## Engage NY Eureka Math 2nd Grade Module 6 Lesson 14 Answer Key

### Eureka Math Grade 2 Module 6 Lesson 14 Sprint Answer Key

A. Subtraction from Teens.

Question 1.
11 – 10 =
1

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 11 – 10. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 1 – 0 = 1. Hence the answer is 1.

Question 2.
12 – 10 =
2

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 12 – 10. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 2 – 0 = 2. Hence the answer is 2.

Question 3.
13 – 10 =
3

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 13 – 10. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 3 – 0 = 3. Hence the answer is 3.

Question 4.
19 – 10 =
9

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 19 – 10. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 – 9 = 1. Hence the answer is 9.

Question 5.
11 – 1 =
10

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 11 – 1. Now we need to subtract the one’s digit. Hence the answer is 1.

Question 6.
12 – 2 =
10

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 12 – 2. Now we need to subtract the one’s digit. Hence the answer is 10.

Question 7.
13 – 3 =
10

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 13 – 3. Now we need to subtract the one’s digit. Hence the answer is 10.

Question 8.
17 – 7 =
10

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 17 – 7. Now we need to subtract the one’s digit. Hence the answer is 10.

Question 9.
11 – 2 =
9

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 11 – 2. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 1 – 2 = 9. Hence the answer is 9.

Question 10.
11 – 3 =
8

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 11 – 3. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 1 – 3 = 8. Hence the answer is 8.

Question 11.
11 – 4 =
7

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 11 – 4. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 1 – 4 = 7. Hence the answer is 7.

Question 12.
11 – 8 =
3

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 11 – 8. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 1 – 8 = 3. Hence the answer is 3.

Question 13.
18 – 8 =
10

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 18 – 8. Now we need to subtract the one’s digit. Hence the answer is 10.

Question 14.
13 – 4 =
9

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 13 – 4. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 3 – 4 = 9. Hence the answer is 9.

Question 15.
13 – 5 =
8

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 13 – 5. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 3 – 5 = 8. Hence the answer is 2.

Question 16.
13 – 6 =
7

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 13 – 6. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 3 – 6 = 7. Hence the answer is 7.

Question 17.
13 – 8 =
5

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 13 – 8. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 3 – 8 = 5. Hence the answer is 5.

Question 18.
16 – 6 =
10

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 16 – 6. Now we need to subtract the one’s digit. Hence the answer is 10.

Question 19.
12 – 3 =
9

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 12 – 3. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 2 – 3 = 9. Hence the answer is 9.

Question 20.
12 – 4 =
8

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 12 – 4. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 2 – 4 = 8. Hence the answer is 8.

Question 21.
12 – 5 =
7

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 12 – 5. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 2 – 5 = 7. Hence the answer is 7.

Question 22.
12 – 9 =
3

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 12 – 9. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 2 – 9 = 3. Hence the answer is 3.

Question 23.
19 – 9 =
10

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 19 – 9. Now we need to subtract the one’s digit. Hence the answer is 10.

Question 24.
15 – 6 =
9

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 15 – 6. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 5 – 6 = 9. Hence the answer is 9.

Question 25.
15 – 7 =
8

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 15 – 7. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 5 – 7 = 8. Hence the answer is 8.

Question 26.
15 – 9 =
6

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 15 – 9. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 5 – 9 = 6. Hence the answer is 6.

Question 27.
20 – 10 =
10

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 20 – 10. Now we need to subtract the one’s digit. Hence the answer is 10.

Question 28.
14 – 5 =
9

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 14 – 5. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 4 – 5 = 9. Hence the answer is 9.

Question 29.
14 – 6 =
8

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 14 – 6. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 4 – 6 = 8. Hence the answer is 8.

Question 30.
14 – 7 =
7

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 14 – 7. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 4 – 7 = 7. Hence the answer is 7.

Question 31.
14 – 9 =
5

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 14 – 9. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 4 – 9 = 5. Hence the answer is 5.

Question 32.
15 – 5 =
10

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 15 – 5. Now we need to subtract the one’s digit. Hence the answer is 10.

Question 33.
17 – 8 =
9

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 17 – 8. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 7 – 8 = 9. Hence the answer is 9.

Question 34.
17 – 9 =
8

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 17 – 9. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 7 – 9 = 8. Hence the answer is 8.

Question 35.
18 – 8 =
10

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 18 – 8. Now we need to subtract the one’s digit. Hence the answer is 10.

Question 36.
16 – 7 =
9

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 16 – 7. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 6 – 7 = 9. Hence the answer is 9.

Question 37.
16 – 8 =
8

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 16 – 8. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 6 – 8 = 8. Hence the answer is 8.

Question 38.
16 – 9 =
7

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 16 – 9. Now we need to subtract the one’s digit. Hence the answer is 7.

Question 39.
17 – 10 =
7

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 17 – 10. Now we need to subtract the one’s digit. Hence the answer is 7.

Question 40.
12 – 8 =
4

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 12 – 8. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 2 – 8 = 4. Hence the answer is 4.

Question 41.
18 – 9 =
9

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 18 – 9. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 8 – 9 = 9. Hence the answer is 9.

Question 42.
11 – 9 =
2

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 11 – 9. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 1 – 2 = 2. Hence the answer is 2.

Question 43.
15 – 8 =
7

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 15 – 8. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 5 – 8 = 7. Hence the answer is 7yyyy.

Question 44.
13 – 7 =
6

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 13 – 7. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 3 – 7 = 6. Hence the answer is 6.

B.
Subtraction from Teens.

Question 1.
11 – 1 =
10

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 11 – 1. Now we need to subtract the one’s digit. Hence the answer is 10.

Question 2.
12 – 2 =
10

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 12 – 2. Now we need to subtract the one’s digit. Hence the answer is 10.

Question 3.
13 – 3 =
10

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 13 – 3. Now we need to subtract the one’s digit. Hence the answer is 10.

Question 4.
18 – 8 =
10

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 18 – 8. Now we need to subtract the one’s digit. Hence the answer is 10.

Question 5.
11 – 10 =
1

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 11 – 10. Now we need to subtract the one’s digit. Hence the answer is 1.

Question 6.
12 – 10 =
2

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 12 – 10. Now we need to subtract the one’s digit. Hence the answer is 2.

Question 7.
13 – 10 =
3

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 13 – 10. Now we need to subtract the one’s digit. Hence the answer is 3.

Question 8.
18 – 10 =
8

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 18 – 10. Now we need to subtract the one’s digit. Hence the answer is 8.

Question 9.
11 – 2 =
9

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 11 – 2. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 1 – 2 = 6. Hence the answer is 9.

Question 10.
11 – 3 =
8

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 11 – 3. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 1 – 3= 8. Hence the answer is 8.

Question 11.
11 – 4 =
7

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 11 – 4. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 1 – 4 = 7. Hence the answer is 7.

Question 12.
11 – 7 =
4

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 11 – 7. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 1 – 7 = 4. Hence the answer is 4.

Question 13.
19 – 9 =
10

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 19 – 9. Now we need to subtract the one’s digit. Hence the answer is 10.

Question 14.
12 – 3 =
9

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 12 – 3. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 2 – 3 = 9. Hence the answer is 9.

Question 15.
12 – 4 =
8

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 12 – 4. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 2 – 4 = 8. Hence the answer is 8.

Question 16.
12 – 5 =
7

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 12 – 5. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 2 – 5 = 7. Hence the answer is 7.

Question 17.
12 – 8 =
4

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 12 – 8. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 2 – 8 = 4. Hence the answer is 4.

Question 18.
17 – 7 =
10

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 17 – 7. Now we need to subtract the one’s digit. Hence the answer is 10.

Question 19.
13 – 4 =
9

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 13 – 4. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 3 – 4 = 9. Hence the answer is 9.

Question 20.
13 – 5 =
8

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 13 – 5. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 3 – 5 = 8. Hence the answer is 8.

Question 21.
13 – 6 =
7

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 13 – 6. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 3 – 6 = 7. Hence the answer is 7.

Question 22.
13 – 9 =
5

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 13 – 9. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 3 – 9 = 5. Hence the answer is 5.

Question 23.
16 – 6 =
10

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 16 – 6. Now we need to subtract the one’s digit. Hence the answer is 10.

Question 24.
14 – 5 =
9

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 12 – 8. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 2 – 8 = 4. Hence the answer is 4.

Question 25.
14 – 6 =
8

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 12 – 8. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 2 – 8 = 4. Hence the answer is 4.

Question 26.
14 – 7 =
7

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 12 – 8. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 2 – 8 = 4. Hence the answer is 4.

Question 27.
14 – 9 =
5

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 12 – 8. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 2 – 8 = 4. Hence the answer is 4.

Question 28.
20 – 10 =
10

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 20 – 10. Now we need to subtract the one’s digit. Hence the answer is 10.

Question 29.
15 – 6 =
9

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 15 – 6. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 5 – 6 = 9. Hence the answer is 9.

Question 30.
15 – 7 =
8

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 15 – 7. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 5 – 7 = 8. Hence the answer is 8.

Question 31.
15 – 9 =
6

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 15 – 9. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 5 – 9 = 6. Hence the answer is 6.

Question 32.
14 – 4 =
10

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 14 – 4. Now we need to subtract the one’s digit. Hence the answer is 10.

Question 33.
16 – 7 =
9

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 16 – 7. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 6 – 7 = 9. Hence the answer is 9.

Question 34.
16 – 8 =
8

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 16 – 8. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 6 – 8 = 8. Hence the answer is 8.

Question 35.
16 – 9 =
7

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 12 – 8. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 2 – 8 = 4. Hence the answer is 4.

Question 36.
20 – 10 =
10

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 20 – 10. Now we need to subtract the one’s digit. Hence the answer is 10.

Question 37.
17 – 8 =
9

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 12 – 8. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 2 – 8 = 4. Hence the answer is 4.

Question 38.
17 – 9 =
8

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 12 – 8. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 2 – 8 = 4. Hence the answer is 4.

Question 39.
16 – 10 =
6

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 16 – 10. Now we need to subtract the one’s digit. Hence the answer is 10.

Question 40.
18 – 9 =
9

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 18 – 9. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 8 – 9 = 9. Hence the answer is 9.

Question 41.
12 – 9 =
3

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 12 – 9. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 2 – 9 = 3. Hence the answer is 3.

Question 42.
13 – 7 =
6

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 13 – 7. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 3 – 7 = 6. Hence the answer is 6.

Question 43.
11 – 8 =
2

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 11 – 8. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 1 – 8 = 2. Hence the answer is 2.

Question 44.
15 – 8 =
7

Explanation:
To solve the problem we must put the largest number on top and the smallest number at the bottom 15 – 8. Now we need to subtract the one’s digit. In this case, the subtrahend one’s digit is larger than the minuend one’s digit. Therefore, we need to “borrow” 10 from the minuend ten’s digit which gives you 10 + 5 – 8 = 7. Hence the answer is 7.

### Eureka Math Grade 2 Module 6 Lesson 14 Problem Set Answer Key

Cut out Rectangles A, B, and C. Then, cut according to directions. Answer each of the following using Rectangles A, B, and C.

Question 1.
Cut out each row of Rectangle A.1

a. Rectangle A has _____ rows.
Rectangle A has 2 rows.

Explanation:
As given in the question I had cut out each row of rectangle A. So rectangle A has 2 rows.

b. Each row has ______ squares.
Each row has 4 squares

Explanation:
As given in the question I had cut out each row of rectangle A. So each row has 4 squares.

c. _____ rows of _____ = _____
2 rows of 4 = 8

Explanation:
After cutting out each row of rectangle A we have 2 rows of 4 that is 8 boxes.

d. Rectangle A has ______ squares.
Rectangle A has 8 squares.

Explanation:
As given in the question I had cut out each row of rectangle A. So the rectangle A has 8 squares.

Question 2.
Cut out each column of Rectangle B.

a. Rectangle B has _____ columns.
Rectangle A has 2 rows.

Explanation:
As given in the question I had cut out each row of rectangle A. So rectangle A has 2 rows.

b. Each column has ______ squares.
Each column has 2 squares.

Explanation:
In the given question each column has 2 squares.

c. _____ columns of _____ = _____
4 columns of 2 = 8

Explanation:
After cutting out each row of the rectangle B we have 4 columns of 2 that are 8.

d. Rectangle B has ______ squares.
Rectangle B has 8 sqaures.

Explanation:
In this question, rectangle B has 8 squares.

Question 3.
Cut out each square from both Rectangles A and B.

a. Construct a new rectangle using all 16 squares.

Explanation:
As asked in the question I have constructed a new rectangle using all 16 squares.

b. My rectangle has ______ rows of ______.
My rectangle has 2 rows of 8

Explanation:
In this, my rectangle has 2 rows of 8.

c. My rectangle also has _____ columns of ______.
My rectangle also has 8 columns of 2.

Explanation:
In this, my rectangle has 8 columns of 2.

2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 = 16
8 + 8 = 16

Explanation:
The two repeated addition number sentences to match your rectangle is  2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 = 16. Another one is 8 + 8 = 16

Question 4.
Construct a new array using the 24 squares from Rectangles A, B, and C.

a. My rectangle has ______ rows of ______.
My rectangle has 4 rows of 6.

Explanation:
I have constructed a new array using the 24 squares from my rectangle has 4 rows of 6.

b. My rectangle also has _____ columns of ______.
My rectangle also has 6 columns of 4.

Explanation:
In this, my rectangle also has 6 columns of 4.

4 + 4 + 4 + 4 + 4 + 4 = 24
6 + 6 + 6 + 6 = 24

Explanation:
I have written two repeated addition number sentences to match your rectangle is 4 + 4 + 4 + 4 + 4 + 4 = 24. Another addition number sentence is 6 + 6 + 6 + 6 =24.

Extension:
Construct another array using the squares from Rectangles A, B, and C.

a. My rectangle has ______ rows of ______.
My rectangle has 3 rows of 8.

Explanation:
I have constructed another array using the squares from the rectangle that has 3 rows of 8.

b. My rectangle also has _____ columns of ______.
My rectangle also has 8 columns of 3

Explanation:
In this question, my rectangle also has 8 columns of 3.

8 + 8 + 8 =24
3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 =24

Explanation:
The two repeated addition number sentences to match the rectangle is 8 + 8 + 8 =24. Another addition number sentence is 3 +3 + 3 + 3 + 3 + 3 + 3 + 3 +3 = 24

### Eureka Math Grade 2 Module 6 Lesson 14 Exit Ticket Answer Key

Question 1.
With your tiles, show 1 rectangle with 12 squares. Complete the sentences below.

I see _____ rows of ____.
I see 2 rows of 6

Explanation:
With your tiles, I see 2 rows of 6.

In the exact same rectangle, I see _____ columns of _____.
In the exact same rectangle, I see 6 columns of 2.

Explanation:
I have seen 6 columns of 2 in the exact same rectangle.

### Eureka Math Grade 2 Module 6 Lesson 14 Homework Answer Key

Question 1.
Imagine that you have just cut this rectangle into rows.

a. What do you see? Draw a picture.

How many squares are in each row?
There are 4 squares in each row.

Explanation:
By observing the picture we can tell that there are 4 squares in each row.

b. Imagine that you have just cut this rectangle into columns. What do you see? Draw a picture.

How many squares are in each column?
3

Explanation:
By observing the picture we can tell that there are 3 squares in each column.

Question 2.
Create another rectangle using the same number of squares.

How many squares are in each row?
6

Explanation:
There are 6 squares in each row.

How many squares are in each column?
2

Explanation:
There are 2 squares in each column.

Question 3.
Imagine that you have just cut this rectangle into rows.

a. What do you see? Draw a picture.

How many squares are in each row?
5

Explanation:
I have drawn a picture of cutting the rectangle into 2 rows. And there are 5 squares in each row.

b. Imagine that you have just cut this rectangle into columns. What do you see? Draw a picture.

How many squares are in each column? _______
4

Explanation:
Question 4.
Create another rectangle using the same number of squares.

How many squares are in each row?