer Key

Question 1.
Fill in the blanks to make true number sentences.

Explanation:
Filled in the blanks to make true number sentences as
2 × 3 = 6, 6 ÷ 3 = 2, 1 x 3 = 3, 3 ÷ 3 =1,
7 × 3 = 21, 21 ÷ 3 = 7 and 9 × 3 = 27, 27 ÷ 3 = 9.

Question 2.
Ms. Gillette’s pet fish are shown below.
She keeps 3 fish in each tank.

a. Circle to show how many fish tanks she has.
Then, skip-count to find the total number of fish.

Circled the fish tanks as 5,
The total number of fishes are 15,

Explanation:
Given Ms. Gillette’s pet fishes, She keeps 3 fish in each tank,
Circled to show number of fish tanks she has.
Then, skipped-count to find the total number of fishes as
5 × 3 = 15.

b. Draw and label a tape diagram to represent the problem.
_____15______ ÷ 3 = ____5______
Ms. Gillette has ___5____ fish tanks.

Ms. Gillette has 5 fish tanks.

Explanation:
Drawn and labeled a tape diagram to represent the problem as shown above 15 ÷ 3 = 5 fish tanks.

Question 3.
Juan buys 18 meters of wire. He cuts the wire into pieces that are each 3 meters long. How many pieces of wire does he cut?

Juan cuts 6 pieces of wire.

Explanation:
Given Juan buys 18 meters of wire and he cuts the wire into pieces that are each 3 meters long So number of pieces of wire he cuts is 18 ÷ 3 = 6 pieces.

Question 4.
A teacher has 24 pencils. They are divided equally among 3 students. How many pencils does each student get?

Each student will get 8 pencils,

Explanation:
Given a teacher has 24 pencils and they are divided equally among 3 students, So number of pencils each student gets is
24 ÷ 3 = 8 pencils.

Question 5.
There are 27 third-graders working in groups of 3. How many groups of third-graders are there?

There are 9 groups of third-graders working,

Explanation:
Given there are 27 third-graders working in groups of 3,
So, the number of groups of third-graders working are 27 ÷ 3 = 9 groups.

## Engage NY Eureka Math 3rd Grade Module 1 Lesson 12 Answer Key

### Eureka Math Grade 3 Module 1 Lesson 12 Pattern Sheet Answer Key

Multiply.

multiply by 3 (6–10)

Multiplied by 3 (6–10) as shown below

### Eureka Math Grade 3 Module 1 Lesson 12 Problem Set Answer Key

Question 1.
There are 8 birds at the pet store. Two birds are in each cage.
Circle to show how many cages there are.

8 ÷ 2 = ____4______
There are ___4____ cages of birds.

There are 4 cages of birds,

Explanation:
Given there are 8 birds at the pet store and two
birds are in each cage.
The number of cages are 8 ÷ 2 = 4 cages,
Circled to show 4 cages of birds as shown above.

Question 2.
The pet store sells 10 fish. They equally divide the fish into 5 bowls.
Draw fish to find the number in each bowl.

5 × ___2____ = 10
10 ÷ 5 = ___2_____
There are ____2____ fish in each bowl.

There are 2 fish in each bowl,

Explanation:
Given the pet store sells 10 fish and they are equally divided the fish into 5 bowls.
Means each bowl has 10 ÷ 5 = 2 fish ( 5 X 2 = 10),
Drawn fish and found the number in each bowl as 2 fish,

Question 3.
Match.

Explanation:
Matched expressions as
10 ÷ 2 = 5,
16 ÷ 2 = 8,
18 ÷ 2 = 9,
14 ÷ 2 = 7 and
12 ÷ 2 = 6.

Question 4.
Laina buys 14 meters of ribbon. She cuts her ribbon into 2 equal pieces. How many meters long is each piece?
Label the tape diagram to represent the problem, including the unknown.

Each piece is ____7______ meters long.

Laina’s each piece of ribbon is 7 meters long,

Explanation:
Given Laina buys 14 meters of ribbon and she cuts her ribbon into 2 equal pieces. So number of meters long each piece is 14 ÷ 2 = 7 meters long,
Labeled the tape diagram to represent the problem, including the unknown as shown in the above picture.

Question 5.
Roy eats 2 cereal bars every morning. Each box has a total
of 12 bars. How many days will it take Roy to finish 1 box?

It will take Roy to  finish 1 box in 6 days,

Explanation:
Given Roy eats 2 cereal bars every morning and each box has a total of 12 bars.
So, the Number of days it will take Roy to finish 1 box is
12 ÷ 2 = 6 days.

Question 6.
Sarah and Esther equally share the cost of a present.
The present costs $18. How much does Sarah pay? Answer: Sarah pay’s$9 for the present,

Explanation:
Given Sarah and Esther equally share the cost of a present.
The present costs $18, As 2 persons have equally paid for the present each paid$18 ÷ 2 = $9, Therefore Sarah pay’s$9 for the present.

### Eureka Math Grade 3 Module 1 Lesson 12 Exit Ticket Answer Key

There are 14 mints in 1 box. Cecilia eats 2 mints each day.
How many days does it take Cecilia to eat 1 box of mints?
Draw and label a tape diagram to solve.

It takes Cecilia ____7___ days to eat 1 box of mints.

Cecilia eats 1 box of mints in 7 days,

Explanation:
Given there are 14 mints in 1 box and Cecilia eats 2 mints each day. So, number of days it will take Cecilia to eat 1 box of mints are 14 ÷ 2 = 7 days,
Drawn and labeled a tape diagram to solve as shown above in the picture.

### Eureka Math Grade 3 Module 1 Lesson 12 Homework Answer Key

Question 1.
Ten people wait in line for the roller coaster.
Two people sit in each car. Circle to find the total number of cars needed.

10 ÷ 2 = ____5______
There are ___5____ cars needed.

Number of cars needed are 5,

Explanation:
Given Ten people wait in line for the roller coaster,
Two people sit in each car. So, the number of cars needed are
10 ÷ 2 = 5, Circled the total 5 number of cars needed as shown above in the picture.

Question 2.
Mr. Ramirez divides 12 frogs equally into 6 groups for students to study. Draw frogs to find the number in each group.
Label known and unknown information on the tape diagram to help you solve.

6 × ___2____ = 12
12 ÷ 6 = ___2____
There are ____2____ frogs in each group.

The number of frogs in each group are 2,

Explanation:
Given Mr. Ramirez divides 12 frogs equally into 6 groups for students to study. Drawn frogs to find the number in each group as 12 ÷ 6 = 2 frogs, Labeled known and unknown information on the tape diagram and solved as shown above in the picture.

Question 3.
Match.

Explanation:
Matched expressions as
10 ÷ 2 = 5,
16 ÷ 2 = 8,
18 ÷ 2 = 9 and
14 ÷ 2 = 7 respectively.

Question 4.
Betsy pours 16 cups of water to equally fill 2 bottles. How many cups of water are in each bottle?
Label the tape diagram to represent the problem, including the unknown.
There are ____8_____ cups of water in each bottle.

There are 8 cups of water in each bottle,

Explanation:
Given Betsy pours 16 cups of water to equally fill 2 bottles,
So, number of cups of water in each bottle are 16 ÷ 2 = 8 cups,
Labeled the tape diagram to represent the problem including the unknown as shown above in the picture.

Question 5.
An earthworm tunnels 2 centimeters into the ground each day. The earthworm tunnels at about the same pace every day. How many days will it take the earthworm to tunnel 14 centimeters?

It will take 7 days for the earthworm to tunnel 14 centimeters into the ground,

Explanation:
Given an earthworm tunnels 2 centimeters into the ground each day and the earthworm tunnels at about the same pace every day, It will take the earthworm to tunnel 14 centimeters is 14 ÷ 2 = 7 days.

Question 6.
Sebastian and Teshawn go to the movies. The tickets cost $16 in total. The boys share the cost equally. How much does Teshawn pay? Answer: Teshawn pays$8 cost for the ticket,

Explanation:
Given Sebastian and Teshawn go to the movie and the tickets cost $16 in total. Both the boys share the cost equally means each had cost of$16 ÷ 2 = $8, Therefore Teshawn pays$8 cost for the ticket.

## Engage NY Eureka Math 3rd Grade Module 1 Lesson 11 Answer Key

### Eureka Math Grade 3 Module 1 Lesson 11 Pattern Sheet Answer Key

Multiply.

multiply by 3 (1–5)

Explanation:
Multiplied by 3 (1–5) as shown above.

### Eureka Math Grade 3 Module 1 Lesson 11 Problem Set Answer Key

Question 1.
Mrs. Prescott has 12 oranges. She puts 2 oranges in each bag.
How many bags does she have?
a. Draw an array where each column shows a bag of oranges.
___12___ ÷ 2 = ___6_____.

Mrs. Prescott have 6 bags,

Explanation:
Given Mrs. Prescott has 12 oranges and she puts 2 oranges in each bag, So number of bags she have are 12 ÷ 2 = 6 bags,

a. Drawn an array where each column shows a bag of oranges as shown above in the picture.

b. Redraw the oranges in each bag as a unit in the tape diagram.
The first unit is done for you. As you draw, label the diagram with known and unknown information from the problem.

b.

Explanation:
Redrawn the oranges in each bag as a unit in the tape diagram, labeled the diagram with known and unknown information from the problem as 6 × 2 = 12 oranges, or 12 ÷ 2 = 6 bags.

Question 2.
Mrs. Prescott arranges 18 plums into 6 bags. How many plums are in each bag? Model the problem with both an array and a labeled tape diagram. Show each column as the number of plums in each bag.
There are ____3_____ plums in each bag.

Mrs. Prescott arranges 3 plums in each bag,

Explanation:
Given Mrs. Prescott arranges 18 plums into 6 bags.
So number of  plums in each bag are 18 ÷ 6 = 3 bags
Modeled the problem with both an array and labeled tape diagram as shown each column as the number of plums in each bag.

Question 3.
Fourteen shopping baskets are stacked equally in 7 piles.
How many baskets are in each pile? Model the problem with both an array and a labeled tape diagram.
Show each column as the number of baskets in each pile.

There are 2 baskets in each pile,

Explanation:
Given Fourteen shopping baskets are stacked equally in 7 piles.
So number of baskets in each pile are 14 ÷ 7 = 2 baskets,
Modeled the problem with both an array and labeled tape diagram. Shown each column as the number of baskets in each pile.

Question 4.
In the back of the store, Mr. Prescott packs 24 bell peppers equally into 8 bags. How many bell peppers are in each bag?
Model the problem with both an array and labeled tape diagram.
Show each column as the number of bell peppers in each bag.

There are 3 bell peppers in each bag,

Explanation:
Given In the back of the store, Mr. Prescott packs 24 bell peppers equally into 8 bags. So number of  bell peppers in each bag are 24 ÷ 8 = 3 bell peppers,
Modeled the problem with both an array and labeled tape diagram and shown each column as the number of bell peppers in each bag.

Question 5.
Olga saves $2 a week to buy a toy car. The car costs$16.
How many weeks will it take her to save enough to buy the toy?

It will take 8 weeks to buy a toy car,

Explanation:
Given Olga saves $2 a week to buy a toy car. The car costs$16. So number of weeks will it take her to save enough to buy the toy is $16 ÷$2 = 8 weeks.

### Eureka Math Grade 3 Module 1 Lesson 11 Exit Ticket Answer Key

Ms. McCarty has 18 stickers. She puts 2 stickers on each homework paper and has no more left.
How many homework papers does she have?
Model the problem with both an array and a labeled tape diagram.

Ms. McCarty has 9 homework papers,

Explanation:
Given Ms. McCarty has 18 stickers and she puts 2 stickers on each homework paper and has no more left.
So number of homework papers does she have are 18 ÷ 2 = 9 homework papers,
Modeled the problem with both an array and labeled tape diagram as shown above in the picture.

### Eureka Math Grade 3 Module 1 Lesson 11 Homework Answer Key

Question 1.
Fred has 10 pears. He puts 2 pears in each basket.
How many baskets does he have?
a. Draw an array where each column represents the number of pears in each basket.
___10____ ÷ 2 = ___5_____

Explanation:
Given Fred has 10 pears and he puts 2 pears in each basket.
So number of baskets does he have are 10 ÷ 2 = 5 baskets,

a. Drawn an array where each column represents the number of pears in each basket as shown in the picture above.

b. Redraw the pears in each basket as a unit in the tape diagram.
Label the diagram with known and unknown information from the problem.

Redrawn the pears in each basket as a unit in the tape diagram,

Explanation:
Redrawn the pears in each basket as a unit in the tape diagram.
Labeled the diagram with known and unknown information from the problem as 10 ÷ 2 = 5 baskets or 5 × 2 = 10 pears.

Question 2.
Ms. Meyer organizes 15 clipboards equally into 3 boxes.
How many clipboards are in each box? Model the problem with both an array and a labeled tape diagram. Show each column as the number of clipboards in each box.
There are ____5_____ clipboards in each box.

Ms. Meyer organizes 5 clipboards in each box,

Explanation:
Given Ms. Meyer organizes 15 clipboards equally into 3 boxes.
So, Number of clipboards in each box are 15 ÷ 3 = 5,
Modeled the problem with both an array and labeled tape diagram as shown above each column has 5 number of clipboards in each box.

Question 3.
Sixteen action figures are arranged equally on 2 shelves.
How many action figures are on each shelf?
Model the problem with both an array and a labeled tape diagram. Show each column as the number of action figures on each shelf.

There are 8 action figures on each shelf,

Explanation:
Given Sixteen action figures are arranged equally on 2 shelves.
So number of action figures on each shelf are 16 ÷ 2 = 8,
Modeled the problem with both an array and labeled tape diagram as show each column has 8 number of action figures on each shelf.

Question 4.
Jasmine puts 18 hats away. She puts an equal number of hats on 3 shelves. How many hats are on each shelf?
Model the problem with both an array and a labeled tape diagram. Show each column as the number of hats on each shelf.

On each shelf there are 6 hats,

Explanation:
Given Jasmine puts 18 hats away and she puts an equal number of hats on 3 shelves. So number of hats on each shelf are 18 ÷ 3 = 6 hats,
Modeled the problem with both an array and labeled tape diagram as shown each column has 6 number of hats on each shelf.

Question 5.
Corey checks out 2 books a week from the library.
How many weeks will it take him to check out a total of 14 books?

Corey will take 7 weeks to check out total 14 books,

Explanation:
Given Corey checks out 2 books a week from the library.
So, number of weeks it will take Corey to check out a total of 14 books are 14 ÷ 2 = 7 weeks.

## Engage NY Eureka Math 3rd Grade Module 1 Lesson 10 Answer Key

### Eureka Math Grade 3 Module 1 Lesson 10 Pattern Sheet Answer Key

Multiply.

multiply by 2 (6–10)

Explanation:
Multiplied by 2 (6–10) as shown above.

### Eureka Math Grade 3 Module 1 Lesson 10 Problem Set Answer Key

Question 1.
7 × 3 = (5 × 3) + (2 × 3) = ___21_______

(5 × 3) + (2 × 3) = 15 + ___6___
15 + ___6___ = _____21________

7 × 3 = (5 × 3) + (2 × 3) =
15 + 6 = 21 or 7 × 3 = 21.

Explanation:
Given 7 × 3 wrote 7 as (5 + 2) × 3 =
(5 × 3) + (2 × 3) =
15 + 6 = 21 or 7 × 3 = 21.

Question 2.
8 × 3 = (4 × 3) + (4 × 3) = __24____

(4 × 3) + (4 × 3) = ____12_____ + _____12____ = 24,
____8_____ × 3 = ____24______

8 × 3 = (4 × 3) + (4 × 3) =
12 + 12 = 24 or 8 × 3 = 24,

Explanation:
Given 8 × 3 wrote 8 as (4 + 4) × 3 =
(4 × 3) + (4 × 3) =
12 + 12 = 24 or 8 × 3 = 24.

Question 3.
Ruby makes a photo album. One page is shown below.
Ruby puts 3 photos in each row.
a. Fill in the equations on the right.
Use them to help you draw arrays that show the photos on the top and bottom parts of the page.

Explanation:
Filled in the equations on the right as 2 × 3 = 6, 3 × 3 =9,
Used them to help to draw arrays that showed the photos on the top and bottom parts of the page as shown above in the picture.

b. Ruby calculates the total number of photos as shown below.
Use the array you drew to help explain Ruby’s calculation.

Explanation:
Ruby calculates the total 15 number of photos as shown above,
Used the array to drew to help explain Ruby’s calculation as
(2 × 3) + (3 × 3) = 6 + 9 = 15.

### Eureka Math Grade 3 Module 1 Lesson 10 Exit Ticket Answer Key

Question 1.
6 × 3 = ___18___

(4 × 3) + (2 × 3) = __12__ + ___6___
6 × 3 = _12__ + _6__
_6_ × 3 = _18__

6 × 3  = (4 × 3) + (2 × 3) = 12 + 6 = 18 or 6 × 3 = 18,

Explanation:
Given 6 × 3 wrote 6 as (4 + 2) × 3 =
(4 × 3) + (2 × 3) = 12 + 6 = 18 or 6 × 3 = 18.

Question 2.
7 × 3 = _21_

(5 × 3) + (2 × 3) = __ + __
7 × 3 = __ + __
__ × 3 = ___

7 × 3  = (5 × 3) + (2 × 3) = 15 + 6 = 21 or 7 × 3 = 21,

Explanation:
Given 7 × 3 wrote 7 as (5 + 2) × 3 =
(5 × 3) + (2 × 3) =
15 + 6 = 21 or 7 × 3 = 21.

### Eureka Math Grade 3 Module 1 Lesson 10 Homework Answer Key

Question 1.
6 × 3 = ____18______

6 × 3 = (4 × 3) + (2 × 3) = 12 + 6 = 18 or 6 × 3 = 18,

Explanation:
Given 6 × 3 wrote 6 as (4 + 2) × 3 =
(4 × 3) + (2 × 3) =
12 + 6 = 18 or 6 × 3 = 18.

Question 2.
8 × 2 = _16_

8 × 2 = (4 × 2) + (4 × 2) = 8 + 8 = 16 or 8 × 2 = 16,

Explanation:
Given 8 × 2 wrote 8 as (4 + 4) × 2 =
(4 × 2) + (4 × 2) =
8 + 8 = 16 or 8 × 2 = 16.

Question 3.
Adriana organizes her books on shelves. She puts 3 books in each row.
a. Fill in the equations on the right. Use them to draw arrays that show the books on Adriana’s top and bottom shelves.

Explanation:
Given Adriana organizes her books on shelves.
She puts 3 books in each row.
a. Filled in the equations on the right as (5 × 3), (1 × 3)
Used them to draw arrays that show the books on
Adriana’s top and bottom shelves as shown above.

b. Adriana calculates the total number of books as shown below.
Use the array you drew to help explain Adriana’s calculation.

Explanation:
Adriana calculates the total 18 number of books as shown above,
Used the array to drew to help explain Adriana’s calculation as
6 × 3 = (5 × 3) + (1 × 3) = 15 + 3 = 18 or 6 × 3 = 18.

## Engage NY Eureka Math 3rd Grade Module 1 Lesson 9 Answer Key

### Eureka Math Grade 3 Module 1 Lesson 9 Pattern Sheet Answer Key

multiply by 2 (1–5)

Explanation:
Multiply by 2 (1–5) as shown above.

### Eureka Math Grade 3 Module 1 Lesson 9 Problem Set Answer Key

Question 1.
The team organizes soccer balls into 2 rows of 5.
The coach adds 3 rows of 5 soccer balls.
Complete the equations to describe the total array.

Explanation:
Given the team organizes soccer balls into 2 rows of 5 as
2 × 5 = 10 and the coach adds 3 rows of 5 soccer balls as
3 × 5 = 15, Completed the equations to described the
total array as 5 × 5 = (2 + 3) × 5 = (2 × 5) + (3 × 5) =
10 + 15 = 25 or 5 × 5 = 25.

Question 2.
7 × 2 = __14___

7 × 2 = 14,

Explanation:
Given 7 × 2, we wrote 7 × 2 as (5 + 2) × 2 =
(5 × 2) + ( 2 × 2) = 10 + 4 = 14 or
7 × 2 = 14.

Question 3.
9 × 2 = __18___

9 × 2 = 18,

Explanation:
Given 9 × 2  we wrote 9 × 2 as
(10 – 1) × 2 = (10 × 2) – (1 × 2) =
20 – 2 = 18 or 9 × 2 = 18.

Question 4.
Matthew organizes his baseball cards in 4 rows of 3.
a. Draw an array that represents Matthew’s cards using an x to show each card.
b. Solve the equation to find Matthew’s total number of cards.
4 × 3 = __12__,
a.

Explanation:
Given Matthew organizes his baseball cards in 4 rows of 3,
So array shown as 4 × 3,
Drawn an array that represents Matthew’s cards using an x to show each card as shown above.

b. Total number of  Matthew’s cards are 12,

Explanation:
Solved the equation to find Matthew’s total number of cards as 4 × 3 = 12.

Question 5.
Matthew adds 2 more rows. Use circles to show his new cards on the array in Problem 4(a).
a. Write and solve a multiplication equation to represent the circles you added to the array.
___2___ × 3 = __6____

Explanation:
Given Matthew adds 2 more rows.
Used circles to show his new cards on the array in
Problem 4(a) as shown above.

b. Add the totals from the equations in Problems 4(b) and 5(a) to find Matthew’s total cards.
__12____ + ___6___ = 18

Explanation:
Added the totals from the equations in Problems 4(b) and 5(a) to find Matthew’s total cards as
(4 × 3) + (2 × 3) = 12 + 6 = 18.

c. Write the multiplication equation that shows Matthew’s total number of cards.
___6___ × ___3___ = 18,

The multiplication equation to show total number of cards is 6 × 3 = 18,

Explanation:
The multiplication equation that shows Matthew’s total number of cards is 6 X 3 = (4 X 3) + (2 X 3) =
12 + 6 = 18 or 6 × 3 = 18.

### Eureka Math Grade 3 Module 1 Lesson 9 Exit Ticket Answer Key

Question 1.
Mrs. Stern roasts cloves of garlic. She places 10 rows of
two cloves on a baking sheet. Write an equation to describe
the number of cloves Mrs. Stern bakes.
___10____ × ___2____ = __20____ cloves

The number of cloves Mrs. Stern bakes is 20 cloves,

Explanation:
Given Mrs. Stern roasts cloves of garlic. She places 10 rows of two cloves on a baking sheet. The equation to describe the number of cloves Mrs. Stern bakes is 10 × 2 = 20 cloves.

Question 2.
When the garlic is roasted, Mrs. Stern uses some for a recipe.
There are 2 rows of two garlic cloves left on the pan.
a. Complete the equation below to show how many garlic cloves Mrs. Stern uses.
____10____ twos – ____2____ twos = ____8___twos,

10 twos – 2 twos = 8 twos,

Explanation:
Completed the equation below to show how many garlic cloves Mrs. Stern uses as 10 twos – 2 twos = 8 twos.

b. 20 – ________ = 16
20 – 4 = 16,

Explanation:
Subtracted 4 from 20 we get 16 as 20 – 4 =16 cloves.

c. Write an equation to describe the number of garlic cloves
Mrs. Stern uses. ___8____ × 2 = ___16_____,

The number of garlic cloves Mrs. Stern uses are 16 cloves,

Explanation:
Given Mrs. Stern roasts cloves of garlic,
She places 10 rows of two cloves on a baking sheet and
Mrs. Stern uses some for a recipe there are 2 rows of two garlic cloves left on the pan, 10 x 2 = 20 cloves and left are
2 × 2 = 4 cloves, Means used cloves are ( 10 × 2) – (2 × 2) =
20 – 4 = 16 cloves or (10 – 2) × 2 = 8 × 2= 16 cloves.
Therefore, the equation for number of garlic cloves Mrs. Stern uses are 8 × 2 = 16 cloves.

### Eureka Math Grade 3 Module 1 Lesson 9 Homework Answer Key

Question 1.
Dan organizes his stickers into 3 rows of four.
Irene adds 2 more rows of stickers. Complete the equations to describe the total number of stickers in the array.

a. (4 + 4 + 4) + (4 + 4) = __12 + 8 = ____20_____
b. 3 fours + ___2___ fours = _____5______ fours
c. ___5_____ × 4 = ____20____

a. (4 + 4 + 4) + (4 + 4) = 12 + 8 = 20,
b. 3 fours + 2 fours = 5 fours,
c. 5 X 4 = 20,

Explanation:
Given Dan organizes his stickers into 3 rows of four.
Irene adds 2 more rows of stickers.
Completed the equations to describe the total number of stickers in the array as 5 X 5 =
(3 × 5) + (2 × 5) = 15 + 10 = 25 or 5 × 5 = 25,
a. We wrote 5 × 5 as (4 + 4 + 4) + (4 + 4) = 12 + 8 = 20,
b. We wrote 5 × 5 as 3 fours + 2 fours = 5 fours,
c. We wrote 5 × 4 as 20, 5 × 4 = 20.

Question 2.
7 × 2 = __14____

7 × 2 = 14,

Explanation:
Given 7 × 2 we wrote 7 × 2 as (6 + 1) × 2 =
(6 × 2) + (1 × 2) = 12 + 2 = 14 or 7 × 2 = 14.

Question 3.
9 × 3 = __27___

9 × 3 = 27,

Explanation:
Given 9 × 3 we wrote 9 × 3 as (10 – 1) × 3 =
(10 × 3) – (1 × 3) = 30 – 3 = 27 or 9 x 2 = 27.

Question 4.
Franklin collects stickers. He organizes his stickers in 5 rows of four.
a. Draw an array to represent Franklin’s stickers.
Use an x to show each sticker.
b. Solve the equation to find Franklin’s total number of stickers. 5 × 4 = ___20___
a.

b. Franklin’s total number of stickers are 20.

Explanation:
Given Franklin collects stickers. He organizes his stickers in 5 rows of four.
a. Drawn an array to represent Franklin’s stickers,
Used an x to show each sticker as shown above.
b. Solved the equation to find Franklin’s total number of stickers as 5 × 4 = 20.

Question 5.
Franklin adds 2 more rows. Use circles to show his new stickers
on the array in Problem 4(a).
a. Write and solve an equation to represent the circles you added to the array.
___2___ × 4 = ___8___

Explanation:
Given Franklin adds 2 more rows. Used circles to show his new stickers on the array in Problem 4(a).
a. Wrote and solved an equation to represent the circles I added to the array as 2 × 4 = 8.

b. Complete the equation to show how you add the totals of 2 multiplication facts to find Franklin’s total number of stickers. __20____ + ___8___ = 28,

Equation of totals of 2 multiplication facts to find Franklin’s total number of stickers are 20 + 8 = 28,

Explanation:
Completed the equation to show how I added the totals of 2 multiplication facts to find Franklin’s total number of stickers as (5 × 4) + (2 × 4) = 20 + 8 = 28.

c. Complete the unknown to show Franklin’s total number of stickers.
__5___ × 4 = 20,

The unknown Franklin’s total number of stickers are 20,

Explanation:
To show unknown Franklin’s total number of stickers as given Franklin collects stickers. He organizes his stickers in 5 rows of four, So, Franklin’s total number of stickers are 5 × 4 = 20.

## Engage NY Eureka Math 3rd Grade Module 1 Lesson 8 Answer Key

### Eureka Math Grade 3 Module 1 Lesson 8 Problem Set Answer Key

Question 1.
Draw an array that shows 5 rows of 3.

Explanation:
Drawn an array that shows 5 rows of 3 as 5 × 3 as shown above.

Question 2.
Draw an array that shows 3 rows of 5.

Explanation:
Drawn an array that shows 3 rows of 5 as 3 × 5 as shown above.

Question 3.
Write multiplication expressions for the arrays in Problems 1 and 2. Let the first factor in each expression represent the number of rows. Use the commutative property to make sure the equation below is true.

Explanation:
Wrote multiplication expressions for the arrays in Problems 1 and 2 as 5 × 3, 3 × 5 and let the first factor in each expression represent the number of rows.
Used the commutative property to make sure the equation below is true as 5 × 3 = 15, 3 × 5 = 15,
So,  5 × 3 = 3 × 5 is true equals to 15.

Question 4.
Write a multiplication sentence for each expression.
You might skip-count to find the totals. The first one is done for you.
a. 2 threes: 2 × 3 = 6
b. 3 twos: _________________
c. 3 fours: ________________
d. 4 threes: ________________
e. 3 sevens: ________________
f. 7 threes: ________________
g. 3 nines: _________________
h. 9 threes: ________________
i. 10 threes: _______________

b. 3 twos : 3 x 2 = 6,
Explanation:
Given 3 twos, 3 multiplied by 2 gives 6,
So, 3 × 2 = 6.

c. 3 fours: 3 × 4 = 12,
Explanation:
Given 3 fours, 3 multiplied by 4 gives 12,
So, 3 × 4 = 12.

d. 4 threes: 4 × 3 = 12,
Explanation:
Given 4 threes, 4 multiplied by 3 gives 12,
So, 4 × 3 = 12.

e. 3 sevens:  3 x 7 = 21,
Explanation:
Given 3 sevens, 3 multiplied by 7 gives 21,
So, 3 × 7 = 21.

f. 7 threes:  7 × 3 = 21,
Explanation:
Given 7 threes, 7 multiplied by 3 gives 21,
So, 7 × 3 = 21.

g. 3 nines: 3 × 9 = 27,
Explanation:
Given 3 nines, 3 multiplied by 9 gives 27,
So, 3 × 9 = 27.

h. 9 threes: 9 × 3 = 27,
Explanation:
Given 9 threes, 9 multiplied by 3 gives 27,
So, 9 × 3 = 27.

i. 10 threes: 10 x 3 =30,
Explanation:
Given 10 threes, 10 multiplied by 3 gives 30,
So, 10 × 3 = 30.

Question 5.
Find the unknowns that make the equations true.
Then, draw a line to match related facts.
a. 3 + 3 + 3 + 3 + 3 = _________
b. 3 × 9 = _________
c. 7 threes + 1 three = _________
d. 3 × 8 = _________
e. _________ = 5 × 3
f. 27 = 9 × _________

a. 3 + 3 + 3 + 3 + 3 = 15,

Explanation:
Given 3 + 3 + 3 + 3 + 3  adding 3, 5 times gives 15,
So 3 + 3 + 3 + 3 + 3 = 15.

b. 3 × 9 = 27,

Explanation:
Given 3 × 9, 3 multiplied by 9 gives 27,
So 3 × 9 = 27.

c. 7 threes + 1 three = 8 threes = 24,

Explanation:
Given 7 threes + 1 three = 7 × 3 + 1 × 3 = 21 + 3 = 24,
So, 7 threes + 1 three = 8 threes = 24.

d. 3 × 8 = 24,

Explanation:
Given 3 × 8, 3 multiplied by 8 gives 24,
So 3 × 8 = 24.

e. 15 = 5 × 3,

Explanation:
Given 5 × 3, 5 multiplied by 3 gives 15,
So 15 = 5 × 3.

f. 27 = 9 × 3

Explanation:
Given 27 = 9 × ___, Lets take missing number as x,
27 = 9 × x, So x = 27 ÷ 9 = 3, So 27 = 9 × 3.

Question 6.
Isaac picks 3 tangerines from his tree every day for 7 days.
a. Use circles to draw an array that represents the
tangerines Isaac picks.

Explanation:
Given Isaac picks 3 tangerines from his tree every day for 7 days.
a. Used circles to draw an array that represents the tangerines Isaac picks as 3 × 7 as shown above.

b. How many tangerines does Isaac pick in 7 days?
Write and solve a multiplication sentence to find the total.

Isaac picks 21 tangerines in 7 days,
Multiplication sentence to find the total is 3 x 7 = 21.

Explanation:
Wrote and solved a multiplication sentence to find the total as 3 x 7 = 21, therefore Isaac picks 21 tangerines in 7 days.

c. Isaac decides to pick 3 tangerines every day for 3 more days.
Draw x’s to show the new tangerines on the array in Part (a).

Explanation:
Given Isaac decides to pick 3 tangerines every day for 3 more days.
Drawn x’s to show the new tangerines on the array in Part (a) as shown above in the picture.

d. Write and solve a multiplication sentence to find the total number of tangerines Isaac picks.

Multiplication sentence is 3 x 10 = (3 × 7) + (3 × 3) = 21 + 9 = 30,
The total number of tangerines Isaac picks are 30,

Explanation:
Wrote and solved a multiplication sentence as
3 x 10 = (3 × 7) + (3 × 3) = 21 + 9 = 30,
Therefore the total number of tangerines Isaac picks are 30.

Question 7.
Sarah buys bottles of soap. Each bottle costs $2. a. How much money does Sarah spend if she buys 3 bottles of soap? _____$2_____ × ____3______ = $___6_____ b. How much money does Sarah spend if she buys 6 bottles of soap? _____$2_____ × _____6_____ = $__12______ a. Sarah spends$6 if she buys 3 bottles of soap,

Explanation:
Given Sarah buys bottles of soap. Each bottle costs $2, So money spent by Sarah if she buys 3 bottles of soap are$2 × 3 = $6. b. Sarah spends$12 if she buys 6 bottles of soap,

Explanation:
Given Sarah buys bottles of soap. Each bottle costs $2, So money spent by Sarah if she buys 6 bottles of soap are$2 × 6 = \$12.

### Eureka Math Grade 3 Module 1 Lesson 8 Exit Ticket Answer Key

Mary Beth organizes stickers on a page in her sticker book.
She arranges them in 3 rows and 4 columns.
a. Draw an array to show Mary Beth’s stickers.
b. Use your array to write a multiplication sentence to find Mary Beth’s total number of stickers.
c. Label your array to show how you skip-count to solve your multiplication sentence.
d. Use what you know about the commutative property to write a different multiplication sentence for your array.

a.
Explanation:
Given Mary Beth organizes stickers on a page in her sticker book. She arranges them in 3 rows and 4 columns.
Drawn an array as 3 × 4 to show Mary Beth’s stickers.

b. Mary Beth’s total number of stickers are 12,

Explanation:
Used my array to write a multiplication sentence as 3 × 4 = 12, in finding Mary Beth’s total number of stickers.

c.

Explanation:
Labeled my array to show skip-count to 12 and solved my multiplication sentence as 3 x 4 = 12.

d. Commutative property to write a different multiplication sentence for my array is 3 × 4 = 4 x 3,

Explanation:
Used what I know about the commutative property to write a different multiplication sentence for my array as
3 × 4 = 4 x 3.

### Eureka Math Grade 3 Module 1 Lesson 8 Homework Answer Key

Question 1.
Draw an array that shows 6 rows of 3.

Explanation:
Drawn an array that shows 6 rows of 3 as 6 × 3 as shown above.

Question 2.
Draw an array that shows 3 rows of 6.

Explanation:
Drawn an array that shows 3 rows of 6 as 3 × 6 as shown above.

Question 3.
Write multiplication expressions for the arrays in Problems 1 and 2. Let the first factor in each expression represent the number of rows. Use the commutative property to make sure the equation below is true.

Explanation:
Wrote multiplication expressions for the arrays in Problems 1 and 2 as 6 × 3, 3 × 6 and let the first factor in each expression represent the number of rows.
Used the commutative property to make sure the equation below is true as 6 × 3 = 18, 3 × 6 = 18,
So,  6 × 3 = 3 × 6 is true equals to 18.

Question 4.
Write a multiplication sentence for each expression.
You might skip-count to find the totals. The first one is done for you.
a. 5 threes: 5 × 3 = 15
b. 3 fives: __________________
c. 6 threes: ________________
d. 3 sixes: ___________________
e. 7 threes: __________________
f. 3 sevens: __________________
g. 8 threes: ________________
h. 3 nines: _________________
i. 10 threes: _______________

b. 3 fives: 3 × 5 = 15,

Explanation:
Given 3 fives, 3 multiplied by 5 gives 15,
So, 3 × 5 = 15.

c. 6 threes: 6 × 3 = 18,

Explanation:
Given 6 threes, 6 multiplied by 3 gives 18,
So, 6 × 3 = 18.

d. 3 sixes: = 3 × 6 = 18,

Explanation:
Given 3 sixes, 3 multiplied by 6 gives 18,
So, 3 × 6 = 18.

e. 7 threes: 7 × 3 = 21,

Explanation:
Given 7 threes, 7 multiplied by 3 gives 21,
So, 7 × 3 = 21.

f. 3 sevens: 3 × 7 = 21,

Explanation:
Given 3 sevens, 3 multiplied by 7 gives 21,
So, 3 × 7 = 21.

g. 8 threes: 8 × 3 = 24,

Explanation:
Given 8 threes, 8 multiplied by 3 gives 24,
So, 8 × 3 = 24.

h. 3 nines: 3 × 9 = 27,

Explanation:
Given 3 nines, 3 multiplied by 9 gives 27,
So, 3 × 9 = 27.

i. 10 threes: 10 × 3 = 30,

Explanation:
Given 10 threes, 10 multiplied by 3 gives 30,
So, 10 X 3 = 30.

Question 5.
Find the unknowns that make the equations true. Then, draw a line to match related facts.
a. 3 + 3 + 3 + 3 + 3 + 3 = _________
b. 3 × 5 = _________
c. 8 threes + 1 three = _________
d. 3 × 9 = _________
e. _________ = 6 × 3
f. 15 = 5 × _________

a. 3 + 3 + 3 + 3 + 3 + 3 = 18,

Explanation:
Given 3 + 3 + 3 + 3 + 3 + 3 adding 3, 6 times gives 18,
So 3 + 3 + 3 + 3 + 3 + 3 = 18.

b. 3 × 5 = 15,

Explanation:
Given 3 × 5, 3 multiplied by 5 gives 15,
So 3 × 5 = 15.

c. 8 threes + 1 three =9 threes = 27,

Explanation:
Given 8 threes + 1 three = 8 × 3 + 1 × 3 = 24 + 3 = 27,
So, 8 threes + 1 three = 9 threes = 27.

d. 3 × 9 = 27,

Explanation:
Given 3 × 9, 3 multiplied by 9 gives 27,
So 3 × 9 = 27.

e. 18 = 6 × 3,

Explanation:
Given 6 × 3, 6 multiplied by 3 gives 18,
So 18 = 6 × 3.

f. 15 = 5 × 3,

Explanation:
Given 15 = 5 × ___, Lets take missing number as x,
15 = 5 × x, So x = 15 ÷ 5 = 3, So 15 = 5 × 3.

Question 6.
Fernando puts 3 pictures on each page of his photo album.
He puts pictures on 8 pages.
a. Use circles to draw an array that represents the total number of pictures in Fernando’s photo album.
b. Use your array to write and solve a multiplication sentence to find Fernando’s total number of pictures.
c. Fernando adds 2 more pages to his book. He puts 3 pictures on each new page. Draw x’s to show the new pictures on the array in Part (a).
d. Write and solve a multiplication sentence to find the new the total number of pictures in Fernando’s album.
a.

Explanation:
Given Fernando puts 3 pictures on each page of his photo album.
He puts pictures on 8 pages.
a. Used circles to draw an array that represents the total number of pictures in Fernando’s photo album as 3 X 8.

b. Multiplication sentence for Fernando’s total number of pictures is 3 X 8 = 24,

Explanation:
Used my array to write and solve a multiplication sentence to find Fernando’s total number of pictures as 3 X 8 = 24.

c.

Explanation:
Fernando adds 2 more pages to his book. He puts 3 pictures on each new page. Drawn x’s to show the new pictures on the array in Part (a) as shown above.

d. Multiplication sentence is 3 x 10 =
(3× 8) + (3 × 2) = 24 + 6 = 30,
The new total number of pictures in Fernando’s album are 30,

Explanation:
Wrote and solved a multiplication sentence as
3 x 10 = (3 × 8) + (3 × 2) = 24 + 6 = 30,
Therefore the new total number of pictures in Fernando’s album are 30.

Question 7.
Ivania recycles. She gets 3 cents for every can she recycles.
a. How much money does Ivania make if she recycles 4 cans?
____3______ × ___4_______ = ___12_____ cents
b. How much money does Ivania make if she recycles 7 cans?
____3______ × ____7______ = ____21____ cents

a. Ivania makes 12 cents if she recycles 4 cans,

Explanation:
Given Ivania recycles and she gets 3 cents for every can she recycles,
So money Ivania makes if she recycles 4 cans is
3 cents × 4 = 12 cents.

b. Ivania makes 21 cents if she recycles 7 cans,

Explanation:
Given Ivania recycles and she gets 3 cents for every can she recycles,
So money Ivania makes if she recycles 7 cans is
3 cents × 7 = 21 cents.

## Engage NY Eureka Math 3rd Grade Module 7 Lesson 14 Answer Key

### Eureka Math Grade 3 Module 7 Lesson 14 Pattern Sheet Answer Key

Multiply.

multiply by 8 (6–10)

Explanation:
8 × 5 = 40
8 × 6 = 48
8 × 7 = 56
8 × 8 = 64
8 × 9 = 72
8 × 10 = 80.

### Eureka Math Grade 3 Module 7 Lesson 14 Problem Set Answer Key

Question 1.
Label the unknown side lengths of the regular shapes below. Then, find the perimeter of each shape.
a.

Perimeter = _______ in
Length of the side of the ABCDEFG Octogen = 64in.

Explanation:

Length of the side of the ABCDEFG Octogen = 8in
Perimeter of the ABCDEFG Octogen = 8 × side
= 8 × 8in
= 64in.

b.

Perimeter = _______ ft
Perimeter of the ABC Triangle = 21ft.

Explanation:

Length of the side of the ABC Triangle = 7ft
Perimeter of the ABC Triangle = 3 × Side
= 3 × 7ft
= 21ft.

c.

Perimeter = _______ m
Perimeter of the ABCD Square = 36m.

Explanation:

Length of the Side of the ABCD Square = 9m
Perimeter of the ABCD Square = 4 × Side
= 4 × 9m
= 36m.

d.

Perimeter = _______ in
Perimeter of the ABCDE Pentagon = 36in.

Explanation:

Length of the side of the ABCDE Pentagon = 6in
Perimeter of the ABCDE Pentagon = 6 × Side
= 6 × 6in
= 36in.

Question 2.
Label the unknown side lengths of the rectangle below. Then, find the perimeter of the rectangle.

Perimeter = _______ cm
Perimeter of the side of the ABCD Rectangle = 18cm.

Explanation:

Length of the side of the ABCD Rectangle = 7cm
Width of the side of the ABCD Rectangle = 2cm
Perimeter of the side of the ABCD Rectangle = 2 (Length + Width)
= 2 ( 7cm + 2cm )
= 2 × 9cm
= 18cm.

Question 3.
David draws a regular octagon and labels a side length as shown below. Find the perimeter of David’s octagon.

Perimeter of the ABCDEFGH Octogen = 36cm.

Explanation:

Length of the side of the ABCDEFGH Octogen = 6cm
Perimeter of the ABCDEFGH Octogen = 6 × Side
= 6 × 6cm
= 36cm.

Question 4.
Paige paints an 8-inch by 9-inch picture for her mom’s birthday. What is the total length of wood that Paige needs to make a frame for the picture?
Perimeter of the Paige’s paints = 34inch.

Explanation:
Length of the Paige’s paints = 9inch
Width of the Paige’s paints = 8inch
Perimeter of the Paige’s paints = 2 (Length + Width )
= 2 (9inch + 8inch)
= 2 × 17inch
= 34inch.

Question 5.
Mr. Spooner draws a regular hexagon on the board. One of the sides measures 4 centimeters. Giles and Xander find the perimeter. Their work is shown below. Whose work is correct? Explain your answer.
Giles’s Work
Perimeter = 4 cm + 4 cm + 4 cm + 4 cm + 4 cm + 4 cm
Perimeter = 24 cm

Xander’s Work
Perimeter = 6 × 4 cm
Perimeter = 24 cm
Perimeter of the Hexagon = 24 centimeters.
Both Giles and Xander’s work is correct because they got the calculation value correct even though the methodology was different of each.

Explanation:
Length of the side of the Hexagon = 4 centimeters
Perimeter of the Hexagon = 6 × Side
= 6 × 4 centimeters
= 24 centimeters.
Both are correct.

### Eureka Math Grade 3 Module 7 Lesson 14 Exit Ticket Answer Key

Travis traces a regular pentagon on his paper. Each side measures 7 centimeters. He also traces a regular hexagon on his paper. Each side of the hexagon measures 5 centimeters. Which shape has a greater perimeter? Show your work.
Perimeter of the Pentagon is greater than the Perimeter of the regular hexagon because the measurement value of the Pentagon is more than the measurement value of the regular hexagon.

Explanation:

Length of the side of the Pentagon = 7 centimeters
Perimeter of the Pentagon = 5 × Side
= 5 × 7 centimeters
= 35 centimeters.
Length of the side of the regular hexagon = 5 centimeters
Perimeter of the regular hexagon = 6 × Side
= 6 × 5 centimeters
= 30 centimeters.

### Eureka Math Grade 3 Module 7 Lesson 14 Homework Answer Key

Question 1.
Label the unknown side lengths of the regular shapes below. Then, find the perimeter of each shape.
a.

Perimeter = _______ in
Perimeter of the ABC Triangle = 16in.

Explanation:

Length of the Side of the ABC Triangle = 4in
Perimeter of the ABC Triangle = Side + Side + Side
= AB + BC + CA
= 4in + 4in + 4in
= 12in + 4in
=16in.

b.

Perimeter = _______ cm

Perimeter of the square = 32cm.

Explanation:

Length of the Side of the square = 8cm
Perimeter of the square = 4 × Side
= 4 × 8cm
= 32cm.

c.

Perimeter = _______ m
Perimeter of the Octagon = 72m.

Explanation:

Length of the side of the Octagon = 9m
Perimeter of the Octagon = 8 × Side
= 8 × 9m
= 72m.

d.

Perimeter = _______ in
Perimeter of the Hexagon = 36in.

Explanation:

Length of the side of the Hexagon = 6in
Perimeter of the Hexagon = 6 × Side
= 6 × 6in
= 36in.

Question 2.
Label the unknown side lengths of the rectangle below. Then, find the perimeter of the rectangle.

Perimeter = _______ cm
Perimeter of the rectangle =  2 ( Length + Width )
= 2 ( 9cm + 4cm )
= 2 × 13cm
= 26cm.

Explanation:
Length of the rectangle = 9cm
Width of the rectangle = 4cm
Perimeter of the rectangle =  2 ( Length + Width )
= 2 ( 9cm + 4cm )
= 2 × 13cm
= 26cm.

Question 3.
Roxanne draws a regular pentagon and labels a side length as shown below. Find the perimeter of Roxanne’s pentagon.

Perimeter of the Roxanne’s pentagon = 5 × Side
= 5 × 7cm
= 35cm.

Explanation:
Length of the side of the Roxanne’s pentagon = 7cm
Perimeter of the Roxanne’s pentagon = 5 × Side
= 5 × 7cm
= 35cm.

Question 4.
Each side of a square field measures 24 meters. What is the perimeter of the field?
Perimeter of the Square field = 4 × Side
= 4 × 24meters
= 96meters.

Explanation:
Length of the side of the Square field = 24 meters
Perimeter of the Square field = 4 × Side
= 4 × 24meters
= 96meters.

Question 5.
What is the perimeter of a rectangular sheet of paper that measures 8 inches by 11 inches?