Go through the **enVision Math Common Core Grade 3 Answer Key Topic 10 Multiply by Multiples of 10** and finish your homework or assignments.

## enVision Math Common Core 2nd Grade Answers Key Topic 10 Multiply by Multiples of 10

**enVision STEM Project: Animal and Plant Characteristics**

**Do Research** Use the Internet or other sources to find information about how the characteristics of some plants and animals help them survive. Think about how characteristics can be different among members of the same species.

**Journal: Write a Report** Include what you found. Also in your report:

- Tell about an insect that uses camouflage.
- Describe an example of how a plant’s thorns help it survive.
- Make up and solve multiplication problems about the animals or plants you research. Use multiples of 10.

**Review What You Know**

**Vocabulary**

Choose the best term from the box. Write it on the blank.

• multiplication

• factor

• equation

• Zero Property of Multiplication

Question 1.

A number sentence where the value on the left and right of the equal sign (=) is the same is called a(n) ___

Answer:

A number sentence where the value on the left and right of the equal sign (=) is the same is called a(n) = Equation .

Question 2.

The ___ states that any number multiplied by zero has a product of zero.

Answer:

The Zero Property of Multiplication states that any number multiplied by zero has a product of zero.

Question 3.

___ is an operation that gives the total number that results when you join equal groups.

Answer:

Multiplication is an operation that gives the total number that results when you join equal groups.

**Multiplication Table**

Find the value that makes the equations true. Use the multiplication table to help.

.

21 ÷ 7 = ___

7×__= 21

Answer:

21 ÷ 7 = 3

7× 3= 21

Explanation :

Step 1: Choose the first number from the numbers listed in the left-most column and the second number from the top-most row.

Step 2: Starting from the 3 move towards the right and starting from the 7 move towards down. The square where the two numbers meet gives the product 21 .

Question 5.

45 ÷ 5 = ___

5 × __ = 45

Answer:

45 ÷ 5 = 9

5 × 9 = 45

Explanation :

Step 1: Choose the first number from the numbers listed in the left-most column and the second number from the top-most row.

Step 2: Starting from the 9 move towards the right and starting from the 5 move towards down. The square where the two numbers meet gives the product 45 .

Question 6.

48 ÷ 6 = ___

6 × __ = 48

Answer:

48 ÷ 6 = 8

6 × 8 = 48

Explanation :

Step 1: Choose the first number from the numbers listed in the left-most column and the second number from the top-most row.

Step 2: Starting from the 8 move towards the right and starting from the 7 move towards down. The square where the two numbers meet gives the product 56 .

Question 7.

56 ÷ 8 = ___

8 × __= 56

Answer:

56 ÷ 8 = 7

8 × 7 = 56

Explanation :

Step 1: Choose the first number from the numbers listed in the left-most column and the second number from the top-most row.

Step 2: Starting from the 3 move towards the right and starting from the 7 move towards down. The square where the two numbers meet gives the product 21 .

**Multiplication Properties**

Find each product.

Question 8.

3 × 3 × 2 =___

Answer:

3 × 3 × 2 = 9 × 2 = 18

Question 9.

5 × 1 × 3 = ___

Answer:

5 × 1 × 3 = 5 × 3 = 15

Question 10.

4 × 2 × 4 = ___

Answer:

4 × 2 × 4 = 8 × 4 = 24

Question 11.

2 × 2 × 4 = ___

Answer:

2 × 2 × 4 =4 × 4 = 16

Question 12.

4 × 0 × 2 = ___

Answer:

4 × 0 × 2 = 0 × 2 =0

Question 13.

2 × 5 × 3 = ___

Answer:

2 × 5 × 3 = 10 × 3 =30

**Multiplication on the Number Line**

Question 14.

Which equation does the number line show?

A. 1 × 10 = 10

B. 3 × 10 × 1 = 30

C. 4 × 5 = 20

D. 5 × 10 = 50

Answer :

Option D. 5 × 10 = 50

Explanation:

Each jump represents + 10 .

Number of jumps made = 5

so, 5 × 10 = 50 .

from 0 to 50 the equation is represented .

**Pick a Project**

**PROJECT 10A**

What do you need to do to plan a trip?

Project: Research the Distance Between Two Cities

**PROJECT 10B**

How do stores make sure they have enough of an item to sell?

Project: Create Your Own Store

**PROJECT 10C**

How do trees help our environment?

Project: Design a Park and Sing a Song

**PROJECT 10D**

How many items can you fit in a box?

Project: Make a Product Game

### Lesson 10.1 Use Patterns to Multiply

**Activity**

**Solve & Share**

Companies package their goods in a variety of ways. One company packages a case of water as 2 rows of 10 bottles. How many bottles are in each of the cases shown in the table below? Explain your thinking.

You can use appropriate tools. Place-value blocks or a number line can help you apply the math you know.

**Look Back!** How can place-value patterns help you when multiplying by 20?

Answer :

Number of bottles in 1 case = 2 rows of 10 bottles = 2 × 10 = 20 bottles .

Explanation :

Number of bottles in 1 case = 1 jump of 20 is 20. 1 × 20 = 20

Number of bottles in 2 case = 2 jumps of 20 are 40. 2 × 20 = 40

Number of bottles in 3 case = 3 jumps of 20 are 60. 3 × 20 = 60

Number of bottles in 4 case = 4 jumps of 20 are 80. 4 × 20 = 80

**Visual Learning Bridge**

**Glossary**

**Essential Question**

How Can You Use Patterns to Multiply?

**A.**

A half-century is a period of 50 years. Find the number of years in 5 half-centuries.

You can use place-value blocks or an open number line to multiply.

**B.**

**One Way**

Find 5 × 50. Use place-value blocks.

1 × 50 is 1 group of 5 tens = 5 tens or 50

2 × 50 is 2 groups of 5 tens = 10 tens or 100

3 × 50 is 3 groups of 5 tens = 15 tens or 150

4 × 50 is 4 groups of 5 tens = 20 tens or 200

5 × 50 is 5 groups of 5 tens = 25 tens or 250

You can skip count to find the number of years in 5 half-centuries.

There are 250 years in 5 half-centuries.

**C.**

**Another Way**

Find 5 × 50. Use an open number line.

1 jump of 50 is 50. 1 × 50 = 50

2 jumps of 50 are 100. 2 × 50 = 100

3 jumps of 50 are 150. 3 × 50 = 150

4 jumps of 50 are 200. 4 × 50 = 200

5 jumps of 50 are 250. 5 × 50 = 250

There are place-value patterns when multiplying by multiples of 10.

There are 250 years in 5 half-centuries.

**Convince Me!** Use Structure Suppose the multiple of 10 in the table above was 40 years instead of 50. Explain how you can use place-value patterns to find each product.

Answer :

Find 5 × 50. Use place-value blocks.

1 × 40 is 1 group of 4 tens = 4 tens or 40

2 × 40 is 2 groups of 4 tens = 80 tens or 80

3 × 40 is 3 groups of 4 tens = 12 tens or 120

4 × 40 is 4 groups of 4 tens = 16 tens or 160

5 × 40 is 5 groups of 4 tens = 20 tens or 200

There are 200 years in 5 half-centuries.

**Guided Practice**

**Do You Understand?**

Question 1.

Explain how to use place-value patterns to multiply 9 × 50.

Answer:

1 jump of 50 is 50. 1 × 50 = 50

2 jumps of 50 are 100. 2 × 50 = 100

3 jumps of 50 are 150. 3 × 50 = 150

4 jumps of 50 are 200. 4 × 50 = 200

5 jumps of 50 are 250. 5 × 50 = 250

6 jumps of 50 are 250. 6 × 50 = 300

7 jumps of 50 are 350. 7 × 50 = 350

8 jumps of 50 are 400. 8 × 50 = 400

9 jumps of 50 are 450. 9 × 50 = 450

There are place-value patterns when multiplying by multiples of 10.

Question 2.

How are the products in Box B on the previous page like skip counting by 5?

Answer:

**Do You Know How?**

Question 3.

Draw or use place-value blocks to show 3 × 60. Then find the product.

Answer:

1 × 60 is 1 group of 6 tens = 6 tens or 60

2 × 60 is 2 groups of 6 tens = 12 tens or 120

3 × 60 is 3 groups of 6 tens = 18 tens or 180

This are place value blocks of 3 × 60 = 180 .

Question 4.

Use the open number line to multiply 4 × 60.

Answer:

1 jump of 60 is 60. 1 × 60 = 60

2 jumps of 60 are 120. 2 × 60 = 120

3 jumps of 60 are 180. 3 × 60 = 180

4 jumps of 60 are 240. 4 × 60 = 240

**Independent Practice**

Leveled Practice In 5-10, use an open number line or draw place-value blocks to find each product.

Question 5.

3 × 70

Answer:

1 jump of 70 is 70. 1 × 70 = 70

2 jumps of 70 are 140. 2 × 70 = 140

3 jumps of 70 are 210. 3 × 70 = 210

4 jumps of 70 are 280. 4 × 70 = 280

Question 6.

8 × 20

Answer:

1 × 20 is 1 group of 2 tens = 2 tens or 20

2 × 20 is 2 groups of 2 tens = 4 tens or 40

3 × 20 is 3 groups of 2 tens = 6 tens or 60

4 × 20 is 4 groups of 2 tens = 8 tens or 80

5 × 20 is 5 groups of 2 tens = 10 tens or 100

6 × 20 is 6 groups of 2 tens = 12 tens or 120

7 × 20 is 7 groups of 2 tens = 14 tens or 140

8 × 20 is 8 groups of 2 tens = 16 tens or 160

This are place value blocks of 8 × 20 = 160 .

Question 7.

9 × 30

Answer:

1 jump of 30 is 30. 1 × 30 = 30

2 jumps of 30 are 90. 2 × 30 = 90

3 jumps of 30 are 120. 3 × 30 = 120

4 jumps of 30 are 120. 4 × 30 = 120

5 jumps of 30 are 150. 5 × 30 = 150

6 jumps of 30 are 180. 6 × 30 = 180

7 jumps of 30 are 210. 7 × 30 = 210

8 jumps of 30 are 240. 8 × 30 = 240

9 jumps of 30 are 270. 9 × 30 = 270

There are place-value patterns when multiplying by multiples of 10.

Question 8.

5 × 60

Answer:

1 jump of 60 is 60. 1 × 60 = 60

2 jumps of 60 are 120. 2 × 60 = 120

3 jumps of 60 are 180. 3 × 60 = 180

4 jumps of 60 are 240. 4 × 60 = 240

5 jumps of 60 are 300. 5 × 60 = 300

Question 9.

6 × 60

Answer:

1 jump of 60 is 60. 1 × 60 = 60

2 jumps of 60 are 120. 2 × 60 = 120

3 jumps of 60 are 180. 3 × 60 = 180

4 jumps of 60 are 240. 4 × 60 = 240

5 jumps of 60 are 300. 5 × 60 = 300

6 jumps of 60 are 360. 6 × 60 = 360

Question 10.

2 × 30

Answer:

1 jump of 30 is 30. 1 × 30 = 30

2 jumps of 30 are 90. 2 × 30 = 60

There are place-value patterns when multiplying by multiples of 10.

**Problem Solving**

Question 11.

The Aztecs had a solar calendar. How many days are in 7 of the longer months in all? Show how to use place value to solve.

Answer:

Question 12.

**Higher Order Thinking** On one open number line, show 4 × 30. On the other open number line, show 3 × 40. How are the problems alike? How are they different?

Answer:

1 jump of 30 is 30. 1 × 30 = 30

2 jumps of 30 are 90. 2 × 30 = 60

3 jump of 30 is 30. 3 × 30 = 90

4 jumps of 30 are 120. 4 × 30 = 120 .

1 jump of 40 is 40. 1 × 40 = 40

2 jumps of 40 are 80. 2 × 40 = 80

3 jumps of 40 are 120. 3 × 40 = 120

jump of both number lines are different but the product is same .

Question 13.

**Reasoning** Martina has $504. She spends $199 on new computer software. Use mental math to find how much money Martina has left.

Answer:

Total Money with Martina = $504 .

Cost of New computer software = $199 .

Money left with Martina = $504 – $199 = 500 + 4 – (200 – 1) = 300 + 5 = 305$ .

Question 14.

Use place-value blocks to find 1 × 40, 2 × 40,3 × 40, and 4 × 40. What is the same in each of the products you listed?

Answer:

1 × 40 is 1 group of 4 tens = 4 tens or 40

2 × 40 is 2 groups of 4 tens = 80 tens or 80

3 × 40 is 3 groups of 4 tens = 12 tens or 120

4 × 40 is 4 groups of 4 tens = 16 tens or 160

All products end with 0 and all are even numbers .

Question 15.

A package of crepe paper streamers has 2 rolls. Yen bought 3 packages. How many inches of crepe paper did Yen get?

Answer:

Number of rolls in each package = 2

Number of packages = 3

Number of inches of crepe paper in 3 = 3 × 2 = 6 rolls .

**Assessment Practice**

Question 16.

Select all the expressions that have a product of 300.

3 × 10

5 × 60

5 × 600

6 × 50

6 × 500

Answer:

Explanation :

3 × 10 = 30

5 × 60 = 300

5 × 600 = 3000

6 × 50 = 300

6 × 500 = 3000

Question 17.

Select all the expressions that have a product of 240.

3 × 80

4 × 60

6 × 40

8 × 30

9 × 30

Answer:

Explanation :

3 × 80 = 240

4 × 60 = 240

6 × 40 = 240

8 × 30 = 240

9 × 30 = 270

### Lesson 10.2 Use Mental Math to Multiply

**Activity**

**Solve & Share**

Find the products of 4 × 50, 3 × 40, and 9 × 20. Describe the patterns you find.

You can look for relationships. Think about how place-value patterns can help you solve the problems.

**Look Back!** How can you use place value to describe the patterns in the products?

Answer :

**Visual Learning Bridge**

**Essential Question**

How Can Place Value Help You Use Mental Math to Multiply by a Multiple of 10?

**A.**

A regular box of crayons has 30 crayons. A jumbo box holds 60 crayons. There are 5 boxes of regular crayons on one shelf and 5 boxes of jumbo crayons on another shelf. How many crayons are on each shelf?

You can use basic multiplication facts to multiply by multiples of 10.

**B.**

Find 5 × 30.

Think about tens. Multiply 5 by the number of tens.

5 × 30 = 5 × 3 tens

5 × 30 = 15 tens

5 × 30 = 150

There are 150 crayons on one shelf.

**C.**

Find 5 × 60.

Sometimes the basic multiplication fact makes the product look different.

5 × 60 = 5 × 6 tens

5 × 60 = 30 tens

5 × 60 = 300

There are 300 crayons on the other shelf.

**Convince Me!** Make Sense and Persevere Suppose there are 50 crayons in each of the 5 boxes. Use mental math to find 5 × 50. How many crayons are in 5 boxes?

Answer :

Number of crayons in each box = 50

Number of boxes = 5

Number of crayons in 5 boxes = 5 × 50

5 × 50 = 5 × 5 tens

5 × 50 = 25 tens

5 × 50 = 250 crayons.

Therefore, Number of crayons in 5 boxes = 250 crayons .

**Guided Practice**

**Do You Understand?**

Question 1.

How can you find the product of 9 × 80? explain.

Answer:

Question 2.

Jon says, “4 × 6 is 4 groups of 6 ones. 4 times 6 equals 24.”

Complete the sentences to describe 4 × 60 in a similar way.

4 × 60 is 4 groups of 6 ___

4 times 60 equals ___

Answer:

4 × 60 is 4 groups of 6 = 4 × 6 = 24 .

4 times 60 equals = 4 × 60 = 240 .

**Do You Know How?**

In 3-8, complete each equation.

Question 3.

6 × 6 = ___

6 × 60 = ___

Answer:

6 × 6 = 36

6 × 60 =36 tens = 360 .

Question 4.

3 × 2 = ___

3 × 20 = ___

Answer:

3 × 2 = 6

3 × 20 = 60 = 6 tens

Question 5.

5 × 4 = ___

5 × 40 = ___

Answer:

5 × 4 = 20

5 × 40 = 20 tens = 200 .

Question 6.

8 × 2 = ___

80 × 2 = ___

Answer:

8 × 2 = 16

80 × 2 = 16 tens = 160 .

Question 7.

4 × 9 = ___

40 × 9 = ___

Answer:

4 × 9 = 36

40 × 9 = 36 tens = 360 .

Question 8.

7 × 8 = ___

70 × 8 = ___

Answer:

7 × 8 = 56

70 × 8 =56 tens = 560 .

**Independent Practice**

Leveled Practice In 9-19, complete each equation.

Question 9.

6 × 70 = (6 × __ ) tens

6 × 70 = __ tens

6 × 70 = __

Answer:

6 × 70 = (6 × 7 ) tens

6 × 70 = 42 tens

6 × 70 = 420

Question 10.

9 × 50 = (9 × __) tens

9 × 50 = __ tens

9 × 50 = ___

Answer:

9 × 50 = (9 × 5 ) tens

9 × 50 = 45 tens

9 × 50 = 450

Question 11.

2 × 6 = ___

2 × 60 = __

Answer:

2 × 6 = 12

2 × 60 = 12 tens

2 × 60 = 120

Question 12.

5 × 8 = ___

5 × 80 = __

Answer:

5 × 8 = 40

5 × 80 = 40 tens

5 × 80 = 400

Question 13.

9 × 4 = ___

9 × 40 = ___

Answer:

9 × 4 = 36

9 × 40 = 36 tens

9 × 40 = 360

Question 14.

2 × 30 = ___

Answer:

2 × 3 = 6

2 × 30 = 6 tens

2 × 30 = 60

Question 15.

60 × 9 = ___

Answer:

6 × 9 = 54

60 × 9 = 54 tens

60 × 9 = 540

Question 16.

___ = 8 × 20

Answer:

8 × 2 = 16

8 × 20 = 16 tens

8 × 20 = 160

Question 17.

80 × 5 = ___

Answer:

8 × 5 = 40

80 × 5 = 40 tens

80 × 5 = 400

Question 18.

___ = 90 × 2

Answer:

9 × 2 = 18

90 × 2 = 18 tens

90 × 2 = 180

Question 19.

30 × 4 = ___

Answer:

3 × 4 = 12

30 × 4 = 12 tens

30 × 4 = 120 .

**Problem Solving**

Question 20.

The horse conch can reach a length of 24 inches. Use multiplication to write 2 different equations that represent the conch’s length.

Answer:

Length of the horse conch = 24 inches .

The two different equations that represent length of horse conch =

24 = 6 × 4

24 = 3 × 8

Question 21.

**Model with Math** Juanita buys 7 sheets of postage stamps at the post office. Each sheet has 20 stamps. How many stamps does she buy in all? Explain how you solved the problem. Tell why you chose that method.

Answer:

Number of sheets of postage stamps = 7

Number of postage stamps for each sheet = 20 .

Number of postage stamps for 7 sheets = 7 × 20

7 × 2 = 14

7 × 20 = 4 tens

7 × 20 = 140 .

Therefore, Number of postage stamps for 7 sheets = 140 stamps .

This method is chosen because where 7 × 2 = 14 is the simply calculation steps are used to calculate the products .

Question 22.

**Algebra** What value makes the equation below true?

9 × ? = 630

Answer:

9 × ? = 630

9 × ? = 63 Tens

9 × 7 = 63

9 × 70 = 630

Question 23.

Janet bought 137 green beads. Now she has 349 beads. How many beads did Janet have before?

Answer:

Number of green beads = 137 .

Number of beads now = 349 .

Number of beads Janet have before = 349 – 137 = 212 beads .

Therefore, Number of beads Janet have before = 212 beads

Question 24.

**Higher Order Thinking** Ali and his family are going to the amusement park. If there are 2 adults and 5 children, how much will the tickets cost?

Answer:

Ticket cost for adult = $30 .

Number of Adults = 2

Tickets cost for adults = 2 × $30 = $60 .

Ticket cost for child = $20 .

Number of children = 5

Tickets cost for children’s = 5 × $20 = $100 .

Total Tickets cost = $60 + $ 100 = $160 .

**Assessment Practice**

Question 25.

Mr. Ridley owns a clothing store. The table at the right shows the number of racks and the number of pieces of clothing on each rack. Match each equation with its product to find the number of pieces of each type of clothing that are on the racks.

Answer:

2 × 60 = 120 .

3 × 40 = 120 .

4 × 20 = 80 .

2 × 40 = 80 .

### Lesson 10.3 Use Properties to Multiply

**Activity**

**Solve & Share**

Three students found 5 × 30 in different ways. Which student is correct? Explain.

Properties can help you critique reasoning.

**Look Back!** What property of multiplication did Earl use in his reasoning?

Answer :

Property used is Associative property

Associative property :

For all real numbers a, b and c .

(a⋅b)⋅c=a⋅(b⋅c)

When you multiply any three real numbers, the grouping (or association) of the numbers does not change the result.

**Visual Learning Bridge**

**Essential Question**

How Can You Use Properties to Multiply by Multiples of 10?

**A.**

How can you find the product of 4 × 20?

Remember the 10s facts pattern. Think about the product of a number and 10. The product has a zero in the ones place. The other factor is written to the left of the zero.

You know how to use an open number line to model multiplication.

You can use properties to explain a rule for finding a product when one factor is a multiple of 10.

**B.**

**One Way**

You can use the Associative Property of Multiplication to group the factors.

Think of 20 as 2 × 10

4 × 20 = 4 × (2 × 10)

4 × 20 = (4 × 2) × 10

4 × 20 = 8 × 10

4 × 20 = 80

**C.**

**Another Way**

You can use the Distributive Property to decompose a factor.

4 × 20 = (2 + 2) × 20

4 × 20 = (2 × 20) + (2 × 20)

4 × 20 = 40 + 40

4 × 20 = 80

**Convince Me! Be Precise** Use properties of multiplication to explain why 3 × 60 = 18 × 10.

Answer :

3 × 60 =

You can use the Associative Property of Multiplication to group the factors.

Think of 60 as 6 × 10

3 × 60 = 3 × (6 × 10)

3 × 60 = (3 × 6) × 10

3 × 60 = 18 × 10

3 × 60 = 180

3 × 60 = 18 × 10 = 180 .

**Guided Practice**

**Do You Understand?**

Question 1.

Why can you say that 3 × 20 = (2 × 20) + 20?

Answer:

Yes, 3 × 20 = (2 × 20) + 20 because

3 × 20 = 20 + 20 + 20 = (2 × 20 )+ 20 .

Question 2.

Why can you say that 3 × 20 = (3 × 2) × 10?

Answer:

3 × 20 =

You can use the Distributive Property to decompose a factor.

20 = 2 × 10

so , 3 × 20 = (3 × 2) × 10 = 6 × 10 = 60 .

**Do You Know How?**

In 3 and 4, find each product using properties of multiplication.

Question 3.

9 × 60 = 9 × (__ × 10)

9 × 60 = (9 × __) × 10

9 × 60 = ___ × 10 = ___

Answer:

You can use the Associative Property of Multiplication to group the factors.

9 × 60 = 9 × ( 6 × 10)

9 × 60 = (9 × 6) × 10

9 × 60 = 54 × 10 = 540

Question 4.

4 × 90 = (___ + 2) × 90

4 × 90 = (__ × 90) + ( ___ × 90)

4 × 90 = ___ + __ = ___

Answer:

You can use the Distributive Property to decompose a factor.

4 × 90 = (2 + 2) × 90

4 × 90 = (2 × 90) + ( 2 × 90)

4 × 90 = 180 + 180 = 360 .

**Independent Practice**

**Leveled Practice** In 5-12, show how to find each product using properties of multiplication.

Question 5.

7 × 60 = 7 × (___ × 10)

7 × 60 = (7 × __ ) × 10

7 × 60 = __ × 10 = ___

Answer:

You can use the Associative Property of Multiplication to group the factors

7 × 60 = 7 × ( 6 × 10)

7 × 60 = (7 × 6 ) × 10

7 × 60 = 42 × 10 = 420

Question 6.

5 × 40 = __ × (__ × 10)

5 × 40 = (__ × __) × 10

5 × 40 = ___ × ___ = __

Answer:

You can use the Associative Property of Multiplication to group the factors

5 × 40 = 5 × ( 4 × 10)

5 × 40 = (5 × 4) × 10

5 × 40 = 20 × 10 = 200

Question 7.

8 × 30

Answer:

8 × 30 = 8 × ( 3 × 10)

8 × 30 = (8 × 3) × 10

8 × 30 = 24 × 10 = 240

Question 8.

4 × 70

Answer:

You can use the Distributive Property to decompose a factor.

4 × 70 = (2 + 2) × 70

4 × 70 = (2 × 70) + ( 2 × 70)

4 × 70 = 140 + 140 = 280 .

Question 9.

5 × 90

Answer:

You can use the Associative Property of Multiplication to group the factors

5 × 90 = 5 × ( 9 × 10)

5 × 90 = (5 × 9) × 10

5 × 90 = 45 × 10 = 450

Question 10.

8 × 80

Answer:

You can use the Distributive Property to decompose a factor.

8 × 80 = (4 + 4) × 80

8 × 80 = (4 × 80) + ( 4 × 80)

8 × 80 = 320 + 320 = 640 .

Question 11.

6 × 40

Answer:

You can use the Associative Property of Multiplication to group the factors

6 × 40 = 6 × ( 4 × 10)

6 × 40 = (6 × 4) × 10

6 × 40 = 24 × 10 = 240 .

Question 12.

9 × 80

Answer:

You can use the Associative Property of Multiplication to group the factors

9 × 80 = 9 × ( 8 × 10)

9 × 80 = (9 × 8) × 10

9 × 80 = 72 × 10 = 720 .

**Problem Solving**

Question 13.

Look at the picture graph at the right. How many pounds of newspaper did Grade 3 collect?

Answer:

Each rectangle represents 30 pounds .

Number of pounds of newspaper in Grade 3 = 4 rectangles = 4 × 30 = 120 pounds .

Question 14.

How many pounds of newspaper did Grade 3 and Grade 4 collect together? Explain your plan for solving.

Answer:

Each rectangle represents 30 pounds .

Number of pounds of newspaper in Grade 3 = 4 rectangles = 4 × 30 = 120 pounds .

Number of pounds of newspaper in Grade 4 = 3 rectangles = 3 × 30 = 90 pounds .

Total pounds of newspaper did Grade 3 and Grade 4 collect together = 120 + 90 = 210 pounds .

Question 15.

**Higher Order Thinking** Grade 5 collected 150 pounds of newspaper. How many more symbols would be in the row for Grade 5 than for Grade 2?

Answer:

Number of pounds of newspapers Grade 5 collected = 150 pounds .

Each rectangle represents 30 pounds .

Number of rectangles symbol in grade 5 = 150 pounds ÷ 30 = 5 rectangles .

Number of rectangles in grade 2 = 2 rectangles.

Number of more symbols would be in the row for Grade 5 than for Grade 2 = 5 – 2 = 3 more symbols .

Question 16.

**Generalize** Without finding the products, how can you tell whether 4 × 60 or 7 × 40 is greater?

Answer:

4 × 60 or 7 × 40 is greater 7 × 40 .

4 × 60 = 4 × 6 × 10 .

7 × 40 = 4 × 7 × 10 .

we notice 4 × 10 is common so, greater than number greater the product. we notice 7 is greater than 6 so , 7 × 40 = 280 is greater than 4 × 60

Question 17.

Explain how to use mental math to add 521 + 104.

Answer:

521 + 104 = 625 .

add ones values numbers 1 + 4 = 5 .

add tens value numbers = 2 + 0 = 2

Add hundred value numbers = 5 + 1 = 6

so, the sum = 625 .

Question 18.

Tikie said that it is easy to count by 50s. Explain how she could use counting by 50s to find 5 × 60.

You can use properties and equations to help construct an argument!

Answer:

You can use the Associative Property of Multiplication to group the factors

5 × 60 = 5 × ( 6 × 10)

5 × 60 = (5 × 6) × 10

5 × 60 = 30 × 10 = 300 .

**Assessment Practice**

Question 19.

Which products are equal to 180? Select all that apply.

1 × 80

6× (3 × 10)

6× 30

3 × (6 × 10)

3 × 60

Answer:

Explanation :

1 × 80 =80

6× (3 × 10) = 180

6× 30 = 180

3 × (6 × 10) = 180

3 × 60 = 180

Question 20.

Which products are equal to 200? Select all that apply.

2 × 10

5 × (4 × 10)

5 × 40

2 × (1 × 10)

4 × 50

Answer:

Explanation :

2 × 10 = 20

5 × (4 × 10) = 200

5 × 40 = 200

2 × (1 × 10) = 20

4 × 50 = 200

### Lesson 10.4 Look For and Use Structure

**Problem Solving**

**Activity**

**Solve & Share**

Stefan says that he could use this multiplication table to help multiply 3 × 40 to get 120. Explain Stefan’s strategy.

**Thinking Habits**

Be a good thinker! These questions can help you.

• What patterns can I see and describe?

• How can I use the patterns to solve the problem?

• Can I see expressions and objects in different ways?

Answer :

3 × 40 = 120 .

Explanation :

Reading a multiplication chart

Step 1: Choose the first number 3 from the numbers listed in the left-most column and the second number 40 from the top-most row.

Step 2: Starting from the first number 3 move towards the right and starting from the second number 40 move towards down. The square where the two numbers meet gives the product 120 !

The multiplication tables of 1, 2, 5, and 10 are easier to remember as they follow a pattern. The product of any number with 1 is the number itself whereas the product of any number with 2 is double the number. The ones digits of the multiplication table of 5 alternates between 0 and 5 and it is easy to remember the table of 10 as well because the digit at the ones place is always zero. These parts of the multiplication chart which are easy to remember are called lower times table.

One important property of multiplication is that the order in which you multiply any two numbers does not affect the product.

So, in a multiplication chart, for any product, you can find the identical number with the numbers reversed in the statement.

**Look Back! Use Structure** Could Stefan also use the multiplication table to solve 4 × 40 in the same way? explain how you decided.

Answer :

Yes, it is explained in the same way .

4 × 40 = 160 .

**Explanation :
**Reading a multiplication chart

Step 1: Choose the first number 4 from the numbers listed in the left-most column and the second number 40 from the top-most row.

Step 2: Starting from the first number 4 move towards the right and starting from the second number 40 move towards down. The square where the two numbers meet gives the product 160 !

**Visual Learning Bridge**

**Essential Question**

How Can I Use Structure to Multiply with Multiples of 10?

**A.**

Find the missing products in the multiplication table.

You can look for relationships in the multiplication table.

**B.**

How can I make use of structure to solve this problem?

I can

• look for patterns to help solve a problem.

• describe the patterns that i find.

• identify how numbers are organized.

**C.**

Here’s my thinking

As I move down the columns, the numbers increase by the value of the column.

As I move across the rows, the numbers increase by the value in the column where 10 is a factor.

I used patterns I know for multiplying by multiples of 10.

**Convince Me! Use Structure** The ones digit never changes in the products in the multiplication table above. Explain why.

**Guided Practice**

**Use Structure** Sean is making muffins. He is choosing to make either 7 or 8 batches. He is also choosing whether to use 40, 50, 60, or 70 raisins for each batch. Sean starts this table to show the total number of raisins he will need for each choice.

You can use the structure of the products and factors to find a pattern.

Question 1.

Find the missing products in the table to show how many raisins Sean will use for each batch. Think about patterns or properties you know.

Answer:

Explanation :

As I move down the columns, the numbers increase by the value of the column that is 40, 50, 60 and 70 respectively .

As I move across the rows, the numbers increase by the value in the column where 10 is a factor.

Question 2.

Sean uses 480 raisins in total. How many batches does he make? How many raisins does he use for each batch?

Answer:

Explanation :

Total Raisins used = 480

The column represents the number of batches that is 8 .

The Row represents the number of raisins in each batch = 60 raisins.

8 × 60 = 480 .

**Independent Practice**

**Use Structure**

Jolene is making a display with equal rows of stickers. She is choosing whether to use 20, 30, 40, or 50 stickers in each row. She is also choosing whether to have 2, 3, or 4 rows. Jolene starts this table to show the total number of stickers she will need for each choice.

Question 3.

Find the missing products in the table to show how many stickers Jolene will need for each choice. Think about patterns or properties you know.

Answer:

Explanation :

As I move down the columns, the numbers increase by the value of the column that is 20, 30, 40 and 50 respectively .

As I move across the rows, the numbers increase by the value in the column where 10 is a factor.

Question 4.

Jolene uses 150 stickers in total. How many rows does she have in her display? How many stickers does she put in each row?

Answer:

Explanation :

Number of stickers used = 150 .

Number of rows used represents the row value that is 3 .

Number of stickers in each row represents the column value that is 50 .

3 × 50 = 150 stickers .

**Problem Solving**

**Performance Task**

**Music Lessons**

Four students each took music lessons for different instruments this month. They want to know who spent the most money on music lessons.

Question 5.

**Make Sense and Persevere** What do you need to do to solve the problem?

Answer:

To calculate the problem we need .

Price paid for 1 lesson and Number of lessons .

Total cost = Price paid for 1 lesson × Number of lessons .

June = 60 × 4 = 240 dollars

Li = 20 × 8 = 160 dollars .

Mick = 10 × 9 = 90 dollars .

Rita = 40 × 7 = 280 dollars

Question 6.

**Use Structure** How can you find the total amount for each student? Think about properties or patterns you know.

Answer:

Think about and look for relationships to help solve problems.

Answer :

Explanation :

To calculate the problem we need .

Price paid for 1 lesson and Number of lessons .

Total cost = Price paid for 1 lesson × Number of lessons .

June = 60 × 4 = 240 dollars

Li = 20 × 8 = 160 dollars .

Mick = 10 × 9 = 90 dollars .

Rita = 40 × 7 = 280 dollars

Question 7.

**Model with Math** Use math you know to complete the table. Circle the name of the student who spent the greatest amount.

Answer:

Explanation :

Total cost = Price paid for 1 lesson × Number of lessons .

June = 60 × 4 = 240 dollars

Li = 20 × 8 = 160 dollars .

Mick = 10 × 9 = 90 dollars .

Rita = 40 × 7 = 280 dollars

Among all Rita spends more money than all .

280 > 240 >160 > 90 .

Question 8.

**Construct Arguments** Did the student who spent the most per lesson also spend the greatest amount in total? explain why or why not.

Answer:

No, the student who spent the most per lesson did not spend the greatest amount in total because the student attends only 4 classes .

The Student spend the greatest amount in total attends 7 classes for 40 dollars for each class spends 280 dollars in total .

That means it depends on number of classes and cost of each class

# Topic 10 Fluency Practice Activity

Shade a path from START to FINISH. Follow the sums or differences that are correct. You can only move up, down, right, or left.

Answer :

**Topic 10 Vocabulary Review**

**Glossary**

**Understand Vocabulary**

**Word List**

• Associative Property of Multiplication

• Distributive Property

• equal groups

• factor

• open number line

• product

• skip count

Question 1.

Skip count by 20s. Cross out any numbers that you do NOT say

when skip counting by 20s.

20 30 40 50 90

Answer:

Question 2.

Cross out any equations below in which 10 is NOT a factor.

3 × 10 = 30 10 = 5 × 2 50 = 10 × 5 10 × 0 = 0

Answer:

Explanation :

10 is the sum of factors 5 and 2 . so it doesn’t have 10 factor .

Question 3.

Cross out any equations below that do NOT show the Associative Property of Multiplication.

(4 × 6) × 7 = 4 (6 × 7) 4 × 3 = 3 × 4 0 = 2 × 0

Answer:

Explanation :

Associative property :

For all real numbers a, b and c .

(a⋅b)⋅c=a⋅(b⋅c)

When you multiply any three real numbers, the grouping (or association) of the numbers does not change the result.

Question 4.

Cross out any equations below in which 8 is NOT the product.

8 = 2 × 4 8 × 8 = 64 2 × (4 × 1) = 8 2 × 8 = 16

Answer:

Write T for true or F for false.

____

Question 5.

An example of the Distributive Property is 6 × 0 = 0.

Answer:

False .

Explanation :

1.Simplify the numbers. In this example, 101 = 100 + 1, so . . . . . .

2.Split the problem into two easier problems. Take the number outside the parentheses, and multiply it by each number inside the parentheses, one at a time.

3.Add the products.

Question 6.

Equal groups have the same amount in each group.

Answer:

True.

Question 7.

An open number line is a plain line that can be used to help you multiply.

Answer:

True .

Explanation :

Multiplying on the number line works no matter what number you count off by.

For example, the number line in the following figure counts off by 5s. This time, the only numbers marked are the multiples of 5, so you can use this number line to multiply any number by 5.

**Use Vocabulary in Writing**

Question 8.

Use at least 2 terms from the Word List to explain how to solve 3 × 30.

Answer:

Distributive property

open number line .

### Topic 10 Reteaching

**Set A**

pages 381-384

Find 5 × 70.

Show 5 jumps of 70 on the number line.

1 jump of 70 is 70. 1 × 70 = 70

2 jumps of 70 are 140. 2 × 70 = 140

3 jumps of 70 are 210. 3 × 70 = 210

4 jumps of 70 are 280. 4 × 70 = 280

5 jumps of 70 are 350. 5 × 70 = 350

There are place-value patterns when multiplying by 10.

**Remember** that you can skip count to show multiplication.

In 1-3, use an open number line to solve.

Question 1.

4 × 80

Answer:

Explanation:

1 jump of 80 is 80. 1 × 80 = 80

2 jumps of 80 are 160. 2 × 80 = 160

3 jumps of 80 are 240. 3 × 80 = 240

4 jumps of 80 are 320. 4 × 80 = 320

There are place-value patterns when multiplying by 10.

Question 2.

7 × 20

Answer:

Explanation :

1 jump of 20 is 20. 1 × 20 = 20

2 jumps of 20 are 40. 2 × 20 = 40

3 jumps of 20 are 60. 3 × 20 = 60

4 jumps of 20 are 80. 4 × 20 = 80

5 jumps of 20 are 100. 5 × 20 = 100

6 jumps of 20 are 120. 5 × 20 = 120

7 jumps of 20 are 140. 5 × 20 = 140

There are place-value patterns when multiplying by 10.

Question 3.

3 × 50

Answer:

Explanation :

1 jump of 50 is 50. 1 × 50 = 50

2 jumps of 50 are 100. 2 × 50 = 100

3 jumps of 50 are 150. 3 × 50 = 150

here are place-value patterns when multiplying by 10.

**Set B**

pages 385-388

You can use basic multiplication facts to multiply by multiples of 10.

Find 6 × 30

Multiply the number of tens by 6.

6 × 30 = 6 × 3 tens

6 × 30 = 18 tens

6 × 30 = 180

Place-value patterns can help you learn a shortcut!

**Remember** to think about basic facts.

In 1-10, find each product.

Question 1.

3 × 30

Answer:

You can use basic multiplication facts to multiply by multiples of 10.

3 × 30

Multiply the number of tens by 3.

3 × 30 = 3 × 3 tens

3 × 30 = 9 tens

3 × 30 = 90

Question 2.

50 × 9

Answer:

You can use basic multiplication facts to multiply by multiples of 10.

9 × 50

Multiply the number of tens by 9.

9 × 50 = 9 × 5 tens

9 × 50 = 45 tens

9 × 50 = 450

Question 3.

6 × 60

Answer:

You can use basic multiplication facts to multiply by multiples of 10.

6 × 60

Multiply the number of tens by 6.

6 × 60 = 6 × 6 tens

6 × 60 = 36 tens

6 × 60 = 360

Question 4.

5 × 80

Answer:

You can use basic multiplication facts to multiply by multiples of 10.

5 × 80

Multiply the number of tens by 5.

5 × 80 = 5 × 8 tens

5 × 80 = 40 tens

5 × 80 = 400

Question 5.

8 × 40

Answer:

You can use basic multiplication facts to multiply by multiples of 10.

8 × 40

Multiply the number of tens by 8.

8 × 40 = 8 × 4 tens

8 × 40 = 32 tens

8 × 40 = 320

Question 6.

80 × 7

Answer:

You can use basic multiplication facts to multiply by multiples of 10.

7 × 80

Multiply the number of tens by 7.

7 × 80 = 7 × 8 tens

7 × 80 = 56 tens

7 × 80 = 560

Question 7.

70 × 4

Answer:

You can use basic multiplication facts to multiply by multiples of 10.

4 × 70

Multiply the number of tens by 4.

4 × 70 = 4 × 7 tens

4 × 70 = 28 tens

4 × 70 = 280

Question 8.

8 × 30

Answer:

You can use basic multiplication facts to multiply by multiples of 10.

8 × 30

Multiply the number of tens by 8.

8 × 30 = 8 × 3 tens

8 × 30 = 24 tens

8 × 30 = 240

Question 9.

7 × 70

Answer:

You can use basic multiplication facts to multiply by multiples of 10.

7 × 70

Multiply the number of tens by 7.

7 × 70 = 7 × 7 tens

7 × 70 = 49 tens

7 × 70 = 490

Question 10.

60 × 5

Answer:

You can use basic multiplication facts to multiply by multiples of 10.

5 × 60

Multiply the number of tens by 5.

5 × 60 = 5 × 6 tens

5 × 60 = 30 tens

5 × 60 = 300

**Set C**

pages 389-392

Find 7 × 80.

Think of 80 as 8 × 10. Then use the Associative Property of Multiplication.

7 × 80 = 7 × (8 × 10)

7 × 80 = (7 × 8) × 10)

7 × 80 = 56 × 10

7 × 80 = 560

You can use properties of operations, such as the Associative Property and the Distributive Property, to help multiply.

**Remember** that the Associative Property of Multiplication lets you regroup factors. In 1 and 2, find the product using properties.

Question 1.

5 × 80 = 5 × (__× 10)

5 × 80 = (5 × __ ) × 10

5 × 80 = __ × 10 = __

Answer:

Write 80 as 8 × 10. Then use the Associative Property of Multiplication.

5 × 80 = 5 × ( 8 × 10)

5 × 80 = (5 × 8 ) × 10

5 × 80 = 40 × 10 = 400

Question 2.

7 × 40 = ___ × (__× 10)

7 × 40 = (__ × __) × 10

7 × 40 = ___ × 10 = ___

Answer :

Write 40 as 4 × 10. Then use the Associative Property of Multiplication.

7 × 40 = 7 × ( 4 × 10)

7 × 40 = ( 7 × 4 ) × 10

7 × 40 = 28 × 10 = 280

**Set D**

pages 393-396

Think about these questions to help you make use of structure.

**Thinking Habits**

• What patterns can I see and describe?

• How can I use the patterns to solve the problem?

• Can I see expressions and objects in different ways?

**Remember** to use patterns or properties to multiply by multiples of 10.

Christy is making a savings plan. She wants to know how much she will save if she saves $40 for 6, 7, 8, or 9 weeks.

Question 1.

How can you use patterns to help solve this problem?

Answer:

As I move down the columns, the numbers increase by the value of the column.

As I move across the rows, the numbers increase by the value in the column where 10 is a factor.

I used patterns I know for multiplying by multiples of 10.

Question 2.

Find the total amount Christy would save after 6, 7, 8, or 9 weeks. Think about patterns or properties you know.

Answer:

As I move down the columns, the numbers increase by the value of the column.

As I move across the rows, the numbers increase by the value in the column where 10 is a factor.

I used patterns I know for multiplying by multiples of 10.

### Topic 10 Assessment Practice

Question 1.

Julia gives each of her 4 friends a sheet of stickers. Each sheet has 20 stickers. How many stickers do her friends have in all?

Answer:

Number of friends = 4

Number of stickers = 20 .

Number of stickers with each friend = 20 ÷ 4 = 5 stickers .

Question 2.

Select all of the expressions equal to 8 × 60.

48 × 10

6 × 80

(8 × 6) × 10

8 × (8 × 10)

60 × 80

Answer:

Explanation :

48 × 10 = 480

6 × 80 = 480

(8 × 6) × 10 = 480

8 × (8 × 10) = 640

60 × 80 = 4800

Question 3.

Mrs. Rode bought 80 packs of juice boxes for her school’s party. The juice boxes came in packs of 8. How many juice boxes did Mrs. Rode buy? explain how to solve.

Answer:

Number of juice boxes = 80 packs.

Number of packs = 8 .

Total Number of juices = 8 × 80

Write 80 as 8 × 10. Then use the Associative Property of Multiplication.

8 × 80 = 8 × ( 8 × 10)

8 × 80 = (8 × 8 ) × 10

8 × 80 = 64 × 10 = 640 Juices .

Question 4.

The third-grade teachers at Jenny’s school need 5 boxes of yellow folders and 4 boxes of red folders. Each box has 40 folders. How many folders do the teachers need?

A. 160

B. 320

C. 200

D. 360

Answer:

Option D – 360 folders

Explanation :

Number of Yellow folders = 5 boxes .

Number of Red folders = 4 boxes .

Number of folders in each box = 40 folders .

Total Folders Teacher needs = ( 5 × 40 ) + ( 4 × 40 ) = ( 5 + 4 ) 40 = 9 × 40 = 360 folders

Question 5..

Write each expression in the correct answer space to show expressions equal to 6 × 30 and 3 × 80.

(3 × 8) 10

3 × (6 × 10)

24 × 10

8 × (3 × 10)

6 × (3 × 10)

18 × 10

3 × (8 × 10)

(6 × 3) × 10

Answer:

Question 6.

Match each expression on the left to an equal expression.

Answer:

Question 7.

What is 4 × 30?

A. 22

B. 34

C. 120

D. 160

Answer:

Option C – 120

Explanation :

4 × 30

Write 80 as 8 × 10. Then use the Associative Property of Multiplication.

4 × 30 = 4 × ( 3 × 10)

4 × 30 = (4 × 3 ) × 10

4 × 30 = 12 × 10 = 120

Question 8.

Tyler does 40 pushups each day. How many pushups does he do in 5 days?

Answer:

Number of pushups done in each day = 40

Number of days = 5

Number of pushups done in 5 days = 5 × 40 = 200 pushups.

Question 9.

The family membership to a children’s museum is $90 for a year. On Friday 5 families bought memberships. How much did the museum receive for the new memberships?

Answer:

Cost of Family membership = $90 for a year

Cost of 5 Families membership = 5 × 90 = 450 $ .

Therefore, the museum receive for the new memberships is 450 $ .

Question 10.

Select all of the expressions that are equal to 7 × 50.

7 × (5 × 10)

35 × 10

7 × 5

75 × 10

(7 × 5) × 10

Answer:

Explanation :

7 × (5 × 10) = 350

35 × 10 =350

7 × 5 = 35

75 × 10 =750

(7 × 5) × 10 = 350

Question 11.

Tyrone drives 30 miles every day. How many miles does Tyrone drive in 7 days?

A. Use a number line to solve the problem.

B. Describe another way to solve the problem.

Answer:

Number of miles Tyrone every day = 30 miles .

Number of days Tyrone drives = 7 days.

Number of miles Tyrone drive for 7 days = 7 × 30 = 210 miles .

A .

B.

Write 30 as 3 × 10. Then use the Associative Property of Multiplication.

7 × 30 = 7 × ( 3 × 10)

7 × 30 = (7 × 3 ) × 10

7 × 30 = 21 × 10 = 210 miles.

### Topic 10 Performance Task

**Pet Adoption**

Carson and Adriana volunteer at a local animal rescue center. The adoption fee is different based on the animal and its age.

Carson made an Adoption Fee graph to show the fees for adult dogs, puppies, adult cats, and kittens. Adriana recorded the number of each animal adopted during the summer in the Animals Adopted table.

Use the Adoption Fee graph and the Animals Adopted table to answer Questions 1-3.

Question 1.

Carson wants to find the total adoption fees the rescue center received for adopted adult dogs. Show how Carson can use a number line to do this.

Answer:

Total Adoption fees the rescue center received for adopted adult dogs = $ 60 .

The cost is divided in increase of $20 .

It is represented on a number line is shown below .

Question 2.

Adriana says that she can use (4 × 8) × 10 to find the total adoption fees for adopted puppies. Is she correct? explain why or why not. Then find the total.

Answer:

Yes she is right .

Explanation :

Adoption fee for puppy = $80 .

Number of puppies adopted = 4

Total Fee for adopting puppies = 4 × 80 = 320$ .

Write 80 as 8 × 10. Then use the Associative Property of Multiplication.

4 × 80 = 4 × ( 8 × 10)

4 × 80 = (4 × 8 ) × 10

4 × 80 = 32 × 10 = 320$ .

Question 3.

Find the adoption fees the rescue center received for kittens. Think about patterns or properties you know. Show your work.

Answer:

Adoption fee for kittens = $60 .

Number of kittens adopted = 3

Total Fee for adopting kittens = 3 × 60 = 180$ .

Write 60 as 6 × 10. Then use the Associative Property of Multiplication.

3 × 60 = 3 × ( 6 × 10)

3 × 60 = (3 × 6 ) × 10

3 × 60 = 18 × 10 = 180$ .

Therefore, the adoption fees the rescue center received for kittens = 180$

The animal rescue center sells toy packages for pets.

The Toy Packages graph shows the amount earned for different types of packages. The Toy Packages Sold table shows how many packages were sold in the summer.

Use the Toy Packages graph and the Toy Packages Sold table to answer Questions 4 and 5.

Question 4.

How much money did the animal rescue center earn from toys for large dogs? Show your work.

Answer:

Cost of toy packages of large dogs = $50

Number of packages sold = 5

Money earned for selling 5 large dogs packages = 5 × 50

Write 50 as 5 × 10. Then use the Associative Property of Multiplication.

5 × 50 = 5 × ( 5 × 10)

5 × 50 = (5 × 5 ) × 10

5 × 50 = 25 × 10 = 250$ .

Therefore, Money earned for selling 5 large dogs packages = $250 .

Question 5.

Carson says that the center earned more money selling toys for small dogs than from selling toys for large dogs. Is he correct? explain why or why not.

Use the Toy Packages graph to answer Question 6.

Answer:

No he is wrong , More money is received by selling Large dog packages than small dog packages .

Explanation :

Cost of toy packages of large dogs = $50

Number of packages sold = 5

Money earned for selling 5 large dogs packages = 5 × 50 = $250 .

Cost of toy packages of small dogs = $30

Number of packages sold = 7

Money earned for selling 7 small dogs packages = 7 × 30 = $210 .

$250 >$210

Question 6.

Adriana forgot to record the number of packages of cat toys that were sold. She knows that the center earned a total of $140 from the toys for cats. How many packages of cat toys did they sell?

Answer:

Total Money earned from toys of cats = $140 .

Cost of toy packages of cats = $20 .

Number of toy cats packages sold = 140 ÷ 20 = 7 packages .

Therefore, packages of cat toys sold = 7 packages .