Engage NY Eureka Math 3rd Grade Module 4 Lesson 13 Answer Key
Eureka Math Grade 3 Module 4 Lesson 13 Problem Set Answer Key
Question 1.
Each of the following figures is made up of 2 rectangles. Find the total area of each figure.
Figure 1: Area of A + Area of B: ____18_____ sq units + _____9____ sq units = _____27____ sq units
Figure 2: Area of C + Area of D: ____18_____ sq units + ___15______ sq units = ___33______ sq units
Figure 3: Area of E + Area of F: _____9____ sq units + ____21_____ sq units = ____30_____ sq units
Figure 4: Area of G + Area of H: _____49____ sq units + ___6______ sq units = ____55_____sq units
Answer:
The total area of figure 1 = 27 sq units.
the total area of figure 2 = 33 sq units.
the total area of figure 3 = 30 sq units.
the total area of figure 4 = 55 sq units.
Explanation:
In the above-given question,
given that,
the area of rectangle A + rectangle B = figure 1.
area of rectangle A = 18 sq units.
area of rectangle B = 9 sq units.
so the area of figure 1 = 27 sq units.
the area of rectangle C + rectangle D = figure 2.
area of rectangle C = 18 sq units.
area of rectangle D = 15 sq units.
so the area of figure 2 = 33 sq units.
the area of rectangle E + rectangle F = figure 3.
area of rectangle E = 9 sq units.
area of rectangle F = 21 sq units.
so the area of figure 3 = 30 sq units.
the area of rectangle G + rectangle H = figure 4.
area of rectangle G = 49 sq units.
area of rectangle H = 6 sq units.
so the area of figure 4 = 55 sq units.
Question 2.
The figure shows a small rectangle cut out of a bigger rectangle. Find the area of the shaded figure.
Area of the shaded figure: __90____ – __12____ = ___78___
Area of the shaded figure: ___78___ square centimeters
Answer:
The area of the shaded figure = 78 sq cm.
Explanation:
In the above-given question,
given that,
area of longer rectangle = 90 sq cm.
area = l x b.
area = 9 x 10.
area = 90 sq cm.
area of smaller rectangle = 12 sq cm.
area = l x b.
area = 3 x 4.
area = 12 sq cm.
area of shaded rectangle = area of longer rectangle – area of smaller rectangle.
area of shaded rectangle = 90 – 12.
area of shaded rectangle = 78 sq cm.
Question 3.
The figure shows a small rectangle cut out of a big rectangle.
a. Label the unknown measurements.
Answer:
The unknown measurements = 4 cm and 5 cm.
Explanation:
In the above-given question,
given that,
the longer rectangle = 9 x 7 = 63 cm.
9 – 4 = 3.
7 – 3 = 4.
so the unknown measurements = 4 cm and 5 cm.
b. Area of the big rectangle:
___9__ cm × __7___ cm = __63___ sq cm
Answer:
The area of big rectangle = 63 sq cm.
Explanation:
In the above-given question,
given that,
area of the big rectangle = l x b.
where l = length, and b = breadth.
area = 9 x 7 = 63 sq cm.
so the area of big rectangle = 63 sq cm.
c. Area of the small rectangle:
___5__ cm × __4___ cm = ___20__ sq cm
Answer:
The area of small rectangle = 20 sq cm.
Explanation:
In the above-given question,
given that,
area of the big rectangle = l x b.
where l = length, and b = breadth.
area = 5 x 4 = 20 sq cm.
so the area of big rectangle = 20 sq cm.
d. Find the area of the shaded figure.
Answer:
The area of the shaded figure = 43 sq cm.
Explanation:
In the above-given question,
given that,
the area of the longer rectangle = 63 sq cm.
area = l x b.
area = 9 x 7.
area = 63 sq cm.
area of smaller rectangle = 20 sq cm.
area = l x b.
area = 5 x 4.
area = 20 sq cm.
area of shaded rectangle = area of the longer rectangle – the area of the smaller rectangle.
area of shaded rectangle = 63 – 20.
area of shaded rectangle = 43 sq cm.
Eureka Math Grade 3 Module 4 Lesson 13 Exit Ticket Answer Key
The following figure is made up of 2 rectangles. Find the total area of the figure.
Area of A + Area of B: _____32___ sq units + ____20_____ sq units = ___52______ sq units
Answer:
The area of rectangle A and B = 52 sq units.
Explanation:
In the above-given question,
given that,
the area of rectangle A + rectangle B = figure 1.
area of rectangle A = 32 sq units.
area of rectangle B = 20 sq units.
so the area of rectangle A and B = 52 sq units.
Eureka Math Grade 3 Module 4 Lesson 13 Homework Answer Key
Question 1.
Each of the following figures is made up of 2 rectangles. Find the total area of each figure.
Figure 1: Area of A + Area of B: ____15_____ sq units + ____9_____ sq units = ___24______ sq units
Figure 2: Area of C + Area of D: ___3______ sq units + ____8_____ sq units = ____24_____ sq units
Figure 3: Area of E + Area of F: ___12______ sq units + ____32_____ sq units = ____44_____ sq units
Figure 4: Area of G + Area of H: _____15____ sq units + ____25_____ sq units = ___40______ sq units
Answer:
The total area of figure 1 = 24 sq units.
the total area of figure 2 = 24 sq units.
the total area of figure 3 = 44 sq units.
the total area of figure 4 = 40 sq units.
Explanation:
In the above-given question,
given that,
the area of rectangle A + rectangle B = figure 1.
area of rectangle A = 15 sq units.
area of rectangle B = 9 sq units.
so the area of figure 1 = 24 sq units.
the area of rectangle C + rectangle D = figure 2.
area of rectangle C = 3 sq units.
area of rectangle D = 8 sq units.
so the area of figure 2 = 24 sq units.
the area of rectangle E + rectangle F = figure 3.
area of rectangle E = 12 sq units.
area of rectangle F = 32 sq units.
so the area of figure 3 = 44 sq units.
the area of rectangle G + rectangle H = figure 4.
area of rectangle G = 15 sq units.
area of rectangle H = 25 sq units.
so the area of figure 4 = 40 sq units.
Question 2.
The figure shows a small rectangle cut out of a big rectangle. Find the area of the shaded figure.
Answer:
The area of the shaded figure = 45 sq cm.
Explanation:
In the above-given question,
given that,
the area of the longer rectangle = 56 sq cm.
area = l x b.
area = 7 x 8.
area = 56 sq cm.
area of smaller rectangle = 9 sq cm.
area = l x b.
area = 3 x 3.
area = 9 sq cm.
area of shaded rectangle = area of the longer rectangle – the area of the smaller rectangle.
area of shaded rectangle = 56 – 9.
area of shaded rectangle = 45 sq cm.
Question 3.
The figure shows a small rectangle cut out of a big rectangle.
a. Label the unknown measurements.
Answer:
The unknown measurements = 3 cm and 4 cm.
Explanation:
In the above-given question,
given that,
the longer rectangle = 9 x 8 = 72 cm.
9 – 6 = 3.
8 – 4 = 4.
so the unknown measurements = 3 cm and 4 cm.
b. Area of the big rectangle:
____9__ cm × ___8___ cm = ___72___ sq cm
Answer:
The area of big rectangle = 72 sq cm.
Explanation:
In the above-given question,
given that,
area of the big rectangle = l x b.
where l = length, and b = breadth.
area = 9 x 8 = 72 sq cm.
so the area of big rectangle = 72 sq cm.
c. Area of the small rectangle:
___3___ cm × ___4___ cm = __12____ sq cm
Answer:
The area of small rectangle = 12 sq cm.
Explanation:
In the above-given question,
given that,
area of the big rectangle = l x b.
where l = length, and b = breadth.
area = 3 x 4 = 12 sq cm.
so the area of small rectangle = 12 sq cm.
d. Find the area of the shaded figure.
Answer:
The area of the shaded figure = 43 sq cm.
Explanation:
In the above-given question,
given that,
area of longer rectangle = 72 sq cm.
area = l x b.
area = 9 x 8.
area = 72 sq cm.
area of smaller rectangle = 12 sq cm.
area = l x b.
area = 3 x 4.
area = 12 sq cm.
area of shaded rectangle = area of longer rectangle – area of smaller rectangle.
area of shaded rectangle = 72 – 12.
area of shaded rectangle = 60 sq cm.
Eureka Math Grade 3 Module 4 Lesson 13 Template Answer Key
Area of A + Area of B: _____32___ sq units + ____20_____ sq units = ___52______ sq units
Answer:
The area of rectangle A and B = 52 sq units.
Explanation:
In the above-given question,
given that,
the area of rectangle A + rectangle B = figure 1.
area of rectangle A = 32 sq units.
area of rectangle B = 20 sq units.
so the area of rectangle A and B = 52 sq units.