Tag: Eureka Math Grade 4 Module 3

Engage NY Eureka Math 4th Grade Module 3 Lesson 29 Answer Key

Eureka Math Grade 4 Module 3 Lesson 29 Problem Set Answer Key

Question 1.
Divide, and then check using multiplication.
a. 1,672 ÷ 4
Answer:

Explanation:
Divided 1,672 ÷ 4 = 418 and then checked using multiplication
418 X 4 = 1,672.

b. 1,578 ÷ 4
Answer:

Explanation:
Divided 1,578 ÷ 4 = 394, Remainder 2 and then checked using multiplication and adding 2 as
394 X 4 = 1,576, 1,576 + 2 = 1,578.

c. 6,948 ÷ 2
Answer:

Explanation:
Divided 6,948 ÷ 2 = 3,474 and then checked using
multiplication as 3,474 X 2 = 6,948.

d. 8,949 ÷ 4
Answer:

Explanation:
Divided 8,949 ÷ 4 = 2,237, Remainder 1 and then checked using
multiplication and adding 1 as 2,237 X 4 = 8,948,
8,948+ 1 = 8,949.

e. 7,569 ÷ 2
Answer:

Explanation:
Divided 7,569 ÷ 2 = 3,784, Remainder 1 and then checked using multiplication and adding 1 as
3,784 X 2 = 7,568, 7,568 + 1 = 7,569.

f. 7,569 ÷ 3
Answer:

Explanation:
Divided 7,569 ÷ 3 = 2,523 and then checked using multiplication as 2,523 X 3 = 7,569.

g. 7,955 ÷ 5
Answer:

Explanation:
Divided 7,955 ÷ 5 = 1,591 and then checked using multiplication as 1,591 X 5 = 7,955.

h. 7,574 ÷ 5
Answer:

Explanation:
Divided 7,574 ÷ 5 = 1,514, Remainder 4 and then checked using multiplication and adding 4 as 1,514 X 4 = 7,570, 7,570 + 4 = 7,574.

i. 7,469 ÷ 3
Answer:

Explanation:
Divided 7,469 ÷ 3 = 2,489, Remainder 2 and then checked using multiplication and adding 2 as 2,489 X 2 = 7,467, 7,467 + 2 = 7,469.

j. 9,956 ÷ 4
Answer:

Explanation:
Divided 9,956 ÷ 4 = 2,489 and then checked using multiplication as 2,489 X 4 = 9,956.

Question 2.
There are twice as many cows as goats on a farm. All the cows and goats have a total of 1,116 legs. How many goats are there?
Answer:
There are 93 goats,

Explanation:
Given there are twice as many cows as goats on a farm.
All the cows and goats have a total of 1,116 legs.
Number of cows and goats are 1,116 ÷ 4  = 279,
So number of goats are 279 ÷ 3 = 93 as shown above.

Eureka Math Grade 4 Module 3 Lesson 29 Exit Ticket Answer Key

Question 1.
Divide, and then check using multiplication.
a. 1,773 ÷ 3
Answer:

Explanation:
Divided 1,773 ÷ 3 = 591 and then checked using multiplication as 591 X 3 = 1,773.

b. 8,472 ÷ 5
Answer:

Explanation:
Divided 8,472 ÷ 5 = 1,694, Remainder 2 and then checked using multiplication and adding 2 as 1,694 X 5 = 8,470, 8,470 + 2 = 8,472.

Question 2.
The post office had an equal number of each of 4 types of stamps. There was a total of 1,784 stamps. How many of each type of stamp did the post office have?
Answer:
Each type of stamp did the post office have is 446,

Explantion:
Given the post office had an equal number of each of 4 types of stamps.
There was a total of 1,784 stamps.
So number of each type of stamp did the post office have is
1,784 ÷ 4 =
    446    
4|1,784
   16
     18
     16
       24
       24
0
Therefore, number of each type of stamp did the post office have is 446.

Eureka Math Grade 4 Module 3 Lesson 29 Homework Answer Key

Question 1.
Divide, and then check using multiplication.
a. 2,464 ÷ 4
Answer:

Explanation:
Divided 2,464 ÷ 4 = 616 and then checked using multiplication as 616 X 4 = 2,464.

b. 1,848 ÷ 3
Answer:

Explanation:
Divided 1,848 ÷ 3 = 616 and then checked using multiplication as 616 X 3 = 1,848.

c. 9,426 ÷ 3
Answer:

Explanation:
Divided 9,426 ÷ 3 = 3,142 and then checked using multiplication as 3,142 X 3 = 9,426.

d. 6,587 ÷ 2
Answer:

Explanation:
Divided 6,587 ÷ 2 = 3,293, Remainder 1 and then checked using multiplication and adding 1 as 3,293 X 2 = 6,586, 6,586 + 1 = 6,587.

e. 5,445 ÷ 3
Answer:

Explanation:
Divided 5,445 ÷ 3 = 1,815 and then checked using multiplication as 1,815 X 3 = 5,445.

f. 5,425 ÷ 2
Answer:

Explanation:
Divided 5,425 ÷ 2 = 2,712, Remainder 1 and then checked using multiplication and adding 1 as 2,712 X 2 = 5,424, 5,424 + 1 = 5,425.

g. 8,467 ÷ 3
Answer:

Explanation:
Divided 8,467 ÷ 3 = 2,822, Remainder 1 and then checked using multiplication and adding 1 as 2,822 X 3 = 8,466, 8,466 + 1 = 8,467.

h. 8,456 ÷ 3
Answer:

Explanation:
Divided 8,456 ÷ 3 = 2,818, Remainder 2 and then checked using multiplication and adding 2 as 2,818 X 3 = 8,454, 8,454 + 2 = 8,456.

i. 4,937 ÷ 4
Answer:

Explanation:
Divided 4,937 ÷ 4 = 1,234, Remainder 1 and then checked using multiplication and adding 1 as 1,234 X 4 = 4,936, 4,936 + 1 = 4,937.

j. 6,173 ÷ 5
Answer:

Explanation:
Divided 6,173 ÷ 5 = 1,234, Remainder 3 and then checked using multiplication and adding 3 as 1,234 X 5 = 6,170, 6,170 + 3 = 6,173.

Question 2.
A truck has 4 crates of apples. Each crate has an equal number of apples. Altogether, the truck is carrying 1,728 apples. How many apples are in 3 crates?
Answer:
1,296 apples are there in 3 crates,

Explanation:
Given a truck has 4 crates of apples. Each crate has an equal number of apples.
Altogether, the truck is carrying 1,728 apples.
So, 1 crate of consists of 1,728 ÷ 4 = 432 apples
Therefore number of apples in 3 crates are 432 X 3 = 1,296 apples.

Engage NY Eureka Math 4th Grade Module 3 Lesson 30 Answer Key

Eureka Math Grade 4 Module 3 Lesson 30 Problem Set Answer Key

Divide. Check your solutions by multiplying.
Question 1.
204 ÷ 4
Answer:

Explanation:
Divided 204 ÷ 4 = 51 and checked my soluting by multiplying
51 X 4 = 204.

Question 2.
704 ÷ 3
Answer:

Explanation:
Divided 704 ÷ 3 = 234, remainder 2 and checked my soluting by multiplying and adding 2 as 234 X 3 = 702, 702 + 2 = 704.

Question 3.
627 ÷ 3
Answer:

Explanation:
Divided 627÷ 3 = 209,remainder 0 and checked my solution by multiplying as 3 X 209=627.

Question 4.
407÷ 2
Answer:

Explanation:
Divided 407÷2 = 203, remainder 1 and checked my solution by multiplying and adding 1 as 2 X 203 =406 , 406+1 = 407.

Question 5.
760 ÷ 4
Answer:

Explanation:
Divided 760 ÷ 4 = 180, remainder 0 and checked my solution by multiplying  as 4 X 180 = 760.

Question 6.
5,120 ÷ 4
Answer:

Explanation:
Divided 5,120 ÷ 4 = 1,280, remainder 0 and checked my solution by multiplying  as 1,280 X 4 = 5,120.

Question 7.
3,070 ÷ 5
Answer:

Explanation:
Divided 3,070 ÷5 = 614, remainder 0 and checked my solution by multiplying  as 614 X 4 = 3,070.

Question 8.
6,706 ÷ 5
Answer:

Explanation:
Divided 6706 ÷ 5 = 1,341, remainder 1 and checked my solution by multiplying and adding 1 as 1,341 X 5 = 6,705 , 6,705+1 = 6,706.

Question 9.
8,313 ÷ 4
Answer:

Explanation:
Divided 8,313 ÷ 4 = 2,078, remainder 1and checked my solution by multiplying and adding 1 as 1,341 X 5 = 6,705, 6,705 + 1 = 6,706.

Question 10.
9,008 ÷ 3
Answer:

Explanation:
Divided 9,008 ÷ 3 = 3,002, remainder 2 and checked my solution by multiplying and adding 2 as 3,002 X 3 = 9,006, 9,006 + 2 = 9,008.

Question 11.
a. Find the quotient and remainder for 3,131 ÷ 3.
Answer:

Explanation:
Divided 3,131 ÷ 3 = 1,043, remainder 2 and checked my solution by multiplying and adding 2 as 1,043 X 3 = 3,129 , 3,129 + 2 = 3,131,
So, the remainder is 2 and quotient is 1,043 respectively.

b. How could you change the digit in the ones place of the whole so that there would be no remainder? Explain how you determined your answer.
Answer:
By adding 1 to the dividend we get no remainder,

Explanation:
We change the digit in the ones place of the whole so that there would be no remainder by adding 1 to the remainder as
we got remainder 2 and we have divisor 3, So we need to add
3 – 2 = 1 to dividend so that we get no remainder.
3,131 + 1 = 3,132,  3,132 ÷ 3  = 1,044 with 0 remainder.

Eureka Math Grade 4 Module 3 Lesson 30 Exit Ticket Answer Key

Divide. Check your solutions by multiplying.

Question 1.
380 ÷ 4
Answer:

Explanation:
Divided 380 ÷ 4 = 95, remainder 0 and checked my solution by multiplying  as 95 X 4 = 380.

Question 2.
7,040 ÷ 3
Answer:

Explanation:
Divided 7,040 ÷ 3 = 2,346, remainder 2 and checked my solution by multiplying and adding 2 as 2,346 X 3 = 7,038, 7,038 + 2 = 7,040.

Eureka Math Grade 4 Module 3 Lesson 30 Homework Answer Key

Divide. Check your solutions by multiplying.

Question 1.
409 ÷ 5
Answer:

Explanation:
Divided 409 ÷ 5 = 81, remainder 4 and checked my solution by multiplying and adding 4 as 81 X 5 = 405, 405 + 4 = 409.

Question 2.
503 ÷ 2
Answer:

Explanation:
Divided 503 ÷ 2 = 251 ,remainder 1 and checked my solution by multiplying and adding 1 as 251 X 2 = 502, 502+1= 503.

Question 3.
831 ÷ 4
Answer:

Explanation:
Divided 831 ÷ 4 = 207, remainder 3 and checked my solution by multiplying and adding 3 as 207 X 4 = 828, 828 + 3 = 831.

Question 4.
602 ÷ 3
Answer:

Explanation:
Divided 602 ÷ 3 = 200, remainder 2 and checked my solution by multiplying and adding 2 as 200 X 3 = 600, 600 + 2 = 602.

Question 5.
720 ÷ 3
Answer:

Explanation:
Divided 720 ÷ 3 = 240, remainder 0 and checked my solution by multiplying  as 240 X 3 = 720.

Question 6.
6,250 ÷ 5
Answer:

Explanation:
Divided 6,250 ÷ 5 = 1,250, remainder 0 and checked my solution by multiplying  as 1,250 X 5 = 6,250 .

Question 7.
2,060 ÷ 5
Answer:

Explanation:
Divided 2,060 ÷ 5 = 412 and checked my solution by multiplying as  412 X 5 = 2,060.

Question 8.
9,031 ÷ 2
Answer:

Explanation:
Divided 9,031÷ 2 = 4,515, remainder 1 and checked my solution by multiplying and adding 1 as 4,515 X 2 = 9,030, 9,030 + 1 = 9,031.

Question 9.
6,218 ÷ 4
Answer:

Explanation:
Divided 6,218 ÷ 4 = 1,554, remainder 2 and checked my solution by multiplying and adding 2 as 1,554 X 4  = 6,216, 6,216 + 2 = 6,218.

Question 10.
8,000 ÷ 4
Answer:

Explanation:
Divided 8000 ÷ 4 = 2,000, remainder 0 and checked my solution by multiplying as 2,000 X 4 = 8,000.

Engage NY Eureka Math 4th Grade Module 3 Lesson 28 Answer Key

Eureka Math Grade 4 Module 3 Lesson 28 Problem Set Answer Key

Question 1.
Divide. Check your work by multiplying.
Draw disks on a place value chart as needed.
a. 574 ÷ 2
Answer:

Explanation:
Divided 574 ÷ 2 = 287 and checked my work by
multiplying 287 X 2 =574 as shown above.

b. 861 ÷ 3
Answer:

Explanation:
Divided 861 ÷ 3 = 287 and checked my work by multiplying 287 X 3 = 861,
Drawn disks on a place value chart as needed as shown above.

c. 354 ÷ 2
Answer:

Explanation:
Divided 354 ÷ 2 = 177 and checked my work by multiplying 287 X 3 = 354,
Drawn disks on a place value chart as needed as shown above.

d. 354 ÷ 3
Answer:

Explanation:
Divided 354 ÷ 3 =118 and checked my work by multiplying
118 X 3 = 354 as shown above.

e. 873 ÷ 4
Answer:

Explanation:
Divided 873 ÷ 4 = 218, Remainder 1 and checked my
work by multiplying and adding 1 as 218 X 4 = 872,
872 + 1 = 873 as shown above.

f. 591 ÷ 5
Answer:

Explanation:
Divided 591 ÷ 5 = 118, Remainder 1 and checked my
work by multiplying and adding 1 as 118 X 5 = 590,
590 + 1 = 591 as shown above.

g. 275 ÷ 3
Answer:

Explanation:
Divided 275 ÷ 3 = 91, Remainder 2 and checked my
work by multiplying and adding 2 as 91 X 3 = 273,
273 + 2 = 275 as shown above.

h. 459 ÷ 5
Answer:

Explanation:
Divided 459 ÷ 5 = 91, Remainder 4 and checked my
work by multiplying and adding 4 as 91 X 5 = 455,
455 + 4 = 459 as shown above.

i. 678 ÷ 4
Answer:

Explanation:
Divided 678 ÷ 4 = 169, Remainder 2 and checked my
work by multiplying and adding 2 as 169 X 4 = 676,
676 + 2 = 678 as shown above.

j. 955 ÷ 4
Answer:

Explanation:
Divided 955 ÷ 4 = 238, Remainder 3 and checked my
work by multiplying and adding 3 as 238 X 4 = 952,
952 + 3 = 955 as shown above.

Question 2.
Each filled 581 one-liter bottles with apple cider. He distributed
the bottles to 4 stores. Each store received the same number of bottles.
How many liter bottles did each of the stores receive?
Were there any bottles left over? If so, how many?
Answer:
145 liters of bottles each of the stores receive,

Explanation:
Given each filled 581 one-liter bottles with apple cider.
He distributed the bottles to 4 stores. Each store received
the same number of bottles of 581 ÷ 4 = 145 liters,
Remainder 1, So, 145 liters bottles each of the stores receive,
there are 1 bottle left over.

Eureka Math Grade 4 Module 3 Lesson 28 Exit
Ticket Answer Key

Question 1.
Divide. Check your work by multiplying.
Draw disks on a place value chart as needed.
a. 776 ÷ 2
Answer:

Explanation:
Divided 776 ÷ 2 = 388 and checked my work by
multiplying  as 388 X 2 = 776 as shown above.

b. 596 ÷ 3
Answer:

Explanation:
Divided 596 ÷ 3 = 198, Remainder 2 and checked my work by
multiplying and adding 2 as 198 X 3 = 594, 594 + 2 = 596 as shown above.

Question 2.
A carton of milk contains 128 ounces. Sara’s son drinks 4 ounces of
milk at each meal.
How many 4-ounce servings will one carton of milk provide?
Answer:
32 ounces of 4-ounce servings will one carton of milk provide,

Explanation:
Given a carton of milk contains 128 ounces. Sara’s son drinks 4 ounces of
milk at each meal, So 128 ounces ÷ 4 =
    32  
4|128
12
 008
 008
0
therefore, 32 ounces of 4-ounce servings will one carton of milk provide.

Eureka Math Grade 4 Module 3 Lesson 28 Homework Answer Key

Question 1.
Divide. Check your work by multiplying.
Draw disks on a place value
chart as needed.
a. 378 ÷ 2
Answer:

Explanation:
Divided 378 ÷ 2 = 189 and checked my work by
multiplying as 189 X 2 = 378 as shown above.

b. 795 ÷ 3
Answer:

Explanation:
Divided 795 ÷ 3 = 265 and checked my work by
multiplying as 265 X 3 = 795 as shown above.

c. 512 ÷ 4
Answer:

Explanation:
Divided 512 ÷ 4 = 128  and checked my work by
multiplying as 128 X 4 = 512 as shown above.

d. 492 ÷ 4
Answer:

Explanation:
Divided 492 ÷ 4 = 123  and checked my work by
multiplying as 123 X 4 = 492 as shown above.

e. 539 ÷ 3
Answer:

Explanation:
Divided 539 ÷ 3 = 179, Remainder 2 and checked my work by
multiplying and adding 2 as 179 X 3 = 537, 537 + 2 = 539 as shown above.

f. 862 ÷ 5
Answer:

Explanation:
Divided 862 ÷ 5 = 172, Remainder 2 and checked my work by
multiplying and adding 2 as 172 X 5 = 860, 860 + 2 = 862 as shown above.

g. 498 ÷ 3
Answer:

Explanation:
Divided 498 ÷ 3 = 166 checked my work by
multiplying as 166 X 3 = 498 as shown above.

h. 783 ÷ 5
Answer:

Explanation:
Divided 783 ÷ 5 = 156, Remainder 3 and checked my work by
multiplying and adding 3 as 156 X 5 = 780, 780 + 3 = 783 as shown above.

i. 621 ÷ 4
Answer:

Explanation:
Divided 621 ÷ 4 = 155, Remainder 1 and checked my work by
multiplying and adding 1 as 155 X 4 = 620, 620 + 1 = 621 as shown above.

j. 531 ÷ 4
Answer:

Explanation:
Divided 531 ÷ 4 = 132, Remainder 3 and checked my work by
multiplying and adding 3 as 132 X 4 = 528, 528 + 3 = 531 as shown above.

Question 2.
Selena’s dog completed an obstacle course that was 932 meters long.
There were 4 parts to the course, all equal in length. How long was
1 part of the course?
Answer:
1 part of the course is 233 meters long,

Explanation:
Given Selena’s dog completed an obstacle course that was 932 meters long.
There were 4 parts to the course, all equal in length. Number of
meters long was 1 part of the course is 932 meters ÷ 4 =
   233
4|932
  8
  13
12
    12
12
     0
Therefore, 1 part of the course is 233 meters long.

Engage NY Eureka Math 4th Grade Module 3 Lesson 27 Answer Key

Eureka Math Grade 4 Module 3 Lesson 27 Sprint Answer Key

Circle the Prime Number

Answer:

Question 1.
4          3
Answer:
3 is prime, So circled it,

Explanation:
Given 4, 3 as 3 has 2 factors: 1 and 3 itself
so circled it as prime and 4 has more than 2 factors.

Question 2.
6         3
Answer:
3 is prime, So circled it,

Explanation:
Given 6, 3 as 3 has 2 factors: 1 and 3 itself
so circled it as prime and 6 has more than 2 factors.

Question 3.
8         3
Answer:
3 is prime, So circled it,

Explanation:
Given 8, 3 as 3 has 2 factors: 1 and 3 itself
so circled it as prime and 4 has more than 2 factors.

Question 4.
5         10
Answer:
5 is prime, So circled it,

Explanation:
Given 5, 10 as 5 has 2 factors: 1 and 5 itself
so circled it as prime and 10 has more than 2 factors.

Question 5.
5         12
Answer:
5 is prime, So circled it,

Explanation:
Given 5, 12 as 5 has 2 factors: 1 and 5 itself
so circled it as prime and 12 has more than 2 factors.

Question 6.
5         14
Answer:
5 is prime, So circled it,

Explanation:
Given 5, 14 as 5 has 2 factors: 1 and 5 itself
so circled it as prime and 14 has more than 2 factors.

Question 7.
8         7
Answer:
7 is prime, So circled it,

Explanation:
Given 8, 7 as 7 has 2 factors: 1 and 7 itself
so circled it as prime and 8 has more than 2 factors.

Question 8.
9         11
Answer:
11 is prime, So circled it,

Explanation:
Given 9, 11 as 11 has 2 factors: 1 and 11 itself
so circled it as prime and 9 has more than 2 factors.

Question 9.
11         15
Answer:
11 is prime, So circled it,

Explanation:
Given 11, 15 as 11 has 2 factors: 1 and 11 itself
so circled it as prime and 15 has more than 2 factors.

Question 10.
15         17
Answer:
17 is prime, So circled it,

Explanation:
Given 15, 17 as 17 has 2 factors: 1 and 17 itself
so circled it as prime and 15 has more than 2 factors.

Question 11.
19         16
Answer:
19 is prime, So circled it,

Explanation:
Given 19, 16 as 19 has 2 factors: 1 and 19 itself
so circled it as prime and 19 has more than 2 factors.

Question 12.
14         11
Answer:
11 is prime, So circled it,

Explanation:
Given 14, 11 as 11 has 2 factors: 1 and 11 itself
so circled it as prime and 14 has more than 2 factors.

Question 13.
13         12
Answer:
13 is prime, So circled it,

Explanation:
Given 13, 12 as 13 has 2 factors: 1 and 13 itself
so circled it as prime and 12 has more than 2 factors.

Question 14.
18         17
Answer:
17 is prime, So circled it,

Explanation:
Given 18, 17 as 17 has 2 factors: 1 and 17 itself
so circled it as prime and 18 has more than 2 factors.

Question 15.
19         20
Answer:
19 is prime, So circled it,

Explanation:
Given 19, 20 as 19 has 2 factors: 1 and 19 itself
so circled it as prime and 20 has more than 2 factors.

Question 16.
21         23
Answer:
23 is prime, So circled it,

Explanation:
Given 21, 23 as 23 has 2 factors: 1 and 23 itself
so circled it as prime and 21 has more than 2 factors.

Question 17.
25         19
Answer:
19 is prime, So circled it,

Explanation:
Given 25, 19 as 19 has 2 factors: 1 and 19 itself
so circled it as prime and 25 has more than 2 factors.

Question 18.
29         27
Answer:
29 is prime, So circled it,

Explanation:
Given 29, 27 as 29 has 2 factors: 1 and 29 itself
so circled it as prime and 27 has more than 2 factors.

Question 19.
31         30
Answer:
31 is prime, So circled it,

Explanation:
Given 31, 30 as 31 has 2 factors: 1 and 31 itself
so circled it as prime and 30 has more than 2 factors.

Question 20.
33         37
Answer:
37 is prime, So circled it,

Explanation:
Given 33, 37 as 37 has 2 factors: 1 and 37 itself
so circled it as prime and 33 has more than 2 factors.

Question 21.
9         2
Answer:
2 is prime, So circled it,

Explanation:
Given 9, 2 as 2 has 2 factors: 1 and 2 itself
so circled it as prime and 9 has more than 2 factors.

Question 22.
51         2
Answer:
2 is prime, So circled it,

Explanation:
Given 51, 2 as 2 has 2 factors: 1 and 2 itself
so circled it as prime and 51 has more than 2 factors.

Question 23.
40         41         42
Answer:
41 is prime, So circled it,

Explanation:
Given 40, 41, 42 as 41 has 2 factors: 1 and 41 itself
so circled it as prime and 40, 42 has more than 2 factors.

Question 24.
42         43         44
Answer:
43 is prime, So circled it,

Explanation:
Given 42, 43, 44 as 43 has 2 factors: 1 and 43 itself
so circled it as prime and 42, 44 has more than 2 factors.

Question 25.
49         47         45
Answer:
47 is prime, So circled it,

Explanation:
Given 49, 47, 45 as 47 has 2 factors: 1 and 47 itself
so circled it as prime and 49, 45 has more than 2 factors.

Question 26.
53         50         55
Answer:
53 is prime, So circled it,

Explanation:
Given 53, 50, 55 as 53 has 2 factors: 1 and 53 itself
so circled it as prime and 50, 55 has more than 2 factors.

Question 27.
54         56         59
Answer:
59 is prime, So circled it,

Explanation:
Given 54, 56, 59 as 59 has 2 factors: 1 and 59 itself
so circled it as prime and 54, 56 has more than 2 factors.

Question 28.
99         97         95
Answer:
97 is prime, So circled it,

Explanation:
Given 99, 97, 95 as 97 has 2 factors: 1 and 97 itself
so circled it as prime and 99, 95 has more than 2 factors.

Question 29.
90         92         91
Answer:
91 is prime, So circled it,

Explanation:
Given 90, 92, 91 as 91 has 2 factors: 1 and 91 itself
so circled it as prime and 90, 92 has more than 2 factors.

Question 30.
95         96         97
Answer:
97 is prime, So circled it,

Explanation:
Given 95, 96, 97 as 97 has 2 factors: 1 and 97 itself
so circled it as prime and 95, 96 has more than 2 factors.

Question 31.
88         89         90
Answer:
89 is prime, So circled it,

Explanation:
Given 88, 89, 90 as 89 has 2 factors: 1 and 89 itself
so circled it as prime and 88, 90 has more than 2 factors.

Question 32.
60         61         62
Answer:
61 is prime, So circled it,

Explanation:
Given 60, 61, 62 as 61 has 2 factors: 1 and 61 itself
so circled it as prime and 60, 62 has more than 2 factors.

Question 33.
63         65         67
Answer:
67 is prime, So circled it,

Explanation:
Given 63, 65, 67 as 67 has 2 factors: 1 and 67 itself
so circled it as prime and 63, 65 has more than 2 factors.

Question 34.
71         70         69
Answer:
71 is prime, So circled it,

Explanation:
Given 71, 70, 69 as 71 has 2 factors: 1 and 71 itself
so circled it as prime and 70, 69 has more than 2 factors.

Question 35.
73         75         77
Answer:
73 is prime, So circled it,

Explanation:
Given 73, 75, 77 as 73 has 2 factors: 1 and 73 itself
so circled it as prime and 75, 77 has more than 2 factors.

Question 36.
49         79         99
Answer:
79 is prime, So circled it,

Explanation:
Given 49, 79, 99 as 79 has 2 factors: 1 and 79 itself
so circled it as prime and 49, 99 has more than 2 factors.

Question 37.
63         93         83
Answer:
83 is prime, So circled it,

Explanation:
Given 63, 93, 83 as 83 has 2 factors: 1 and 83 itself
so circled it as prime and 63, 93 has more than 2 factors.

Question 38.
22         2         12
Answer:
2 is prime, So circled it,

Explanation:
Given 22, 2, 12 as 2 has 2 factors: 1 and 2 itself
so circled it as prime and 22, 12 has more than 2 factors.

Question 39.
17         27         57
Answer:
17 is prime, So circled it,

Explanation:
Given 17, 27, 57 as 17 has 2 factors: 1 and 17 itself
so circled it as prime and 27, 57  has more than 2 factors.

Question 40.
5         15         25
Answer:
5 is prime, So circled it,

Explanation:
Given 5, 15, 25 as 5 has 2 factors: 1 and 5 itself
so circled it as prime and 15, 25 has more than 2 factors.

Question 41.
39         49         59
Answer:
59 is prime, So circled it,

Explanation:
Given 39, 49, 59 as 59 has 2 factors: 1 and 59 itself
so circled it as prime and 39, 49 has more than 2 factors.

Question 42.
1         21         31
Answer:
31 is prime, So circled it,

Explanation:
Given 1, 21, 31 as 31 has 2 factors: 1 and 31 itself
so circled it as prime and 1, 21 has more than 2 factors.

Question 43.
51         57         2
Answer:
2 is prime, So circled it,

Explanation:
Given 51, 57, 2 as 2 has 2 factors: 1 and 2 itself
so circled it as prime and 51, 57 has more than 2 factors.

Question 44.
84         95         43
Answer:
43 is prime, So circled it,

Explanation:
Given 84, 95, 43 as 43 has 2 factors: 1 and 43 itself
so circled it as prime and 84, 95 has more than 2 factors.

Circle the Prime Number

Answer:

Question 1.
4         5
Answer:
5 is prime, So circled it,

Explanation:
Given 4, 5 as 5 has 2 factors: 1 and 5 itself
so circled it as prime and 4 has more than 2 factors.

Question 2.
6         5
Answer:
5 is prime, So circled it,

Explanation:
Given 6, 5 as 5 has 2 factors: 1 and 5 itself
so circled it as prime and 6 has more than 2 factors.

Question 3.
8         5
Answer:
5 is prime, So circled it,

Explanation:
Given 8, 5 as 5 has 2 factors: 1 and 5 itself
so circled it as prime and 8 has more than 2 factors.

Question 4.
7         10
Answer:
7 is prime, So circled it,

Explanation:
Given 7, 10 as 7 has 2 factors: 1 and 7 itself
so circled it as prime and 10 has more than 2 factors.

Question 5.
7         12
Answer:
7 is prime, So circled it,

Explanation:
Given 7, 12 as 7 has 2 factors: 1 and 7 itself
so circled it as prime and 12 has more than 2 factors.

Question 6.
7         14
Answer:
7 is prime, So circled it,

Explanation:
Given 7, 14 as 7 has 2 factors: 1 and 7 itself
so circled it as prime and 14 has more than 2 factors.

Question 7.
4         3
Answer:
3 is prime, So circled it,

Explanation:
Given 4, 3 as 3 has 2 factors: 1 and 3 itself
so circled it as prime and 4 has more than 2 factors.

Question 8.
11         10
Answer:
11 is prime, So circled it,

Explanation:
Given 11, 10 as 11 has 2 factors: 1 and 11 itself
so circled it as prime and 10 has more than 2 factors.

Question 9.
15         11
Answer:
11 is prime, So circled it,

Explanation:
Given 15, 11 as 11 has 2 factors: 1 and 11 itself
so circled it as prime and 15 has more than 2 factors.

Question 10.
17         15
Answer:
17 is prime, So circled it,

Explanation:
Given 17, 15 as 17 has 2 factors: 1 and 17 itself
so circled it as prime and 15 has more than 2 factors.

Question 11.
19         20
Answer:
19 is prime, So circled it,

Explanation:
Given 19, 20 as 19 has 2 factors: 1 and 19 itself
so circled it as prime and 20 has more than 2 factors.

Question 12.
14         13
Answer:
13 is prime, So circled it,

Explanation:
Given 14, 13 as 13 has 2 factors: 1 and 13 itself
so circled it as prime and 14 has more than 2 factors.

Question 13.
11         12
Answer:
11 is prime, So circled it,

Explanation:
Given 11, 12 as 11 has 2 factors: 1 and 11 itself
so circled it as prime and 12 has more than 2 factors.

Question 14.
16         17
Answer:
17 is prime, So circled it,

Explanation:
Given 16, 17 as 17 has 2 factors: 1 and 17 itself
so circled it as prime and 16 has more than 2 factors.

Question 15.
19         18
Answer:
19 is prime, So circled it,

Explanation:
Given 19, 18 as 19 has 2 factors: 1 and 19 itself
so circled it as prime and 19 has more than 2 factors.

Question 16.
22         23
Answer:
23 is prime, So circled it,

Explanation:
Given 22, 23 as 5 has 2 factors: 1 and 23 itself
so circled it as prime and 22 has more than 2 factors.

Question 17.
21         19
Answer:
19 is prime, So circled it,

Explanation:
Given 21, 19 as 19 has 2 factors: 1 and 19 itself
so circled it as prime and 21 has more than 2 factors.

Question 18.
29         28
Answer:
29 is prime, So circled it,

Explanation:
Given 29, 28 as 29 has 2 factors: 1 and 29 itself
so circled it as prime and 29 has more than 2 factors.

Question 19.
31         33
Answer:
31 is prime, So circled it,

Explanation:
Given 31, 33 as 31 has 2 factors: 1 and 31 itself
so circled it as prime and 33 has more than 2 factors.

Question 20.
35         37
Answer:
37 is prime, So circled it,

Explanation:
Given 35, 37 as 37 has 2 factors: 1 and 37 itself
so circled it as prime and 35 has more than 2 factors.

Question 21.
2         9
Answer:
2 is prime, So circled it,

Explanation:
Given 2, 9 as 2 has 2 factors: 1 and 2 itself
so circled it as prime and 9 has more than 2 factors.

Question 22.
57         2
Answer:
2 is prime, So circled it,

Explanation:
Given 57, 2 as 2 has 2 factors: 1 and 2 itself
so circled it as prime and 57 has more than 2 factors.

Question 23.
42         41         40
Answer:
41 is prime, So circled it,

Explanation:
Given 42, 41, 40 as 41 has 2 factors: 1 and 41 itself
so circled it as prime and 42, 40 has more than 2 factors.

Question 24.
44         43         42
Answer:
43 is prime, So circled it,

Explanation:
Given 44, 43, 42 as 43 has 2 factors: 1 and 43 itself
so circled it as prime and 44, 42 has more than 2 factors.

Question 25.
45         47         49
Answer:
47 is prime, So circled it,

Explanation:
Given 45, 47, 49 as 47 has 2 factors: 1 and 47 itself
so circled it as prime and 45, 49 has more than 2 factors.

Question 26.
53         55         50
Answer:
53 is prime, So circled it,

Explanation:
Given 53, 55, 50 as 53 has 2 factors: 1 and 53 itself
so circled it as prime and 55, 50 has more than 2 factors.

Question 27.
56         54         59
Answer:
59 is prime, So circled it,

Explanation:
Given 56, 54, 59 as 59 has 2 factors: 1 and 59 itself
so circled it as prime and 56, 54 has more than 2 factors.

Question 28.
95         97         99
Answer:
97 is prime, So circled it,

Explanation:
Given 95, 97, 99 as 97 has 2 factors: 1 and 97 itself
so circled it as prime and 95, 99 has more than 2 factors.

Question 29.
90         91         92
Answer:
91 is prime, So circled it,

Explanation:
Given 90, 91, 92 as 91 has 2 factors: 1 and 91 itself
so circled it as prime and 90, 92 has more than 2 factors.

Question 30.
99         98         97
Answer:
97 is prime, So circled it,

Explanation:
Given 99, 98, 97 as 97 has 2 factors: 1 and 97 itself
so circled it as prime and 99, 98 has more than 2 factors.

Question 31.
90         89         88
Answer:
89 is prime, So circled it,

Explanation:
Given 90, 89, 88 as 89 has 2 factors: 1 and 89 itself
so circled it as prime and 90, 88 has more than 2 factors.

Question 32.
67         65         63
Answer:
67 is prime, So circled it,

Explanation:
Given 67, 65, 63 as 67 has 2 factors: 1 and 67 itself
so circled it as prime and 65, 63 has more than 2 factors.

Question 33.
62         61         60
Answer:
61 is prime, So circled it,

Explanation:
Given 62, 61, 60 as 61 has 2 factors: 1 and 61 itself
so circled it as prime and 62, 60 has more than 2 factors.

Question 34.
72         71         70
Answer:
71 is prime, So circled it,

Explanation:
Given 72, 71, 70 as 71 has 2 factors: 1 and 71 itself
so circled it as prime and 72, 70 has more than 2 factors.

Question 35.
77         75         73
Answer:
73 is prime, So circled it,

Explanation:
Given 77, 75, 73 as 73 has 2 factors: 1 and 73 itself
so circled it as prime and 77, 75 has more than 2 factors.

Question 36.
27         67         77
Answer:
67 is prime, So circled it,

Explanation:
Given 27, 67, 77 as 67 has 2 factors: 1 and 67 itself
so circled it as prime and 27, 77 has more than 2 factors.

Question 37.
39         49         59
Answer:
59 is prime, So circled it,

Explanation:
Given 39, 49, 59 as 59 has 2 factors: 1 and 59 itself
so circled it as prime and 39, 49 has more than 2 factors.

Question 38.
32         2         22
Answer:
2 is prime, So circled it,

Explanation:
Given 32, 2, 22 as 2 has 2 factors: 1 and 2 itself
so circled it as prime and 32, 22 has more than 2 factors.

Question 39.
19         49         69
Answer:
19 is prime, So circled it,

Explanation:
Given 19, 49, 69 as 19 has 2 factors: 1 and 19 itself
so circled it as prime and 49, 69 has more than 2 factors.

Question 40.
5         15         55
Answer:
5 is prime, So circled it,

Explanation:
Given 5, 15, 55 as 5 has 2 factors: 1 and 5 itself
so circled it as prime and 15, 55 has more than 2 factors.

Question 41.
99         49         59
Answer:
59 is prime, So circled it,

Explanation:
Given 99, 49, 59 as 59 has 2 factors: 1 and 59 itself
so circled it as prime and 99, 49 has more than 2 factors.

Question 42.
1         21         41
Answer:
41 is prime, So circled it,

Explanation:
Given 1, 21, 41 as 41 has 2 factors: 1 and 41 itself
so circled it as prime and 21 has more than 2 factors.

Question 43.
45         51         2
Answer:
2 is prime, So circled it,

Explanation:
Given 45, 51, 2 as 2 has 2 factors: 1 and 2 itself
so circled it as prime and 45, 51 has more than 2 factors.

Question 44.
48         85         67
Answer:
67 is prime, So circled it,

Explanation:
Given 48, 85, 67 as 67 has 2 factors: 1 and 67 itself
so circled it as prime and 48, 85 has more than 2 factors.

Eureka Math Grade 4 Module 3 Lesson 27 Problem Set Answer Key

Question 1.
Divide. Use place value disks to model each problem.
a. 324 ÷ 2
Answer:

Explanation:
Divided 324 ÷ 2 = 162 using place value disks  as shown above.

b. 344 ÷ 2
Answer:

Explanation:
Divided 344 ÷ 2 = 172 using place value disks  as shown above.

c. 483 ÷ 3
Answer:

Explanation:
Divided 483 ÷ 3 = 161 using place value disks  as shown above.

d. 549 ÷ 3
Answer:

Explanation:
Divided 549 ÷ 3 = 183 using place value disks  as shown above.

Question 2.
Model using place value disks and record using the algorithm.
a. 655 ÷ 5
Disks                              Algorithm
Answer:

Explanation:
Modeled using place value disks and recorded using
the algorithm as shown 655 ÷ 5 = 131.

b. 726÷ 3
Disks                              Algorithm
Answer:

Explanation:
Modeled using place value disks and recorded using
the algorithm as shown 726 ÷ 3 = 242.

c. 688 ÷ 4
Disks                              Algorithm
Answer:

Explanation:
Modeled using place value disks and recorded using
the algorithm as shown 688 ÷ 4 = 172.

Eureka Math Grade 4 Module 3 Lesson 27 Exit Ticket Answer Key

Divide. Use place value disks to model each problem.
Then, solve using the algorithm.

Question 1.
423 ÷ 3
Disks                              Algorithm
Answer:

Explanation:
Divided using place value disks to model each problem.
Then, solved using the algorithm for 423 ÷ 3 = 141.

Question 2.
564 ÷ 4
Disks                              Algorithm
Answer:

Explanation:
Divided using place value disks to model each problem.
Then, solved using the algorithm for 564 ÷ 4 = 141.

Eureka Math Grade 4 Module 3 Lesson 27 Homework Answer Key

Question 1.
Divide. Use place value disks to model each problem.
a. 346 ÷ 2
Answer:

Explanation:
Divided 346 ÷ 2 = 173 using place value disks  as shown above.

b. 528 ÷ 2
Answer:

Explanation:
Divided 528 ÷ 2 = 264 using place value disks  as shown above.

c. 516 ÷ 3
Answer:

Explanation:
Divided 516 ÷ 3 = 172 using place value disks  as shown above.

d. 729 ÷ 3
Answer:

Explanation:
Divided 729 ÷ 3 = 243 using place value disks  as shown above.

Question 2.
Model using place value disks, and record using the algorithm.
a. 648 ÷ 4
Disks                              Algorithm
Answer:

Explanation:
Modeled using place value disks and recorded using the algorithm as shown 648 ÷ 4 = 162.

b. 755 ÷ 5
Disks                              Algorithm
Answer:

Explanation:
Modeled using place value disks and recorded using the algorithm as shown 755 ÷ 5 = 151.

c. 964 ÷ 4
Disks                              Algorithm
Answer:

Explanation:
Modeled using place value disks and recorded using the algorithm as shown 964 ÷ 4 = 241.

Engage NY Eureka Math 4th Grade Module 3 Lesson 26 Answer Key

Eureka Math Grade 4 Module 3 Lesson 26 Problem Set Answer Key

Question 1.
Draw place value disks to represent the following problems. Rewrite each in unit form and solve.

a. 6 ÷ 2 = ____3____
6 ones ÷ 2 = ___3____ ones

Answer:
6 ÷ 2 = 3
6 ones ÷ 2 = 3 ones,

Explanation:
Drawn place value disks to represent the following problems. Rewrote each in unit form and solved as 6 ÷ 2 = 3,
6 ones ÷ 2 = 3 ones.

b. 60 ÷ 2 = ________
6 tens ÷ 2 = ________
Answer:
60 ÷ 2 = 30
6 tens ÷ 2 = 3 tens,

Explanation:
Drawn place value disks to represent the following problems.
Rewrote each in unit form and solved as 60 ÷ 2 = 30,
6 tens ÷ 2 = 3 tens.

c. 600 ÷ 2 = __300______
_____6 hundreds______ ÷ 2 = ____3 hundreds____
Answer:
600 ÷ 2 = 300,
6 hundreds ÷ 2 = 3 hundreds,

Explanation:
Drawn place value disks to represent the following problems.
Rewrote each in unit form and solved as 600 ÷ 2 = 300,
6 hundred ÷ 2 = 3 hundred.

d. 6,000 ÷ 2 = ___3,000_____
__6 thousands_____ ÷ 2 = ____3 thousands______
Answer:
6000 ÷ 2 = 3,000,
6 thousands ÷ 2 = 3 thousands,

Explanation:
Drawn place value disks to represent the following problems.
Rewrote each in unit form and solved as 6,000 ÷ 2 = 3,000,
6 thousands ÷ 2 = 3 thousands.

Question 2.
Draw place value disks to represent each problem. Rewrite each in unit form and solve.
a. 12 ÷ 3 = ___4_____
12 ones ÷ 3 = _____4____ ones
Answer:
12 ÷ 3 = 4,
12 ones ÷ 3 = 4 ones,

Explanation:
Drawn place value disks to represent each problem. Rewrote each in unit form and solved 12 ÷ 3 = 4,
12 ones ÷ 3 = 4 ones.

b. 120 ÷ 3 = __40______
____12 tens______ ÷ 3 = __4 tens___
Answer:
120 ÷ 3 =  40,
12 tens ÷ 3 = 4 tens,

Explanation:
Drawn place value disks to represent each problem.
Rewrote each in unit form and solved 120 ÷ 3 = 40,
12 tens ÷ 3 = 4 tens.

c. 1,200 ÷ 3 = ____400____
____12 hundreds______ ÷ 3 = __4 hundreds____
Answer:
1,200 ÷ 3 = 400,
12 hundreds ÷ 3 = 4 hundreds,

Explanation:
Drawn place value disks to represent each problem.
Rewrote each in unit form and solved 1,200 ÷ 3 = 400,
12 hundreds ÷ 3 = 4 hundreds.

Question 3.
Solve for the quotient. Rewrite each in unit form.
a. 800 ÷ 2 = 400
8 hundreds ÷ 2 = 4 hundreds
Answer:
800 ÷ 2 = 400,
8 hundreds ÷ 2 = 4 hundreds,

b. 600 ÷ 2 = ____300____
Answer:
Solved for the quotient, Rewrote each in unit form as
600 ÷ 2 = 300,
6 hundreds ÷ 2 = 3 hundreds,

c. 800 ÷ 4 = ___200_____
Answer:
Solved for the quotient, Rewrote each in unit form as
800 ÷ 4 = 200,
8 hundreds ÷ 4 = 2 hundreds,

d. 900 ÷ 3 = __300_____
Answer:
900 ÷ 3 = 300,
9 hundreds ÷ 3 = 3 hundreds,

e. 300 ÷ 6 = ____50_____
30 tens ÷ 6 = __5__ tens
Answer:
300 ÷ 6 = 50,
30 tens ÷ 6 = 5 tens,

f. 240 ÷ 4 = ___60_____
Answer:
240 ÷ 4 = 60,
24 tens ÷ 4 = 6 tens,

g. 450 ÷ 5 = ___90_____
Answer:
450 ÷ 5 = 90,
45 tens ÷ 5 = 9 tens,

h. 200 ÷ 5 = ___40____
Answer:
200 ÷ 5 = 40,
20 tens ÷ 5 = 4 tens,

i. 3,600 ÷ 4 = ___900_____
36 hundreds ÷ 4 = __9__ hundreds
Answer:
3,600 ÷ 4 = 900,
36 hundreds ÷ 4 = 9 hundreds,

j. 2,400 ÷ 4 = ___600_____
Answer:
2,400 ÷ 4 = 600,
24 hundreds ÷ 4 = 6 hundreds,

k. 2,400 ÷ 3 = ____800___
Answer:
2,400 ÷ 3 = 800,
24 hundreds ÷ 3 = 8 hundreds,

l. 4,000 ÷ 5 = __800____
Answer:
4,000 ÷ 5 = 800,
40 hundreds ÷ 5 = 8 hundreds,

Question 4.
Some sand weighs 2,800 kilograms. It is divided equally among 4 trucks. How many kilograms of sand are in each truck?
Answer:
700 kilograms of sand are there in each truck,

Explanation:
Given some sand weighs 2,800 kilograms. It is divided equally among 4 trucks.
Number of kilograms of sand are there in each truck is 2,800 kilograms ÷ 4 = 700 kilograms.
Therefore 700 kilograms of sand are there in each truck.

Question 5.
Ivy has 5 times as many stickers as Adrian has. Ivy has 350 stickers. How many stickers does Adrian have?
Answer:
Adrian have 70 stickers,

Explanation:
Given Ivy has 5 times as many stickers as Adrian has.
Ivy has 350 stickers. Number of stickers does Adrian have are 350 stickers ÷ 5 = 70 stickers, therefore Adrian have 70 stickers.

Question 6.
An ice cream stand sold $1,600 worth of ice cream on Saturday, which was 4 times the amount sold on Friday. How much money did the ice cream stand collect on Friday?
Answer:
On Friday the ice cream stand collected $400,

Explanation:
Given an ice cream stand sold $1,600 worth of ice cream on Saturday, which was 4 times the amount sold on Friday.
So money did the ice cream stand collected on Friday is
$1,600 ÷ 4 = $400.

Eureka Math Grade 4 Module 3 Lesson 26 Exit Ticket Answer Key

Question 1.
Solve for the quotient. Rewrite each in unit form.
a. 600 ÷ 3 = 200
6 hundreds ÷ 3 = __2__ hundreds
Answer:
600 ÷ 3 = 200,
6 hundreds ÷ 3 = 2 hundreds,

b. 1,200 ÷ 6 = ___200____
Answer:
1,200 ÷ 6 = 200,
12 hundreds ÷ 6 = 2 hundreds,

c. 2,100 ÷ 7 = __300_____
Answer:
2,100 ÷ 7 = 300,
21 hundreds ÷ 7 = 3 hundreds,

d. 3,200 ÷ 8 = _400____
Answer:
3,200 ÷ 8 = 400,
32 hundreds ÷ 8 = 4 hundreds,

Question 2.
Hudson and 7 of his friends found a bag of pennies. There were 320 pennies, which they shared equally. How many pennies did each person get?
Answer:
Each person will get 40 pennies,

Explanation:
Given Hudson and 7 of his friends found a bag of pennies. There were 320 pennies, which they shared equally.
So number of pennies did each person will get is 320 pennies ÷ 8 = 40 pennies each.

Eureka Math Grade 4 Module 3 Lesson 26 Homework Answer Key

Question 1.
Draw place value disks to represent the following problems.
Rewrite each in unit form and solve.
a. 6 ÷ 3 = ___2_____
6 ones ÷ 3 = ____2_____ones

Answer:
6 ÷ 3 = 2
6 ones ÷ 3 = 2 ones,

Explanation:
Drawn place value disks to represent the following problems.
Rewrote each in unit form and solved as 6 ÷ 3 = 2,
6 ones ÷ 3 = 2 ones.

b. 60 ÷ 3 = ___20_____
6 tens ÷ 3 = ____2 tens__________
Answer:
60 ÷ 3 = 20
6 tens ÷ 3 = 2 tens,

Explanation:
Drawn place value disks to represent the following problems. Rewrote each in unit form and solved as 60 ÷ 3 = 20,
6 tens ÷ 3 = 2 tens.

c. 600 ÷ 3 = ___200_____
_____6 hundreds____ ÷ 3 =____2 hundreds_______
Answer:
600 ÷ 3 = 200,
6 hundreds ÷ 3 = 2 hundreds,

Explanation:
Drawn place value disks to represent each problem. Rewrote each in unit form and solved 600 ÷ 3 = 200,
6 hundreds ÷ 2 = 2 hundreds.

d. 6,000 ÷ 3 = __2,000______
_______6 thousands____ ÷ 3 = _______2 thousands_______
Answer:
6,000 ÷ 3 = 2,000,
6 thousands ÷ 3 = 2 thousands,

Explanation:
Drawn place value disks to represent the following problems. Rewrote each in unit form and solved as 6,000 ÷ 3 = 2,000,
6 thousands ÷ 3 = 2 thousands.

Question 2.
Draw place value disks to represent each problem. Rewrite each in unit form and solve.
a. 12 ÷ 4 = __3_____
12 ones ÷ 4 = _____3____ones
Answer:
12 ÷ 4 = 3,
12 ones ÷ 4 = 3 ones,

Explanation:
Drawn place value disks to represent each problem. Rewrote each in unit form and solved 12 ÷ 4 = 3,
12 ones ÷ 4 = 3 ones.

b. 120 ÷ 4 = ___30_____
_____12 tens____ ÷ 4 = __________3 tens___________
Answer:
120 ÷ 4 =  30,
12 tens ÷ 4 = 3 tens,

Explanation:
Drawn place value disks to represent each problem. Rewrote each in unit form and solved 120 ÷ 4 = 30,
12 tens ÷ 4 = 3 tens.

c. 1,200 ÷ 4 = ___300_____
____12 hundreds______ ÷ 4 = ___3 hundreds____
Answer:
1,200 ÷ 4 = 300,
12 hundreds ÷ 4 = 3 hundreds,

Explanation:
Drawn place value disks to represent each problem. Rewrote each in unit form and solved 1,200 ÷ 4 = 300,
12 hundreds ÷ 4 = 3 hundreds.

Question 3.
Solve for the quotient. Rewrite each in unit form.
a. 800 ÷ 4 = 200
8 hundreds ÷ 4 = 2 hundreds
Answer:
800 ÷ 4 = 200,
8 hundreds ÷ 4 = 2 hundreds,

Explanation:
Solved for the quotient, Rewrote each in unit form as
800 ÷ 4 = 200,
8 hundreds ÷ 4 = 2 hundreds.

b. 900 ÷ 3 = ____300_____
Answer:
900 ÷ 3 = 300,
9 hundreds ÷ 3 = 3 hundreds,

c. 400 ÷ 2 = ___200_____
Answer:
400 ÷ 2 = 200,
4 hundreds ÷ 2 = 2 hundreds,

d. 300 ÷ 3 = __100___
Answer:
300 ÷ 3 = 100,
30 tens ÷ 3 = 10 tens,

e. 200 ÷ 4 = ___50______
20 tens ÷ 4 = _5___ tens
Answer:
200 ÷ 4 = 50,
20 tens ÷ 4 = 5 tens

f. 160 ÷ 2 = ____80_____
Answer:
160 ÷ 2 = 80,
16 tens ÷ 2 = 8 tens,

g. 400 ÷ 5 = __80______
Answer:
400 ÷ 5 = 80,
40 tens ÷ 5 = 8 tens,

Explanation:
Solved for the quotient, Rewrote each in unit form as
400 ÷ 5 = 80,
40 tens ÷ 5 = 8 tens.

h. 300 ÷ 5 = ___60_____
Answer:
300 ÷ 5 = 60,
30 tens ÷ 5 = 6 tens

i. 1,200 ÷ 3 = ___400______
12 hundreds ÷ 3 = _4___ hundreds
Answer:
1,200 ÷ 3 = 400,
12 hundreds ÷ 3 = 4 hundreds,

j. 1,600 ÷ 4 = ___400_____
Answer:
1,600 ÷ 4 = 400,
16 hundreds ÷ 4 = 4 hundreds

k. 2,400 ÷ 4 = ___600____
Answer:
2,400 ÷ 4 = 600,
24 hundreds ÷ 4 = 6 hundreds

l. 3,000 ÷ 5 = __600____
Answer:
3,000 ÷ 5 = 600,
30 hundreds ÷ 5 = 6 hundreds

Question 4.
A fleet of 5 fire engines carries a total of 20,000 liters of water. If each truck holds the same amount of water. how many liters of water does each truck carry?
Answer:
4,000 liters of water each truck carry,

Explanation:
Given a fleet of 5 fire engines carries a total of 20,000 liters of water.
If each truck holds the same amount of water.
The number of liters of water does each truck carry is
20,000 ÷ 5 = 4,000 liters.

Question 5.
Jamie drank 4 times as much juice as Brodie. Jamie drank 280 milliliters of juice. How much juice did Brodie drink?
Answer:
70 milliliters of juice Brodie drank,

Explanation:
Given Jamie drank 4 times as much juice as Brodie. Jamie drank 280 milliliters of juice.
So number of liters of juice did Brodie drank is 280 milliliters ÷ 4 = 70 milliliters.

Question 6.
A diner sold $2,400 worth of French fries in June, which was 4 times as much as was sold in May. How many dollars’ worth of French fries were sold at the diner in May?
Answer:
$600 dollars’ worth of French fries were sold at the diner in May,

Explanation:
Given a diner sold $2,400 worth of French fries in June, which was 4 times as much as was sold in May.
So number of dollars’ worth of French fries were sold at the diner in May is $2,400 ÷ 4 = $600.

Eureka Math Grade 4 Module 3 Lesson 26 Template Answer Key

thousands	hundreds	tens	ones

_________1,000____________________________

thousands place value chart for dividing
Answer:

Explanation:
Thousands place value chart for dividing is as shown above while dividing 1,000, the digits will move right 3 spaces.

Engage NY Eureka Math 4th Grade Module 3 Lesson 25 Answer Key

Eureka Math Grade 4 Module 3 Lesson 25 Problem Set Answer Key

Question 1.
Follow the directions.
Shade the number 1 red.
a. Circle the first unmarked number.
b. Cross off every multiple of that number except the one you circled. If it’s already crossed off, skip it.
c. Repeat Steps (a) and (b) until every number is either circled or crossed off.
d. Shade every crossed out number in orange.

Answer:

Shaded the number 1 red,
a. Circled the first unmarked numbers
2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97,

b. Crossed off every multiple of that number except the one I circled as 4, 6, 8, 9, 10, 12, 14, 15, 16, 18, 20, 21, 22, 24, 25, 26, 27, 28, 30, 32, 33, 34, 35, 36, 38, 39, 40, 42, 44, 45, 46, 48, 49, 50, 51, 52, 54, 55, 56, 57, 58, 60, 62, 63, 64, 65, 66, 68, 69, 70, 72, 74, 75, 76, 77, 78, 79, 80, 81, 82, 84, 85, 86, 87, 88, 90, 91, 92, 93, 94, 95, 96, 98, 99 and 100, and If it’s already crossed off, skipped it.

c. Repeated Steps (a) and (b) until every number is either circled or crossed off,

Explanation:
Repeated Steps (a) and (b) until every number is either circled or crossed off as shown above.

d. Shaded every crossed out number in orange,

Explanation:
Shaded every crossed out number in orange as shown in the picture above.

Question 2.
a. List the circled numbers.
Answer:
The circled numbers are 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97 respectively,

b. Why were the circled numbers not crossed off along the way?
Answer:
The circled numbers were not crossed off along the way because they are not the multiples of any other numbers except 1 and themselves,

Explanation:
As shown above the circled numbers were not crossed off along the way because they are not the multiples of any other numbers except 1 and themselves, these numbers are 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97 respectively.

c. Except for the number 1, what is similar about all of the numbers that were crossed off?
Answer:
The crossed off numbers are all composite numbers,

Explanation:
Except for the number 1, the similarity about all of the numbers that were crossed off are composite numbers, composite numbers are the numbers which have more than two factors they are 4, 6, 8, 9, 10, 12, 14, 15, 16, 18, 20, 21, 22, 24, 25, 26, 27, 28, 30, 32, 33, 34, 35, 36, 38, 39, 40, 42, 44, 45, 46, 48, 49, 50, 51, 52, 54, 55, 56, 57, 58, 60, 62, 63, 64, 65, 66, 68, 69, 70, 72, 74, 75, 76, 77, 78, 79, 80, 81, 82, 84, 85, 86, 87, 88, 90, 91, 92, 93, 94, 95, 96, 98, 99 and 100 all these numbers have more than two factors.

d. What is similar about all of the numbers that were circled?
Answer:
The circled numbers are all prime numbers,

Explanation:
The similarity  about all of the numbers that were circled are they are all prime numbers.
Prime numbers are numbers that have only 2 factors:
1 and themselves, So all these numbers 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97 are prime numbers.

Eureka Math Grade 4 Module 3 Lesson 25 Exit Ticket Answer Key

Use the calendar below to complete the following:

1. Cross off all composite numbers.
2. Circle all of the prime numbers.
3. List any remaining numbers.

Answer:

1. Crossed off all composite numbers as 4, 6, 8, 9, 10, 12, 14, 15, 16, 18, 20, 21, 22, 24, 25, 26, 27, 28 and 30,
2. Circled all of the prime numbers as 2, 3, 5, 7, 11, 13, 17, 19, 23, 29 and 31,
3. 1 is the only remaining number,

Eureka Math Grade 4 Module 3 Lesson 25 Homework Answer Key

Question 1.
A student used the sieve of Eratosthenes to find all prime numbers less than 100. Create a step-by-step set of directions to show how it was completed.
Use the word bank to help guide your thinking as you write the directions. Some words may be used just once, more than once, or not at all.

Directions for completing the sieve of Eratosthenes activity:
Answer:
A student used the sieve of Eratosthenes to find all prime numbers less than 100. Created a step-by-step set of directions to show how it is completed,
prime numbers are numbers that have only 2 factors: 1 and themselves, So all these numbers 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97 are prime numbers.

Question 2.
What do all of the numbers that are crossed out have in common?
Answer:
The numbers that are crossed out have in common are composite numbers,

Explanation:
The numbers that are crossed out have in common are composite numbers they are 4, 6, 8, 9, 10, 12, 14, 15, 16, 18, 20, 21, 22, 24, 25, 26, 27, 28, 30, 32, 33, 34, 35, 36, 38, 39, 40, 42, 44, 45, 46, 48, 49, 50, 51, 52, 54, 55, 56, 57, 58, 60, 62, 63, 64, 65, 66, 68, 69, 70, 72, 74, 75, 76, 77, 78, 79, 80, 81, 82, 84, 85, 86, 87, 88, 90, 91, 92, 93, 94, 95, 96, 98, 99 and 100.

Question 3.
What do all of the circled numbers have in common?
Answer:
The circled numbers are all prime numbers,

Explanation:
The similarity  about all of the numbers that were circled are they are all prime numbers.
Prime numbers are numbers that have only 2 factors: 1 and themselves, So all these numbers 2, 3, 5, 7, 11, 13, 17,
19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97 are prime numbers.

Question 4.
There is one number that is neither crossed out nor circled.
Why is it treated differently?
Answer:
1, is the one number that is neither crossed out nor circled,

Explanation:
1, is the one number that is neither crossed out nor circled because the only factor of 1 is 1. A prime number has exactly two factors so 1 isn’t prime. A composite number has more than 2 factors, so 1 isn’t composite.

Engage NY Eureka Math 4th Grade Module 3 Lesson 24 Answer Key

Eureka Math Grade 4 Module 3 Lesson 24 Problem Set Answer Key

Question 1.
For each of the following, time yourself for 1 minute. See how many multiples you can write.
a. Write the multiples of 5 starting from 100.
Answer:
100, 105, 110, 115, 120, 125, 130, 135, 140, 145, 150, 155, 160, 165, 170, 175, 180, 185, 190, 195, 200, 205.

Explanation:
Wrote the multiples of 5 starting from 100 as
100, 105, 110, 115, 120, 125, 130, 135, 140, 145, 150, 155, 160, 165, 170, 175, 180, 185, 190, 195, 200, 205.

b. Write the multiples of 4 starting from 20.
Answer:
20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72, 76, 80, 84, 88, 92, 96, 100, 104, 108, 112, 116, 120,

c. Write the multiples of 6 starting from 36.
Answer:
36, 42, 48, 54, 60, 66, 72, 78, 84, 90, 96, 102, 108, 114, 120, 126, 132, 138, 144, 150, 156, 162, 168,

Question 2.
List the numbers that have 24 as a multiple.
Answer:
The numbers that have 24 as a multiple are
1, 2, 3, 4, 6, 8, 12, 24,

Explanation:
Listed the numbers that have 24 as a multiple are
1, 2, 3, 4, 6, 8, 12, 24,
1 X 24 = 24,
2 X 12 = 24,
3 X 8 = 24,
4 X 6 = 24,
8 X 3 = 24,
12 X 2 = 24,
24 X 1 = 24.

Question 3.
Use mental math, division, or the associative property
to solve. (Use scratch paper if you like.)
a. Is 12 a multiple of 4? __Yes____ Is 4 a factor of 12? ____Yes___
Answer:
Yes, 12 is a multiple of 4,
Yes, 4 is a factor of 12,

Explanation:
Yes, 12 is a multiple of 4, 4 X 3 = 12,
So yes 4 is a factor of 12.

b. Is 42 a multiple of 8? __No____ Is 8 a factor of 42? ___No____
Answer:
No, 14 is not a multiple of 8,
No, 8 is not a factor of 42,

Explanation:
No, 42 is not a multiple of 8, 8 X 5 = 40, remainder 2
So no 8 is not a factor of 42.

c. Is 84 a multiple of 6? ___Yes___ Is 6 a factor of 84? _Yes______
Answer:
Yes, 84 is a multiple of 6,
Yes, 6 is a factor of 84,

Explanation:
Yes, 84 is a multiple of 6, 6 X 14 = 84,
So, yes 6 is a factor of 84.

Question 4.
Can a prime number be a multiple of any other number except itself? Explain why or why not.
Answer:
Yes a prime number will be a multiple of other number except itself and 1,

Explanation:
We know a prime number has 2 factors, 1 and itself, So, a prime number will be a multiple of other number except itself and 1.

Question 5.
Follow the directions below.

a. Circle in red the multiples of 2. When a number is a multiple of 2, what are the possible values for the ones digit?
Answer:

Circled in red the multiples of 2 as 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30, 32, 34, 36, 38, 40, 42, 44, 46, 48, 50, 52, 54, 56, 58, 60, 62, 64, 66, 68, 70, 72, 74, 76, 78, 80, 82, 84, 86, 88, 90, 92, 94, 96, 98,
When a number is a multiple of 2, the possible values for the ones digit are 2, 4, 6, 8, 0,

b. Shade in green the multiples of 3. Choose one. What do you notice about the sum of the digits? Choose another. What do you notice about the sum of the digits?
Answer:
The multiples of 3 as 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57, 60, 63, 66, 69, 72, 75, 78, 81, 84, 87, 90, 93, 96 and 99
The sum of the digits is also a multiples of 3,

Explanation:
Shaded in green the multiples of 3 as 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57, 60, 63, 66, 69, 72, 75, 78, 81, 84, 87, 90, 93, 96 and 99 as shown above in the picture, Choosed one number we notice about that the sum of the digits are multiples of 3, 3, 6 = 3 X 2.

c. Circle in blue the multiples of 5. When a number is a multiple of 5, what are the possible values for the ones digit?
Answer:
Circled in blue the multiples of 5 as 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90, 95 and 100, the possible values for the ones digit are 5, 0,

Explanation:
Circled in blue the multiples of 5 as 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90, 95 and 100, When a number is a multiple of 5 the possible values for the ones digit are 5, 0.

d. Draw an X over the multiples of 10. What digit do all multiples of 10 have in common?
Answer:
The multiples of 10 are 10, 20, 30, 40, 50, 60, 70, 80, 90, 100. They all have a zero in the ones place,

Explanation:
The multiples of 10 are 10, 20, 30, 40, 50, 60, 70, 80, 90, 100.
Drawn an X over the multiles of 10, all the digits which are multiples of 10 have zero in the ones place as common.

Eureka Math Grade 4 Module 3 Lesson 24 Exit Ticket Answer Key

Question 1.
Fill in the unknown multiples of 11.
5 × 11 = __55___
6 × 11 = __66___
7 × 11 = __77___
8 × 11 = __88___
9 × 11 = ___99__
Answer:
5 × 11 = 55
6 × 11 = 66
7 × 11 = 77
8 × 11 = 88
9 × 11 = 99,

Explanation:
Filled in the unknown multiples of 11 as
5 × 11 = 55,
11
X 5
55
6 × 11 = 66,
11
X 6
66
7 × 11 = 77,
11
X 7
77
8 × 11 = 88,
11
X 8
88
9 × 11 = 99,
11
X 9
99 respectively.

Question 2.
Complete the pattern of multiples by skip-counting.
7, 14, __21__, 28, __35__, ___42___, ___49___, __56____, ___63___, __70____
Answer:
7, 14, 21, 28, 35, 42, 49, 56, 63, 70,

Explanation:
Completed the pattern of multiples by skip-counting 7 as
7, 14, 21, 28, 35, 42, 49, 56, 63, 70,
7 X 1 = 7
7 X 2 = 14
7 X 3 = 21
7 X 4 = 28
7 X 5 = 35
7 X 6 = 42
7 X 7 = 49
7 X 8 = 56
7 X 9 = 63
7 X 10 = 70.

Question 3.
a. List the numbers that have 18 as a multiple.
Answer:
The numbers that have 18 as a multiple are
1, 2, 3, 6, 9, 18,

Explanation:
Listed the numbers that have 18 as a multiple are
1, 2, 3, 6, 9, 18,
1 X 18 = 18,
2 X 9 = 18,
3 X 6 = 18,
6 X 3 = 18,
9 X 2 = 18,
18 X 1 = 18.

b. What are the factors of 18?
Answer:
Factors of 18 are 1, 2, 3, 6, 9, 18,

Explanation:
Factors of 18 are
1 X 18 = 18,
2 X 9 = 18,
3 X 6 = 18,
6 X 3 = 18,
9 X 2 = 18,
18 X 1 = 18,
1, 2, 3, 6, 9, 18.

c. Are your two lists the same? Why or why not?
Answer:
Yes the two lists are the same,

Explanation:
Yes the two lists are the same as
A multiple is a number that can be divided by another number a certain number of times without a remainder.
A factor is one of two or more numbers that divides a given number without a remainder.
As multiples of 18 are also the factors of 18, So two lists are the same.

Eureka Math Grade 4 Module 3 Lesson 24 Homework Answer Key

Question 1.
For each of the following, time yourself for 1 minute. See how many multiples you can write.
a. Write the multiples of 5 starting from 75.
Answer:
75, 80, 85, 90, 95, 100, 105, 110, 115, 120, 125, 130, 135, 140, 145, 150, 155, 160, 165, 170,

b. Write the multiples of 4 starting from 40.
Answer:
40, 44, 48, 52, 56, 60, 64, 68, 72, 76, 80, 84, 88, 92, 96, 100, 104, 108, 112, 116, 120, 124, 128, 132, 136, 140.

Explanation:
Wrote the multiples of 4 starting from 40 as 40, 44, 48, 52, 56, 60, 64, 68, 72, 76, 80, 84, 88, 92, 96, 100, 104, 108, 112, 116, 120, 124, 128, 132, 136, 140.

c. Write the multiples of 6 starting from 24.
Answer:

24, 30, 36, 42, 48, 54, 60, 66, 72, 78, 84, 90, 96, 102, 108, 114, 120, 126, 132, 138, 144, 150, 156,

Question 2.
List the numbers that have 30 as a multiple.
Answer:
The numbers that have 30 as a multiple are 1, 2, 3, 5, 6, 10, 15, 30,

Explanation:
Listed the numbers that have 30 as a multiple are
1, 2, 3, 5, 6, 10, 15, 30,
1 X 30 = 30,
2 X 15 = 30,
3 X 10 = 30,
5 X 6 = 30,
6 X 5 = 30,
10 X 3 = 30,
15 X 2 = 30,
30 X 1 = 30.

Question 3.
Use mental math, division, or the associative property to solve. (Use scratch paper if you like.)
a. Is 12 a multiple of 3? __Yes____ Is 3 a factor of 12? __Yes_____
Answer:
Yes, 12 is a multiple of 3,
Yes, 3 is a factor of 12,

b. Is 48 a multiple of 8? ___Yes___ Is 48 a factor of 8? __Yes_____
Answer:
Yes, 48 is a multiple of 8,
Yes, 8 is a factor of 48,

c. Is 56 a multiple of 6? ___No___ Is 6 a factor of 56? __No_____
Answer:
No, 6 is not a multiple of 56,
No, 6 is not a factor of 56,

Explanation:
No, 56 is not a multiple of 6, 6 X 9 = 54, remainder 2
So no 6 is not a factor of 56.

Question 4.
Can a prime number be a multiple of any other number except itself? Explain why or why not.
Answer:
Yes a prime number will be a multiple of other number except itself and 1,

Explanation:
We know a prime number has 2 factors, 1 and itself,
So, a prime number will be a multiple of other number except itself and 1.

Question 5.
Follow the directions below.

a. Underline the multiples of 6. When a number is a multiple of 6, what are the possible values for the ones digit?
Answer:

Underlined the multiples of 6 as 6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, 78, 84, 90, 96,
When a number is a multiple of 6, the possible values for the ones digit are 6, 0,

Explanation:
Underlined the multiples of 6 as 6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, 78, 84, 90, 96, When a number is a multiple of 6, the possible values for the ones digit are 6, 0.

b. Draw a square around the multiples of 4. Look at the multiples of 4 that have an odd number in the tens place. What values do they have in the ones place?
Answer:
The multiples of 4 are 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72, 76, 80, 84, 88,  92, 96, 100, the multiples of 4 that have an odd number in the tens place have even number in the ones place, they are 12, 16, 32, 36, 52, 56, 72, 76, 92 and 96,

c. Look at the multiples of 4 that have an even number in the tens place. What values do they have in the ones place? Do you think this pattern would continue with multiples of 4 that are larger than 100?
Answer:
The multiples of 4 are 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72, 76, 80, 84, 88,  92, 96, 100, the multiples of 4 that have an even number in the tens place have even number in the ones place, they are 20, 24, 28, 40, 44, 48, 60, 64, 68, 80, 84, 92, 96 and 100,
Yes, I think this pattern would continue with multiples of 4 that are larger than 100,

d. Circle the multiples of 9. Choose one. What do you notice about the sum of the digits? Choose another one. What do you notice about the sum of the digits?
Answer:
The multiples of 9 as 9, 18, 27, 36, 45, 54, 63, 72, 81, 90 and 99 , The sum of the digits is also a multiples of 9,

Explanation:
Circled the multiples of 9 as 9, 18, 27, 36, 45, 54, 63, 72, 81, 90 and 99 as shown above in the picture,
Choosed one number we notice about that the sum of the digits are multiples of 9 as 9 , 18 = 9 X 2.

Engage NY Eureka Math 4th Grade Module 3 Lesson 23 Answer Key

Eureka Math Grade 4 Module 3 Lesson 23 Problem Set Answer Key

Question 1.
Explain your thinking or use division to answer the following.
a. Is 2 a factor of 84?
Answer:
Yes, 2 is a factor of 84,

Explanation:
84 is a even number, 2 is a factor of every even number, ( 2 X 42 = 84).

b. Is 2 a factor of 83?
Answer:
No, 2 is not a factor of 83,

Explanation:
83 is a odd number, 2 is not a factor of odd numbers, So 2 is not a factor of 83,
(2 X 41 = 82)  and 82 + 1 = 83.

c. Is 3 a factor of 84?
Answer:
Yes, 3 is a factor of 84,

Explanation:
   28
3| 84
  -6
  24  
-24
0
So 3 is a factor of 84.

d. Is 2 a factor of 92?
Answer:
Yes, 2 is a factor of 92 and 92 is even number,

Explanation:
 46
2| 92
 – 8
 12  
-12
0
So 2 is a factor of 92.

e. Is 6 a factor of 84?
Answer:
Yes, 6 is a factor of 84 and 84 is even number,

Explanation:
 14
6| 84
 – 6
 24  
-24
0
So 6 is a factor of 84.

f. Is 4 a factor of 92?
Answer:
Yes, 4 is a factor of 92,

Explanation:
 23
4| 92
 – 8
  12  
-12
0
So 4 is a factor of 92.

g. Is 5 a factor of 84?
Answer:
No, 5 is not a factor of 84,

Explanation:
84 does not have 5 or 0 in ones place, all the numbers that have 5 as a factor have a 5 or  0 in ones  place,
So 5 is not a factor of 84.

h. Is 8 a factor of 92?
Answer:
No, 8 is not a factor of 92,

Explanation:
 11 R4
8| 92
 – 8
  12  
-08
04
So 8 is not a factor of 92 remainder is 4.

Question 2.
Use the associative property to find more factors of 24 and 36.
a. 24 = 12 × 2
= ( _4__ × 3) × 2
= __4_ × (3 × 2)
= _4__ × 6
= __24_
Answer:
24 = 12 X 2
= (4 X 3) X 2
= 4 X (3 X 2)
= 4 X 6
= 24,

Explanation:
Used the associative property to find more factors of 24 as
24 = 12 X 2
= (4 X 3) X 2
= 4 X (3 X 2)
= 4 X 6
= 24.

b. 36 = __9__ × 4
= ( __3__ × 3) × 4
= __3__ × (3 × 4)
= __3__ × 12
= _36__
Answer:
36 = 9 X 4
= (3 X 3) X 4
= 3 X (3 X 4)
= 3 X 12
= 36,

Explanation:
Used the associative property to find more factors of 36 as
36 = 9 X 4
= (3 X 3) X 4
= 3 X (3 X 4)
= 3 X 12
= 36.

Question 3.
In class, we used the associative property to show that when 6 is a factor, then 2 and 3 are factors, because 6 = 2 × 3.
Use the fact that 8 = 4 × 2 to show that 2 and 4 are factors of 56, 72, and 80.
56 = 8 × 7        72 = 8 × 9        80 = 8 × 10
Answer:
56 = 8 X 7
= (4 X 2) X 7
= 4 X (2 X 7)
= 4 X 14
= 56,

72 = 8 X 9
= 8 X 9
= (4 X 2) X 9
= 4 X (2 X 9)
= 4 X 18
= 72,

80 = 8 × 10
= 8 X 10
= (4 X 2) X 10
= 4 X (2 X 10)
= 4 X 20
= 80,

Explanation:
Used the fact that 8 = 4 × 2 to showed that 2 and 4 are factors of 56, 72, and 80 as

56 = 8 X 7
= (4 X 2) X 7
= 4 X (2 X 7)
= 4 X 14
= 56,

72 = 8 X 9
= 8 X 9
= (4 X 2) X 9
= 4 X (2 X 9)
= 4 X 18
= 72,

80 = 8 × 10
= 8 X 10
= (4 X 2) X 10
= 4 X (2 X 10)
= 4 X 20
= 80.

Question 4.
The first statement is false. The second statement is true. Explain why, using words, pictures, or numbers. If a number has 2 and 4 as factors, then it has 8 as a factor. If a number has 8 as a factor, then both 2 and 4 are factors.
Answer:
 14
2|28
  -2
   08
 -08
0
2 X 14 = 28,
 7
4|28
  -28
   0
4 X 7 = 28,
   3, R4
8|28
  -24
   04
28 has 2 and 4 as factors but not 8,

Explanation:
The first statement is false. The second statement is true. If a number has 2 and 4 as factors, then it has 8 as a factor and If a number has 8 as a factor, then both 2 and 4 are factors,
 14
2|28
  -2
   08
 -08
0
2 X 14 = 28,
 7
4|28
  -28
   0
4 X 7 = 28,
   3, R4
8|28
  -24
   04
28 has 2 and 4 as factors but not 8, any number that can be divided exactly by 8 can also be divided by 2 and 4 instead, Since 8 = 2 X 4,
Example: 8 X 5 = 40, (4 X 2) X 5 = 40.

Eureka Math Grade 4 Module 3 Lesson 23 Exit Ticket Answer Key

Question 1.
Explain your thinking or use division to answer the following.
a. Is 2 a factor of 34?
Answer:
Yes, 2 is a factor of 34,

Explanation:
34 is a even number, 2 is a factor of every even
number, (2 X 17 = 34),
 17 R1
2| 34
 – 2
  14  
-14
0
Yes, 2 is a factor of 34.

b. Is 3 a factor of 34?
Answer:
No, 3 is not a factor of 34,

Explanation:
 11 R1
3| 34
 – 3
  04  
-03
01
So 3 is not a factor of 34 remainder is 1.

c. Is 4 a factor of 72?
Answer:
Yes, 4 is a factor of 72,

Explanation:
 18
4| 72
 – 4
  32  
-32
0
So 4 is a factor of 72.

d. Is 3 a factor of 72?
Answer:
Yes, 3 is a factor of 72,

Explanation:
 24
3| 72
 – 6
  12  
-12
0
So 3 is a factor of 72.

Question 2.
Use the associative property to explain why the following statement is true. Any number that has 9 as a factor also has 3 as a factor.
Answer:
Any number that has 9 as a factor also has 3 as a factor because 3 X 3 = 9,

Explanation:
Let’s suppose 9 is a factor of the number N.
That means N is 9 times some integer M.
N = 9M, Since 9 = 3 × 3, we can also write N as N = 3 × 3 × M,
That means N is 3 times some integer (3 × M).
So 3 is also a factor of N.

Eureka Math Grade 4 Module 3 Lesson 23 Homework Answer Key

Question 1.
Explain your thinking or use division to answer the following.
a. Is 2 a factor of 72?
Answer:
Yes, 2 is a factor of 72,

Explanation:
72 is a even number, 2 is a factor of every even number, (2 X 36 = 72),
 36
2| 72
 – 6
  12  
-12
0
Yes, 2 is a factor of 72.

b. Is 2 a factor of 73?
Answer:
No, 2 is not a factor of 73,

Explanation:
73 is a odd number, 2 is a factor of every even number not odd numbers, (2 X 36 = 72),72 + 1 = 73
 36 R 1
2| 73
 – 6
  13  
-12
1
No, 2 is not a factor of 73.

c. Is 3 a factor of 72?
Answer:
Yes, 2 is a factor of 72,

Explanation:
72 is a even number, 2 is a factor of every even number, (2 X 36 = 72),
 36
2| 72
 – 6
  12  
-12
0
Yes, 2 is a factor of 72.

d. Is 2 a factor of 60?
Answer:
Yes, 2 is a factor of 60,

Explanation:
60 is a even number, 2 is a factor of every even number, (2 X 30 = 60),
 30
2| 60
 – 60
 0  
Yes, 2 is a factor of 60.

e. Is 6 a factor of 72?
Answer:
Yes, 6 is a factor of 72,

Explanation:
(6 X 12 = 72),
 12
6| 72
 – 6
  12  
-12
0
Yes, 6 is a factor of 72.

f. Is 4 a factor of 60?
Answer:
Yes, 4 is a factor of 60,

Explanation:
60 is a even number, 4 is a factor of 60, (4 X 15 = 60),
 15
4|60
 -4
  20  
-20
0
Yes, 4 is a factor of 60.

g. Is 5 a factor of 72?
Answer:
No, 5 is not a factor of 72,

Explanation:
72 is a even number, 72 does not have 5 or 0 in ones place, all the numbers that have 5 as a factor have a 5 or  0 in ones  place,
So 5 is not a factor of 72.
 14 R 2
5|72
 -5
  22  
-20
2
No, 5 is not a factor of 72.

h. Is 8 a factor of 60?
Answer:
No, 8 is not a factor of 60,

Explanation:
60 is a even number, 8 is not a factor of 60,
(8 X 7 = 56, remainder 4),
 7 R 4
8|60
 -56
  04  
No, 8 is not a factor of 60.

Question 2.
Use the associative property to find more factors of 12 and 30.
a. 12 = 6 × 2
= ( __3_ × 2) × 2
= _3__ × (2 × 2)
= _3__ × _4__
= _12__
Answer:
12 = 6 X 2
= (3 X 2) X 2
= 3 X (2 X 2)
= 3 X 4
= 12,

Explanation:
Used the associative property to find more factors of 12 as
12 = 6 X 2
= (3 X 2) X 2
= 3 X (2 X 2)
= 3 X 4
= 12.

b. 30 = __6__ × 5
= ( __2__ × 3) × 5
= __2__ × (3 × 5)
= __2__ × 15
= __30__
Answer:
30 = 6 X 5
= (2 X 3) X 5
= 2 X (3 X 5)
= 2 X 15
= 30,

Explanation:
Used the associative property to find more factors of 30 as
30 = 6 X 5
= (2 X 3) X 5
= 2 X (3 X 5)
= 2 X 15
= 30.

Question 3.
In class, we used the associative property to show that when 6 is a factor, then 2 and 3 are factors, because 6 = 2 × 3.
Use the fact that 10 = 5 × 2 to show that 2 and 5 are factors of 70, 80, and 90.
70 = 10 × 7          80 = 10 × 8       90 = 10 × 9
Answer:
70 = 10 X 7
= (5 X 2) X 7
= 5 X (2 X 7)
= 5 X 14
= 70,

80 = 10 X 8
= 10 X 8
= (5 X 2) X 8
= 5 X (2 X 8)
= 5 X 16
= 80,

90 = 10 × 9
= 10 X 9
= (5 X 2) X 9
= 5 X (2 X 9)
= 5 X 18
= 90,

Explanation:
Used the fact that 10 = 5 × 2 to showed that 2 and 5 are factors of 70, 80, and 90 as

70 = 10 X 7
= (5 X 2) X 7
= 5 X (2 X 7)
= 5 X 14
= 70,

80 = 10 X 8
= 10 X 8
= (5 X 2) X 8
= 5 X (2 X 8)
= 5 X 16
= 80,

90 = 10 × 9
= 10 X 9
= (5 X 2) X 9
= 5 X (2 X 9)
= 5 X 18
= 90.

Question 4.
The first statement is false. The second statement is true.
Explain why, using words, pictures, or numbers. If a number has 2 and 6 as factors, then it has 12 as a factor. If a number has 12 as a factor, then both 2 and 6 are factors.
Answer:
 9
2|18
  -18
0
2 X 9 = 18,
 3
6|18
  -18
   0
6 X 3 = 18,
   1, R6
12|18
  – 12
   06
18 has 2 and 6 as factors but not 12,

Explanation:
The first statement is false. The second statement is true. If a number has 2 and 6 as factors, then it has 12 as a factor and If a number has 12 as a factor, then both 2 and 6 are factors,
 9
2|18
  -18
0
2 X 9 = 18,
 3
6|18
  -18
   0
6 X 3 = 18,
   1, R6
12|18
  – 12
   06
18 has 2 and 6 as factors but not 12, any number that can be divided exactly by 12 can also be divided by 2 and 6 instead, Since 12 = 2 X 6.

Engage NY Eureka Math 4th Grade Module 3 Lesson 21 Answer Key

Eureka Math Grade 4 Module 3 Lesson 21 Sprint Answer Key

Division with Remainders

Answer:

Question 1.
8 ÷ 2 Q = ___4___ R = ___0___
Answer:
8 ÷ 2 = 4
quotient = 4 and remainder = 0,

Explanation:
Given 8 ÷ 2 when 8 is divided by 2 we get quotient as 4,
(2 X 4 = 8) and remainder is 0.

Question 2.
9 ÷ 2 Q = ___4___ R = ___1___
Answer:
9 ÷ 2 =
quotient = 4 and remainder = 1,

Explanation:
Given 9 ÷ 2 when 9 is divided by 2 we get quotient as 4,
(2 X 4 = 8) and remainder is 1.

Question 3.
4 ÷ 4 Q = __1____ R = __0____
Answer:
4 ÷ 4 =
quotient = 1 and remainder = 0,

Explanation:
Given 4 ÷ 4 when 4 is divided by 4 we get quotient as 1,
(4 X 1 = 4) and remainder is 0.

Question 4.
5 ÷ 4 Q = ___1___ R = ___1___
Answer:
5 ÷ 4 =
quotient = 1 and remainder = 1,

Explanation:
Given 5 ÷ 4 when 5 is divided by 4 we get quotient as 1,
(4 X 1 = 4) and remainder is 1.

Question 5.
7 ÷ 5 Q = __1____ R = ___2___
Answer:
7 ÷ 5 =
quotient = 1 and remainder = 2,

Explanation:
Given 7 ÷ 5 when 7 is divided by 5 we get quotient as 1,
(5 X 1 = 5) and remainder is 2.

Question 6.
8 ÷ 5 Q = ___1___ R = __3____
Answer:
8 ÷ 5 =
quotient = 1 and remainder = 3,

Explanation:
Given 8 ÷ 5 when 8 is divided by 5 we get quotient as 1,
(5 X 1 = 5) and remainder is 3.

Question 7.
5 ÷ 3 Q = ___1___ R = __2____
Answer:
5 ÷ 3 =
quotient = 1 and remainder = 2,

Explanation:
Given 5 ÷ 3 when 5 is divided by 3 we get quotient as 1,
(3 X 1 = 3) and remainder is 2.

Question 8.
6 ÷ 3 Q = __2____ R = __0__
Answer:
6 ÷ 3 =
quotient = 2 and remainder = 0,

Explanation:
Given 6 ÷ 3 when 6 is divided by 3 we get quotient as 2,
(3 X 2 = 6) and remainder is 0.

Question 9.
8 ÷ 4 Q = __2____ R = __0____
Answer:
8 ÷ 4 =
quotient = 2 and remainder = 0,

Explanation:
Given 8 ÷ 4 when 8 is divided by 4 we get quotient as 2,
(4 X 2 = 8) and remainder is 0.

Question 10.
9 ÷ 4 Q = __2____ R = ___1___
Answer:
9 ÷ 4 =
quotient = 2 and remainder = 1,

Explanation:
Given 9 ÷ 4 when 9 is divided by 4 we get quotient as 2,
(4 X 2 = 8) and remainder is 1.

Question 11.
2 ÷ 2 Q = ___1___ R = __0____
Answer:
2 ÷ 2 =
quotient = 1 and remainder = 0,

Explanation:
Given 2 ÷ 2 when 2 is divided by 2 we get quotient as 1,
(2 X 1 = 2) and remainder is 0.

Question 12.
3 ÷ 2 Q = __1____ R = __1____
Answer:
3 ÷ 2 =
quotient = 1 and remainder = 1,

Explanation:
Given 3 ÷ 2 when 3 is divided by 2 we get quotient as 1,
(2 X 1 = 2) and remainder is 1.

Question 13.
7 ÷ 3 Q = __2____ R = __1____
Answer:
7 ÷ 3 =
quotient = 2 and remainder = 1,

Explanation:
Given 7 ÷ 3 when 7 is divided by 3 we get quotient as 2,
(3 X 2 = 6) and remainder is 1.

Question 14.
8 ÷ 3 Q = ___2___ R = ___2___
Answer:
8 ÷ 3 =
quotient = 2 and remainder = 2,

Explanation:
Given 8 ÷ 3 when 8 is divided by 3 we get quotient as 2,
(3 X 2 = 6) and remainder is 2.

Question 15.
9 ÷ 3 Q = __3____ R = __0____
Answer:
9 ÷ 3 =
quotient = 3 and remainder = 0,

Explanation:
Given 9 ÷ 3 when 9 is divided by 3 we get quotient as 3,
(3 X 3 = 9) and remainder is 0.

Question 16.
8 ÷ 6 Q = ___1___ R = __2____
Answer:
8 ÷ 6 =
quotient = 1 and remainder = 2,

Explanation:
Given 8 ÷ 6 when 8 is divided by 6 we get quotient as 1,
(6 X 1 = 6) and remainder is 2.

Question 17.
9 ÷ 6 Q = __1____ R = __3____
Answer:
9 ÷ 6 =
quotient = 1 and remainder = 3,

Explanation:
Given 9 ÷ 6 when 9 is divided by 6 we get quotient as 1,
(6 X 1 = 6) and remainder is 3.

Question 18.
5 ÷ 5 Q = ___1___ R = __0____
Answer:
5÷ 5 =
quotient = 1 and remainder = 0,

Explanation:
Given 5 ÷ 5 when 5 is divided by 5 we get quotient as 1,
(5 X 1 = 5) and remainder is 0.

Question 19.
6 ÷ 5 Q = ____1__ R = __1____
Answer:
6 ÷ 5 =
quotient = 1 and remainder = 1,

Explanation:
Given 6 ÷ 5 when 6 is divided by 5 we get quotient as 1,
(5 X 1 = 5) and remainder is 1.

Question 20.
8 ÷ 8 Q = __1____ R = __0____
Answer:
8 ÷ 8 =
quotient = 1 and remainder = 0,

Explanation:
Given 8 ÷ 8 when 8 is divided by 8 we get quotient as 1,
(8 X 1 = 8) and remainder is 0.

Question 21.
9 ÷ 8 Q = ___1___ R = __1____
Answer:
9 ÷ 8 =
quotient = 1 and remainder = 1,

Explanation:
Given 9 ÷ 8 when 9 is divided by 8 we get quotient as 1,
(8 X 1 = 8) and remainder is 1.

Question 22.
9 ÷ 9 Q = ___1___ R = __0____
Answer:
9 ÷ 9 =
quotient = 1 and remainder = 0,

Explanation:
Given 9 ÷ 9 when 9 is divided by 9 we get quotient as 1,
(9 X 1 = 9) and remainder is 0.

Question 23.
6 ÷ 2 Q = ___3___ R = __0____
Answer:
6 ÷ 2 =
quotient = 3 and remainder = 0,

Explanation:
Given 6 ÷ 2 when 6 is divided by 2 we get quotient as 3,
(2 X 3 = 6) and remainder is 0.

Question 24.
7 ÷ 2 Q = __3____ R = __1____
Answer:
7 ÷ 2 =
quotient = 3 and remainder = 1,

Explanation:
Given 7 ÷ 2 when 7 is divided by 2 we get quotient as 3,
(2 X 3 = 6) and remainder is 1.

Question 25.
3 ÷ 3 Q = __1____ R = __0____
Answer:
3 ÷ 3 =
quotient = 1 and remainder = 0,

Explanation:
Given 3 ÷ 3 when 3 is divided by 3 we get quotient as 1,
(3 X 1 = 3) and remainder is 0.

Question 26.
4 ÷ 3 Q = ___1___ R = __1____
Answer:
4 ÷ 3 =
quotient = 1 and remainder = 1,

Explanation:
Given 4 ÷ 3 when 4 is divided by 3 we get quotient as 1,
(3 X 1 = 3) and remainder is 1.

Question 27.
6 ÷ 4 Q = ___1___ R = ___2___
Answer:
6 ÷ 4 =
quotient = 1 and remainder = 2,

Explanation:
Given 6 ÷ 4 when 6 is divided by 4 we get quotient as 1,
(4 X 1 = 4) and remainder is 2.

Question 28.
7 ÷ 4 Q = __1____ R = __3____
Answer:
7 ÷ 4 =
quotient = 1 and remainder = 3,

Explanation:
Given 7 ÷ 4 when 7 is divided by 4 we get quotient as 1,
(4 X 1 = 4) and remainder is 3.

Question 29.
6 ÷ 6 Q = ___1___ R = __0____
Answer:
6 ÷ 6 =
quotient = 1 and remainder = 0,

Explanation:
Given 6 ÷ 6 when 6 is divided by 6 we get quotient as 1,
(6 X 1 = 6) and remainder is 0.

Question 30.
7 ÷ 6 Q = ___1___ R = __1____
Answer:
7 ÷ 6 =
quotient = 1 and remainder = 1,

Explanation:
Given 7 ÷ 6 when 7 is divided by 6 we get quotient as 1,
(6 X 1 = 6) and remainder is 1.

Question 31.
4 ÷ 2 Q = ___2___ R = ___0___
Answer:
4 ÷ 2 =
quotient = 2 and remainder = 0,

Explanation:
Given 4 ÷ 2 when 4 is divided by 2 we get quotient as 2,
(2 X 2 = 4) and remainder is 0.

Question 32.
5 ÷ 2 Q = __2____ R = __1____
Answer:
5 ÷ 2 =
quotient = 2 and remainder = 1,

Explanation:
Given 5 ÷ 2 when 5 is divided by 2 we get quotient as 2,
(2 X 2 = 4) and remainder is 1.

Question 33.
9 ÷ 3 Q = ___3___ R = __0____
Answer:
9 ÷ 3 =
quotient = 3 and remainder = 0,

Explanation:
Given 9 ÷ 3 when 9 is divided by 3 we get quotient as 3,
(3 X 3= 9) and remainder is 0.

Question 34.
9 ÷ 5 Q = ___1___ R = ___4___
Answer:
9 ÷ 5 =
quotient = 1 and remainder = 4,

Explanation:
Given 9 ÷ 5 when 9 is divided by 5 we get quotient as 1,
(5 X 1 = 5) and remainder is 4.

Question 35.
7 ÷ 7 Q = __1____ R = __0____
Answer:
7 ÷ 7 =
quotient = 1 and remainder = 0,

Explanation:
Given 7 ÷ 7 when 7 is divided by 7 we get quotient as 1,
(7 X 1 = 7) and remainder is 0.

Question 36.
9 ÷ 9 Q = ___1___ R = __0____
Answer:
9 ÷ 9 =
quotient = 1 and remainder = 0,

Explanation:
Given 9 ÷ 9 when 9 is divided by 9 we get quotient as 1,
(9 X 1 = 9) and remainder is 0.

Question 37.
13 ÷ 4 Q = ___3___ R = __1____
Answer:
13 ÷ 4 =
quotient = 3 and remainder = 1,

Explanation:
Given 13 ÷ 4 when 13 is divided by 4 we get quotient as 3,
(4 X 3 = 12) and remainder is 1.

Question 38.
18 ÷ 5 Q = ___3___ R = __3____
Answer:
18 ÷ 5 =
quotient = 3 and remainder = 3,

Explanation:
Given 18 ÷ 5 when 18 is divided by 5 we get quotient as 3,
(5 X 3 = 15) and remainder is 3.

Question 39.
21 ÷ 6 Q = ____3__ R = __3____
Answer:
21 ÷ 6 =
quotient = 3 and remainder = 3,

Explanation:
Given 21 ÷ 6 when 21 is divided by 6 we get quotient as 3,
(6 X 3 = 18) and remainder is 3.

Question 40.
24 ÷ 7 Q = __3____ R = __3____
Answer:
24 ÷ 7 =
quotient = 3 and remainder = 3,

Explanation:
Given 24 ÷ 7 when 24 is divided by 7 we get quotient as 3,
(7 X 3 = 21) and remainder is 3.

Question 41.
29 ÷ 8 Q = __3____ R = __5____
Answer:
29 ÷ 8 =
quotient = 3 and remainder = 5,

Explanation:
Given 29 ÷ 8 when 29 is divided by 8 we get quotient as 3,
(8 X 3 = 24) and remainder is 5.

Question 42.
43 ÷ 6 Q = ___7___ R = __1____
Answer:
43 ÷ 6 =
quotient = 7 and remainder = 1,

Explanation:
Given 43 ÷ 6 when 43 is divided by 6 we get quotient as 7,
(6 X 7 = 42) and remainder is 1.

Question 43.
53 ÷ 6 Q = __8____ R = ___5___
Answer:
53 ÷ 6 =
quotient = 8 and remainder = 5,

Explanation:
Given 53 ÷ 6 when 53 is divided by 6 we get quotient as 8,
(6 X 8 = 48) and remainder is 5.

Question 44.
82 ÷ 9 Q = ___9___ R = ___1___
Answer:
82 ÷ 9 =
quotient = 9 and remainder = 1,

Explanation:
Given 82 ÷ 9 when 82 is divided by 9 we get quotient as 9,
(9 X 9 = 81) and remainder is 1.

Division with Remainders

Answer:

Question 1.
9 ÷ 8 Q = __1____ R = __1____
Answer:
9 ÷ 8 =
quotient = 1 and remainder = 1,

Explanation:
Given 9 ÷ 8 when 9 is divided by 8 we get quotient as 1,
(8 X 1 = 8) and remainder is 1.

Question 2.
8 ÷ 8 Q = __1____ R = ___0___
Answer:
8 ÷ 8 =
quotient = 1 and remainder = 0,

Explanation:
Given 9 ÷ 8 when 9 is divided by 8 we get quotient as 1,
(8 X 1 = 8) and remainder is 1.

Question 3.
9 ÷ 6 Q = __1____ R = ___2___
Answer:
9 ÷ 6 =
quotient = 1 and remainder = 2,

Explanation:
Given 9 ÷ 6 when 9 is divided by 6 we get quotient as 1,
(6 X 1 = 6) and remainder is 2.

Question 4.
8 ÷ 6 Q = __1____ R = __2____
Answer:
8 ÷ 6 =
quotient = 1 and remainder = 2,

Explanation:
Given 8 ÷ 6 when 8 is divided by 6 we get quotient as 1,
(6 X 1 = 6) and remainder is 2.

Question 5.
5 ÷ 5 Q = __1____ R = __0____
Answer:
5 ÷ 5 =
quotient = 1 and remainder = 0,

Explanation:
Given 5 ÷ 5 when 5 is divided by 5 we get quotient as 1,
(5 X 1 = 5) and remainder is 0.

Question 6.
6 ÷ 5 Q = ___1___ R = __1____
Answer:
6 ÷ 5 =
quotient = 1 and remainder = 1,

Explanation:
Given 6 ÷ 5 when 6 is divided by 5 we get quotient as 1,
(5 X 1 = 5) and remainder is 1.

Question 7.
7 ÷ 4 Q = ___1___ R = __3____
Answer:
7 ÷ 4 =
quotient = 1 and remainder = 3,

Explanation:
Given 7 ÷ 4 when 7 is divided by 4 we get quotient as 3,
(4 X 1 = 4) and remainder is 3.

Question 8.
6 ÷ 4 Q = __1____ R = __2____
Answer:
6 ÷ 4 =
quotient = 1 and remainder = 2,

Explanation:
Given 6 ÷ 4 when 6 is divided by 4 we get quotient as 1,
(4 X 1 = 4) and remainder is 2.

Question 9.
5 ÷ 3 Q = __1____ R = __2____
Answer:
5 ÷ 3 =
quotient = 1 and remainder = 2,

Explanation:
Given 5 ÷ 3 when 5 is divided by 3 we get quotient as 1,
(3 X 1 = 3) and remainder is 2.

Question 10.
6 ÷ 3 Q = __2____ R = ___0___
Answer:
6 ÷ 3 =
quotient = 2 and remainder = 0,

Explanation:
Given 6 ÷ 3 when 6 is divided by 3 we get quotient as 2,
(3 X 2 = 6) and remainder is 0.

Question 11.
2 ÷ 2 Q = __1____ R = __0____
Answer:
2 ÷ 2 =
quotient = 1 and remainder = 0,

Explanation:
Given 2 ÷ 2 when 2 is divided by 2 we get quotient as 1,
(2 X 1 = 2) and remainder is 0.

Question 12.
3 ÷ 2 Q = ___1___ R = ___1___
Answer:
3 ÷ 2 =
quotient = 1 and remainder = 1,

Explanation:
Given 3 ÷ 2 when 3 is divided by 2 we get quotient as 1,
(2 X 1 = 2) and remainder is 1.

Question 13.
3 ÷ 3 Q = ___1___ R = __0____
Answer:
3 ÷ 3 =
quotient = 1 and remainder = 0,

Explanation:
Given 3 ÷ 3 when 3 is divided by 3 we get quotient as 1,
(3 X 1 = 3) and remainder is 0.

Question 14.
4 ÷ 3 Q = __1___ R = ___1___
Answer:
4 ÷ 3 =
quotient = 1 and remainder = 1,

Explanation:
Given 4 ÷ 3 when 4 is divided by 3 we get quotient as 1,
(3 X 1 = 3) and remainder is 1.

Question 15.
8 ÷ 7 Q = __1____ R = ___1__
Answer:
8 ÷ 7 =
quotient = 1 and remainder = 1,

Explanation:
Given 8 ÷ 7 when 8 is divided by 7 we get quotient as 1,
(7 X 1 = 7) and remainder is 1.

Question 16.
9 ÷ 7 Q = ___1___ R = __2____
Answer:

Question 17.
4 ÷ 4 Q = ___1___ R = ___0___
Answer:
4 ÷ 4 =
quotient = 1 and remainder = 0,

Explanation:
Given 4 ÷ 4 when 4 is divided by 4 we get quotient as 1,
(4 X 1 = 4) and remainder is 0.

Question 18.
5 ÷ 4 Q = ___1___ R = __1____
Answer:
5 ÷ 4 =
quotient = 1 and remainder = 1,

Explanation:
Given 5 ÷ 4 when 5 is divided by 4 we get quotient as 1,
(4 X 1 = 4) and remainder is 1.

Question 19.
6 ÷ 2 Q = __3____ R = __0____
Answer:
6 ÷ 2 =
quotient = 3 and remainder = 0,

Explanation:
Given 6÷ 2 when 6 is divided by 2 we get quotient as 3,
(3 X 1 = 3) and remainder is 0.

Question 20.
7 ÷ 2 Q = __3____ R = __1____
Answer:
7 ÷ 2 =
quotient = 3 and remainder = 1,

Explanation:
Given 7 ÷ 2 when 7 is divided by 2 we get quotient as 3,
(2 X 3 = 6) and remainder is 1.

Question 21.
8 ÷ 5 Q = __1____ R = __3____
Answer:
8 ÷ 5 =
quotient = 1 and remainder = 3,

Explanation:
Given 8 ÷ 5 when 8 is divided by 5 we get quotient as 1,
(5 X 1 = 5) and remainder is 3.

Question 22.
7 ÷ 5 Q = ___1___ R = __2____
Answer:
7 ÷ 5 =
quotient = 1 and remainder = 2,

Explanation:
Given 7 ÷ 5 when 7 is divided by 5 we get quotient as 1,
(5 X 1 = 5) and remainder is 2.

Question 23.
4 ÷ 2 Q = __2____ R = __0____
Answer:
4 ÷ 2 =
quotient = 2 and remainder = 0,

Explanation:
Given 4 ÷ 2 when 4 is divided by 2 we get quotient as 2,
(2 X 1 = 2) and remainder is 0.

Question 24.
5 ÷ 2 Q = __2____ R = __1____
Answer:
5 ÷ 2 =
quotient = 2 and remainder = 1,

Explanation:
Given 5 ÷ 2 when 5 is divided by 2 we get quotient as 2,
(2 X 2 = 4) and remainder is 1.

Question 25.
8 ÷ 4 Q = ___2___ R = ___0___
Answer:
8 ÷ 4 =
quotient = 2 and remainder = 0,

Explanation:
Given 8 ÷ 4 when 8 is divided by 4 we get quotient as 2,
(4 X 2 = 8) and remainder is 0.

Question 26.
9 ÷ 4 Q = ___2___ R = __1____
Answer:
9 ÷ 4 =
quotient = 2 and remainder = 1,

Explanation:
Given 9 ÷ 4 when 9 is divided by 4 we get quotient as 2,
(4 X 2 = 8) and remainder is 1.

Question 27.
9 ÷ 3 Q = ___3___ R = __0____
Answer:
9 ÷ 3 =
quotient = 3 and remainder = 0,

Explanation:
Given 9 ÷ 3 when 9 is divided by 3 we get quotient as 3,
(3 X 3 = 9) and remainder is 0.

Question 28.
8 ÷ 3 Q = ___2___ R = __2____
Answer:
8 ÷ 3 =
quotient = 2 and remainder = 2,

Explanation:
Given 8 ÷ 3 when 8 is divided by 3 we get quotient as 2,
(3 X 2 = 6) and remainder is 2.

Question 29.
9 ÷ 5 Q = __1____ R = ___4___
Answer:
9 ÷ 5 =
quotient = 1 and remainder = 4,

Explanation:
Given 9 ÷ 5 when 9 is divided by 5 we get quotient as 1,
(5 X 1 = 5) and remainder is 4.

Question 30.
6 ÷ 6 Q = ___1___ R = ___0___
Answer:
6 ÷ 6 =
quotient = 1 and remainder = 0,

Explanation:
Given 6 ÷ 6 when 6 is divided by 6 we get quotient as 1,
(6 X 1 = 6) and remainder is 0.

Question 31.
7 ÷ 6 Q = __1____ R = ___1___
Answer:
7 ÷ 6 =
quotient = 1 and remainder = 1,

Explanation:
Given 7 ÷ 6 when 7 is divided by 6 we get quotient as 1,
(6 X 1 = 6) and remainder is 1.

Question 32.
9 ÷ 9 Q = __1____ R = ___0___
Answer:
9 ÷ 9 =
quotient = 1 and remainder = 0,

Explanation:
Given 9 ÷ 9 when 9 is divided by 9 we get quotient as 1,
(9 X 1 = 9) and remainder is 0.

Question 33.
7 ÷ 7 Q = ___1___ R = _0_____
Answer:
7 ÷ 7 =
quotient = 1 and remainder = 0,

Explanation:
Given 7 ÷ 7 when 7 is divided by 7 we get quotient as 1,
(7 X 1 = 7) and remainder is 0.

Question 34.
9 ÷ 2 Q = ___4___ R = ___1___
Answer:
9 ÷ 2 =
quotient = 4 and remainder = 1,

Explanation:
Given 9 ÷ 2 when 9 is divided by 2 we get quotient as 4,
(2 X 4 = 8) and remainder is 1.

Question 35.
8 ÷ 2 Q = ___4___ R = ___0___
Answer:
8 ÷ 2 =
quotient = 4 and remainder = 0,

Explanation:
Given 8 ÷ 2 when 8 is divided by 2 we get quotient as 4,
(2 X 4 = 8) and remainder is 0.

Question 36.
37 ÷ 8 Q = ___4___ R = ___5___
Answer:
37 ÷ 8 =
quotient = 4 and remainder = 5,

Explanation:
Given 37 ÷ 8 when 37 is divided by 8 we get quotient as 4,
(8 X 4 = 32) and remainder is 5.

Question 37.
50 ÷ 9 Q = ___5___ R = __5____
Answer:
50 ÷ 9 =
quotient = 5 and remainder = 5,

Explanation:
Given 50 ÷ 9 when 50 is divided by 9 we get quotient as 5,
(9 X 5 = 45) and remainder is 5.

Question 38.
17 ÷ 6 Q = ___2___ R = __5____
Answer:
17 ÷ 6 =
quotient = 2 and remainder = 5,

Explanation:
Given 17 ÷ 6 when 17 is divided by 6 we get quotient as 2,
(6 X 2 = 12) and remainder is 5.

Question 39.
48 ÷ 7 Q = __6____ R = __6____
Answer:
48 ÷ 7 =
quotient = 6 and remainder = 6,

Explanation:
Given 48 ÷ 7 when 48 is divided by 7 we get quotient as 6,
(7 X 6 = 42) and remainder is 6.

Question 40.
51 ÷ 8 Q = ___6___ R = ___3___
Answer:
51 ÷ 8 =
quotient = 6 and remainder = 3,

Explanation:
Given 51 ÷ 8 when 51 is divided by 8 we get quotient as 6,
(8 X 6 = 48) and remainder is 3.

Question 41.
68 ÷ 9 Q = __7____ R = ___5___
Answer:
68 ÷ 9 =
quotient = 7 and remainder = 5,

Explanation:
Given 68 ÷ 9 when 68 is divided by 9 we get quotient as 7,
(9 X 7= 63) and remainder is 5.

Question 42.
53 ÷ 6 Q = __8____ R = __5____
Answer:
53 ÷ 6 =
quotient = 8 and remainder = 5,

Explanation:
Given 53 ÷ 6 when 53 is divided by 6 we get quotient as 8,
(6 X 8 = 48) and remainder is 5.

Question 43.
61 ÷ 8 Q = ___7___ R = __5____
Answer:
61 ÷ 8 =
quotient = 7 and remainder = 5,

Explanation:
Given 61 ÷ 8 when 61 is divided by 8 we get quotient as 71,
(8 X 7 = 56) and remainder is 5.

Question 44.
70 ÷ 9 Q = __7____ R = __7____
Answer:
70 ÷ 9 =
quotient = 7 and remainder = 7,

Explanation:
Given 70 ÷ 9 when 70 is divided by 9 we get quotient as 7,
(9 X 7 = 63) and remainder is 7.

Eureka Math Grade 4 Module 3 Lesson 21 Problem Set Answer Key

Question 1.
Solve 37 ÷ 2 using an area model. Use long division and
the distributive property to record your work.
Answer:

Explanation:
Solved 37 ÷ 2 using an area model. Using long division and the distributive property to record my work as shown above.

Question 2.
Solve 76 ÷ 3 using an area model. Use long division and the distributive property to record your work.
Answer:

Explanation:
Solved 76 ÷ 3 using an area model. Used long division and the distributive property to record your work.

Question 3.
Carolina solved the following division problem by drawing an area model.

a. What division problem did she solve?
Answer:
53 ÷ 4

Explanation:
Carolina solved the following division problem by using an area model as 40 + 12 + 1 = 53 divided by 4.

b. Show how Carolina’s model can be represented using the distributive property.
Answer:

Explanation:
Shown how Carolina’s model can be represented using the distributive property above.

Solved the following problems using the area model. Supported the area model with long division or the distributive property.

Question 4.
48 ÷ 3
Answer:
48 ÷ 3 =
quotient = 16 and remainder = 0,

Explanation:
Given 48 ÷ 3 when 48 is divided by 3 we get quotient as 16,
(3 X 16 = 48) and remainder is 0.
Solved the following problem using the area model. Supported the area model with long division and the distributive property.

Question 5.
49 ÷ 3
Answer:
49 ÷ 3 =
quotient = 16 and remainder = 1,

Explanation:
Given 49 ÷ 3 when 49 is divided by 3 we get quotient as 16,
(3 X 16 = 48) and remainder is 1.
Solved the following problem using the area model. Supported the area model with long division and the distributive property.

Question 6.
56 ÷ 4
Answer:
56 ÷ 4 =
quotient = 14 and remainder = 0,

Explanation:
Given 56 ÷ 4 when 56 is divided by 4 we get quotient as 14, (4 X 14 = 56) and remainder is 0.
Solved the following problem using the area model. Supported the area model with long division and the distributive property.

Question 7.
58 ÷ 4
Answer:
58 ÷ 4 =
quotient = 14 and remainder = 2,

Explanation:
Given  58 ÷ 4 when 58 is divided by 4 we get quotient as 14, (4 X 14 = 58) and remainder is 2.
Solved the following problem using the area model. Supported the area model with long division and the distributive property.

Question 8.
66 ÷ 5
Answer:
66 ÷ 5 =
quotient = 13 and remainder = 1,

Explanation:
Given  66 ÷ 5 when 66 is divided by 5 we get quotient as 13, (5 X 13 = 65) and remainder is 1.
Solved the following problem using the area model. Supported the area model with long division and the distributive property.

Question 9.
79 ÷ 3
Answer:
79 ÷ 3 =
quotient = 26 and remainder = 1,

Explanation:
Given 79 ÷ 3 when 79 is divided by 3 we get quotient as 26,
(3 X 26 = 78 ) and remainder is 1.
Solved the following problem using the area model. Supported the area model with long division and the distributive property.

Question 10.
Seventy-three students are divided into groups of 6 students each. How many groups of 6 students are there? How many students will not be in a group of 6?

Answer:
There are 12 groups of 6 students are there, 1 student will not be in a group of 6,

Explanation:
Given Seventy-three students are divided into groups of 6 students each.
The number of groups of 6 students are 73 ÷ 6 = quotient = 12 and remainder = 1 means there are 12 groups of 6 students are there and 1 student will not be in a group of 6.

Eureka Math Grade 4 Module 3 Lesson 21 Exit Ticket Answer Key

Question 1.
Kyle drew the following area model to find an unknown length. What division equation did he model?

Answer:
Kyle’s equation is 59 ÷ 2,

Explanation:
Kyle drew the following area model to find an unknown length.
The division equation did he modeled is 59 ÷ 2 as
(40 + 18 + 1) ÷ 2 = 59 ÷ 2.

Question 2.
Solve 93 ÷ 4 using the area model, long division, and the distributive property.
Answer:

Explanation:
Solved 93 ÷ 4 using the area model, long division, and the distributive property as shown above.

Eureka Math Grade 4 Module 3 Lesson 22 Homework Answer Key

Question 1.
Solve 35 ÷ 2 using an area model. Use long division and the distributive property to record your work.
Answer:

Explanation:
Solved 35 ÷ 2 using an area model. Used long division and the distributive property to record my work as shown above.

Question 2.
Solve 79 ÷ 3 using an area model. Use long division and the distributive property to record your work.
Answer:

Explanation:
Solved 79 ÷ 3 using an area model. Used long division and the distributive property to record your work.

Question 3.
Paulina solved the following division problem by drawing an
area model.

a. What division problem did she solve?
Answer:
Paulina solved the following division problem as 98 ÷ 4,

Explanation:
Paulina solved the following division problem by drawing an area model as (40 + 40 + 16 + 2) ÷ 4 = 98 ÷ 4.

b. Show how Paulina’s model can be represented using the
distributive property.
Answer:
Explanation:
Shown how Paulina’s model can be represented using the distributive property above.

Solve the following problems using the area model. Support the area model with long division or the distributive property.

Question 4.
42 ÷ 3
Answer:
42 ÷ 3 =
quotient = 14 and remainder = 0,

Explanation:
Given 42 ÷ 3 when 14 is divided by 3 we get quotient as 14,
(3 X 14 = 42) and remainder is 0.
Solved the following problem using the area model. Supported the area model with long division and the distributive property.

Question 5.
43 ÷ 3
Answer:
43 ÷ 3 =
quotient = 14 and remainder = 1,

Explanation:
Given  43 ÷ 3 when 43 is divided by 3 we get quotient as 14,
(3 X 14 = 42) and remainder is 1.
Solved the following problem using the area model. Supported the area model with long division and the distributive property.

Question 6.
52 ÷ 4
Answer:
52 ÷ 4 =
quotient = 13 and remainder = 0,

Explanation:
Given  52 ÷ 4 when 52 is divided by 4 we get quotient as 13,
(4 X 13 = 52) and remainder is 0.
Solved the following problem using the area model. Supported the area model with long division and the distributive property.

Question 7.
54 ÷ 4
Answer:
54 ÷ 4 =
quotient = 13 and remainder = 2,
Explanation:
Given  54 ÷ 4 when 54 is divided by 4 we get quotient as 13,
(4 X 13 = 52) and remainder is 2.
Solved the following problem using the area model. Supported the area model with long division and the distributive property.

Question 8.
61 ÷ 5
Answer:
61 ÷ 5 =
quotient = 12 and remainder = 1,

Explanation:
Given  61 ÷ 5 when 61 is divided by 5 we get quotient as 12,
(5 X 12 = 60) and remainder is 1.
Solved the following problem using the area model. Supported the area model with long division and the distributive property.

Question 9.
73 ÷ 3
Answer:
73 ÷ 3 =
quotient = 24 and remainder = 1,

Explanation:
Given  73 ÷ 3 when 73 is divided by 3 we get quotient as 24,
(3 X 24 = 73) and remainder is 1.
Solved the following problem using the area model. Supported the area model with long division and the distributive property.

Engage NY Eureka Math 4th Grade Module 3 Lesson 22 Answer Key

Eureka Math Grade 4 Module 3 Lesson 22 Problem Set Answer Key

Question 1.
Record the factors of the given numbers as multiplication sentences and as a list in order from least to greatest. Classify each as prime (P) or composite (C). The first problem is done for you.

Answer:

Explanation:
A composite number is a natural number or a positive integer which has more than two factors. For example, 15 has factors 1, 3, 5 and 15, hence it is a composite number.
Prime numbers are numbers that have only 2 factors:
1 and themselves. For example, the first 5 prime numbers are 2, 3, 5, 7, and 11.
Recorded the factors of the given numbers as multiplication sentences and as a list in order from least to greatest.
Classified each as prime (P) or composite (C) as shown above.

Question 2.
Find all factors for the following numbers, and classify each number as prime or composite. Explain your classification of each as prime or composite.

Answer:

25 is composite,

Explanation:
Found all factors for the following number of 25 as
1 X 25 = 25, 5 X 5 = 25 and classified the number 25 as composite because 25 has more than 2 factors 1, 5, 25.

Answer:

28 is composite,

Explanation:
Found all factors for the following number of 28 as 1 X 28 = 28, 2 X 14 = 28, 4 X 7= 28 and classified the number 28 as composite because 28 has more than 2 factors 1, 2, 4, 7, 14, 28.

Answer:

29 is prime,

Explanation:
Found all factors for the following number of 29 as 1 X 29 = 29 and classified the number 29 as prime because 29 has only 2 factors just 1, 29.

Question 3.
Bryan says all prime numbers are odd numbers.
a. List all of the prime numbers less than 20 in numerical order.
Answer:
2, 3, 5, 7, 11, 13, 17, 19,

Explanation:
Listed all the prime numbers less than 20 in numerical order are 2, 3, 5, 7, 11, 13, 17, 19.

b. Use your list to show that Bryan’s claim is false.
Answer:
Bryan’s claim is false because 2 is even number,

Explanation:
Bryan says all prime numbers are odd numbers but all the prime numbers less than 20 in order are 2, 3, 5, 7, 11, 13, 17, 19 from the list number 2 is even number so Bryan’s claim is false.

Question 4.
Sheila has 28 stickers to divide evenly among 3 friends. She thinks there will be no leftovers. Use what you know about factor pairs to explain if Sheila is correct.
Answer:
Sheila is incorrect, there will be 1 left over,

Explanation:
Given Sheila has 28 stickers to divide evenly among 3 friends.
She thinks there will be no leftovers but 3 is not a factor of 28, but 3 is a factor of 27, So each friend could receive 9 stickers each and there would be 1 sticker leftover.
3 X 9 = 27, 27 + 1 = 28.
So Sheila is incorrect, there will be 1 leftover.

Record the factors of the given numbers as multiplication sentences and as a list in order from least to greatest.
Classify each as prime (P) or composite (C).

Answer:

Explanation:
Recorded the factors of the given numbers as multiplication sentences and as a list in order from least to greatest.
Classified each as prime (P) or composite (C) as shown above.

Question 1.
Record the factors of the given numbers as multiplication sentences and as a list in order from least to greatest. Classify each as prime (P) or composite (C). The first problem is done for you.

Answer:

Explanation:
Recorded the factors of the given numbers as multiplication sentences and as a list in order from least to greatest.
Classified each as prime (P) or composite (C) as shown above.

Question 2.
Find all factors for the following numbers, and classify each number as prime or composite. Explain your classification of each as prime or composite.

Answer:

19 is prime,

Explanation:
Found all factors for the following number of 19 as 1 X 19 = 19 and classified the number 19 as prime because 19 has only 2 factors just 1, 19.

Answer:

21 is composite,

Explanation:
Found all factors for the following number of 28 as 1 X 21 = 21, 3 X 7 = 21 and classified the number 21 as composite because 21 has more than 2 factors 1, 3, 7, 21.

Answer:

24 is composite,

Explanation:
Found all factors for the following number of 24 as 1 X 24 = 24, 2 X 12 = 24, 3 X 8= 24, 4 X 6 = 24 and classified the number 24 as composite because 24 has more than 2 factors 1, 2, 3, 4, 6, 8, 12, 24.

Question 3.
Bryan says that only even numbers are composite.
a. List all of the odd numbers less than 20 in numerical order.
Answer:
2, 3, 5, 7, 11, 13, 17, 19,

Explanation:
Listed all the odd numbers less than 20 in numerical order are 2, 3, 5, 7, 9, 11, 13, 17, 19.

b. Use your list to show that Bryan’s claim is false.
Answer:
Bryan’s claim is false because only even numbers are composite even odd numbers are also composite because 9 is a odd number which is composite,

Explanation:
Bryan’s claim is false because only even numbers are composite even odd numbers are also composite because 9 is a odd number which is composite
1 X 9 = 9, 3 X 3 = 9, 9 has more than 2 factors, So Bryan’s claim is false.

Question 4.
Julie has 27 grapes to divide evenly among 3 friends. She thinks there will be no leftovers. Use what you know about factor pairs to explain whether or not Julie is correct.
Answer:
Julie is correct, there will be no leftovers,

Explanation:
Given Julie has 27 grapes to divide evenly among 3 friends. She thinks there will be no leftovers yes 3 is a factor of 27,
So each friend could receive 9 grapes each and there would be no grape left over,
3 X 9 = 27
So Julie is correct, there will be no leftovers.