## Engage NY Eureka Math 3rd Grade Module 7 Lesson 23 Answer Key

### Eureka Math Grade 3 Module 7 Lesson 23 Sprint Answer Key

A

Multiply or Divide by 5

Answer:

Question 1.

2 × 5 =

Answer:

2 × 5 = 10.

Question 2.

3 × 5 =

Answer:

3 × 5 = 15.

Question 3.

4 × 5 =

Answer:

4 × 5 = 20.

Question 4.

5 × 5 =

Answer:

5 × 5 = 25.

Question 5.

1 × 5 =

Answer:

1 × 5 = 5.

Question 6.

10 ÷ 5 =

Answer:

10 ÷ 5 = 2.

Question 7.

15 ÷ 5 =

Answer:

15 ÷ 5 = 3.

Question 8.

25 ÷ 5 =

Answer:

25 ÷ 5 = 5.

Question 9.

5 ÷ 5 =

Answer:

5 ÷ 5 = 1.

Question 10.

20 ÷ 5 =

Answer:

20 ÷ 5 = 4.

Question 11.

6 × 5 =

Answer:

6 × 5 = 30.

Question 12.

7 × 5 =

Answer:

7 × 5 = 35.

Question 13.

8 × 5 =

Answer:

8 × 5 = 40.

Question 14.

9 × 5 =

Answer:

9 × 5 = 45.

Question 15.

10 × 5 =

Answer:

10 × 5 = 50.

Question 16.

40 ÷ 5 =

Answer:

40 ÷ 5 = 8.

Question 17.

35 ÷ 5 =

Answer:

35 ÷ 5 = 7.

Question 18.

45 ÷ 5 =

Answer:

45 ÷ 5 = 9.

Question 19.

30 ÷ 5 =

Answer:

30 ÷ 5 = 6.

Question 20.

50 ÷ 5 =

Answer:

50 ÷ 5 = 10.

Question 21.

___ × 5 = 25

Answer:

5 × 5 = 25.

Question 22.

___ × 5 = 5

Answer:

1 × 5 = 5.

Question 23.

___ × 5 = 50

Answer:

10 × 5 = 50.

Question 24.

___ × 5 = 10

Answer:

2 × 5 = 10.

Question 25.

___ × 5 = 15

Answer:

3 × 5 = 15.

Question 26.

50 ÷ 5 =

Answer:

50 ÷ 5 = 10.

Question 27.

25 ÷ 5 =

Answer:

25 ÷ 5 = 5.

Question 28.

5 ÷ 5 =

Answer:

5 ÷ 5 = 1.

Question 29.

10 ÷ 5 =

Answer:

10 ÷ 5 = 2.

Question 30.

15 ÷ 5 =

Answer:

15 ÷ 5 = 3.

Question 31.

___ × 5 = 30

Answer:

6 × 5 = 30.

Question 32.

___ × 5 = 35

Answer:

7 × 5 = 35.

Question 33.

___ × 5 = 45

Answer:

9 × 5 = 45.

Question 34.

___ × 5 = 40

Answer:

8 × 5 = 40.

Question 35.

35 ÷ 5 =

Answer:

35 ÷ 5 = 7.

Question 36.

45 ÷ 5 =

Answer:

45 ÷ 5 = 9.

Question 37.

30 ÷ 5 =

Answer:

30 ÷ 5 = 6.

Question 38.

40 ÷ 5 =

Answer:

40 ÷ 5 = 8.

Question 39.

11 × 5 =

Answer:

11 × 5 = 55.

Question 40.

55 ÷ 5 =

Answer:

55 ÷ 5 = 11.

Question 41.

15 ÷ 5 =

Answer:

15 ÷ 5 = 3.

Question 42.

60 ÷ 5 =

Answer:

60 ÷ 5 = 12.

Question 43.

12 × 5 =

Answer:

12 × 5 = 60.

Question 44.

70 ÷ 5 =

Answer:

70 ÷ 5 = 14.

B

Multiply or Divide by 5

Answer:

Question 1.

1 × 5 =

Answer:

1 × 5 = 5.

Question 2.

2 × 5 =

Answer:

2 × 5 = 10.

Question 3.

3 × 5 =

Answer:

3 × 5 = 15.

Question 4.

4 × 5 =

Answer:

4 × 5 = 20.

Question 5.

5 × 5 =

Answer:

5 × 5 = 25.

Question 6.

15 ÷ 5 =

Answer:

15 ÷ 5 = 3.

Question 7.

10 ÷ 5 =

Answer:

10 ÷ 5 = 2.

Question 8.

20 ÷ 5 =

Answer:

20 ÷ 5 = 4.

Question 9.

5 ÷ 5 =

Answer:

5 ÷ 5 = 1.

Question 10.

25 ÷ 5 =

Answer:

25 ÷ 5 = 5.

Question 11.

10 × 5 =

Answer:

10 × 5 = 50.

Question 12.

6 × 5 =

Answer:

6 × 5 = 30.

Question 13.

7 × 5 =

Answer:

7 × 5 = 35.

Question 14.

8 × 5 =

Answer:

8 × 5 = 40.

Question 15.

9 × 5 =

Answer:

9 × 5 = 45.

Question 16.

35 ÷ 5 =

Answer:

35 ÷ 5 = 7.

Question 17.

30 ÷ 5 =

Answer:

30 ÷ 5 = 6.

Question 18.

40 ÷ 5 =

Answer:

40 ÷ 5 = 8.

Question 19.

50 ÷ 5 =

Answer:

50 ÷ 5 = 10.

Question 20.

45 ÷ 5 =

Answer:

45 ÷ 5 = 9.

Question 21.

___ × 5 = 5

Answer:

1 × 5 = 5.

Question 22.

___ × 5 = 25

Answer:

5 × 5 = 25.

Question 23.

___ × 5 = 10

Answer:

2 × 5 = 10.

Question 24.

___ × 5 = 50

Answer:

10 × 5 = 50.

Question 25.

___ × 5 = 15

Answer:

3 × 5 = 15.

Question 26.

10 ÷ 5 =

Answer:

10 ÷ 5 = 50.

Question 27.

5 ÷ 5 =

Answer:

Question 28.

50 ÷ 5 =

Answer:

Question 29.

25 ÷ 5 =

Answer:

Question 30.

15 ÷ 5 =

Answer:

Question 31.

___ × 5 = 15

Answer:

Question 32.

___ × 5 = 20

Answer:

Question 33.

___ × 5 = 45

Answer:

Question 34.

___ × 5 = 35

Answer:

Question 35.

40 ÷ 5 =

Answer:

Question 36.

45 ÷ 5 =

Answer:

Question 37.

30 ÷ 5 =

Answer:

Question 38.

35 ÷ 5 =

Answer:

Question 39.

11 × 5 =

Answer:

Question 40.

55 ÷ 5 =

Answer:

Question 41.

12 × 5 =

Answer:

Question 42.

60 ÷ 5 =

Answer:

Question 43.

13 × 5 =

Answer:

Question 44.

65 ÷ 5 =

Answer:

### Eureka Math Grade 3 Module 7 Lesson 23 Problem Set Answer Key

Question 1.

Gale makes a miniature stop sign, a regular octagon, with a perimeter of 48 centimeters for the town he built with blocks. What is the length of each side of the stop sign?

Answer:

The length of each side of the stop sign = 6 centimeters.

Explanation:

Perimeter of Gale a miniature stop sign, a regular octagon = 48 centimeters

Number of sides of Gale a miniature stop sign, a regular octagon = 8

The length of each side of the stop sign = Perimeter of Gale a miniature stop sign, a regular octagon ÷ Number of sides of Gale a miniature stop sign, a regular octagon

= 48 centimeters ÷ 8

= 6 centimeters.

Question 2.

Travis bends wire to make rectangles. Each rectangle measures 34 inches by 12 inches. What is the total length of the wire needed for two rectangles?

Answer:

The total length of the wire needed for two rectangles = 184 inches.

Explanation:

Length of the Travis’s rectangle = 34 inches

Width of the Travis’s rectangle = 12 inches

Perimeter of the Travis’s rectangle = 2 ( Length + Width)

= 2 ( 34 inches + 12 inches )

= 2 × 46 inches

= 92 inches.

The total length of the wire needed for two rectangles = 2 × Perimeter of the Travis’s rectangle

= 2 × 92 inches

= 184 inches.

Question 3.

The perimeter of a rectangular bathroom is 32 feet. The width of the room is 8 feet. What is the length of the room?

Answer:

The length of the room = 8 feet.

Explanation:

Perimeter of a rectangular bathroom = 32 feet.

Width of a rectangular bathroom = 8 feet.

Length of a rectangular bathroom = ??

Perimeter of a rectangular bathroom = 2 ( Length + Width)

=> 32 feet = (2 × Length) + (2 × 8 feet)

=> 32 feet = (2 × Length) + 16 feet

=> 32 feet – 16 feet = (2 × Length)

=> 16 feet = (2 × Length)

=> 16 feet ÷ 2 = Length

=> 8 feet = Length

Question 4.

Raj uses 6-inch square tiles to make a rectangle, as shown below. What is the perimeter of the rectangle in inches?

Answer:

Perimeter of the rectangle in inches =96-inches.

Explanation:

Length of the side square tiles Raj uses to make a rectangle = 6-inch

Number of side of square tiles in the rectangle = 16

Perimeter of the rectangle in inches = Length of the side square tiles Raj uses to make a rectangle × Number of side of square tiles in the rectangle

= 6-inch × 16

= 96-inches.

Question 5.

Mischa makes a 4-foot by 6-foot rectangular banner. She puts ribbon around the outside edges. The ribbon costs $2 per foot. What is the total cost of the ribbon?

Answer:

Total cost of the ribbon = $20.

Explanation:

Length of the rectangular banner = 6-foot

Width of the rectangular banner = 4-foot

Perimeter of the rectangular banner = 2 ( Length + Width)

= 2 ( 6-foot + 4-foot )

= 2 × 10-foot

= 20- foot.

Cost of the ribbon per foot = $2

Total cost of the ribbon = Perimeter of the rectangular banner × Cost of the ribbon per foot

= 20- foot × $2

= $40.

Question 6.

Colton buys a roll of wire fencing that is 120 yards long. He uses it to fence in his 18-yard by 24-yard rectangular garden. Will Colton have enough wire fencing left over to fence in a 6-yard by 8-yard rectangular play space for his pet rabbit?

Answer:

Yes, Colton has wire fencing left over to fence for rectangular play space for his pet rabbit.

Explanation:

Total length of wire Colton purchased = 120 yards.

Length of the rectangular garden = 24-yard

Width of the rectangular garden = 18-yard

Perimeter of the rectangular garden = 2 ( Length + Width)

= 2 ( 24-yard + 18-yard )

= 2 × 42-yard

= 84-yard.

Wire used = Total length of wire Colton purchased – Perimeter of the rectangular garden

= 120 yards – 84 yards

= 36 yards.

Length of the rectangular play space for his pet rabbit = 8-yard

Width of the rectangular play space for his pet rabbit = 6-yard

Perimeter of the rectangular play space for his pet rabbit = 2 ( Length + Width)

= 2 ( 8-yard + 6-yard )

= 2 × 14-yard

= 28-yard.

Wire left = Wire used – Perimeter of the rectangular play space for his pet rabbit

= 36 yards – 28 yards

= 8 yards.

### Eureka Math Grade 3 Module 7 Lesson 23 Exit Ticket Answer Key

Adriana traces a regular triangle to create the shape below. The perimeter of her shape is 72 centimeters. What are the side lengths of the triangle?

Answer:

The side lengths of the triangle = 9 centimeters.

Explanation:

Perimeter of Adriana’s shape = 72 centimeters

Number of sides of the triangle shape = 8

The side lengths of the triangle = Perimeter of Adriana’s shape ÷ Number of sides of the triangle shape

= 72 centimeters ÷ 8

= 9 centimeters.

### Eureka Math Grade 3 Module 7 Lesson 23 Homework Answer Key

Question 1.

Rosie draws a square with a perimeter of 36 inches. What are the side lengths of the square?

Answer:

The side lengths of the square = 9 inches.

Explanation:

Perimeter of the Square = 36 inches

Number of sides in the square = 4

The side lengths of the square = Perimeter of the Square ÷ Number of sides in the square

= 36 inches ÷ 4

= 9 inches.

Question 2.

Judith uses craft sticks to make two 24-inch by 12-inch rectangles. What is the total perimeter of the 2 rectangles?

Answer:

Total perimeter of the 2 rectangles = 144 inches.

Explanation:

Length of the rectangle = 24-inch

Width of the rectangle = 12-inch

Perimeter of the rectangle = 2 ( Length + Width)

= 2 ( 24-inch + 12-inch )

= 2 × 36-inch

= 72 inches.

Total perimeter of the 2 rectangles = Perimeter of the rectangle × 2

= 72 inches × 2

= 144 inches.

Question 3.

An architect draws a square and a rectangle, as shown below, to represent a house that has a garage. What is the total perimeter of the house with its attached garage?

Answer:

Perimeter of the attached garage = 250 ft.

Explanation:

Length of the side AB in the attached garage = 55 ft

Length of the side BC in the attached garage = 10 ft

Length of the side CD in the attached garage = 30 ft

Length of the side DE in the attached garage = 30 ft

Length of the side EF in the attached garage = 30 ft

Length of the side FG in the attached garage = 55 ft

Length of the side GA in the attached garage = 40 ft

Perimeter of the attached garage = Length of the side AB in the attached garage + Length of the side BC in the attached garage + Length of the side CD in the attached garage + Length of the side DE in the attached garage + Length of the side EF in the attached garage + Length of the side FG in the attached garage + Length of the side GA in the attached garage

= 55 ft + 10 ft + 30 ft + 30 ft + 30 ft + 55 ft + 40 ft

= 65 ft + 30 ft + 30 ft + 30 ft + 55 ft + 40 ft

= 95 ft + 30 ft + 30 ft + 55 ft + 40 ft

= 125 ft + 30 ft + 55 ft + 40 ft

= 155 ft + 55 ft + 40 ft

= 210 ft + 40ft

= 250 ft.

Question 4.

Manny draws 3 regular pentagons to create the shape shown below. The perimeter of 1 of the pentagons is 45 inches. What is the perimeter of Manny’s new shape?

Answer:

Perimeter of Manny’s new shape = 99 inches.

Explanation:

Perimeter of the regular pentagons Manny draws = 45 inches

Number of side in the regular pentagons Manny draws = 5

Length of the side of the regular pentagons Manny draws = Perimeter of the regular pentagons Manny draws ÷ Number of side in the regular pentagons Manny draws

= 45 inches ÷ 5

= 9 inches.

Number of side Manny’s new shape has = 11 ( Side AB + Side BC +Side CD + Side DE + Side EF +Side FG + Side GH + Side HI + Side IJ +Side JK + Side KA )

Perimeter of Manny’s new shape = Number of side Manny’s new shape has × Length of the side of the regular pentagons Manny draws

= 11 × 9 inches

= 99 inches.

Question 5.

Johnny uses 2-inch square tiles to make a square, as shown below. What is the perimeter of Johnny’s square?

Answer:

Perimeter of Johnny’s square = 24 inches.

Explanation:

Number of side in the Johnny’s square = 12

Length of side in the Johnny’s square = 2 inches

Perimeter of Johnny’s square = Number of side in the Johnny’s square × Length of side in the Johnny’s square

= 12 × 2 inches

= 24 inches.

Question 6.

Lisa tapes three 7-inch by 9-inch pieces of construction paper together to make a happy birthday sign for her mom. She uses a piece of ribbon that is 144 inches long to make a border around the outside edges of the sign. How much ribbon is leftover?

Answer:

Ribbon leftover = 76 inches.

Explanation:

Length of the Lisa’s piece of construction paper = 9-inch

Width of the Lisa’s piece of construction paper = 7-inch

Perimeter of the pieces of construction paper used to make a happy birthday sign for her mom = Side AB + Side BC + Side CD + Side DE + Side EF + Side FG + Side GH +Side HA

= 9-inch + 9-inch + 9-inch + 7-inch + 9-inch + 9-inch + 9-inch + 7-inch

= 18-inch + 9-inch + 7-inch + 9-inch + 9-inch + 9-inch + 7-inch

= 27-inch + 7-inch + 9-inch + 9-inch + 9-inch + 7-inch

= 34-inch + 9-inch + 9-inch + 9-inch + 7-inch

= 43-inch + 9-inch + 9-inch + 7-inch

= 52-inch + 9-inch + 7-inch

= 61-inch + 7-inch

= 68-inch.

Piece of ribbon Lisa’s has = 144 inches

Ribbon leftover = Piece of ribbon Lisa’s has – Perimeter of the pieces of construction paper used to make a happy birthday sign for her mom

= 144 inches – 68-inch.

= 76 inches.