Printable Area of Regular Figures Worksheets contain questions for finding areas of different 2D Shapes such as Triangles, Squares, Rectangles, Pentagons, Circles, Quadrilaterals, etc. These Sample Area of Regular Shapes Worksheets are exclusively designed for students to aid their preparation. You can check out the step-by-step explanation provided for finding areas of different regular figures along with their formulas. Try to solve the Questions on the Area of Regular Polygons on your own and then verify with the Answers Provided here to understand your subject knowledge.
Also, Read:
Area of Regular Shapes Worksheets
Example 1.
Find the area of the below figure
1. 
2.
3. 
Solution:
1. Area of the rectangle=length × breadth
The length of the rectangle=12
The breadth of the rectangle=10
Area of the given rectangle=12 × 10=120 sq cm
2. Area of the square=side × side
Given side of the square=7 m
=7 × 7=49 sq m
3. Area of the rectangle=length × breadth
The length of the given rectangle=14 cm
The breadth of the given rectangle=15 cm
=14 × 15=210 sq cm
Example 2.
Find the area of the figures
1.
2. 
3. 
Solution:
1. Length of the rectangle=8 cm
The breadth of the rectangle=9 cm
Area of the rectangle=length × breadth
=8 cm × 9 cm=72 sq cm
2.Length of the rectangle=16 cm
The breadth of the rectangle=11 cm
Area of the rectangle=16 cm × 11 cm=176 sq cm
Hence, the area of the given rectangle=176 sq cm
3. Length of the rectangle=16 cm
The breadth of the rectangle=21 cm
Area of the rectangle=16 cm × 21 cm=336 sq cm
Hence, the area of the given rectangle=336 sq cm
Example 3.
Find the area of the following figures
1.
2. 
3. 
Solution:
1. Length of the given rectangle=15 m
The breadth of the given rectangle=5 m
Area of the given rectangle=length × breadth
=5 m × 15 m=75 sq m
Therefore, the Area of the rectangle=75 sq cm
2. Length of the given rectangle=16 cm
The breadth of the given rectangle=5 cm
Area of the given rectangle=length × breadth
=16 m × 5 m=80 sq m
Therefore, the Area of the rectangle=80 sq m
3. Length of the given rectangle=23 m
The breadth of the given rectangle=7 m
Area of the given rectangle=length × breadth
=23 m × 7 m=161 sq m
Therefore, the Area of the rectangle=161 sq m.
Example 4.
Find the area of an equilateral triangle whose perimeter is 18 cm?
Solution:
Given perimeter = 18 cm
We know that the perimeter of an equilateral triangle = 3a
Therefore, 3a=18
a=18/3=6 cm
Hence, the length of the side of an equilateral triangle is 6 cm.
Area= \(\sqrt{ 3 }\)a2/4 sq cm
=\(\sqrt{ 3 }\)62/4 sq cm
=\(\sqrt{ 3 }\)36/4 sqcm
=9\(\sqrt{ 3 }\)sq cm
Therefore, the area of an equilateral triangle is 9\(\sqrt{ 3 }\) sq cm.
Example 5.
Find the area of an equilateral triangle whose side is 4 cm?
Solution:
Area of an equilateral triangle=\(\sqrt{ 3 }\)a2/4
=\(\sqrt{ 3 }\) 42/4 cm
=\(\sqrt{ 3 }\) 16/4 cm
=4\(\sqrt{ 3 }\) sq cm
Hence, the area of an equilateral triangle is 4\(\sqrt{ 3 }\) sq cm.
Example 6.
What is the area of the circle if the radius is 14 cm?
Solution:
Given radius=14 cm
Area of the circle= π × r2
=22/7 × 14 × 14
=22 × 28
=616
Hence, the area of the circle is 616 sq cm.
Example 7.
If the diameter of the circle is 14 cm. Find the area of the circle?
Solution:
Given diameter=14 cm
So radius=14/2=7 cm
Hence area of the circle=π × r2
=22/7 × 7 ×7
=22 ×7
=154 sq cm
Example 8.
Find the area of the pentagon of the side 14 cm and apothem length 8 cm?
Solution:
Given pentagon side=14 cm,apothem length=8 cm
Area of the pentagon=5/2 ×s ×a
=5/2×14×8
=5×7×8
=280 sq cm
Hence, the area of the pentagon is 280 sq cm
Example 9.
Find the area of the regular hexagon whose side is 2 cm?
Solution:
Given side of the hexagon=2 cm
Area of the hexagon=3\(\sqrt{ 3}\)/2 s2
=3\(\sqrt{ 3 }\)/2 22
=3\(\sqrt{ 3 }\) × 2
=6\(\sqrt{ 3 }\) sq cm
Therefore, Area of the regular hexagon is 6\(\sqrt{ 3 }\) sq cm.
Example 10.
Find the area of the pentagon of the side 12 cm and apothem length 4 cm?
Solution:
Given pentagon side=12 cm,apothem length=4 cm
Area of the pentagon=5/2 ×s ×a
=5/2×12×4
=5×6×4
=120 sq cm
Hence, the area of the pentagon is 120 sq cm