Engage NY Eureka Math 3rd Grade Module 7 Lesson 14 Answer Key

Eureka Math Grade 3 Module 7 Lesson 14 Pattern Sheet Answer Key

Multiply.
Engage NY Math 3rd Grade Module 7 Lesson 14 Pattern Sheet Answer Key p 1
multiply by 8 (6–10)
Answer:
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-14-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 14 Pattern Sheet Answer Key

Explanation:
8 × 5 = 40
8 × 6 = 48
8 × 7 = 56
8 × 8 = 64
8 × 9 = 72
8 × 10 = 80.

Eureka Math Grade 3 Module 7 Lesson 14 Problem Set Answer Key

Question 1.
Label the unknown side lengths of the regular shapes below. Then, find the perimeter of each shape.
a.
Engage NY Math Grade 3 Module 7 Lesson 14 Problem Set Answer Key pr 1
Perimeter = _______ in
Answer:
Length of the side of the ABCDEFG Octogen = 64in.

Explanation:
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-14-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 14 Problem Set Answer Key-1a
Length of the side of the ABCDEFG Octogen = 8in
Perimeter of the ABCDEFG Octogen = 8 × side
= 8 × 8in
= 64in.

b.
Engage NY Math Grade 3 Module 7 Lesson 14 Problem Set Answer Key pr 2
Perimeter = _______ ft
Answer:
Perimeter of the ABC Triangle = 21ft.

Explanation:
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-14-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 14 Problem Set Answer Key-1b
Length of the side of the ABC Triangle = 7ft
Perimeter of the ABC Triangle = 3 × Side
= 3 × 7ft
= 21ft.

c.
Engage NY Math Grade 3 Module 7 Lesson 14 Problem Set Answer Key pr 3
Perimeter = _______ m
Answer:
Perimeter of the ABCD Square = 36m.

Explanation:
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-14-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 14 Problem Set Answer Key-1c
Length of the Side of the ABCD Square = 9m
Perimeter of the ABCD Square = 4 × Side
= 4 × 9m
= 36m.

d.
Engage NY Math Grade 3 Module 7 Lesson 14 Problem Set Answer Key pr 4
Perimeter = _______ in
Answer:
Perimeter of the ABCDE Pentagon = 36in.

Explanation:
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-14-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 14 Problem Set Answer Key-1d
Length of the side of the ABCDE Pentagon = 6in
Perimeter of the ABCDE Pentagon = 6 × Side
= 6 × 6in
= 36in.

Question 2.
Label the unknown side lengths of the rectangle below. Then, find the perimeter of the rectangle.
Engage NY Math Grade 3 Module 7 Lesson 14 Problem Set Answer Key pr 5
Perimeter = _______ cm
Answer:
Perimeter of the side of the ABCD Rectangle = 18cm.

Explanation:

Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-14-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 14 Problem Set Answer Key-2
Length of the side of the ABCD Rectangle = 7cm
Width of the side of the ABCD Rectangle = 2cm
Perimeter of the side of the ABCD Rectangle = 2 (Length + Width)
= 2 ( 7cm + 2cm )
= 2 × 9cm
= 18cm.

Question 3.
David draws a regular octagon and labels a side length as shown below. Find the perimeter of David’s octagon.
Engage NY Math Grade 3 Module 7 Lesson 14 Problem Set Answer Key pr 6
Answer:
Perimeter of the ABCDEFGH Octogen = 36cm.

Explanation:
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-14-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 14 Problem Set Answer Key-3
Length of the side of the ABCDEFGH Octogen = 6cm
Perimeter of the ABCDEFGH Octogen = 6 × Side
= 6 × 6cm
= 36cm.

Question 4.
Paige paints an 8-inch by 9-inch picture for her mom’s birthday. What is the total length of wood that Paige needs to make a frame for the picture?
Answer:
Perimeter of the Paige’s paints = 34inch.

Explanation:
Length of the Paige’s paints = 9inch
Width of the Paige’s paints = 8inch
Perimeter of the Paige’s paints = 2 (Length + Width )
= 2 (9inch + 8inch)
= 2 × 17inch
= 34inch.

Question 5.
Mr. Spooner draws a regular hexagon on the board. One of the sides measures 4 centimeters. Giles and Xander find the perimeter. Their work is shown below. Whose work is correct? Explain your answer.
Giles’s Work
Perimeter = 4 cm + 4 cm + 4 cm + 4 cm + 4 cm + 4 cm
Perimeter = 24 cm

Xander’s Work
Perimeter = 6 × 4 cm
Perimeter = 24 cm
Answer:
Perimeter of the Hexagon = 24 centimeters.
Both Giles and Xander’s work is correct because they got the calculation value correct even though the methodology was different of each.

Explanation:
Length of the side of the Hexagon = 4 centimeters
Perimeter of the Hexagon = 6 × Side
= 6 × 4 centimeters
= 24 centimeters.
Both are correct.

Eureka Math Grade 3 Module 7 Lesson 14 Exit Ticket Answer Key

Travis traces a regular pentagon on his paper. Each side measures 7 centimeters. He also traces a regular hexagon on his paper. Each side of the hexagon measures 5 centimeters. Which shape has a greater perimeter? Show your work.
Answer:
Perimeter of the Pentagon is greater than the Perimeter of the regular hexagon because the measurement value of the Pentagon is more than the measurement value of the regular hexagon.

Explanation:
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-14-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 14 Exit Ticket Answer Key
Length of the side of the Pentagon = 7 centimeters
Perimeter of the Pentagon = 5 × Side
= 5 × 7 centimeters
= 35 centimeters.
Length of the side of the regular hexagon = 5 centimeters
Perimeter of the regular hexagon = 6 × Side
= 6 × 5 centimeters
= 30 centimeters.

Eureka Math Grade 3 Module 7 Lesson 14 Homework Answer Key

Question 1.
Label the unknown side lengths of the regular shapes below. Then, find the perimeter of each shape.
a.
Eureka Math Grade 3 Module 7 Lesson 14 Homework Answer Key h 1
Perimeter = _______ in
Answer:
Perimeter of the ABC Triangle = 16in.

Explanation:
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-14-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 14 Homework Answer Key-1a
Length of the Side of the ABC Triangle = 4in
Perimeter of the ABC Triangle = Side + Side + Side
= AB + BC + CA
= 4in + 4in + 4in
= 12in + 4in
=16in.

b.
Eureka Math Grade 3 Module 7 Lesson 14 Homework Answer Key h 2
Perimeter = _______ cm

Answer:
Perimeter of the square = 32cm.

Explanation:
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-14-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 14 Homework Answer Key-1b
Length of the Side of the square = 8cm
Perimeter of the square = 4 × Side
= 4 × 8cm
= 32cm.

c.
Eureka Math Grade 3 Module 7 Lesson 14 Homework Answer Key h 3
Perimeter = _______ m
Answer:
Perimeter of the Octagon = 72m.

Explanation:
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-14-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 14 Homework Answer Key-1c
Length of the side of the Octagon = 9m
Perimeter of the Octagon = 8 × Side
= 8 × 9m
= 72m.

d.
Eureka Math Grade 3 Module 7 Lesson 14 Homework Answer Key h 4
Perimeter = _______ in
Answer:
Perimeter of the Hexagon = 36in.

Explanation:
Engage-NY-Eureka-Math-3rd-Grade-Module-7-Lesson-14-Answer-Key-Eureka Math Grade 3 Module 7 Lesson 14 Homework Answer Key-1d
Length of the side of the Hexagon = 6in
Perimeter of the Hexagon = 6 × Side
= 6 × 6in
= 36in.

Question 2.
Label the unknown side lengths of the rectangle below. Then, find the perimeter of the rectangle.
Eureka Math Grade 3 Module 7 Lesson 14 Homework Answer Key h 5
Perimeter = _______ cm
Answer:
Perimeter of the rectangle =  2 ( Length + Width )
= 2 ( 9cm + 4cm )
= 2 × 13cm
= 26cm.

Explanation:
Length of the rectangle = 9cm
Width of the rectangle = 4cm
Perimeter of the rectangle =  2 ( Length + Width )
= 2 ( 9cm + 4cm )
= 2 × 13cm
= 26cm.

Question 3.
Roxanne draws a regular pentagon and labels a side length as shown below. Find the perimeter of Roxanne’s pentagon.
Eureka Math Grade 3 Module 7 Lesson 14 Homework Answer Key h 6
Answer:
Perimeter of the Roxanne’s pentagon = 5 × Side
= 5 × 7cm
= 35cm.

Explanation:
Length of the side of the Roxanne’s pentagon = 7cm
Perimeter of the Roxanne’s pentagon = 5 × Side
= 5 × 7cm
= 35cm.

Question 4.
Each side of a square field measures 24 meters. What is the perimeter of the field?
Answer:
Perimeter of the Square field = 4 × Side
= 4 × 24meters
= 96meters.

Explanation:
Length of the side of the Square field = 24 meters
Perimeter of the Square field = 4 × Side
= 4 × 24meters
= 96meters.

Question 5.
What is the perimeter of a rectangular sheet of paper that measures 8 inches by 11 inches?
Answer:
Perimeter of the rectangular sheet of paper = 2 ( Length  + Width )
= 2 (11inches + 8inches)
= 38inches.

Explanation:
Length of the rectangular sheet of paper = 11inches
Width of the rectangular sheet of paper = 8inches
Perimeter of the rectangular sheet of paper = 2 ( Length  + Width )
= 2 (11inches + 8inches)
= 2 × 19inches
= 38inches.

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