## Engage NY Eureka Math 6th Grade Module 1 Lesson 27 Answer Key

### Eureka Math Grade 6 Module 1 Lesson 27 Example Answer Key

Example 1.
Solve the following three problems.
Write the words PERCENT, WHOLE, or PART under each problem to show which piece you were solving for.
60% of 300 = ____________            60% of ____________ = 300           60 out of 300 = ____________ %

____________________                       ____________________                      ____________________ How did your solving method differ with each problem?
Solutions will vary. A possible answer may include: When solving for the part, I need to find the missing number in the numerator. When solving for the whole, I solve for the denominator. When I solve for the percent, I need to find the numerator when the denominator is 100.

### Eureka Math Grade 6 Module 1 Lesson 27 Exercise Answer Key

Exercise 1.
Use models, such as 10 × 10 grids, ratio tables, tape diagrams, or double number line diagrams, to solve the following situation.
Priya is doing her back-to-school shopping. Calculate all of the missing values in the table below, rounding to the nearest penny, and calculate the total amount Priya will spend on her outfit after she receives the indicated discounts.  Shirt 25% = $$\frac{25}{100}=\frac{1}{4}=\frac{11}{44}$$ The discount is $11. The cost of the shirt is$33 because $44 –$11 = $33. Pants 30% = $$\frac{30}{100}=\frac{15}{50}$$ The original price is$50. The price of the pants is $35 because$50 – $15 =$35.
Shoes 15% = $$\frac{15}{100}=\frac{3}{20}=\frac{9}{60}$$ The original price is $60. The cost of the shoes is$51 because $60 –$9 = $51. Necklace 10% = $$\frac{1}{10}=\frac{2}{20}$$ The discount is$2. The cost of the necklace is $18 because$20 – $2 =$18.