In this article, you will learn how to find the Perimeter and Area of irregular figures. An irregular shape can be of any size and length. Irregular shapes can be seen all around us, for example, a diamond shape, a kite, a leaf, a flower, etc. The Area of irregular shapes means the space occupied by the shape which is measured in square units. The Perimeter of irregular shapes is by adding the length of their sides. Any shape whose sides and angles are not of equal length is termed an irregular shape.

On this page, learn about the definition of the Area and perimeter of irregular figures, how to find the area and perimeter of irregular figures, solve example problems, and so on.

Also, Read Some More Articles:

### Definition of Irregular Figures

Irregular Figures is defined as a figure that is not a standard geometric shape. An irregular shape is simply a shape where not every single side is the same length. But some irregular figures are made up of two or more standard geometric shapes. If the shape is irregular then it has angles that are not all the same size. Based on the number of sides or corners we can decide the irregular figure.

### How to find Perimeter and Area of Irregular Figures?

The following are the steps for finding the area and perimeter of irregular figures:

**How to find Area of Irregular Shapes or Figures?**

Step 1: First, divide the compound shape into a basic regular shape.

Step 2: Next, find each basic shape area separately.

Step 3: Then Add all the areas of basic shapes together.

Step 4: Now, write the final answer in square units.

**How to find the Perimeter of Irregular Figures?
**To find the perimeter of the irregular figure, we can simply add up each of its outer sides length of a shape. To find the perimeter of any shape like rectangle, square, and so on you have to add all the lengths of four sides. Consider ‘A’ is in this case the length of the rectangle and ‘B’ is the width of the rectangle.

Read Similar Shapes:

### Solved Examples on Perimeter and Area of Irregular Figures

**Example 1:** The Irregular Figure is given below. Find the area of that figure.

**Solution: **

As given in the question, the irregular figure is given.

Now, we can break the given irregular figure. After splitting the figure we have two rectangles.

Next, we will find the area of the two rectangles. The area of the irregular figure is the sum of the areas of two rectangles.

The width of one rectangle is 12 and the length of the rectangle is 4.

Next, the width of the other rectangle is 2, but its length is not given. By using the upper rectangle length we can find the length of the lower rectangle. So the right side of the figure is the length of the upper rectangle plus the length of the lower rectangle.

Since the total length is 10 units, the right side of the upper rectangle is 4 units long. So the length of the lower rectangle will be 6 units.

So the area of the figure is,

The Area of the figure is the Area of the upper rectangle + Area of the lower rectangle

We know that the Area of the rectangle is, length x width (or) breadth.

So, the area of a figure is , lw + lw = 12(4) + 2(6).

Area of the figure is = 48 + 12 = 60sq.units.

Therefore, the total area of the figure is 60 square units.

**Example 2:** Find the area of the below-given irregular figure.

**Solution:**

As given in the question, the given figure is an irregular figure.

Now, we can break the given irregular figure. After splitting the figure, we have one triangle and one rectangle.

Next, we will find the area of the irregular figure. The area of the irregular figure is the sum of the areas of two rectangles.

The rectangle has a length of 8 units and a width of 4 units. We need to find the base and height of the triangle.

On both sides of the rectangle 4units, the vertical side of the triangle is 3 units, which is 7- 4 = 3units.

Next, the length of the rectangle is 8units, so the base of the triangle is 3units, which is 8-5= 4units.

Now, we can add the areas then we get the area of the irregular figure.

So, the Area of the figure is the Area of the rectangle + the Area of the triangle.

We know the formulas, the area of the rectangle is, length x width (or) breadth.

The area of the triangle is 1/2bh.

So, the area of a figure is , lw + 1/2bh = 8(4) + 1/2(3)(3).

Area of the figure is = 32 + 4.5 = 36.5sq.units.

Hence, the total area of the given irregular figure is 36.5square units.

Example 3: