## Engage NY Eureka Math 4th Grade Module 3 Lesson 30 Answer Key

### Eureka Math Grade 4 Module 3 Lesson 30 Problem Set Answer Key

Divide. Check your solutions by multiplying.

Question 1.

204 ÷ 4

Answer:

Explanation:

Divided 204 ÷ 4 = 51 and checked my soluting by multiplying

51 X 4 = 204.

Question 2.

704 ÷ 3

Answer:

Explanation:

Divided 704 ÷ 3 = 234, remainder 2 and checked my soluting by multiplying and adding 2 as 234 X 3 = 702, 702 + 2 = 704.

Question 3.

627 ÷ 3

Answer:

Explanation:

Divided 627÷ 3 = 209,remainder 0 and checked my solution by multiplying as 3 X 209=627.

Question 4.

407÷ 2

Answer:

Explanation:

Divided 407÷2 = 203, remainder 1 and checked my solution by multiplying and adding 1 as 2 X 203 =406 , 406+1 = 407.

Question 5.

760 ÷ 4

Answer:

Explanation:

Divided 760 ÷ 4 = 180, remainder 0 and checked my solution by multiplying as 4 X 180 = 760.

Question 6.

5,120 ÷ 4

Answer:

Explanation:

Divided 5,120 ÷ 4 = 1,280, remainder 0 and checked my solution by multiplying as 1,280 X 4 = 5,120.

Question 7.

3,070 ÷ 5

Answer:

Explanation:

Divided 3,070 ÷5 = 614, remainder 0 and checked my solution by multiplying as 614 X 4 = 3,070.

Question 8.

6,706 ÷ 5

Answer:

Explanation:

Divided 6706 ÷ 5 = 1,341, remainder 1 and checked my solution by multiplying and adding 1 as 1,341 X 5 = 6,705 , 6,705+1 = 6,706.

Question 9.

8,313 ÷ 4

Answer:

Explanation:

Divided 8,313 ÷ 4 = 2,078, remainder 1and checked my solution by multiplying and adding 1 as 1,341 X 5 = 6,705, 6,705 + 1 = 6,706.

Question 10.

9,008 ÷ 3

Answer:

Explanation:

Divided 9,008 ÷ 3 = 3,002, remainder 2 and checked my solution by multiplying and adding 2 as 3,002 X 3 = 9,006, 9,006 + 2 = 9,008.

Question 11.

a. Find the quotient and remainder for 3,131 ÷ 3.

Answer:

Explanation:

Divided 3,131 ÷ 3 = 1,043, remainder 2 and checked my solution by multiplying and adding 2 as 1,043 X 3 = 3,129 , 3,129 + 2 = 3,131,

So, the remainder is 2 and quotient is 1,043 respectively.

b. How could you change the digit in the ones place of the whole so that there would be no remainder? Explain how you determined your answer.

Answer:

By adding 1 to the dividend we get no remainder,

Explanation:

We change the digit in the ones place of the whole so that there would be no remainder by adding 1 to the remainder as

we got remainder 2 and we have divisor 3, So we need to add

3 – 2 = 1 to dividend so that we get no remainder.

3,131 + 1 = 3,132, 3,132 ÷ 3 = 1,044 with 0 remainder.

### Eureka Math Grade 4 Module 3 Lesson 30 Exit Ticket Answer Key

Divide. Check your solutions by multiplying.

Question 1.

380 ÷ 4

Answer:

Explanation:

Divided 380 ÷ 4 = 95, remainder 0 and checked my solution by multiplying as 95 X 4 = 380.

Question 2.

7,040 ÷ 3

Answer:

Explanation:

Divided 7,040 ÷ 3 = 2,346, remainder 2 and checked my solution by multiplying and adding 2 as 2,346 X 3 = 7,038, 7,038 + 2 = 7,040.

### Eureka Math Grade 4 Module 3 Lesson 30 Homework Answer Key

Divide. Check your solutions by multiplying.

Question 1.

409 ÷ 5

Answer:

Explanation:

Divided 409 ÷ 5 = 81, remainder 4 and checked my solution by multiplying and adding 4 as 81 X 5 = 405, 405 + 4 = 409.

Question 2.

503 ÷ 2

Answer:

Explanation:

Divided 503 ÷ 2 = 251 ,remainder 1 and checked my solution by multiplying and adding 1 as 251 X 2 = 502, 502+1= 503.

Question 3.

831 ÷ 4

Answer:

Explanation:

Divided 831 ÷ 4 = 207, remainder 3 and checked my solution by multiplying and adding 3 as 207 X 4 = 828, 828 + 3 = 831.

Question 4.

602 ÷ 3

Answer:

Explanation:

Divided 602 ÷ 3 = 200, remainder 2 and checked my solution by multiplying and adding 2 as 200 X 3 = 600, 600 + 2 = 602.

Question 5.

720 ÷ 3

Answer:

Explanation:

Divided 720 ÷ 3 = 240, remainder 0 and checked my solution by multiplying as 240 X 3 = 720.

Question 6.

6,250 ÷ 5

Answer:

Explanation:

Divided 6,250 ÷ 5 = 1,250, remainder 0 and checked my solution by multiplying as 1,250 X 5 = 6,250 .

Question 7.

2,060 ÷ 5

Answer:

Explanation:

Divided 2,060 ÷ 5 = 412 and checked my solution by multiplying as 412 X 5 = 2,060.

Question 8.

9,031 ÷ 2

Answer:

Explanation:

Divided 9,031÷ 2 = 4,515, remainder 1 and checked my solution by multiplying and adding 1 as 4,515 X 2 = 9,030, 9,030 + 1 = 9,031.

Question 9.

6,218 ÷ 4

Answer:

Explanation:

Divided 6,218 ÷ 4 = 1,554, remainder 2 and checked my solution by multiplying and adding 2 as 1,554 X 4 = 6,216, 6,216 + 2 = 6,218.

Question 10.

8,000 ÷ 4

Answer:

Explanation:

Divided 8000 ÷ 4 = 2,000, remainder 0 and checked my solution by multiplying as 2,000 X 4 = 8,000.